Reasoning PYQs

The table is drawn describing symbols and their meanings,

1. N is the father of D. E is married to N. G and D are siblings. C is married to G. N has no son.
2. Eight members of a family are living in a house, in which two are married couples. K is the father of E. Q is the only son of C. A is the brother-in-law of N.

Therefore, the final arrangement will be,

Hence, K is the grandfather of D.

The table is drawn describing symbols and their meanings,

1. N is the father of D. E is married to N. G and D are siblings. C is married to G. N has no son.
2. Eight members of a family are living in a house, in which two are married couples. K is the father of E. Q is the only son of C. A is the brother-in-law of N.

Therefore, the final arrangement will be,

Hence, N is the husband of E is the correct option.

Persons : T, N, R, C, G

Days : Monday to Friday

Cloths : Cotton, Silk, Wool, Leather, Linen.

1) Five persons T, N, R, C and G went to the market on different days of a week from Monday to Friday, but not necessarily in the same order. 

⇒ We can draw the following table according to the information given.

 

2. The number of persons who went to the market before N is more than the number of persons went to the market after N.

⇒ We can draw the following cases : 

 

3. Two persons went to the market between R and N.

⇒ We can place R in both the cases as shown below:

 

4. Three persons went to the market between the persons who wore Cotton and Leather. R and G did not wear Leather.

⇒ We get to know that persons wearing Cotton and Leather must have gone on either Monday or Friday. Thus from Case 2 we have one more case. 

 

4. T wore Silk cloth and went on one of the days after C. R and G did not wear Leather. C did not go to the market on Monday.

⇒ Here Case 1 and Case 2A gets eliminated as G is wearing Leather in these cases.

 

5) C did not wear Linen.

⇒ We get that R wore Linen and C wore Wool. Thus we get completed arrangement as shown below.

 

We can see that, G went to the market on Monday.

Persons : T, N, R, C, G

Days : Monday to Friday

Cloths : Cotton, Silk, Wool, Leather, Linen.

1) Five persons T, N, R, C and G went to the market on different days of a week from Monday to Friday, but not necessarily in the same order. 

⇒ We can draw the following table according to the information given.

 

2. The number of persons who went to the market before N is more than the number of persons went to the market after N.

⇒ We can draw the following cases : 

 

3. Two persons went to the market between R and N.

⇒ We can place R in both the cases as shown below:

 

4. Three persons went to the market between the persons who wore Cotton and Leather. R and G did not wear Leather.

⇒ We get to know that persons wearing Cotton and Leather must have gone on either Monday or Friday. Thus from Case 2 we have one more case. 

 

4. T wore Silk cloth and went on one of the days after C. R and G did not wear Leather. C did not go to the market on Monday.

⇒ Here Case 1 and Case 2A gets eliminated as G is wearing Leather in these cases.

 

5) C did not wear Linen.

⇒ We get that R wore Linen and C wore Wool. Thus we get completed arrangement as shown below.

We can see that, C wore Wool.

Persons : T, N, R, C, G

Days : Monday to Friday

Cloths : Cotton, Silk, Wool, Leather, Linen.

1) Five persons T, N, R, C and G went to the market on different days of a week from Monday to Friday, but not necessarily in the same order. 

⇒ We can draw the following table according to the information given.

 

2. The number of persons who went to the market before N is more than the number of persons went to the market after N.

⇒ We can draw the following cases : 

 

3. Two persons went to the market between R and N.

⇒ We can place R in both the cases as shown below:

 

4. Three persons went to the market between the persons who wore Cotton and Leather. R and G did not wear Leather.

⇒ We get to know that persons wearing Cotton and Leather must have gone on either Monday or Friday. Thus from Case 2 we have one more case. 

 

4. T wore Silk cloth and went on one of the days after C. R and G did not wear Leather. C did not go to the market on Monday.

⇒ Here Case 1 and Case 2A gets eliminated as G is wearing Leather in these cases.

 

5) C did not wear Linen.

⇒ We get that R wore Linen and C wore Wool. Thus we get completed arrangement as shown below.

 

We can see that, No one went to the market between T and N.

Persons : T, N, R, C, G

Days : Monday to Friday

Cloths : Cotton, Silk, Wool, Leather, Linen.

1) Five persons T, N, R, C and G went to the market on different days of a week from Monday to Friday, but not necessarily in the same order. 

