Reasoning PYQs

Given persons are D, H, K, M, R and T; given fruits are Apple, Banana, Grapes, Guava, Kiwi and Orange.

1. There is only one floor between R and the person who likes Kiwi.

2. The person who likes Kiwi lives below the floor of M.

 

3. The person who likes Orange lives to the Northeast of M who does not like Apple.

4. Neither M nor R likes Guava.

5. No one sits to the west of the person who likes Guava. So, case 1 is eliminated.

 

6. The person who likes Apple lives to the Northwest of H who lives in the same flat as of D. So, case 3 and case 4(b) are eliminated.

7. D and T do not live on same floor and same type of flat.

8. The person who likes Banana and the one who likes Guava live on same type of flat.

 

9. T lives neither on same floor as of R nor to the south of K, who does not like Grapes. So, case 4(a) is eliminated. Hence, the final arrangement is as follows

 

Since, R lives on Flat A not in Flat B and likes Apple so combination first is incorrect, H lives on Floor 1 and likes Kiwi so second combination is incorrect, since T lives on Flat A and likes Guava so third combination is incorrect and M lives on Floor 2 and likes Banana so combination fourth is correct. 

Hence, the correct combination is M - Floor 2 - Banana.

Given persons are D, H, K, M, R and T; given fruits are Apple, Banana, Grapes, Guava, Kiwi and Orange.

1. There is only one floor between R and the person who likes Kiwi.

2. The person who likes Kiwi lives below the floor of M.

 

3. The person who likes Orange lives to the Northeast of M who does not like Apple.

4. Neither M nor R likes Guava.

5. No one sits to the west of the person who likes Guava. So, case 1 is eliminated.

 

6. The person who likes Apple lives to the Northwest of H who lives in the same flat as of D. So, case 3 and case 4(b) are eliminated.

7. D and T do not live on same floor and same type of flat.

8. The person who likes Banana and the one who likes Guava live on same type of flat.

 

9. T lives neither on same floor as of R nor to the south of K, who does not like Grapes. So, case 4(a) is eliminated. Hence, the final arrangement is as follows

 

Hence, D likes Grapes.

According to the given condition, in the given number 90273465 when we add 2 in each even digits and subtract 2 from each odd digits then the number becomes 72451683. 

Now, we arrange the new number according to numeric series it becomes 12345678.

Hence, the digit comes third from right end is 6.

Given, persons B, D, H, J, M, P, R and U; given years are 1987, 1992, 1996, 1998, 2004, 2006, 2009 and 2011.

1. The age of M is twice the age of B.

2. D born in a leap year.

 

3.  The difference between ages of H and U is one more than that of between P and M. So, case 2 is eliminated.

4. As many persons born before P as many persons after H.     

 

5. J does not born before R but born before D. So, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, statement first the age of R is a prime number is correct, statement second M born just before D is correct, statement third J born in a leap year is correct and statement fourth U is two years older than B is also correct. Therefore, all the given statements are correct.

Hence, the correct answer is None of these.

Given, persons B, D, H, J, M, P, R and U; given years are 1987, 1992, 1996, 1998, 2004, 2006, 2009 and 2011.

1. The age of M is twice the age of B.

2. D born in a leap year.

 

3.  The difference between ages of H and U is one more than that of between P and M. So, case 2 is eliminated.

4. As many persons born before P as many persons after H.     

 

5. J does not born before R but born before D. So, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, B is the youngest person.

Given, persons B, D, H, J, M, P, R and U; given years are 1987, 1992, 1996, 1998, 2004, 2006, 2009 and 2011.

1. The age of M is twice the age of B.

2. D born in a leap year.

 

3.  The difference between ages of H and U is one more than that of between P and M. So, case 2 is eliminated.

4. As many persons born before P as many persons after H.     

 

5. J does not born before R but born before D. So, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, R born in a prime year before D.

Given, persons B, D, H, J, M, P, R and U; given years are 1987, 1992, 1996, 1998, 2004, 2006, 2009 and 2011.

