SBI Clerk · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 61–80 of 1495Page 4 of 75
SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 61

SBI Clerk 2025• Numerical Ability• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Average number of cakes sold on Tuesday in shop B, C and D is 42. Find the difference between number of cakes sold in shop A and D on Tuesday?

  1. AOption (a)

    44

  2. BOption (b)

    28

  3. COption (c)

    22

  4. DOption (d)

    26

  5. EOption (e)

    32

View answer & explanation

Correct answer

Answer: (b)B.

28

Why this answer is correct

Calculation

Given: Average (B + C + D)/3 = 42

→ B + C + D = 42 × 3 = 126

B + C = 50 + 48 = 98 → D = 126 – 98 = 28

Shop A on Tuesday = 56

Difference = 56 – 28 = 28 cakes

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 62

SBI Clerk 2025• Numerical Ability• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Ratio of number of cakes sold on Wednesday and Thursday in shop C is 4:5. Number of cakes sold on Thursday in shop B is 19 more than the cakes sold in Thursday in shop C. Find the number of cakes sold in shop B on Thursday?

  1. AOption (a)

    39

  2. BOption (b)

    79

  3. COption (c)

    66

  4. DOption (d)

    54

  5. EOption (e)

    68

View answer & explanation

Correct answer

Answer: (b)B.

79

Why this answer is correct

Calculation

Given: Shop C on Wednesday = 48

Ratio C (Wed) : C (Thu) = 4 : 5

→ C (Thu) = (48 × 5)/4 = 60

Shop B (Thu) = C (Thu) + 19 = 60 + 19 = 79 cakes

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 63

SBI Clerk 2025• Numerical Ability• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Find the ratio of number of cakes sold in shop A on Tuesday and Wednesday together and Number of cakes sold in shop C on Wednesday?

  1. AOption (a)

    19:17

  2. BOption (b)

    21:8

  3. COption (c)

    3:2

  4. DOption (d)

    4:5

  5. EOption (e)

    6:5

View answer & explanation

Correct answer

Answer: (b)B.

21:8

Why this answer is correct

Calculation

Shop A (Tue + Wed) = 56 + 70 = 126

Shop C Wed = 48

Ratio = 126 : 48

→ 21 : 8

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 64

SBI Clerk 2025• Numerical Ability• Numerical Ability

The given table shows the number of cakes sold in three shops [A, B, and C] in four days [ Sunday, Monday, Tuesday, and Wednesday].  

DayCakes sold in shop ACakes sold in shop BCakes sold in shop C
Sunday845564
Monday483232
Tuesday565048
Wednesday706548

Number of cakes sold in shop C on Monday is what percent more or less than the number of cakes sold in same shop on Wednesday?

  1. AOption (a)

    19%

  2. BOption (b)

    33.33%

  3. COption (c)

    25%

  4. DOption (d)

    37.5%

  5. EOption (e)

    20%

View answer & explanation

Correct answer

Answer: (b)B.

33.33%

Why this answer is correct

Calculation

Shop C Monday = 32, Wednesday = 48

Difference = 48 – 32 = 16

Percentage less = (16 ÷ 48) × 100 = 33.33%

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 65

SBI Clerk 2025• Numerical Ability• Numerical Ability

A person covers two- third of distance by bus at 60 km/hr and remaining distance by bicycle at 30 km/hr. He takes 3 hours to cover the total distance. What is the distance covered by bicycle?

  1. AOption (a)

    135 km

  2. BOption (b)

    45 km

  3. COption (c)

    4.5 km

  4. DOption (d)

    13.5 km

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

45 km

Why this answer is correct

Shortcut Trick

Let the total distance be 3x km. Bus distance = 2x, Bicycle distance = x.

Total time = (Distance1 ÷ Speed1) + (Distance2 ÷ Speed2)

⇒ 3 = (2x ÷ 60) + (x ÷ 30) ⇒ 3 = (x ÷ 30) + (x ÷ 30) ⇒ 3 = 2x ÷ 30

⇒ x = (3 × 30) ÷ 2 = 45 km.

∴ The correct answer is 45 km.

Alternate Method

Given: Bus Speed = 60 km/hr, Bicycle Speed = 30 km/hr, Total Time = 3 hours.

Formula: Time = Distance ÷ Speed

Let total distance be D.

