Given equation: (36 ÷ 2) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 3 + 2).
BODMAS Table:
Let's check each option one by one.
Option 1) 4 and 2
Given: (36 ÷ 2) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 3 + 2)
After interchanging the numbers we get;
⇒ (36 ÷ 4) × 5 – 15 × 2 = 20 − 260 ÷ (5 × 3 + 4)
⇒ 9 × 5 – 15 × 2 = 20 − 260 ÷ (15 + 4)
⇒ 45 – 30 = 20 − 260 ÷ 19
⇒ 15 = 20 − 13.7
⇒ -15 ≠ 6.3
⇒ LHS ≠ RHS
Option 2) 3 and 5
Given: (36 ÷ 2) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 3 + 2)
After interchanging the numbers we get;
⇒ (36 ÷ 2) × 3 – 15 × 4 = 20 − 260 ÷ (3 × 5 + 2)
⇒ 18 × 3 – 15 × 4 = 20 − 260 ÷ (15 + 2)
⇒ 54 – 60 = 20 − 260 ÷ 17
⇒ –10 = 20 − 15.3
⇒ -10 ≠ 4.7
⇒ LHS ≠ RHS
Option 3) 20 and 36
Given: (36 ÷ 2) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 3 + 2)
After interchanging the numbers we get;
⇒ (20 ÷ 2) × 5 – 15 × 4 = 36 − 260 ÷ (5 × 3 + 2)
⇒ 10 × 5 – 15 × 4 = 36 − 260 ÷ (15 + 2)
⇒ 50 – 60 = 36 − 260 ÷ 17
⇒ -10 = 36 − 15.3
⇒ -10 ≠ -20.7
⇒ LHS ≠ RHS
Option 4) 2 and 3
Given: (36 ÷ 2) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 3 + 2)
After interchanging the numbers we get;
⇒ (36 ÷ 3) × 5 – 15 × 4 = 20 − 260 ÷ (5 × 2 + 3)
⇒ 12 × 5 – 15 × 4 = 20 − 260 ÷ (10 + 3)
⇒ 60 – 60 = 20 − 260 ÷ 13
⇒ 0 = 20 − 20
⇒ 0 = 0
⇒ LHS = RHS
Hence, the correct answer is "Option 4".