Bharat starts from point Y and drives 31 km north. He then turns left and drives 31 km, then turns left and drives 43 km. He then turns right and drives 17 km. He then turns right and drives 51 km. He then turns right and drives 23 km, then turns right and drives 39 km and stops at point Z. How far (the shortest distance) and in which direction should he drive to reach point Y again?
(Unless otherwise specified, all turns are 90-degree turns only.)
- AOption (a)
19 km towards East
- BOption (b)
27 km towards west
- COption (c)
21 km towards west
- DOption (d)
25 km towards East
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Correct answer
25 km towards East
Why this answer is correct
Given:
Bharat starts from point Y and drives 31 km north.
He then turns left and drives 31 km, then turns left and drives 43 km.
He then turns right and drives 17 km.
He then turns right and drives 51 km.
He then turns right and drives 23 km,
Then turns right and drives 39 km and stops at point Z.
Net North-South Displacement:
N = (+31) + (-43) + (+51) + (-39)
N = 82 - 82 = 0
The net North-South displacement is 0 km.
Net East-West Displacement:
E = (+23) + (-31) + (-17)
E = 23 - 48 = -25
The negative sign means point Z is 25 km West of point Y.
So, to reach point Y again, Bharat should drive 25 km East.
Hence, the correct answer is "Option 4".
