Reasoning PYQs

Given equation: 65 * 56 * 8 * 19 * 2 * 34.

BODMAS Table: 

Let's check each option one by one.

Option 1) −, ÷, −, ×, =

Given: 65 * 56 * 8 * 19 * 2 * 34

After replacing the * signs we get;

⇒ 65 - 56 ÷ 8 - 19 × 2 = 34

⇒ 65 - 7 - 19 × 2 = 34

⇒ 65 - 7 - 38 = 34

⇒ 20 ≠ 34

⇒ LHS ≠ RHS

Option 2) +, +, −, ×, =

Given: 65 * 56 * 8 * 19 * 2 * 34

After replacing the * signs we get;

⇒ 65 + 56 + 8 - 19 × 2 = 34

⇒ 65 + 56 + 8 - 38 = 34

⇒ 129 - 38 = 34

⇒ 91 ≠ 34

⇒ LHS ≠ RHS

Option 3) +, ×, −, ×, =

Given: 65 * 56 * 8 * 19 * 2 * 34

After replacing the * signs we get;

⇒ 65 + 56 × 8 - 19 × 2 = 34

⇒ 65 + 448 - 38 = 34

⇒  513 - 38 = 34

⇒ 475 ≠ 34

⇒ LHS ≠ RHS

Option 4) +, ÷, −, ×, =

Given: 65 * 56 * 8 * 19 * 2 * 34

After replacing the * signs we get;

⇒ 65 + 56 ÷ 8 - 19 × 2 = 34

⇒ 65 + 7 - 19 × 2 = 34

⇒ 65 + 7 - 38 = 34

⇒ 72 - 38 = 34

⇒ 34 = 34

⇒ LHS = RHS

Hence, the correct answer is "Option 4".

The logic followed here is:

Option 1) MPJ

Option 2) DIB

Option 3) HKE

Option 4) TWQ

Here, 'DIB' is odd among the given options.

Hence, the correct answer is "Option 2".

Given

Statements:

All beards are nails.

Some nails are rings.

All rings are pendants.

The least possible Venn diagram for the given statement is:

Conclusions:

I. All rings can never be nails - False (Because, Some rings are nails).

II. Some beards are rings - False (Because, No definite relation given between beards and rings, so it can be possible only).

III. Some nails are pendants - True (Because, those part of nails that is ring is also pendants).

So, Only conclusion III follows.

Hence, the correct answer is "Option 2".

The logic followed here is:

Logic: **(**1^st number)² + (2nd number)² = 3^rd number.

Now,

For (16, 11, 377) 

→ (16)² + (11)2

→ 256 + 121 = 377.

Now, checking the options:

Option 1: (12, 15, 367)

→ (12)2 + (15)2

→ 144 + 225 = 369 ≠ 367.

Option 2: (16, 14, 452)

→ (16)2 + (14)2

→ 256 + 196 = 452.

Option 3: (14, 12, 340) 

→ (14)2 + (12)2

→ 196 + 144 = 340.

Option 4: (18, 13, 493) 

→ (18)2 + (13)2

→ 324 + 169 = 493.

Hence, the correct answer is "Option 1".

Given: 

Town M is to the west of Town D.

Town C is to the south-west of Town D.

Town D is to the north of Town B.

Town A is to the south of Town C.

Town M is to the north of Town C.

Town B is to the north-east of Town A.

So, Town B is South-east of Town M.

Hence, the correct answer is "Option 3".

The logic followed here is:

Logic: **(**1^st number)² + 2^nd number = 3^rd number.

Now,

(11, 100, 221)

→ (11)² + 100

→ 121 + 100 = 221.

(14, 104, 300)

→ (14)2 + 104

→ 196 + 104 = 300.

Similarly, for (13, 162, 331)

→ (13)2 + 162

→ 169 + 162 = 331.

Hence, the correct answer is "Option 4".

Given equation: (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 9.

BODMAS Table: 

Let's check each option one by one.

