Reasoning PYQs

Given series is:

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & % > 5 F R 7 A Y 4 Right Side

Arrangement required: Letter(A-M) → Symbol/Number → Letter(A-M)

We have to find symbols and numbers each of which is either immediately preceded or immediately followed by any of the English letters from A to M

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & %  > 5 F R 7 A Y 4 Right Side

Hence, there are 8 symbols and numbers that follow the above condition.

Given series is:

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & %  > 5 F R 7 A Y 4 Right Side

In all other groups, there are five elements between first element and the second element, six elements between the second and the third element except in P L <.

Hence, P L < does not belong to the group.

Given series is:

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & % > 5 F R 7 A Y 4 Right Side

The series after rearrangement is:

Left Side 2 P J 8 # L @ B 1 V Q * 6 G < W 9 K C D 3 % & 5 > F R 7 A Y 4 Right Side

Arrangement required: Symbol → Letter → Number

Hence, there are two such pairs:  @ B 1, < W 9.

Given series:

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & % > 5 F R 7 A Y 4 Right Side

In each pair, the corresponding elements of both the terms occupy the same position from the beginning and end of the given sequence. In the same @ **1 *** is related to F % 3.

Hence, @ 1 * is related to F % 3.

Given series:

Left Side 2 P J # 8 @ L B 1 V * Q 6 < G W 9 K C D 3 & % > 5 F R 7 A Y 4 Right Side

The elements eliminated from the sequence are: P # @ B V Q < W K D & > F 7 Y

Number of symbols = 5; Number of letters = 9; Number of numbers =1

Hence, symbols, letters and numbers eliminated respectively are 5, 9 & 1.

1- Only two people are sitting between E and Q. 

2- E is sitting on one of the ends. 

3- One person is sitting between Q and R. 

4- R is not an immediate neighbor of E. 

Case-1

Case-2

 

5- D sits third to the left of R and only five people are sitting between D and S. 

6- S is not an immediate neighbor of Q. 

7- B is sitting second to the right of S. 

8- S is sitting fourth to the right of C. 

9- Only six people are sitting between C and U. 

10- U is sitting on one end. 

Case-1

Case-2

11- Only Two people sitting between A and U. So, case-1 gets eliminated.

So, Final arrangement;

 

Hence, Twenty six people are siiting in the row.

1- Only two people are sitting between E and Q. 

2- E is sitting on one of the ends. 

3- One person is sitting between Q and R. 

4- R is not an immediate neighbor of E.

Case-1

Case-2

 

 

5- D sits third to the left of R and only five people are sitting between D and S. 

6- S is not an immediate neighbor of Q. 

7- B is sitting second to the right of S. 

8- S is sitting fourth to the right of C. 

9- Only six people are sitting between C and U. 

10- U is sitting on one end. 

Case-1

Case-2

11- Only Two people sitting between A and U. So, case-1 gets eliminated.

So, Final arrangement;

Hence, Three people are sitting between A and C.

1- Only two people are sitting between E and Q. 

2- E is sitting on one of the ends. 

3- One person is sitting between Q and R. 

4- R is not an immediate neighbor of E. 

Case-1

Case-2

 

5- D sits third to the left of R and only five people are sitting between D and S. 

6- S is not an immediate neighbor of Q. 

7- B is sitting second to the right of S. 

8- S is sitting fourth to the right of C. 

9- Only six people are sitting between C and U. 

10- U is sitting on one end. 

Case-1

Case-2

11- Only Two people sitting between A and U. So, case-1 gets eliminated.

So, Final arrangement;

Hence, U sitting on the extreme left end of the row.

Given:

10 people – A, B, C, D, E, P, Q, R, S, and T

People in Row 1 face South.

People in Row 2 face North.

1. E sits opposite the one who sits to the immediate right of Q, who sits in the middle of the row.

2. A sits beside C, neither of whom sit at the end of the row.

3. D sits to the right of B.

4. 2 people sit between S and P, who sits at an end of the row.

5. T sits to the left of R.

6. S does not sit opposite E, who does not sit beside A.

Final Arrangement:

Hence, C sits in the middle of Row 1.

Given:

10 people – A, B, C, D, E, P, Q, R, S, and T

People in Row 1 face South.

People in Row 2 face North.

