UPTET · Topic Collection

Mathematics and Science PYQs

Elementary mathematics and science content with the pedagogical issues of teaching both subjects, as asked in upper-primary teacher papers.

300 Total Questions5 Official PapersYears: 2016–2021Search in Mathematics and Science
Showing questions 81–100 of 300Page 5 of 15
UPTET 2019 Paper 2 (Maths & Science) (Hindi / English / Sanskrit) (Previous Year Paper)·Mathematics and Science
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Question 81

UPTET 2019• Mathematics and Science• Mathematics and Science

For the equation y = 7x - 2, which of the following statement is true?

  1. AOption (a)

    It has a unique solution.

  2. BOption (b)

    It has two solutions

  3. COption (c)

    It has infinite number of solutions

  4. DOption (d)

    It has no solution

View answer & explanation

Correct answer

Answer: (c)C.

It has infinite number of solutions

Why this answer is correct

Calculation:

For the equation y = 7x - 2

To find the number of solutions we need to calculate the 

Substituting x = 0

y = -2

Similarly,

for y = 0, x = 2/7

The given equation y = 7x - 2 is similar to equation of straight line y = mx + c,

As we know that, a straight line has an infinite number of solutions;

∴ y = 7x - 2 has an infinite number of solutions.

UPTET 2019 Paper 2 (Maths & Science) (Hindi / English / Sanskrit) (Previous Year Paper)·Mathematics and Science
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Question 82

UPTET 2019• Mathematics and Science• Mathematics and Science

(49)15 - 1 is completely divisible by which number?

i. 50

ii. 48

iii. 29

iv. 8

  1. AOption (a)

    ii and iv

  2. BOption (b)

    iii and iv

  3. COption (c)

    i and iii

  4. DOption (d)

    i and ii

View answer & explanation

Correct answer

Answer: (a)A.

ii and iv

Why this answer is correct

an - bn is divisible by a - b for all n.

an - bn is divisible by a + b if n is Even.

an + bn is divisible by a + b if n is Odd.

(49)15 - (1)15, here n = 15 i.e. odd

So it will be divisible by 49 - 1 = 48

(49)15 can also be written as (72)15 = (7)30

∴ (49)15 - (1)15 = (7)30 - (1)30 

So it will also be divisible by 7 + 1 = 8

UPTET 2019 Paper 2 (Maths & Science) (Hindi / English / Sanskrit) (Previous Year Paper)·Mathematics and Science
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Question 83

UPTET 2019• Mathematics and Science• Mathematics and Science

Value of \(\dfrac{\cos 135^\circ \sin 210^\circ \cos 150^\circ}{\sin 270^\circ \cos 315^\circ}\) is

  1. AOption (a)

    \(\dfrac{1}{\sqrt{3}}\)

  2. BOption (b)

    \(\dfrac{\sqrt{3}}{4}\)

  3. COption (c)

    \(\sqrt{3}\)

  4. DOption (d)

    \(\dfrac{\sqrt{3}}{2}\)

View answer & explanation

Correct answer

Answer: (b)B.

\(\dfrac{\sqrt{3}}{4}\)

Why this answer is correct

Concept Used:

Calculation:

cos135° = cos(45 + 90) = - cos45° = - 1/√2

sin210° = sin(180 + 30) = - sin30° = - 1/2

cos150° = cos(90 + 60) = - sin60° = - √3/2

sin270° = sin(90 + 180) = - sin90 = - 1

cos315° = cos(360 - 45) = cos45° = 1/√2

Put the above value in equation:

{(-1/√2) × (-1/2) × (-√3/2)} / {(-1) × (1/√2)}

⇒ (- √3 / 4√2) / (- 1/ √2)

⇒ √3 / 4

∴ The required simplified value is √3/4.

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Question 84

UPTET 2019• Mathematics and Science• Mathematics and Science

The multiplication of two consecutive odd numbers is 6723, then square root of the smaller number is

  1. AOption (a)

    7

  2. BOption (b)

    729

  3. COption (c)

    91

  4. DOption (d)

    9

View answer & explanation

Correct answer

Answer: (d)D.

