Reasoning PYQs

As per the given information,

1. Julie starts her journey from point ‘Z’ and walks 10km east to reach point ‘Y’

2. then she turns to her left and walks 3km to reach point ‘R’ and,

3. then she turns to her left again and walks 12km to reach point ‘S’.

4. Again, she turns to her left and walks 3km to reach point ‘E’.

5. Finally, she took to her right and moves for another 4km to reach point J.

Therefore, the final diagram is 

Hence, Point E is in the Southwest direction with respect to point R.

As per the given information,

1. Julie starts her journey from point ‘Z’ and walks 10km east to reach point ‘Y’

 

2. then she turns to her left and walks 3km to reach point ‘R’ and,

3. then she turns to her left again and walks 12km to reach point ‘S’.

4. Again, she turns to her left and walks 3km to reach point ‘E’.

5. Finally, she took to her right and moves for another 4km to reach point J.

Therefore, the final diagram is 

As per the question

 

Hence, 13Km is the shortest distance between point K and point Y.

As per the given information,

1. Julie starts her journey from point ‘Z’ and walks 10km east to reach point ‘Y’

 

2. then she turns to her left and walks 3km to reach point ‘R’ and,

3. then she turns to her left again and walks 12km to reach point ‘S’.

4. Again, she turns to her left and walks 3km to reach point ‘E’.

5. Finally, she took to her right and moves for another 4km to reach point J.

Therefore, the final diagram is 

 

Hence, Point S is to the northwest of Point Z.

Given : MOTIVATION

After changing the vowels to the next letter and the consonants to the previous letter;

LPSJUBSJPM

Hence, there are two letters (P, S, J) in the given words which are repeated more than once.

Given: 945217

By adding 2 in the even digits and subtracting 1 from the odd digits, we will get,

Here can clearly says that 8 and 0 are not repeated.

Therefore, sum of the number = 8 + 0 = 8

Hence, "8" is the correct answer.

According to the given question,

The forward pairs are - EF, TV

The Backward pairs are - EF, CF 

Hence, there are four pairs.

1. Equal number of boxes are kept above and below A
2. Three boxes are kept between A and B

3. The number of boxes kept above B is the same as the number of boxes kept below C.
4. Only two boxes are kept between C and I.

5. One box is kept between A and G, which is not kept immediate above I.

6. No box is kept between F and D, which is not kept above F → D is kept immediately below F
7. E is placed below H, which is kept immediate below D → Case 1 and Case 2 gets canceled because the given statement will not be satisfied.

So, the final arrangement will be

Hence, only two boxes are kept between Fand A.

1. Equal number of boxes are kept above and below A
2. Three boxes are kept between A and B

3. The number of boxes kept above B is the same as the number of boxes kept below C.
4. Only two boxes are kept between C and I.

5. One box is kept between A and G, which is not kept immediate above I.

6. No box is kept between F and D, which is not kept above F → D is kept immediately below F
7. E is placed below H, which is kept immediate below D → Case 1 and Case 2 gets canceled because the given statement will not be satisfied.

So, the final arrangement will be

Hence, A is kept immediately below H.

1. Equal number of boxes are kept above and below A
2. Three boxes are kept between A and B

3. The number of boxes kept above B is the same as the number of boxes kept below C.
4. Only two boxes are kept between C and I.

5. One box is kept between A and G, which is not kept immediate above I.

6. No box is kept between F and D, which is not kept above F → D is kept immediately below F
7. E is placed below H, which is kept immediate below D → Case 1 and Case 2 gets canceled because the given statement will not be satisfied.

So, the final arrangement will be

There are two boxes between I and C, whereas there is only one box between other pairs.

Hence, IC does not belong to the group.

1. Equal number of boxes are kept above and below A
2. Three boxes are kept between A and B

3. The number of boxes kept above B is the same as the number of boxes kept below C.
4. Only two boxes are kept between C and I.

5. One box is kept between A and G, which is not kept immediate above I.

6. No box is kept between F and D, which is not kept above F → D is kept immediately below F
7. E is placed below H, which is kept immediate below D → Case 1 and Case 2 gets canceled because the given statement will not be satisfied.

So, the final arrangement will be

Hence, CB represent the lowermost box and topmost box.

1. Equal number of boxes are kept above and below A
2. Three boxes are kept between A and B

3. The number of boxes kept above B is the same as the number of boxes kept below C.
4. Only two boxes are kept between C and I.

