SBI Clerk Β· Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 101–120 of 1495Page 6 of 75
SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)Β·Numerical Ability
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Question 101

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

A bike man can reach a certain place in 45 hrs. If he reduced his speed by 3/5, he goes 54 km less in that time. What is his speed?

  1. AOption (a)

    3 km/hr

  2. BOption (b)

    2 km/hr

  3. COption (c)

    4 km/hr

  4. DOption (d)

    8 km/hr

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

2 km/hr

Why this answer is correct

Shortcut Trick

When time is constant, the distance ratio is equal to the speed ratio.

Speed reduced by 3/5 β†’ New Speed = 1 βˆ’ 3/5 = 2/5 of Original Speed.

Ratio of Speeds (Original : New) = 5 : 2 ∴ Ratio of Distance = 5 : 2.

Difference in distance = 5 βˆ’ 2 = 3 units β†’ 54 km. So, 1 unit = 18 km.

Original Distance = 5 units Γ— 18 = 90 km. Speed = 90 km Γ· 45 hrs = 2 km/hr.

∴ The correct answer is 2 km/hr.

Alternate Method

Given: Time (T) = 45 hrs, Speed reduction = 3/5, Distance reduction = 54 km.

Formula: Distance = Speed Γ— Time

β‡’ Let the original speed be 's' km/hr.

β‡’ Reduced speed = s βˆ’ (3/5)s = (2/5)s km/hr.

β‡’ Original Distance (D1) = s Γ— 45

β‡’ New Distance (D2) = (2/5)s Γ— 45 = 18s

β‡’ Difference in distance (D1 βˆ’ D2) = 45s βˆ’ 18s = 54 km

β‡’ 27s = 54

β‡’ s = 54 Γ· 27 = 2 km/hr

∴ The correct answer is 2 km/hr.

Additional Information

Constant Time Property

When time is kept constant, the ratio of the speeds of two objects is directly proportional to the ratio of the distances covered by them (S1/S2 = D1/D2).

Average Speed

If a person covers a certain distance at speed x and the same distance at speed y, the average speed for the whole journey is (2xy)/(x + y).

Relative Speed

Speed of two bodies moving in the same direction is the difference of their speeds (u βˆ’ v), and in the opposite direction is the sum of their speeds (u + v).

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)Β·Numerical Ability
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Question 102

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Three numbers are in the ratio of 5 : 4 : 8. The sum of first number and second number is equal to sum of third number and 18. Find the difference between third number and second number.

  1. AOption (a)

    90

  2. BOption (b)

    72

  3. COption (c)

    108

  4. DOption (d)

    54

  5. EOption (e)

    60

View answer & explanation

Correct answer

Answer: (b)B.

72

Why this answer is correct

Shortcut Trick

Ratio of numbers = 5 : 4 : 8

Sum of (1st + 2nd) ratio units = 5 + 4 = 9 units

Difference between this sum and 3rd ratio unit = 9 βˆ’ 8 = 1 unit

Given 1 unit = 18

Difference between 3rd (8 units) and 2nd (4 units) = 8 βˆ’ 4 = 4 units

4 units = 4 Γ— 18 = 72

∴ The correct answer is 72.

Alternate Method

Given: Ratio of three numbers = 5 : 4 : 8

Let the three numbers be 5x, 4x, and 8x.

As per the question:

β‡’ (5x + 4x) = 8x + 18

β‡’ 9x = 8x + 18

β‡’ 9x βˆ’ 8x = 18

β‡’ x = 18

To find the difference between the third number and second number:

β‡’ Difference = 8x βˆ’ 4x

β‡’ Difference = 4x

β‡’ Difference = 4 Γ— 18

β‡’ Difference = 72

∴ The correct answer is 72.

Additional Information

Ratio and Proportion

A ratio compares values by division. If a : b : c is given, numbers are assumed as ax, bx, and cx where x is the common multiplier.

Property of Equations

When translating word problems to linear equations, carefully group terms like 'sum of' and 'difference between' to maintain equality.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)Β·Numerical Ability
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Question 103

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Suresh and Goutam started a business to invest their amount in the ratio of 11 ∢ 9 for a year. At the end of the year the total profit will be Rs. 5,000. Find the amount which is 20% more than the profit of Goutam.