9

Why this answer is correct

Let the two odd numbers be x and x + 2

According to question:

x( x + 2) = 6723

x² + 2x = 6723

x² + 2x - 6723 = 0

So x = 81 and x + 2 = 83

Smaller number = 81

Square root of 81 = 9

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Question 85

UPTET 2019• Mathematics and Science• Mathematics and Science

If highest common factor of x2 + px - q and 5x2 - 3px - 15q is (x - 3), then value of p and q will be

  1. AOption (a)

    \(-\dfrac{5}{3}, 4\)

  2. BOption (b)

    \(-\dfrac{5}{3}, -4\)

  3. COption (c)

    \(\dfrac{5}{3}, 4\)

  4. DOption (d)

    \(4, - \dfrac{3}{5}\)

View answer & explanation

Correct answer

Answer: (a)A.

\(-\dfrac{5}{3}, 4\)

Why this answer is correct

GIVEN:

x2 + px - q      ----(1)

5x2 - 3px - 15q      ----(2)

(x - 3) is a factor 

CALCULATION:

As (x - 3) is a factor

On substituting x = 3, the equations (1) and (2) will be 0

Now, equation (1) becomes

9 + 3p - q = 0      ----(3)

Similarly, equation (2) becomes

45 - 9p -15q = 0      ----(4)

On solving (3) and (4) simultaneously, we get

∴ p = -5/3, q = 4

UPTET 2019 Paper 2 (Maths & Science) (Hindi / English / Sanskrit) (Previous Year Paper)·Mathematics and Science
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Question 86

UPTET 2019• Mathematics and Science• Mathematics and Science

A hemisphere and a cone is having same base and same height. Their area of curved surfaces are in the ratio

  1. AOption (a)

    \(1 :\sqrt{2}\)

  2. BOption (b)

    \( \sqrt{3}: 1\)

  3. COption (c)

    \( 1 : \sqrt{3}\)

  4. DOption (d)

    \( \sqrt{2} : 1\)

View answer & explanation

Correct answer

Answer: (d)D.

\( \sqrt{2} : 1\)

Why this answer is correct

Given:

Hemisphere and a cone is having the same base and the same height

Formula used:

The curved surface area of hemisphere = 2πr2

Curved surface area of cone = πrl = πr(√r2 + h2)

Calculation:

Given that base is also the same, so their radius will also be the same.

Also, the height of the hemisphere is equal to its Radius = r

Height of both hemisphere and cone = r or r = h

Curved surface area of cone = πrl = πr(√r2 + h2) = πr(√r2 + r2) = πr√2 × r

∴ Ratio = 2πr2 : πr√2 × r = √2 : 1

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Question 87

UPTET 2019• Mathematics and Science• Mathematics and Science

If the difference between the selling price of the article when there is 15% loss and 15% gain is Rs. 450, then the cost price is.

  1. AOption (a)

    Rs. 1,500

  2. BOption (b)

    Rs. 2,000

  3. COption (c)

    Rs. 2,200

  4. DOption (d)

    Rs. 1,200

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 1,500

Why this answer is correct

Calculation:

Let CP = Rs. 100

Profit = Cost Price + Profit on CP

15% gain = 100 + 15% of 100 = Rs. 115 

15% loss = 100 - 15% of 100 = Rs. 85

According to the question:

(115 - 85) unit = Rs. 450 (given)

∴  1 unit = Rs. 15

∴ Cost price = 100 × 15 = Rs. 1500

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Question 88

UPTET 2019• Mathematics and Science• Mathematics and Science

If ΔABC is an isosceles triangle such that ∠ABC = 90°, then the true statement about ΔABC is    

  1. AOption (a)

    2(AC)2 = (AB)2

  2. BOption (b)

    (AB)2 + (AC)2 = (BC)2

  3. COption (c)

    (BC)2 + (AC)2 = (AB)2

  4. DOption (d)

    (AC)2 = 2(AB)2

View answer & explanation

Correct answer

Answer: (d)D.