⇒ Time taken by bus = (2D/3) ÷ 60 = 2D ÷ 180 = D ÷ 90

⇒ Time taken by bicycle = (D/3) ÷ 30 = D ÷ 90

⇒ Total Time = (D ÷ 90) + (D ÷ 90) = 3

⇒ 2D ÷ 90 = 3

⇒ D = (3 × 90) ÷ 2 = 135 km

⇒ Distance by bicycle = (1/3) × 135

∴ The correct answer is 45 km.

Additional Information

Average Speed Formula

When a distance is divided into parts, Average Speed = Total Distance ÷ Total Time.

Time, Speed, Distance Relationship

For a constant distance, speed is inversely proportional to time (S1/S2 = T2/T1).

Unit Conversion

To convert km/hr to m/s, multiply by 5/18. To convert m/s to km/hr, multiply by 18/5.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 66

SBI Clerk 2025• Numerical Ability• Numerical Ability

At an election involving two candidates, 68 votes were declared invalid. The winning candidate secures 52% and wins by 98 votes. The total number of votes polled is ?

  1. AOption (a)

    2610

  2. BOption (b)

    2500

  3. COption (c)

    2518

  4. DOption (d)

    2382

  5. EOption (e)

    3000

View answer & explanation

Correct answer

Answer: (c)C.

2518

Why this answer is correct

Shortcut Trick

Difference in percentage votes = 52% − (100% − 52%) = 52% − 48% = 4%.

Since 4% of valid votes = 98 votes, then 100% of valid votes = (98 ÷ 4) × 100 = 2450.

Total votes polled = Valid votes + Invalid votes = 2450 + 68 = 2518.

∴ The correct answer is 2518 votes.

Alternate Method

Given: Invalid votes = 68, Winner share = 52%, Victory margin = 98 votes.

Let the total valid votes be V.

⇒ Winner = 52% of V

⇒ Loser = (100 − 52)% of V = 48% of V

⇒ Margin = 52% of V − 48% of V = 4% of V

⇒ 4% of V = 98

⇒ V = (98 × 100) ÷ 4 = 2450

⇒ Total votes polled = V + 68 = 2450 + 68 = 2518

∴ The correct answer is 2518 votes.

Additional Information

Percentage Change Base

Always ensure the percentage is calculated on the Valid Votes base unless the question specifies it is on the Total Polled Votes.

Successive Elections

If voters didn't cast votes, subtract them from Total Voters before calculating Invalid Votes: Total → Cast → Valid → Result.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 67

SBI Clerk 2025• Numerical Ability• Numerical Ability

After giving a discount of 12%, a laptop is sold for Rs. 22,880. Find the market price of the laptop

  1. AOption (a)

    Rs. 24,000

  2. BOption (b)

    Rs. 26,000

  3. COption (c)

    Rs. 34,000

  4. DOption (d)

    Rs. 23,000

  5. EOption (e)

    Rs. 39,000

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 26,000

Why this answer is correct

Shortcut Trick

Market Price (MP) represents 100%.

Discount = 12% ⇒ Selling Price (SP) = 100% − 12% = 88%.

Given SP = Rs. 22,880.

Using unitary method: 88% = 22,880.

1% = 22,880 ÷ 88 = 260.

100% = 260 × 100 = 26,000.

∴ The correct answer is Rs. 26,000.

Alternate Method

Given → Selling Price (SP) = Rs. 22,880 | Discount Percentage = 12%
Formulas: SP = MP × (100 − Discount%) ÷ 100 | MP = (SP × 100) ÷ (100 − Discount%)

⇒ Let the Market Price (MP) be x.
⇒ SP = MP − Discount
⇒ 22,880 = x − (12% of x)
⇒ 22,880 = x − 0.12x
⇒ 22,880 = 0.88x
⇒ x = 22,880 ÷ 0.88
⇒ x = 26,000

∴ The correct answer is Rs. 26,000.

Additional Information

Market Price & Discount

Market Price (List Price) is the price printed on the product. Discount is always calculated on the Market Price.