  1. AOption (a)

    Rs. 2,500

  2. BOption (b)

    Rs. 2,700

  3. COption (c)

    Rs. 3,600

  4. DOption (d)

    Rs. 2,000

  5. EOption (e)

    Rs. 5,400

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 2,700

Why this answer is correct

Shortcut Trick

Total ratio parts = 11 + 9 = 20 units.

Total profit = Rs. 5,000 β‡’ 1 unit = 5,000 Γ· 20 = Rs. 250. Goutam profit = 9 units = 9 Γ— 250 = Rs. 2,250.

Required value = 120% of Goutam profit = 1.2 Γ— 2,250 = Rs. 2,700.

∴ The correct answer is Rs. 2,700.

Alternate Method

Given β†’ Investment ratio Suresh : Goutam = 11 : 9, Time = 1 year, Total Profit = Rs. 5,000. Formulas: Profit Ratio = Investment Γ— Time | Individual Profit = (Own Ratio Γ· Total Ratio) Γ— Total Profit.

β‡’ Ratio of profits = 11 Γ— 1 : 9 Γ— 1 = 11 : 9. β‡’ Goutam share of profit = (9 Γ· (11 + 9)) Γ— 5,000. β‡’ Goutam profit = (9 Γ· 20) Γ— 5,000 = 9 Γ— 250 = Rs. 2,250. β‡’ Amount 20% more than Goutam profit = 2,250 + (20% of 2,250). β‡’ Result = 2,250 + 450 = Rs. 2,700.

∴ The correct answer is Rs. 2,700.

Additional Information

Partnership Concept

Profit is distributed in the ratio of the product of Investment and Time Period.

Percentage Increase

To find a value x% more than A, use the formula: Result = A Γ— (100 + x) Γ· 100.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)Β·Numerical Ability
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Question 104

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

An article costing Rs.964 is marked to be sold at a price which gives a profit of 25%. What will be its Profit percentage (approx) in a sale when 17% is taken off the marked price?

  1. AOption (a)

    3.7%

  2. BOption (b)

    4%

  3. COption (c)

    3.5%

  4. DOption (d)

    3.2%

  5. EOption (e)

    4.2%

View answer & explanation

Correct answer

Answer: (a)A.

3.7%

Why this answer is correct

Shortcut Trick

Successive percentage formula: Net Change = a + b + (a Γ— b) Γ· 100

Here, profit markup (a) = +25% and discount (b) = βˆ’17%.

Net Profit% = 25 βˆ’ 17 + (25 Γ— βˆ’17) Γ· 100

Net Profit% = 8 βˆ’ 425 Γ· 100 = 8 βˆ’ 4.25 = 3.75%.

The approximate value is 3.7%.

∴ The correct answer is 3.7%.

Alternate Method

Given: Cost Price (CP) = Rs. 964, Markup Profit% = 25%, Discount% = 17%. Formulas: MP = CP Γ— (100 + Markup%) Γ· 100 | SP = MP Γ— (100 βˆ’ Discount%) Γ· 100 | Profit% = (SP βˆ’ CP) Γ· CP Γ— 100.

β‡’ Assume CP = 100 units (

Note:

Actual CP of 964 is redundant for percentage calculation). β‡’ Marked Price (MP) = 100 + 25% of 100 = 125 units. β‡’ Selling Price (SP) = 125 βˆ’ 17% of 125 = 125 βˆ’ 21.25 = 103.75 units. β‡’ Profit = 103.75 βˆ’ 100 = 3.75 units. β‡’ Profit% = (3.75 Γ· 100) Γ— 100 = 3.75%. β‡’ Approx profit percentage = 3.7%.

∴ The correct answer is 3.7%.

Additional Information

Marked Price & Discount

Marked price is the price tagged on an article. Discount is always calculated on the Marked Price unless stated otherwise.

Redundant Data

When the final answer is required in percentage and the initial conditions are in percentages, the absolute value (Rs. 964) does not affect the result.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)Β·Numerical Ability
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Question 105

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

In an election between two candidates, one got 60% of the total valid votes, 30% of the votes were invalid. If the total number of votes was 8000, the number of valid votes that the other candidate got?

  1. AOption (a)

    2280

  2. BOption (b)

    2260

  3. COption (c)

    2220

  4. DOption (d)

    2200

  5. EOption (e)

    2240

View answer & explanation

Correct answer

Answer: (e)E.