1. The age of M is twice the age of B.

2. D born in a leap year.

 

3.  The difference between ages of H and U is one more than that of between P and M. So, case 2 is eliminated.

4. As many persons born before P as many persons after H.     

 

5. J does not born before R but born before D. So, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, P born in a leap year so statement A is correct, U is the second youngest person so statement B is correct and M born just after P not just before so statement C is correct.

Hence, the correct answer is Both A and B.

Given, persons B, D, H, J, M, P, R and U; given years are 1987, 1992, 1996, 1998, 2004, 2006, 2009 and 2011.

1. The age of M is twice the age of B.

2. D born in a leap year.

 

3.  The difference between ages of H and U is one more than that of between P and M. So, case 2 is eliminated.

4. As many persons born before P as many persons after H.     

 

5. J does not born before R but born before D. So, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, two persons born between U and M.

From the question, Eight persons G, H, I, J, R, S, T and U sit on two parallel rows such that on row 1 R, S, T and U sit and faces towards North direction whereas on row 2 G, H, I and J sit and face towards South direction so that each person on row 1 faces each person on row 2.

From statement I, J sits two places away from I who sits opposite to T. Two persons sit between R and S who does not sit opposite to H.

Therefore, statement I alone in not sufficient to answer the given question.

From statement II, Neither U nor S sits opposite to J. S does not sit to the left of T. G sits three places away from the person who sits opposite to R.

Therefore, statement II alone is not sufficient to answer the given question.

Now by combining both the statements, we get

Therefore, both statement I and statement II together are required to answer the question.

Hence, both statement I and statement II together are necessary to answer the question.

From the question, Seven boxes D, J, N, O, T, U and V are stacked one over another from bottom to top.

From the statement I, Only two boxes placed between box J and box N which is placed just above the box D. Not more than three boxes are placed below box N.

 

Therefore, statement I alone is not sufficient to answer the given question.

From statement II, As many box placed above O as many box placed below it.

Only one box is placed between box J and box T. Since, we cannot conclude anything by second statement.

Therefore, statement II alone is not sufficient to answer the given question.

If we combine both the statement we get,

 

Both statement I and statement II together are not sufficient to answer the given question.

Hence, both statement I and statement together are not sufficient to answer the given question.

Given persons D, H, I, L, N, O, P and S.

1. Only three persons sit between O and N who faces in North direction.

2. O sits second to the right of P who sits immediate left of L.

3. I sit second to the left of N who sits immediate right of H.

4. The person who sits at extreme end faces in opposite direction.

5. S sits second left of D.

6. I and H face in same direction but opposite to S who faces in the same direction as of N. Therefore, both I and H face in south direction whereas S faces in North direction. So, case – 2 is eliminated.

7. H sits two places away from D. So, case – 3 is eliminated.

8. S does not sit to the right of O. So, case – 4 is eliminated.

Hence, the final arrangement is as follows

Hence, the correct answer is PH.

Given persons D, H, I, L, N, O, P and S.

1. Only three persons sit between O and N who faces in North direction.

2. O sits second to the right of P who sits immediate left of L.

3. I sit second to the left of N who sits immediate right of H.

4. The person who sits at extreme end faces in opposite direction.

5. S sits second left of D.

6. I and H face in same direction but opposite to S who faces in the same direction as of N. Therefore, both I and H face in south direction whereas S faces in North direction. So, case – 2 is eliminated.

7. H sits two places away from D. So, case – 3 is eliminated.

8. S does not sit to the right of O. So, case – 4 is eliminated.

Hence, the final arrangement is as follows

Since, all except I faces towards North direction whereas I faces towards South direction.

Hence, the correct answer is I.

Given persons D, H, I, L, N, O, P and S.

1. Only three persons sit between O and N who faces in North direction.

2. O sits second to the right of P who sits immediate left of L.

3. I sit second to the left of N who sits immediate right of H.

4. The person who sits at extreme end faces in opposite direction.

5. S sits second left of D.

6. I and H face in same direction but opposite to S who faces in the same direction as of N. Therefore, both I and H face in south direction whereas S faces in North direction. So, case – 2 is eliminated.