1. E sits opposite the one who sits to the immediate right of Q, who sits in the middle of the row.

2. A sits beside C, neither of whom sit at the end of the row.

3. D sits to the right of B.

4. 2 people sit between S and P, who sits at an end of the row.

5. T sits to the left of R.

6. S does not sit opposite E, who does not sit beside A.

Final Arrangement:

Hence, nobody sits between S and T.

Given:

10 people – A, B, C, D, E, P, Q, R, S, and T

People in Row 1 face South.

People in Row 2 face North.

1. E sits opposite the one who sits to the immediate right of Q, who sits in the middle of the row.

2. A sits beside C, neither of whom sit at the end of the row.

3. D sits to the right of B.

4. 2 people sit between S and P, who sits at an end of the row.

5. T sits to the left of R.

6. S does not sit opposite E, who does not sit beside A.

 

Final Arrangement:

Hence, P sits at the right end of Row 2.

Given:

10 people – A, B, C, D, E, P, Q, R, S, and T

People in Row 1 face South.

People in Row 2 face North.

1. E sits opposite the one who sits to the immediate right of Q, who sits in the middle of the row.

2. A sits beside C, neither of whom sit at the end of the row.

3. D sits to the right of B.

4. 2 people sit between S and P, who sits at an end of the row.

5. T sits to the left of R.

6. S does not sit opposite E, who does not sit beside A.

 

Final Arrangement:

 

A sits opposite S.

E sits second to the left of A.

Hence, R sits opposite E.

Given:

10 people – A, B, C, D, E, P, Q, R, S, and T

People in Row 1 face South.

People in Row 2 face North.

1. E sits opposite the one who sits to the immediate right of Q, who sits in the middle of the row.

2. A sits beside C, neither of whom sit at the end of the row.

3. D sits to the right of B.

4. 2 people sit between S and P, who sits at an end of the row.

5. T sits to the left of R.

6. S does not sit opposite E, who does not sit beside A.

 

Final Arrangement:

Hence, D sits opposite T.

First of all we will write number of position of ‘COMBINE’ word according to English alpahbet i.e. C is written as 3 and O will be written as 15 and so on.

Here we can see that only B and E is making one pair.

Hence, One pair is there in the word ‘COMBINE’, each of which has as many letters between them in the word (both forward and backward direction) as they have between them in the English Alphabet.

Hence, the third letter is Y.

Given

Statements:

P > Q > R ; R > S ≥ T

On Combining : P > Q > R > S ≥ T

Conclusions:

I. R > T → True ( As R > S ≥ T ; Thus clear relation between R and T can be determined )

II. P > S → True ( As P > Q > R > S ; Thus clear relation between P and S can be determined )

Therefore Both conclusion I and II are True.

**Given

Statements:

**  X ≤ U < V > T; U < S; H > V

On combining:X ≤ U < V > T; U < S; H > V

Conclusions:

I. X < H → True (H > V and  V > U ≥ X → X < H)

II. T ≤ S → False (U <  S and U < V > T  → thus clear relation between T and  S cannot be determined)

Therfore Only conclusion I is True.

**Given

Statements:

** A > B ≥ C ; C < D

Conclusions:

I. A > D → False (as A > B ≥ C < D )

II. A > C → True (as A > B ≥ C → A > C)

Only II is true.

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7^th and 28^th;

1. Only two persons gave after U.
2. Only one person gave between U and S.

From this we get the possible arrangements:

3. S and R gave on different dates.
4. R gave after S.

    From this case II is eliminated as we cannot determine the month in which R gave the exam.

5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.

7. Y gave after Z, who gave in the month which has odd number of days.

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

Y gave the exam in the month of June.

Persons – 8; R, S, T, U, W, X, Y and Z;

Months – April, May, June and July;

Dates – 7^th and 28^th;

1. Only two persons gave after U.
2. Only one person gave between U and S.

From this we get the possible arrangements:

3. S and R gave on different dates.
4. R gave after S.

    From this case II is eliminated as we cannot determine the month in which R gave the exam.

5. Five persons gave between W and T.
6. T gave before R and both gave on different dates.

7. Y gave after Z, who gave in the month which has odd number of days.

8. Y and W did not give in the same month.

From this case I is eliminated, as Y and W attended in the same month which is not possible. From this we get the final arrangement as follows.

Only one person gave the exam between X and Z.