2240

Why this answer is correct

Shortcut Trick

Total Votes = 8000

Valid Votes = 70% of 8000 = 5600

Other candidate percentage = 100% βˆ’ 60% = 40%

Required Votes = 40% of 5600 = 2240

∴ The correct answer is 2240.

Alternate Method

Given:

Total votes = 8000

Invalid votes = 30%

First candidate share = 60% of valid votes

Calculations:

β‡’ Valid votes % = 100% βˆ’ 30% = 70%

β‡’ Number of valid votes = 8000 Γ— (70/100) = 5600

β‡’ Share of the other candidate = 100% βˆ’ 60% = 40%

β‡’ Votes of the other candidate = 5600 Γ— (40/100)

β‡’ Votes of the other candidate = 56 Γ— 40 = 2240

∴ The correct answer is 2240.

Additional Information

Percentage Change Base

Always ensure the percentage is applied to the correct base. Here, the candidate share is 60% of valid votes, not total votes.

Valid vs Invalid Votes

Valid Votes = Total Votes βˆ’ Invalid Votes.

Only valid votes are distributed among candidates.

Successive Multiplication

The result can be found in one step: Result = Total Γ— (Valid% / 100) Γ— (Other Candidate% / 100).

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 106

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The table below provides data on the number of two types of shoes, Leather) and Non-leather, sold by differentΒ retailers.

RetailerLeatherNon-leather
A450320
B510480
C480500
D550450
E620580

The total number of shoes sold by retailer E is what percentage of the total number of shoes sold by A?

  1. AOption (a)

    152.28%

  2. BOption (b)

    150.09%

  3. COption (c)

    156.12%

  4. DOption (d)

    155.84%

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

155.84%

Why this answer is correct

Total shoes sold by Retailer E = 620 + 580 = 1200

Total shoes sold by Retailer A = 450 + 320 = 770

Percentage = (Total E Γ· Total A) Γ— 100 = (1200 Γ· 770) Γ— 100 β‰ˆ 155.84%

Hence, the correct answer is 155.84%.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 107

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The table below provides data on the number of two types of shoes, Leather) and Non-leather, sold by differentΒ retailers.

RetailerLeatherNon-leather
A450320
B510480
C480500
D550450
E620580

What is the average number of Non-leather shoes sold per retailer?

  1. AOption (a)

    472

  2. BOption (b)

    484

  3. COption (c)

    466

  4. DOption (d)

    458

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

466

Why this answer is correct

Total Non-leather shoes sold by all retailers:

320 + 480 + 500 + 450 + 580 = 2330

Number of retailers = 5

Average = Total Γ· Number of retailers = 2330 Γ· 5 = 466

Hence, the correct answer is 466.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 108

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The table below provides data on the number of two types of shoes, Leather) and Non-leather, sold by differentΒ retailers.

RetailerLeatherNon-leather
A450320
B510480
C480500
D550450
E620580

What is the ratio of the total number of Leather shoes sold by A and B to the total number of Non-leather shoes sold by B and C?

  1. AOption (a)

    48:49

  2. BOption (b)

    80:99

  3. COption (c)

    66:67

  4. DOption (d)

    54:59

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

48:49

Why this answer is correct

Total Leather shoes sold by A and B:

Leather (A + B) = 450 + 510 = 960

Total Non-leather shoes sold by B and C:

Non-leather (B + C) = 480 + 500 = 980

Leather (A + B) : Non-leather (B + C) = 960 : 980 = 48 : 49

Hence, the correct answer is 48 : 49.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 109

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The table below provides data on the number of two types of shoes, Leather) and Non-leather, sold by differentΒ retailers.

RetailerLeatherNon-leather
A450320
B510480
C480500
D550450
E620580

By what percentage are the sales of Leather shoes less in B as compared to D?Β 

  1. AOption (a)

    4.69%

  2. BOption (b)

    10.23%

  3. COption (c)

    7.27%

  4. DOption (d)

    2.51%

  5. EOption (e)

    5.48%

View answer & explanation

Correct answer

Answer: (c)C.

7.27%

Why this answer is correct

Leather shoes sold:

Retailer B = 510

Retailer D = 550

Difference = 550 βˆ’ 510 = 40

Percentage less = (Difference Γ· D) Γ— 100 = (40 Γ· 550) Γ— 100 β‰ˆ 7.27%

Hence, the correct answer is β‰ˆ 7.27%.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 110

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

The table below provides data on the number of two types of shoes, Leather) and Non-leather, sold by differentΒ retailers.