5. One box is kept between A and G, which is not kept immediate above I.

6. No box is kept between F and D, which is not kept above F → D is kept immediately below F
7. E is placed below H, which is kept immediate below D → Case 1 and Case 2 gets canceled because the given statement will not be satisfied.

So, the final arrangement will be

Hence, three boxes are kept between E and H.

The least possible diagram for the given statements is as follows:

Conclusions:

I. Some D are not A → False (as there is no direct relation between D and A, it is possible but not definite. So, it is false)

II. Some D are not B → True (as Only a few D are C, and All B are C, some part of D which is not C will not be B. So, it is true)

Hence, Only conclusion II follows.

Confusion PointsPlease note that according to the statement given 'Only a few D are C.' some D will definitely not be C and those D which are not C can not be B either.

Hence, the conclusion 'Some D are not B ' is true.

The least possible diagram for the given statements is as follows;

Conclusions:

I. All Sparrow are Parrot → False (as Some Sparrow are Parrot and about the remaining part of Sparrow and Parrot, we cannot say definite relation whether it is true or not. So, it is false)

II. Some Parrot are not Camel → True (as Only a few Parrot are Camel → Some Parrot are Camel and Some Parrot are not Camel. So, it is true)

Hence, Only conclusion II follows.

The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. Some Car is Truck → False (As there is no direct relation between Car and Truck it is possible but not definite. So, it is false)

II. All Bus being Car is a possibility → False (As only a few Bus is Car means some Bus is Car and some Bus is not Car and possibility of all Bus being Car is false. So, it is false)

Hence, Neither I nor II follows.

Persons : A, C, P, L, J, K, F

Only 2 are facing inside and rest are facing outside.

1) A is sitting to the immediate left of F and facing outside.

⇒ Here direction of F is not known, hence we will make following cases :

Case 1 : F is facing inside.

Case 2 : F is facing outside.

2. Three persons are sitting between F and P when counted from the right of F.

⇒ We will place P according to the condition given.

Case 1 :

Case 2 :

3. L is sitting to the immediate left of P.

 L is not an immediate neighbor of A or F.

⇒ We get that in case 1, P faces inside and in case 2, P faces outside. 

Case 1 :

Case 2 :

4. J is an immediate neighbor of neither F nor P.

⇒ We get the position of J from above hint.

Case 1 :

Case 2 : 

5) L is sitting second to the left of K who is facing inside. Both the immediate neighbors of K are facing in opposite direction as that of K.

⇒ We get the position of K from above hint.

Case 1 :

We can see that in case 1, both the immediate neighbors of K are not facing in opposite direction as that of K. Hence case 1 gets eliminated.

Case 2 :

6) The person sitting adjacent to both J and P is facing outside.

⇒ We get that L is facing outside and C is facing inside. (As the only person left was C and two persons were facing inside). Hence we get completed circular arrangement as shown below :

We can see from final diagram, L is sitting to the immediate right of J.

Persons : A, C, P, L, J, K, F

Only 2 are facing inside and rest are facing outside.

1) A is sitting to the immediate left of F and facing outside.

⇒ Here direction of F is not known, hence we will make following cases :

Case 1 : F is facing inside.

Case 2 : F is facing outside.

2. Three persons are sitting between F and P when counted from the right of F.

⇒ We will place P according to the condition given.

Case 1 :

Case 2 :

3. L is sitting to the immediate left of P.

 L is not an immediate neighbor of A or F.

⇒ We get that in case 1, P faces inside and in case 2, P faces outside. 

Case 1 :

Case 2 :

4. J is an immediate neighbor of neither F nor P.

⇒ We get the position of J from above hint.

Case 1 :

Case 2 : 

5) L is sitting second to the left of K who is facing inside. Both the immediate neighbors of K are facing in opposite direction as that of K.

⇒ We get the position of K from above hint.

Case 1 :

We can see that in case 1, both the immediate neighbors of K are not facing in opposite direction as that of K. Hence case 1 gets eliminated.

Case 2 :

6) The person sitting adjacent to both J and P is facing outside.

⇒ We get that L is facing outside and C is facing inside. (As the only person left was C and two persons were facing inside). Hence we get completed circular arrangement as shown below :

We can see that either 2 or 3 persons are sitting between K and P depending upon direction of counting.