⇒ We can draw the following table according to the information given.

 

2. The number of persons who went to the market before N is more than the number of persons went to the market after N.

⇒ We can draw the following cases : 

 

3. Two persons went to the market between R and N.

⇒ We can place R in both the cases as shown below:

 

4. Three persons went to the market between the persons who wore Cotton and Leather. R and G did not wear Leather.

⇒ We get to know that persons wearing Cotton and Leather must have gone on either Monday or Friday. Thus from Case 2 we have one more case. 

 

4. T wore Silk cloth and went on one of the days after C. R and G did not wear Leather. C did not go to the market on Monday.

⇒ Here Case 1 and Case 2A gets eliminated as G is wearing Leather in these cases.

 

5) C did not wear Linen.

⇒ We get that R wore Linen and C wore Wool. Thus we get completed arrangement as shown below.

 

We can see that G and N went to the market at first and last respectively.

Persons : T, N, R, C, G

Days : Monday to Friday

Cloths : Cotton, Silk, Wool, Leather, Linen.

1) Five persons T, N, R, C and G went to the market on different days of a week from Monday to Friday, but not necessarily in the same order. 

⇒ We can draw the following table according to the information given.

 

2. The number of persons who went to the market before N is more than the number of persons went to the market after N.

⇒ We can draw the following cases : 

 

3. Two persons went to the market between R and N.

⇒ We can place R in both the cases as shown below:

 

4. Three persons went to the market between the persons who wore Cotton and Leather. R and G did not wear Leather.

⇒ We get to know that persons wearing Cotton and Leather must have gone on either Monday or Friday. Thus from Case 2 we have one more case. 

 

4. T wore Silk cloth and went on one of the days after C. R and G did not wear Leather. C did not go to the market on Monday.

⇒ Here Case 1 and Case 2A gets eliminated as G is wearing Leather in these cases.

 

5) C did not wear Linen.

⇒ We get that R wore Linen and C wore Wool. Thus we get completed arrangement as shown below.

 

We know from above arrangement that N went on Friday. Hence, N went on Thursday is false.

Statement:

P ≤ Q < S = T ≥ U ≥ W < Z

Conclusion:

I. S > W: False: As, P ≤ Q < S = T ≥ U ≥ W < Z. so, the relation between S and W is S ≥ W.

II. W = T: False: As, P ≤ Q < S = T ≥ U ≥ W < Z. so, the relation between T and W is T ≥ W.

As S = T, Both form complementary pairs.

Therefore, either I or II follows.

**Given

Statement:

** 

H > G < C, E ≥ K < D ≤ B, E = C

On combining: 

\()H > G < C = E ≥ K < D ≤ B

Conclusions:

 I. G ≤ D→ False (No definite information regarding G and D).

II. G > D → False (No definite information regarding G and D).

On combining conclusions I and II, G can be greater than, smaller than, and equal to D,

Hence Either conclusion I and II follow.

**Given

Statements:

** H ≤ X ≤ R = O > T; Y = F ≥ R > D

Conclusions:

I. H > Y → False (as H ≤ X ≤ R ≤ F = Y, thus H ≤ Y)

II. Y > H → False (as H ≤ X ≤ R ≤ F = Y, thus H ≤ Y)

After combining the statement we are getting 

H ≤ X ≤ R≤ F = Y

H≤Y

that is why either or case is not possible because it leads to a common conclusion.

Hence, Neither I nor II is true.

Persons : P, Q, R, S, T, U

 Months : May, September, November

 Dates : 9, 16

1) Six persons P, Q, R, S, T and U were born in three different months May, September and November, on two different dates- 9 and 16 not necessarily in the same order.

⇒ We can draw following table according to the information given.

 

2. Number of persons born before S is equal to the number of persons born after T. T was born in a month having even number of days.

⇒ T can be born in September or November. Thus we can have the following cases :

 

3. Two persons were born between R and T.

⇒ We can place R according to the condition given. Case 3 will be eliminated as it is not possible to place R in case 3.

 

4. P was born after R but not on the same date as that of R.

⇒ We can place P according to the condition given. Case 1 is eliminated as there is no suitable place for P. From Case 2 we get one more case as shown below :

 

5. Q and U were born in the same month.

⇒ This is possible only in case 2.

 

 

No further information is given for Q and U, hence Q and U can be born on either 9^th or 16^th of November. Thus Case 2 will be our final solution.