RetailerLeatherNon-leather
A450320
B510480
C480500
D550450
E620580

What is the total number of shoes (Leather + Non-leather) sold by Retailer C & E?

  1. AOption (a)

    2150

  2. BOption (b)

    2180

  3. COption (c)

    2260

  4. DOption (d)

    2250

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

2180

Why this answer is correct

Retailer C β†’ Leather = 480, Non-leather = 500 β†’ Total = 480 + 500 = 980Β Β 

Retailer E β†’ Leather = 620, Non-leather = 580 β†’ Total = 620 + 580 = 1200Β Β 

Combined total = 980 + 1200 = 2180

Hence, the correct answer is 2180.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 111

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

A boat covers the distance of 11 km in 2 hours along the stream and the same distance in 4 hours against the stream. Find the speed of the boat in still water and current respectively.

  1. AOption (a)

    4.152 km/h and 1.375 km/h

  2. BOption (b)

    4.5 km/h and 1.5 km/h

  3. COption (c)

    4.125 km/h and 1.375 km/hΒ 

  4. DOption (d)

    4.125 km/h and 1.357 km/h

  5. EOption (e)

    4.215 km/h and 1.735 km/h

View answer & explanation

Correct answer

Answer: (c)C.

4.125 km/h and 1.375 km/hΒ 

Why this answer is correct

Shortcut Trick

Downstream Speed (u) = 11 Γ· 2 = 5.5 km/h

Upstream Speed (v) = 11 Γ· 4 = 2.75 km/h

Boat Speed = (u + v) Γ· 2 = (5.5 + 2.75) Γ· 2 = 8.25 Γ· 2 = 4.125 km/h

Current Speed = (u βˆ’ v) Γ· 2 = (5.5 βˆ’ 2.75) Γ· 2 = 2.75 Γ· 2 = 1.375 km/h

∴ The correct answer is 4.125 km/h and 1.375 km/h.

Alternate Method

Given:

Distance (D) = 11 km

Time taken along the stream (t1) = 2 hours

Time taken against the stream (t2) = 4 hours

Formula Used:

Speed = Distance Γ· Time

Downstream Speed (u) = x + y | Upstream Speed (v) = x βˆ’ y

Speed of boat in still water (x) = (u + v) Γ· 2

Speed of current (y) = (u βˆ’ v) Γ· 2

Calculations:

β‡’ Downstream Speed (u) = 11 Γ· 2 = 5.5 km/h

β‡’ Upstream Speed (v) = 11 Γ· 4 = 2.75 km/h

β‡’ Speed of boat (x) = (5.5 + 2.75) Γ· 2

β‡’ x = 8.25 Γ· 2 = 4.125 km/h

β‡’ Speed of current (y) = (5.5 βˆ’ 2.75) Γ· 2

β‡’ y = 2.75 Γ· 2 = 1.375 km/h

∴ The correct answer is 4.125 km/h and 1.375 km/h.

Additional Information

Relative Speed in Water

When moving with the flow, the speeds add up (x + y). When moving against the flow, the stream speed is subtracted from the boat speed (x βˆ’ y).

Average Speed of Boat

If the boat covers equal distance upstream and downstream, Average Speed = (u Γ— v) / x = (x2 βˆ’ y2) / x km/h.

Time Ratio Property

The ratio of Speed of Boat to Speed of Current is given by (tup + tdown) : (tup βˆ’ tdown).

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 112

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

A merchant sells 980 kg of fruits in two parts. One at 11% profit and other at 18% profit. He gains 14% on overall selling. Find how much quantity he sold at 18% profit?

  1. AOption (a)

    490 kg

  2. BOption (b)

    430 kg

  3. COption (c)

    410 kg

  4. DOption (d)

    420 kg

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

420 kg

Why this answer is correct

Shortcut Trick

Use the Alligation Method to find the ratio of quantities.

Profit 1: 11%, Profit 2: 18%, Mean Profit: 14%.

Ratio = (18 βˆ’ 14) : (14 βˆ’ 11) = 4 : 3.

Total units = 4 + 3 = 7 units.

7 units = 980 kg β‡’ 1 unit = 140 kg.