(AC)2 = 2(AB)2

Why this answer is correct

Calculation:

In isosceles triangle, 2 sides are equal,

 ∠ABC = 90°, then AB = BC  and AC will be hypotenuse.

By Pythagoras theorem

∴ AC2 = AB2 + BC2 = 2AB2

(AC)2 = 2(AB)2

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Question 89

UPTET 2019• Mathematics and Science• Mathematics and Science

If a man covers \(\frac{4}{5}^{\rm th}\) part of a circular track in m minutes, at the same rate, how many minutes does he take to complete one revolution around the entire track?

  1. AOption (a)

    \(\frac{4 m}{4}\) minutes

  2. BOption (b)

    \(\frac{4 m}{5}\) minutes

  3. COption (c)

    \(\frac{5m }{4}\) minutes

  4. DOption (d)

    \(\frac{m}{4}\) minutes

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{5m }{4}\) minutes

Why this answer is correct

Calculation:

Time taken to cover (4/5)th of the track = m minutes

Time taken to cover 1 revolution = m × (5/4) = 5m/4 minutes

4/5 part of the circular track is covered in m minutes.

Total Part = 5 unit

Part covered in m minutes = 4 unit

Efficiency is inversely proportional to the Time taken when the amount of work done is constant.

∴ Time taken to cover entire track is 5m/4 minutes

Alternate Method

Time taken to cover (4/5)th of the track = m minutes

Time taken to cover 1 revolution = m × (5/4) = 5m/4 minutes

∴ Time taken to cover entire track is 5m/4 minutes

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Question 90

UPTET 2019• Mathematics and Science• Mathematics and Science

If x + y = 2z, then the value of \(\dfrac{x}{x-z}+\dfrac{z}{y-z}\) is

  1. AOption (a)

    1

  2. BOption (b)

    2

  3. COption (c)

    xyz

  4. DOption (d)

    0

View answer & explanation

Correct answer

Answer: (a)A.

1

Why this answer is correct

Given:

x + y = 2z

Calculation:

x/(x - z) + z/(y - z)

⇒ (xy - xz + zx - z2)/(x - z)(y - z)     (Taking LCM of (x - z)(y - z))

⇒ (xy - z2)/xy - z(x + y) + z2

⇒ (xy - z2)/xy - z(2z) + z2 (∵ x + y = 2z)

⇒ (xy - z2)/(xy - z2) = 1

UPTET 2019 Paper 2 (Maths & Science) (Hindi / English / Sanskrit) (Previous Year Paper)·Mathematics and Science
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Question 91

UPTET 2019• Mathematics and Science• Mathematics and Science

Which of the following vitamins acts as hormone?

  1. AOption (a)

    Vitamin C

  2. BOption (b)

    Vitamin D

  3. COption (c)

    Vitamin E

  4. DOption (d)

    Vitamin B

View answer & explanation

Correct answer

Answer: (b)B.

Vitamin D

Why this answer is correct

The correct answer is Vitamin D.

  • Vitamin D
  • It is a hormone produced by the kidneys.
  • The liver and kidneys convert vitamin D into the active hormone, which is called calcitriol.
  • It primarily helps in controlling the concentration of calcium in the blood.
  • It is also vital for the development of strong bones.

Additional Information

VitaminChemical nameDisease due to deficiency
Vitamin CAscorbic acidScurvy
Vitamin Dergocalciferol-D2, cholecalciferol-D3Rickets
Vitamin ETocopherolsIt can cause nerve and muscle damage
Vitamin Bthiamin (B1) riboflavin (B2) niacin (B3) pantothenic acid (B5) pyridoxine (B6) biotin (B7) cyanocobalamin (B12)Beriberi (B1) Pellagra (B3) Anaemia (B6 and B12)
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Question 92

UPTET 2019• Mathematics and Science• Mathematics and Science

According to the five-kingdom system of classification, bacteria and blue-green algae are included in

  1. AOption (a)

    Fungi

  2. BOption (b)

    Monera

  3. COption (c)

    Plantae

  4. DOption (d)

    Protista

View answer & explanation

Correct answer

Answer: (b)B.

