A pyramid has an equilateral triangle as its base, of which each side is 8 cm. Its slant edge is 24 cm. The whole surface area of the pyramid (in cm2) is:
- AOption (a)
- BOption (b)
- COption (c)
- DOption (d)
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Correct answer
Why this answer is correct
Shortcut Trick
Base Area (Equilateral) = (√3/4) × 82 = 16√3 cm2.
Slant height (l) of a face = √(Slant edge2 − (Side/2)2) = √(242 − 42) = 4√35 cm.
Lateral Surface Area (LSA) = 3 × (1/2 × 8 × 4√35) = 48√35 cm2.
Whole Surface Area = Base Area + LSA = (16√3 + 48√35) cm2.
∴ The correct answer is (16√3 + 48√35) cm2.
Alternate Method
Given:
Side of equilateral base (a) = 8 cm
Slant edge (e) = 24 cm
Formula Used:
Area of equilateral triangle = (√3/4) × side2
Slant height (l) = √(slant edge2 − (side/2)2)
Whole Surface Area (WSA) = Base Area + 3 × (Lateral Face Area)
⇒ Area of base = (√3 / 4) × 8 × 8 = 16√3 cm2
⇒ Half of base side = 8 ÷ 2 = 4 cm
⇒ Slant height (l) = √(242 − 42) = √(576 − 16) = √560
⇒ l = √(16 × 35) = 4√35 cm
⇒ Area of one lateral face = 1/2 × base × l = 1/2 × 8 × 4√35 = 16√35 cm2
⇒ Total Lateral Surface Area = 3 × 16√35 = 48√35 cm2
⇒ Whole Surface Area = Base Area + LSA = (16√3 + 48√35) cm2
∴ The correct answer is (16√3 + 48√35) cm2.
Additional Information
Volume of a Pyramid
The volume of any pyramid is given by V = (1/3) × Base Area × Vertical Height (h).
Slant Height vs Vertical Height
For a regular pyramid, l2 = h2 + r2, where l is the slant height, h is the vertical height, and r is the inradius of the base.
Regular Tetrahedron
A regular tetrahedron is a special pyramid where all four faces are congruent equilateral triangles; its total surface area is √3 × a2.







