Quantity at 18% profit = 3 Γ— 140 = 420 kg.

∴ The correct answer is 420 kg.

Alternate Method

Given: Total quantity = 980 kg, Part 1 profit = 11%, Part 2 profit = 18%, Overall profit = 14%.

Formulas: Profit = SP βˆ’ CP | Weighted Average = (n1x1 + n2x2) Γ· (n1 + n2)

β‡’ Let quantity at 18% be x kg, then quantity at 11% is (980 βˆ’ x) kg.

β‡’ 11(980 βˆ’ x) + 18x = 14 Γ— 980

β‡’ 10780 βˆ’ 11x + 18x = 13720

β‡’ 7x = 13720 βˆ’ 10780

β‡’ 7x = 2940

β‡’ x = 420 kg.

∴ The correct answer is 420 kg.

Additional Information

Alligation Rule

It is used to find the ratio in which two ingredients at given prices/profits are mixed to produce a mixture of a mean price/profit.

Profit and Loss on Quantities

When overall profit % is given for two parts of a total quantity, the ratio of quantities is inversely proportional to the deviation of their profit % from the mean profit %.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 113

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What should come in place of question mark β€˜?’ in the following number series?

5, 12, 17, 29, 46, 75, 121, ?

  1. AOption (a)

    196

  2. BOption (b)

    192

  3. COption (c)

    185

  4. DOption (d)

    188

  5. EOption (e)

    216

View answer & explanation

Correct answer

Answer: (a)A.

196

Why this answer is correct

The pattern of the given series is a Fibonacci series.

Every number from third number is a sum of the previous two numbers.

β‡’ 17 = 5 + 12

β‡’ 29 = 17 + 12

β‡’ 46 = 29 + 17

β‡’ 75 = 46 + 29

β‡’ 121 = 75 + 46

β‡’ 196 = 121 + 75

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 114

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What should come in place of question mark β€˜?’ in the following series?

3, 4, 13, ?, 87, 168

  1. AOption (a)

    13

  2. BOption (b)

    87

  3. COption (c)

    38

  4. DOption (d)

    168

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

38

Why this answer is correct

The series is formed by the following logic

β‡’ 3 + 12 = 4

β‡’ 4 + 32 = 13

β‡’ 13 + 52 = 38

β‡’ 38 + 72 = 87

β‡’ 87 + 92 = 168

∴ the answer is 38

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 115

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What will come in place of the question mark (?) in the following number series?

17, 38, 80, 164, 332, 668, ?

  1. AOption (a)

    1380

  2. BOption (b)

    1320

  3. COption (c)

    1360

  4. DOption (d)

    1340

  5. EOption (e)

    1260

View answer & explanation

Correct answer

Answer: (d)D.

1340

Why this answer is correct

The pattern of the number series is as follows:

17 Γ— 2 + 4 = 38

38 Γ— 2 + 4 = 80

80 Γ— 2 + 4 = 164

164 Γ— 2 + 4 = 332

332 Γ— 2 + 4 = 668

668 Γ— 2 + 4 = 1340

∴ The required next number is 1340.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 116

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

The population of a town is 63400. It increases by 15% in the first year and decreases by 20% in the second year. what is the population of the town at the end of 2 year?

  1. AOption (a)

    56300

  2. BOption (b)

    57300

  3. COption (c)

    58300

  4. DOption (d)

    58328

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

58328

Why this answer is correct

Given:

Population of town is 63400

In the first year 15% and second year decreases by 20%

Calculation:

According to question,

β‡’ {63400Β Γ— (115/100)Β Γ— (80/100)}

β‡’ 58328

∴ After 2 year later population of town is 58328

Β 

Formula used:

[X + Y + {(XY)/100}%]

β‡’ X = 15%, and Y = - 20%

Applying the net% effect formula

β‡’ [(+15 - 20) - {15Β Γ— 20}/100]

β‡’ - 5 - 3Β 

β‡’ - 8

So, (100 - 8)% of 63400

β‡’ 92% of 63400

β‡’ 58328

∴ After 2 year later population of town is 58328

Β 

1st year 15% increase(3/20) , 2nd year 20% decrease(1/5)

Β  Β yearΒ  =Β  Β  Β  Β  Β  Β Present pop.Β  Β  Β  Β  Β  Β  Β  Β  last pop.