Monera

Why this answer is correct

The correct answer is Monera.

Important Points

  • The Monera Kingdom is classified into three sub-kingdoms- Archaebacteria, Eubacteria, and Cyanobacteria.
  • Blue-green algae are cyanobacteria.
  • They are found in the aquatic region.
  • Characteristics of Monera-
  • These are unicellular organisms.
  • They reproduce asexually by binary fission or budding.
  • It lacks organelles like mitochondria, lysosomes, plastids, Golgi bodies, endoplasmic reticulum, centrosome, etc.

Additional Information

  • Fungi are eukaryotic organisms that include microorganisms such as yeasts, moulds, and mushrooms. 
  • Fungi store their food in the form of starch.
  • Kingdom Plantae includes all the plants. 
  • They reproduce asexually by vegetative propagation or sexually.
  • They make their own food hence are called autotrophs.
  • Protists are eukaryotic organisms that are neither plants nor animals or fungi. 
  • Most protists live in water, damp terrestrial environments, or even as parasites.
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Question 93

UPTET 2019• Mathematics and Science• Mathematics and Science

Which of the following is a tissue?

  1. AOption (a)

    Blood

  2. BOption (b)

    Kidney

  3. COption (c)

    Lung

  4. DOption (d)

    Ovary

View answer & explanation

Correct answer

Answer: (a)A.

Blood

Why this answer is correct

The correct answer is Blood.

Important Points

  • Connective tissues are composed of a matrix consisting of living cells and a non-living substance, called the ground substance.
  • It provides support, binds together, and protects tissues and organs of the body.
  • Blood is a connective tissue because it has a matrix.
  • ​The living cell types are red blood cells and white blood cells.
  • The fluid portion of whole blood, its matrix, is commonly called plasma.

Additional Information

  • The kidneys are bean-shaped organs in the renal system.
  • It helps in regulating and filtering minerals from blood.
  • It also helps in filtering waste materials from food and toxic substances.
  • The lungs are the centre of the respiratory system.
  • The primary function is to help oxygen enter the red cells in the blood.
  • The ovaries produce and release eggs into the female reproductive tract at the mid-point of each menstrual cycle.
  • They also produce the female hormones oestrogen and progesterone.
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Question 94

UPTET 2019• Mathematics and Science• Mathematics and Science

Name of the hormone which is at the peak during ovulation is

  1. AOption (a)

    Estrogen

  2. BOption (b)

    FSH

  3. COption (c)

    LH

  4. DOption (d)

    Progesterone

View answer & explanation

Correct answer

Answer: (c)C.

LH

Why this answer is correct

The correct answer is LH.

Key Points

  • Ovulation is the release of a mature egg from one of the ovaries. 
  • After the egg is released, it travels down the fallopian tube, where fertilization by a sperm cell may occur.
  • LH-Luteinizing Hormone.
  • When the level of estrogen is sufficiently high, it produces a sudden release of LH. It usually takes place around day thirteen of the cycle.
  • LH at the peak during ovulation.
  • Luteinizing hormone is produced and released in the anterior pituitary gland. It stimulates the ovaries to produce oestradiol. If fertilization occurs, luteinizing hormone will stimulate the corpus luteum, which produces progesterone to sustain the pregnancy.

Additional Information

  • Estrogen
  • This hormone is responsible for female physical features and reproduction.
  • The ovaries, adrenal glands, and fat tissues produce estrogen.
  • Both female and male bodies have this hormone, but females create more of it.
  • It contributes to cognitive health, bone health, the function of the cardiovascular system, and other essential bodily processes.
  • FSH
  • The full form is Follicle-stimulating hormone.
  • It is synthesized and secreted by the gonadotropic cells of the anterior pituitary gland.
  • It regulates the development, growth, pubertal maturation, and reproductive processes of the body.
  • Progesterone
  • It is a female hormone that regulates the menstrual cycle.
  • It is released by the corpus luteum in the ovary.
  • It helps the uterus thicken in anticipation of receiving a fertilized egg.
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Question 95

UPTET 2019• Mathematics and Science• Mathematics and Science

Hippocampus is a

  1. AOption (a)

    Protochordate

  2. BOption (b)

    Fish

  3. COption (c)

    Mammal

  4. DOption (d)

    Coelenterate

View answer & explanation

Correct answer

Answer: (b)B.