Ratio Method

12% discount = 12/100 = 3/25. If MP = 25 units, Discount = 3 units, then SP = 22 units. 22 units = 22,880 ⇒ 1 unit = 1,040 ⇒ 25 units = 26,000.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 68

SBI Clerk 2025• Numerical Ability• Numerical Ability

P, Q, R started a business with capital ₹ 35000, ₹ 65000 and ₹ 75000 respectively. At the end of 2 years, the total loss is 70000. What is the loss share of P?

  1. AOption (a)

    ₹ 14000

  2. BOption (b)

    ₹ 20000

  3. COption (c)

    ₹ 25000

  4. DOption (d)

    ₹ 30000

  5. EOption (e)

    ₹ 35000

View answer & explanation

Correct answer

Answer: (a)A.

₹ 14000

Why this answer is correct

Shortcut Trick

Ratio of investments P : Q : R = 35000 : 65000 : 75000 = 7 : 13 : 15.

Total ratio parts = 7 + 13 + 15 = 35 units.

Total loss =  ₹ 70000.

Value of 1 unit = 70000 ÷ 35 =  ₹ 2000.

Loss share of P = 7 units × 2000 =  ₹ 14000.

∴ The correct answer is  ₹ 14000.

Alternate Method

Given: Capital of P =  ₹ 35000, Q =  ₹ 65000, R =  ₹ 75000. Total loss =  ₹ 70000. Time = 2 years (constant).

Formula: Profit/Loss Share = Investment × Time Period.

⇒ Since time is the same for all, the loss is divided in the ratio of their capitals.

⇒ Ratio of loss = 35000 : 65000 : 75000 = 7 : 13 : 15.

⇒ Loss of P = [7 ÷ (7 + 13 + 15)] × 70000.

⇒ Loss of P = (7 ÷ 35) × 70000.

⇒ Loss of P = 7 × 2000 = 14000.

∴ The correct answer is  ₹ 14000.

Additional Information

Partnership Ratios

When the time period for all investments is the same, the profit or loss is shared strictly in the ratio of the capital invested.

Variable Time Investment

If partners invest for different durations, the ratio is calculated as: (C1 × T1) : (C2 × T2) : (C3 × T3).

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 69

SBI Clerk 2025• Numerical Ability• Numerical Ability

A and B start a business with Rs. 10000 and Rs. 14000. A invest his money for 12 months and B invest his money for n months. After one year ratio of investment of A and B is 15:14. The share of profit of A is Rs. 1200 where total profit is Rs. 2320. If A invest for n months and B invest for 12 months and total profit is Rs. 7750 then the share of profit of B is Rs. z.

Find the value of n?

  1. AOption (a)

    10

  2. BOption (b)

    6

  3. COption (c)

    5

  4. DOption (d)

    4

  5. EOption (e)

    8

View answer & explanation

Correct answer

Answer: (e)E.

8

Why this answer is correct

Profit ratio is proportional to investment × time:

[A × 12] / [B × n] = 15/14

[10000 × 12] / [14000 × n] = 15/ 14

[120000 × 14 = 15 × 14000 × n]

n = 8 months

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 70

SBI Clerk 2025• Numerical Ability• Numerical Ability

A and B start a business with Rs. 10000 and Rs. 14000. A invest his money for 12 months and B invest his money for n months. After one year ratio of investment of A and B is 15:14. The share of profit of A is Rs. 1200 where total profit is Rs. 2320. If A invest for n months and B invest for 12 months and total profit is Rs. 7750 then the share of profit of B is Rs. z.

Find the value of z?

  1. AOption (a)

    4720

  2. BOption (b)

    5250

  3. COption (c)

    6250

  4. DOption (d)

    4750

  5. EOption (e)

    3600

View answer & explanation

Correct answer

Answer: (b)B.

5250

Why this answer is correct

Common calculation

Profit ratio is proportional to investment × time:

[A × 12] / [B × n] = 15/14

[10000 × 12] / [14000 × n] = 15/ 14

[120000 × 14 = 15 × 14000 × n]

n = 8 months

Now, New case A invest for n = 8 months and B for 12 months

A invests = 10,000 for 8 months → A × time = 10,000 × 8 = 80,000

B invests = 14,000 for 12 months → B × time = 14,000 × 12 = 168,000

Profit ratio A : B = 80,000 : 168,000 = 10 : 21

Total ratio sum = 10 + 21 = 31

Total profit = 7750

B’s share z = [21/31] × 7750 = 5250

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 71

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the average number of males in company A and C?