1st year =Β  Β  Β  Β  Β  20Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β 23

2nd yrs =Β  Β  Β  Β  Β  Β  5Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  4

After 2 yrs present pop. 100Β  and last pop.Β 92Β 

Given to 100 unit = 63400

β‡’ 1 unit = 634

β‡’ last population = 634Β Γ— 92

β‡’ 58328

∴ After 2 year later population of town is 58328

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 117

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

Train A started its journey from Vashi at 9 a.m. and arrives Mulund at 2 p.m. on the same day. Train is travelling at a speed of 37 km/h. find the distance between Vashi and Mulund.

  1. AOption (a)

    200 km

  2. BOption (b)

    210 km

  3. COption (c)

    130 km

  4. DOption (d)

    185 km

  5. EOption (e)

    100 km

View answer & explanation

Correct answer

Answer: (d)D.

185 km

Why this answer is correct

Shortcut Trick

Total Time taken from 9 a.m. to 2 p.m. = 5 hours.

Distance = Speed Γ— Time

Distance = 37 Γ— 5 = 185 km.

∴ The correct answer is 185 km.

Alternate Method

Given:

Starting time = 9 a.m.

Arrival time = 2 p.m.

Speed of Train A = 37 km/h

Formula Used:

Distance = Speed Γ— Time

Calculations:

β‡’ Time duration = 2 p.m. βˆ’ 9 a.m.

β‡’ Time duration = (12 βˆ’ 9) + 2 = 5 hours

β‡’ Distance = 37 km/h Γ— 5 hours

β‡’ Distance = 185 km

∴ The correct answer is 185 km.

Additional Information

Speed-Distance Relation

The fundamental relation is Distance = Speed Γ— Time. If Speed is in km/h and Time is in hours, Distance will be in km.

Unit Conversion

To convert Speed from km/h to m/s, multiply by 5/18. To convert m/s to km/h, multiply by 18/5.

Average Speed

Average Speed = Total Distance Γ· Total Time. For two equal distances with speeds x and y, Average Speed = 2xy Γ· (x + y).

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 118

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What will come in the place of the question mark β€˜?’ in the following question?

Β 48% of 250 + 1050 Γ· 3 – √(?) = 423

  1. AOption (a)

    2205

  2. BOption (b)

    2209

  3. COption (c)

    2289

  4. DOption (d)

    2286

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

2209

Why this answer is correct

Given expression:

β‡’ 48% of 250 + 1050 Γ· 3 – √(?) = 423

β‡’ (48/100) Γ— 250 + 1050 Γ· 3 – √(?) = 423

β‡’ (48/100) Γ— 250 + 350 – √(?) = 423

β‡’ 120 + 350 – √(?) = 423

β‡’ 470 – √(?) = 423

β‡’ √(?) = 470 – 423

β‡’ √(?) = 47

β‡’ ? = 2209

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 119

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What approximate value should come in place of the question mark (?) in the following equation

139% of 459 + \(5\frac{1}{2}\)Β of 384 = ?

  1. AOption (a)

    2760

  2. BOption (b)

    2860

  3. COption (c)

    2960

  4. DOption (d)

    2660

  5. EOption (e)

    2560

View answer & explanation

Correct answer

Answer: (a)A.

2760

Why this answer is correct

Given, 139% of 459 + \(5\frac{1}{2}\)Β of 384

Approximating terms to the closest values, we get

β‡’ 140% of 460 + 11/2 Γ— 384

β‡’ (140 Γ— 460)/100 + 11/2 Γ— 384

β‡’ 644 + 2112 = 2756 β‰ˆ 2760

∴ Approx value of the expression is 2760

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 2) (Previous Year Paper)Β·Numerical Ability
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Question 120

SBI Clerk 2025β€’ Numerical Abilityβ€’ Numerical Ability

What should come in the place of question mark β€˜?’ in the following question?

150 + 45 Γ— 2(36 – 16) Γ· 18 = ?

  1. AOption (a)

    500

  2. BOption (b)

    450

  3. COption (c)

    250

  4. DOption (d)

    350

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

250

Why this answer is correct

β‡’ 150 + 45 Γ— 2(36 – 16) Γ· 18 = ?

β‡’ 150 + 45 Γ— 2(20) Γ· 18

β‡’ 150 + 100 = 250

How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.