Fish

Why this answer is correct

The correct answer is Fish.

Key Points

  • The genus Hippocampus contains more than 70 species found mostly in shallow tropical and temperate marine and estuarine waters throughout the world.
  • Seahorse is the name given to 54 species of small marine fishes in the genus Hippocampus.
  • Their habitats include coral reefs, mangroves, seagrass beds, and estuaries.

Additional Information

  • Coelenterata
  • Phylum Coelenterata is a group of aquatic, or marine organisms.
  • They are diploblastic animals, in which, the body is made up of two layers of cells: Ectoderm and Endoderm.
  • The nervous system and the circulatory system is absent.
  • Coelenterates are classified into three different classes: Anthozoa, Hydrozoa, and Scyphozoa.
  • Protochordate
  • It is an informal category of organisms to describe the invertebrates that are closely related to vertebrates.
  • Their body is bilaterally symmetrical, triploblastic, and coelomated.
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Question 96

UPTET 2019• Mathematics and Science• Mathematics and Science

The ore copper pyrite is concentrated by

  1. AOption (a)

    Froth floatation process

  2. BOption (b)

    Gravitational method

  3. COption (c)

    None of these

  4. DOption (d)

    Magnetic process

View answer & explanation

Correct answer

Answer: (a)A.

Froth floatation process

Why this answer is correct

The correct answer is Froth floatation process.

Key Points

  • Froth floatation
  • It is a process that selectively separates materials based upon whether they are water-repelling (hydrophobic) or have an affinity for water (hydrophilic).
  • If the minerals are of Hydrophobic nature then only can get attracted toward froth and not with water.
  • Ores containing multiple metals such as lead, copper and zinc can be selectively extracted by using froth floatation.
  • Froth flotation can primarily be done under two common techniques:
  • Direct floatation technique- The mineral sticks to the air bubble and the remaining gangue settles down at the bottom.
  • Reverse floatation technique- The gangue sticks to the air bubble and ore particle settle down in the bottom.

Important Points

  • Copper is extracted from its principal ore Copper pyrites (CuFeS2).
  • The ore is concentrated by froth flotation process.
  • Then, the concentrated ore is roasted in a furnace where reactions remove sulphur and Arsenic gases:
  • S+O2 ​ →SO2​ and 4As+3O2 ​ ⟶2As2 ​O3 ​
  • The copper pyrite gets converted to a mixture of Cu2S and FeS by the reactions given below:
  • 2CuFeS2 ​ +O2 ​ ⟶ Cu2 ​S+2FeS+SO2 ​
  • These Sulphides are then oxidized and smelted. Hence, copper is extracted.
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Question 97

UPTET 2019• Mathematics and Science• Mathematics and Science

Number of 3°-carbons in 2-methyl propane is 

  1. AOption (a)

    3

  2. BOption (b)

    Zero

  3. COption (c)

    2

  4. DOption (d)

    1

View answer & explanation

Correct answer

Answer: (d)D.

1

Why this answer is correct

The correct answer is 1.

Key Points

  • 2-methyl propane is  H3C−CH(CH3)−CH3.
  • A methyl group substitutes the chain at C2.
  • There is one "three-carbon" longest chain in 2-methyl propane.
  • 2-methyl propane is also known as Isobutane.
  • It is a colourless, odourless gas.
  • It is obtained by isomerization of butane.
  • It is also the principal feedstock in alkylation units of refineries.
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Question 98

UPTET 2019• Mathematics and Science• Mathematics and Science

IUPAC name of the following compound is 

  1. AOption (a)

    2-methoxy-2-methyl ethane

  2. BOption (b)

    2-methoxy propane

  3. COption (c)

    Isopropyl methyl ether

  4. DOption (d)

    1-methoxy-1-methyl ethane

View answer & explanation

Correct answer

Answer: (b)B.