Persons : A, C, P, L, J, K, F

Only 2 are facing inside and rest are facing outside.

1) A is sitting to the immediate left of F and facing outside.

⇒ Here direction of F is not known, hence we will make following cases :

Case 1 : F is facing inside.

Case 2 : F is facing outside.

2. Three persons are sitting between F and P when counted from the right of F.

⇒ We will place P according to the condition given.

Case 1 :

Case 2 :

3. L is sitting to the immediate left of P.

 L is not an immediate neighbor of A or F.

⇒ We get that in case 1, P faces inside and in case 2, P faces outside. 

Case 1 :

Case 2 :

4. J is an immediate neighbor of neither F nor P.

⇒ We get the position of J from above hint.

Case 1 :

Case 2 : 

5) L is sitting second to the left of K who is facing inside. Both the immediate neighbors of K are facing in opposite direction as that of K.

⇒ We get the position of K from above hint.

Case 1 :

We can see that in case 1, both the immediate neighbors of K are not facing in opposite direction as that of K. Hence case 1 gets eliminated.

Case 2 :

6) The person sitting adjacent to both J and P is facing outside.

⇒ We get that L is facing outside and C is facing inside. (As the only person left was C and two persons were facing inside). Hence we get completed circular arrangement as shown below :

We can see that if A and L interchange their positions then A will be sitting third left of L.

Persons : A, C, P, L, J, K, F

Only 2 are facing inside and rest are facing outside.

1) A is sitting to the immediate left of F and facing outside.

⇒ Here direction of F is not known, hence we will make following cases :

Case 1 : F is facing inside.

Case 2 : F is facing outside.

2. Three persons are sitting between F and P when counted from the right of F.

⇒ We will place P according to the condition given.

Case 1 :

Case 2 :

3. L is sitting to the immediate left of P.

 L is not an immediate neighbor of A or F.

⇒ We get that in case 1, P faces inside and in case 2, P faces outside. 

Case 1 :

Case 2 :

4. J is an immediate neighbor of neither F nor P.

⇒ We get the position of J from above hint.

Case 1 :

Case 2 : 

5) L is sitting second to the left of K who is facing inside. Both the immediate neighbors of K are facing in opposite direction as that of K.

⇒ We get the position of K from above hint.

Case 1 :

We can see that in case 1, both the immediate neighbors of K are not facing in opposite direction as that of K. Hence case 1 gets eliminated.

Case 2 :

6) The person sitting adjacent to both J and P is facing outside.

⇒ We get that L is facing outside and C is facing inside. (As the only person left was C and two persons were facing inside). Hence we get completed circular arrangement as shown below :

We can see that among the given options, only K is facing inside.

Hence, K is the odd one out.

Persons : A, C, P, L, J, K, F

Only 2 are facing inside and rest are facing outside.

1) A is sitting to the immediate left of F and facing outside.

⇒ Here direction of F is not known, hence we will make following cases :

Case 1 : F is facing inside.

Case 2 : F is facing outside.

2. Three persons are sitting between F and P when counted from the right of F.

⇒ We will place P according to the condition given.

Case 1 :

Case 2 :

3. L is sitting to the immediate left of P.

 L is not an immediate neighbor of A or F.

⇒ We get that in case 1, P faces inside and in case 2, P faces outside. 

Case 1 :

Case 2 :

4. J is an immediate neighbor of neither F nor P.

⇒ We get the position of J from above hint.

Case 1 :

Case 2 : 

5) L is sitting second to the left of K who is facing inside. Both the immediate neighbors of K are facing in opposite direction as that of K.

⇒ We get the position of K from above hint.

Case 1 :

We can see that in case 1, both the immediate neighbors of K are not facing in opposite direction as that of K. Hence case 1 gets eliminated.

Case 2 :

6) The person sitting adjacent to both J and P is facing outside.

⇒ We get that L is facing outside and C is facing inside. (As the only person left was C and two persons were facing inside). Hence we get completed circular arrangement as shown below :

From the final arrangement we can see that, C is sitting to the fifth right of F.

The table is drawn describing symbols and their meanings,

1. N is the father of D. E is married to N. G and D are siblings. C is married to G. N has no son.
2. Eight members of a family are living in a house, in which two are married couples. K is the father of E. Q is the only son of C. A is the brother-in-law of N.

Therefore, the final arrangement will be,

Hence, C is the son-in-law of N.