7. H sits two places away from D. So, case – 3 is eliminated.

8. S does not sit to the right of O. So, case – 4 is eliminated.

Hence, the final arrangement is as follows

Hence, the correct statement is H sits at one of the extreme end.

Given persons D, H, I, L, N, O, P and S.

1. Only three persons sit between O and N who faces in North direction.

2. O sits second to the right of P who sits immediate left of L.

3. I sit second to the left of N who sits immediate right of H.

4. The person who sits at extreme end faces in opposite direction.

5. S sits second left of D.

6. I and H face in same direction but opposite to S who faces in the same direction as of N. Therefore, both I and H face in south direction whereas S faces in North direction. So, case – 2 is eliminated.

7. H sits two places away from D. So, case – 3 is eliminated.

8. S does not sit to the right of O. So, case – 4 is eliminated.

Hence, the final arrangement is as follows

Since, S sits immediate left to O and L sits second left to S.

Hence, the correct answer is L.

Given persons D, H, I, L, N, O, P and S.

1. Only three persons sit between O and N who faces in North direction.

2. O sits second to the right of P who sits immediate left of L.

3. I sit second to the left of N who sits immediate right of H.

4. The person who sits at extreme end faces in opposite direction.

5. S sits second left of D.

6. I and H face in same direction but opposite to S who faces in the same direction as of N. Therefore, both I and H face in south direction whereas S faces in North direction. So, case – 2 is eliminated.

7. H sits two places away from D. So, case – 3 is eliminated.

8. S does not sit to the right of O. So, case – 4 is eliminated.

Hence, the final arrangement is as follows

Since, D sits immediate left to I so, statement A is correct.

Five persons faces towards North direction whereas only three persons facing towards South direction so statement B is also correct.

H sits at extreme right end not at left end so, statement C is incorrect.

Hence, the correct answer is More than one option.

Boxes: P, Q, R, S, T, U and V.

1. Equal number of boxes are above and below box R.
2. There is one box between box R and box U.

 

3. Box P is just above box V, which is an even-numbered box.

 

4. Box T is above box S and neither box T nor S is adjacent to box R. So, case 2 would be invalid. Also, box Q must be box 3.

Hence, box Q is just above box R.

Boxes: P, Q, R, S, T, U and V.

1. Equal number of boxes are above and below box R.
2. There is one box between box R and box U.

 

3. Box P is just above box V, which is an even-numbered box.

 

4. Box T is above box S and neither box T nor S is adjacent to box R. So, case 2 would be invalid. Also, box Q must be box 3.

 

So, Box T is the topmost box.

Hence, "only statement (3)" is correct.

Boxes: P, Q, R, S, T, U and V.

1. Equal number of boxes are above and below box R.
2. There is one box between box R and box U.

 

3. Box P is just above box V, which is an even-numbered box.

 

4. Box T is above box S and neither box T nor S is adjacent to box R. So, case 2 would be invalid. Also, box Q must be box 3.

 

So, box U remains at the same position when boxes are arranged in reverse alphabetical order from top to bottom.

Hence, the correct answer is "U".

Boxes: P, Q, R, S, T, U and V.

1. Equal number of boxes are above and below box R.
2. There is one box between box R and box U.

 

3. Box P is just above box V, which is an even-numbered box.

 

4. Box T is above box S and neither box T nor S is adjacent to box R. So, case 2 would be invalid. Also, box Q must be box 3.

Hence, five boxes are above box V.

Boxes: P, Q, R, S, T, U and V.

1. Equal number of boxes are above and below box R.
2. There is one box between box R and box U.

 

3. Box P is just above box V, which is an even-numbered box.

 

4. Box T is above box S and neither box T nor S is adjacent to box R. So, case 2 would be invalid. Also, box Q must be box 3.

 

Hence, box S is the bottommost box.