Time, Speed & Distance Guide & Practice
Practice average speed, relative speed, train problems, and boat-stream questions with shortcut formulas, solved examples and online mock tests. Explore dynamic solver blueprints, master fundamental equations, examine step-by-step solved examples, and practice with real exam-grade mock test sets.
Core Foundations
Fundamental Formulas
- Basic Relation: $\text{Speed} = \frac{\text{Distance}}{\text{Time}}$
- Distance: $\text{Distance} = \text{Speed} \times \text{Time}$
- Time: $\text{Time} = \frac{\text{Distance}}{\text{Speed}}$
Unit Conversions
- km/hr to m/s: Multiply by $\frac{5}{18}$
- m/s to km/hr: Multiply by $\frac{18}{5}$
- Other Conversions:
- 1 mile = 1.609 km = 1760 yards = 5280 feet
- 1 yard = 3 feet
- 1 km = 1000 m
- 1 hr = 60 min = 3600 sec
Proportionality Rules (When one variable is constant)
- Time is constant: Distance is directly proportional to Speed ($D \propto S$).
- Speed is constant: Distance is directly proportional to Time ($D \propto T$).
- Distance is constant: Speed is inversely proportional to Time ($S \propto \frac{1}{T}$).
- If speeds are in the ratio $a:b$, time taken will be in the ratio $b:a$.
Thematic Deep-Dive
1. Average Speed
- General Formula: $\text{Average Speed} = \frac{\text{Total Distance Travelled}}{\text{Total Time Taken}}$
- Constant Distance: If an object covers equal distances at speeds $x$ and $y$:
- $\text{Average Speed} = \frac{2xy}{x+y}$
- Constant Time: If an object travels for equal time intervals at speeds $x$ and $y$:
- $\text{Average Speed} = \frac{x+y}{2}$
2. Relative Speed
- Opposite Direction: Speeds are added ($S_1 + S_2$).
- Same Direction: Speeds are subtracted ($|S_1 - S_2|$).
- Meeting Point: If two objects start at the same time towards each other, the time taken to meet is $\frac{\text{Initial Distance}}{\text{Relative Speed}}$.
3. Problems on Trains
- Crossing a Point Object (Pole, Man): $\text{Distance} = \text{Length of Train}$.
- Crossing a Long Object (Platform, Bridge): $\text{Distance} = \text{Length of Train} + \text{Length of Object}$.
- Two Trains Crossing: $\text{Distance} = \text{Length of Train 1} + \text{Length of Train 2}$.
- Use relative speed based on direction.
4. Boats and Streams
- Still Water Speed ($u$): Speed of boat in stationary water.
- Stream Speed ($v$): Speed of the current.
- Downstream Speed ($D$): $u + v$ (with the flow).
- Upstream Speed ($U$): $u - v$ (against the flow).
- Derived Formulas:
- $u = \frac{D + U}{2}$
- $v = \frac{D - U}{2}$
Solved Examples
Question: A truck covers a distance of 1200 km in 40 hours. What is its average speed? a) 25 km/hr b) 30 km/hr c) 35 km/hr d) 40 km/hr
Question: A 150 m long train crosses a 270 m long platform in 15 seconds. How much time will it take to cross a platform of 186 m? a) 10 sec b) 12 sec c) 15 sec d) 18 sec
Question: A boat takes 40 minutes to travel 20 km downstream. If the speed of the stream is 2.5 km/hr, how much more time will it take to return? a) 5 min b) 8 min c) 10 min d) 12 min
Question: After moving 100 km, a train meets with an accident and travels at 3/4 of its normal speed, arriving 55 min late. Had the accident occurred 20 km further, it would have been only 45 min late. Find the usual speed. a) 30 km/hr b) 40 km/hr c) 50 km/hr d) 60 km/hr