  1. AOption (a)

    24

  2. BOption (b)

    31

  3. COption (c)

    28

  4. DOption (d)

    35

  5. EOption (e)

    26

View answer & explanation

Correct answer

Answer: (c)C.

28

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Males in A = 20, Males in C = 36

Average = (20 + 36) ÷ 2 = 56 ÷ 2 = 28

Hence, the correct answer is 28.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 72

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

If the number of females in company C were 10% more, what would be the new total number of females?

  1. AOption (a)

    82

  2. BOption (b)

    79

  3. COption (c)

    67

  4. DOption (d)

    55

  5. EOption (e)

    94

View answer & explanation

Correct answer

Answer: (c)C.

67

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Original females:

A = 25

B = 20

C = 20

Increase females in C by 10%:

New females in C = 20 × 1.10 = 22

Total females now = 25 + 20 + 22 = 67

Hence, the correct answer is 67.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 73

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the ratio of the number of males in company C to the number of females in company B?

  1. AOption (a)

    8:3

  2. BOption (b)

    9:5

  3. COption (c)

    4:1

  4. DOption (d)

    5:3

  5. EOption (e)

    6:5

View answer & explanation

Correct answer

Answer: (b)B.

9:5

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

From previous solution:

Males in C = 36

Females in B = 20

Ratio (Males in C : Females in B) = 36 : 20 = 9 : 5

Hence, the correct answer is 9 : 5.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 74

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

The number of females in company B is what percentage of the number of males in company A?

  1. AOption (a)

    25%

  2. BOption (b)

    50%

  3. COption (c)

    75%

  4. DOption (d)

    100%

  5. EOption (e)

    125%

View answer & explanation

Correct answer

Answer: (d)D.

100%

Why this answer is correct

Females with B = 20

Males with A = 20

Required percentage = (Females B ÷ Males A) × 100

= (20 ÷ 20) × 100 = 100%

Hence, the correct answer is 100%.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 75

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the difference between the number of males and females in company C?

  1. AOption (a)

    14

  2. BOption (b)

    12

  3. COption (c)

    10

  4. DOption (d)

    16

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (d)D.

16

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

From general solution, Person C has:

Males = 36

Females = 20

Difference = Males − Females = 36 − 20 = 16

Hence, the correct answer is 16.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 76

SBI Clerk 2025• Numerical Ability• Numerical Ability

Directions: Read the following information carefully and answer the questions based on it.

There are three companies: A, B, and C, each with a certain number of males and females.

The total number of males across A, B, and C is 86. The number of females with person A is 25% more than the number of females with person B. The number of males with person B is 1.5 times the number of males with person A. The number of males with person C is 6 more than the number of males with person B. The number of females with person C is 20, which is 20% less than the number of females in A.

What is the total number of females with companies A and B combined?

  1. AOption (a)

    48

  2. BOption (b)

    39

  3. COption (c)

    46

  4. DOption (d)

    55

  5. EOption (e)

    45

View answer & explanation

Correct answer

Answer: (e)E.

45

Why this answer is correct

General Solution:

Let

Males: A = x, B = y, C = z

Total males: x + y + z = 86

Given: y = 1.5 × x ⇒ y = 3x/2

z = y + 6 = 3x/2 + 6

Solve for x:

x + y + z = 86 ⇒ x + 3x/2 + (3x/2 + 6) = 86

x + 1.5x + 1.5x + 6 = 86

4x + 6 = 86 ⇒ 4x = 80 ⇒ x = 20

Then y = 1.5 × 20 = 30

z = 30 + 6 = 36

Females:

Let females in B = fB

Females in A = fA = 1.25 × fB

Females in C = fC = 20 = 0.8 × fA ⇒ fA = 25

Then fB = fA/1.25 = 25/1.25 = 20

Thus,

Males: A = 20, B = 30, C = 36

Females: A = 25, B = 20, C = 20

Calculations:

Females with A = 25, Females with B = 20

Total females with A and B = 25 + 20 = 45

Hence, the correct answer is 45.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 77

SBI Clerk 2025• Numerical Ability• Numerical Ability

A borrowed sum was paid in two instalments of Rs.121 each. If the rate of compound interest is 10% per annum , what sum was borrowed?