 

We can see that, either Q or U must have born on 16^th November.

Persons : P, Q, R, S, T, U

 Months : May, September, November

 Dates : 9, 16

1) Six persons P, Q, R, S, T and U were born in three different months May, September and November, on two different dates- 9 and 16 not necessarily in the same order.

⇒ We can draw following table according to the information given.

 

2. Number of persons born before S is equal to the number of persons born after T. T was born in a month having even number of days.

⇒ T can be born in September or November. Thus we can have the following cases :

 

3. Two persons were born between R and T.

⇒ We can place R according to the condition given. Case 3 will be eliminated as it is not possible to place R in case 3.

 

4. P was born after R but not on the same date as that of R.

⇒ We can place P according to the condition given. Case 1 is eliminated as there is no suitable place for P. From Case 2 we get one more case as shown below :

 

5. Q and U were born in the same month.

⇒ This is possible only in case 2.

 

 

No further information is given for Q and U, hence Q and U can be born on either 9^th or 16^th of November. Thus Case 2 will be our final solution.

 

We can see from above table, R was born first, hence No one was born immediately before R.

Persons : P, Q, R, S, T, U

 Months : May, September, November

 Dates : 9, 16

1) Six persons P, Q, R, S, T and U were born in three different months May, September and November, on two different dates- 9 and 16 not necessarily in the same order.

⇒ We can draw following table according to the information given.

 

2. Number of persons born before S is equal to the number of persons born after T. T was born in a month having even number of days.

⇒ T can be born in September or November. Thus we can have the following cases :

 

3. Two persons were born between R and T.

⇒ We can place R according to the condition given. Case 3 will be eliminated as it is not possible to place R in case 3.

 

4. P was born after R but not on the same date as that of R.

⇒ We can place P according to the condition given. Case 1 is eliminated as there is no suitable place for P. From Case 2 we get one more case as shown below :

 

5. Q and U were born in the same month.

⇒ This is possible only in case 2.

 

 

No further information is given for Q and U, hence Q and U can be born on either 9^th or 16^th of November. Thus Case 2 will be our final solution.

 

R and P were born on the dates, 9^th and 16^th respectively. Sum of 9 and 16 is 25. Its square root is 5.

Persons : P, Q, R, S, T, U

 Months : May, September, November

 Dates : 9, 16

1) Six persons P, Q, R, S, T and U were born in three different months May, September and November, on two different dates- 9 and 16 not necessarily in the same order.

⇒ We can draw following table according to the information given.

 

2. Number of persons born before S is equal to the number of persons born after T. T was born in a month having even number of days.

⇒ T can be born in September or November. Thus we can have the following cases :

 

3. Two persons were born between R and T.

⇒ We can place R according to the condition given. Case 3 will be eliminated as it is not possible to place R in case 3.

 

4. P was born after R but not on the same date as that of R.

⇒ We can place P according to the condition given. Case 1 is eliminated as there is no suitable place for P. From Case 2 we get one more case as shown below :

 

5. Q and U were born in the same month.

⇒ This is possible only in case 2.

 

 

No further information is given for Q and U, hence Q and U can be born on either 9^th or 16^th of November. Thus Case 2 will be our final solution.

 

As the position of U is not fixed, we cannot determine how many persons were born between P and U.

Persons : P, Q, R, S, T, U

 Months : May, September, November

 Dates : 9, 16

1) Six persons P, Q, R, S, T and U were born in three different months May, September and November, on two different dates- 9 and 16 not necessarily in the same order.

⇒ We can draw following table according to the information given.

 

2. Number of persons born before S is equal to the number of persons born after T. T was born in a month having even number of days.

⇒ T can be born in September or November. Thus we can have the following cases :

 

3. Two persons were born between R and T.

⇒ We can place R according to the condition given. Case 3 will be eliminated as it is not possible to place R in case 3.

 

4. P was born after R but not on the same date as that of R.

⇒ We can place P according to the condition given. Case 1 is eliminated as there is no suitable place for P. From Case 2 we get one more case as shown below :

 

5. Q and U were born in the same month.

⇒ This is possible only in case 2.

 

 

No further information is given for Q and U, hence Q and U can be born on either 9^th or 16^th of November. Thus Case 2 will be our final solution.

 

Hence, we can see that among the given options, R was born in a month having odd number of days.