2-methoxy propane

Why this answer is correct

The correct answer is 2-methoxy propane.

Key Points

  • The International Union of Pure and Applied Chemistry (IUPAC) is an international federation of National Adhering Organizations that represents chemists in individual countries.
  • It is best known for its works standardizing nomenclature in chemistry.
  • The IUPAC nomenclature of organic chemistry is a method of naming organic chemical compounds as recommended by IUPAC.
  • It is published in the Nomenclature of Organic Chemistry.
  • 2-methoxy propane is an ether compound having methyl and isopropyl as the two alkyl groups. The molecular formula is C4H10O.

Additional Information

  • The molecular formula of 2-methoxy-2-methyl ethane is C8H18O.

  • The molecular formula of 1-methoxy-1-methyl ethane is C5H12O2.

  • The molecular formula of Isopropyl methyl ether is C4H10O. But, it cannot be the answer as it is not the IUPAC name of the compound given.

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Question 99

UPTET 2019• Mathematics and Science• Mathematics and Science

The bond energy for catenation next to carbon is

  1. AOption (a)

    S

  2. BOption (b)

    Si

  3. COption (c)

    P

  4. DOption (d)

    N

View answer & explanation

Correct answer

Answer: (b)B.

Si

Why this answer is correct

The correct answer is Si.

Important Points

  • Catenation is the binding of an element to itself through covalent bonds to form chain or ring molecules.
  • Carbon is the most common element that exhibits catenation.
  • It can form long hydrocarbon chains and rings like benzene.
  • Please note that the smaller the atom, the stronger the tendency of catenation.
  • All the elements of the carbon family or group 4 family exhibit catenation property.
  • The carbon family includes carbon (C), silicon (Si), germanium (Ge), tin (Sn), lead (Pb), and flerovium (Fl).
  • The ability of an element to catenate is primarily based on the bond energy of the element to itself, which decreases with more diffuse orbitals.
  • The bond length decreases across a row in the periodic table and increases down a group.
  • The bond energy of S-S is 266 Kj/mol.
  • The bond energy of Si-Si is 340 Kj/mol.
  • The bond energy of P-P is 54 Kj/mol.
  • The bond energy of N-N is 160 Kj/mol.

Additional Information

  • Catenation tendency decreases down the group.
  • This happens because the atomic size increases down the group and the strength of the covalent bond decreases.
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Question 100

UPTET 2019• Mathematics and Science• Mathematics and Science

nx mole of substance x was dissolved in ny mole of substance y.

A. The total of mole fractions of substance x and y remain 1.

B. Mole fraction of \(\rm x=\dfrac{\rm No. \ of \ moles \ of \ x}{\rm No. \ of \ moles \ of \ solution}\)

C. Mole fraction of \(\rm y = \dfrac{n_y}{n_x + n_y}\)

D. Mole fraction of \(\rm x = \dfrac{n_x}{n_y + n_y}\)

The correct statements is /are:

  1. AOption (a)

    Only A

  2. BOption (b)

    Only A, B

  3. COption (c)

    A, B and C

  4. DOption (d)

    Only D

View answer & explanation

Correct answer

Answer: (c)C.

A, B and C

Why this answer is correct

The correct answer is A, B and C.

Key Points

  • Mole fraction is the total number of moles of a solute divided by the total number of moles in a solution.
  • It is given that nx mole of substance x (solute) was dissolved in ny mole of substance y (solvent).
  • Mole fraction of x = Total number of moles of substance x /(Total number of moles of substance x + Total number of moles of substance y)
  • Mole fraction of x = nx/(nx + ny)
  • Mole fraction of y = Total number of moles of substance y /(Total number of moles of substance x + Total number of moles of substance y)
  • Mole fraction of y = ny/(nx + ny)
  • The total mole fractions = nx/(nx + ny) + ny/(nx + ny) = (nx + ny) /(nx + ny)  = 1
  • Hence, the total of mole fractions of substance x and y remain 1.

 

  • The statement in option D is incorrect since the total number of moles in a solution is not considered in denominator.

How should I prepare for Mathematics and Science in UPTET?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.