  1. AOption (a)

    220

  2. BOption (b)

    210

  3. COption (c)

    200

  4. DOption (d)

    240

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

210

Why this answer is correct

Shortcut Trick

Rate = 10% = 1/10. For Compound Interest instalments, ratio of Principal to Amount for 1st year is 10 : 11 and for 2nd year is 102 : 112 = 100 : 121.

To make instalments equal, multiply 1st year ratio by 11: (10 × 11) : (11 × 11) = 110 : 121.

Total Principal = 110 + 100 = 210 units. Given instalment (121 units) = ₹121.

∴ 1 unit = ₹1. Total sum = 210 × 1 = ₹210.

∴ The correct answer is ₹210.

Alternate Method

Given: Instalment (I) = ₹121, Rate (r) = 10%, n = 2 years.

Formula Used: Principal (P) = [I / (1 + r/100)1] + [I / (1 + r/100)2]

⇒ P = [121 / (1 + 10/100)] + [121 / (1 + 10/100)2]

⇒ P = [121 / (1.1)] + [121 / (1.1)2]

⇒ P = [121 / 1.1] + [121 / 1.21]

⇒ P = 110 + 100

⇒ P = ₹210

∴ The correct answer is ₹210.

Additional Information

CI Instalment Formula

The total principal P for n instalments of value I is P = I × [((1+R)n − 1) / (R(1+R)n)], where R is the decimal rate.

Present Value Method

Total sum borrowed is the sum of the present values of each instalment: P = PV1 + PV2 + ... + PVn.

SI vs CI Instalment

In Simple Interest, instalments are calculated on a linear basis, whereas in Compound Interest, each instalment reduces the principal exponentially.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 78

SBI Clerk 2025• Numerical Ability• Numerical Ability

The circle and rectangle have the same area. The length and breadth of the rectangle are 44 cm and 56 cm respectively, then what is the area of the circle?

  1. AOption (a)

    2464 cm2

  2. BOption (b)

    2500 cm2

  3. COption (c)

    2564 cm2

  4. DOption (d)

    2600 cm2

  5. EOption (e)

    2574 cm2

View answer & explanation

Correct answer

Answer: (a)A.

2464 cm2

Why this answer is correct

Shortcut Trick

Since Area of Circle = Area of Rectangle, simply multiply the dimensions of the rectangle.

Area = Length × Breadth = 44 × 56.

Calculation: 44 × 56 = 2464 cm2.

∴ The correct answer is 2464 cm2.

Alternate Method

Given:

Length of rectangle (L) = 44 cm

Breadth of rectangle (B) = 56 cm

Formula Used:

Area of Rectangle = Length × Breadth

Calculations:

⇒ Area of rectangle = 44 × 56

⇒ Area of rectangle = 2464 cm2

⇒ According to the question, Area of Circle = Area of Rectangle

⇒ Area of Circle = 2464 cm2

∴ The correct answer is 2464 cm2.

Additional Information

Area of Circle

The area of a circle is calculated using the formula A = πr2, where r is the radius.

Perimeter of Rectangle

The perimeter of a rectangle is the total distance around the outside, calculated as P = 2 × (Length + Breadth).

Circumference of Circle

The boundary of a circle is called the circumference, given by the formula C = 2πr or πd.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 79

SBI Clerk 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

410 × ? × 26 = 67250 + 50010

  1. AOption (a)

    11

  2. BOption (b)

    14

  3. COption (c)

    16

  4. DOption (d)

    22

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

11

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 410 × ? × 26 = 67250 + 50010

⇒ 10660 × ? = 117260

⇒ \(?; = ;\frac{{117260}}{{10660}}; = ;11\)

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 1) (Previous Year Paper)·Numerical Ability
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Question 80

SBI Clerk 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

207 ÷ 3 × 2.25 + 43.5 – 9 = ?

  1. AOption (a)

    136.45

  2. BOption (b)

    123.85

  3. COption (c)

    142.95

  4. DOption (d)

    189.75

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

189.75

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 207 ÷ 3 × 2.25 + 43.5 – 9 = ?

⇒ 69 × 2.25 + 43.5 – 9 = ?

⇒ 155.25 + 43.5 – 9 = ?

⇒ 198.75 – 9 = ?

⇒ 189.75 = ?

How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.