Option 1) 11 and 28

Given: (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 9

After interchanging the numbers we get;

⇒ (357 ÷ 2 + 3) ÷ 28 − 4 = (11 × 3 + 7) ÷ 9

⇒ (187.5 + 3) ÷ 28 − 4 = (33 + 7) ÷ 9

⇒ 190.5 ÷ 28 − 4 = 40 ÷ 9

⇒ 6.80 − 4 = 4.44

⇒ 2.80 ≠ 4.44

⇒ LHS ≠ RHS

Option 2) 2 and 3

Given: (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 9

After interchanging the numbers we get;

⇒ (357 ÷ 3 + 2) ÷ 11 − 4 = (28 × 2 + 7) ÷ 9

⇒ (119 + 2) ÷ 11 − 4 = (56 + 7) ÷ 9

⇒ 121 ÷ 11 − 4 = 63 ÷ 9

⇒ 11 - 4 = 7

⇒ 7 = 7

⇒ LHS = RHS

Option 3) 7 and 9

Given: (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 9

After interchanging the numbers we get;

⇒ (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 9) ÷ 7

⇒ (187.5 + 3) ÷ 11 − 4 = (84 + 9) ÷ 7

⇒ 190.5 ÷ 11 − 4 = 93 ÷ 7

⇒ 17.32 - 4 = 13.28

⇒ 13.32 ≠ 13.28

⇒ LHS ≠ RHS

Option 4) 2 and 9

Given: (357 ÷ 2 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 9

After interchanging the numbers we get;

⇒ (357 ÷ 9 + 3) ÷ 11 − 4 = (28 × 3 + 7) ÷ 2

⇒ (39.67 + 3) ÷ 11 − 4 = (84 + 7) ÷ 2

⇒ 42.67 ÷ 11 − 4 = 91 ÷ 2

⇒ 3.88 − 4 = 45.5

⇒ -0.12 ≠ 45.5

⇒ LHS ≠ RHS

Hence, the correct answer is "Option 2".

The correct mirror image of the given figure is:

Hence, the correct answer is "Option 1".

The logic followed here is:

Logic: 1^st number × (1^st number + 1) + 1 = 2^nd number.

Now,

6 : 43

→ 6 × (6 + 1) + 1,

→ 6 × 7 + 1 = 43.

4 : 21

→ 4 × (4 + 1) + 1,

→ 4 × 5 + 1 = 21.

Similarly, for 11 : ?

→ 11 × (11 + 1) + 1,

→ 11 × 12 + 1 = 133.

Hence, the correct answer is "Option 2".

The squares are:

So, there is '28' squares in the given figure.

Hence, the correct answer is "Option 1".

The logic followed here is:

Logic: **(√**1^st number + 1)² × 2 = 2^nd number.

Now,

For 16 : 50

→ (√16 + 1)² × 2

→ (4 + 1)2 × 2

→ 25 × 2 = 50.

For 144 : 338 

→ (√144 + 1)2 × 2

→ (12 + 1)2 × 2

→ 169 × 2 = 338.

Similarly, for 49 : ?

→ (√49 + 1)2 × 2

→ (7 + 1)2 × 2

→ 64 × 2 = 128.

Hence, the correct answer is "Option 1".

The logic followed here is:

For, MASTER : TSAMRE

For, SMILES : LIMSSE

Similarly, for FLIMSY : ?

Hence, the correct answer is "Option 3".

The logic followed here is:

So, '93' will complete the series.

Hence, the correct answer is "Option 2".

Given: Six friends A, C, D, E, F and G are sitting in a straight row, facing north.

They are waiting for their seventh friend B to join.

1. Exactly three people are sitting to the left of A.

2.  D is sitting to the immediate left of A, and E is second to the right of A.

3) C is occupying an end seat. 

4) F and D are immediate neighbours of G. 

Here, 'B' sit Fourth to the right of F.

Hence, the correct answer is "Option 1".

Given equation: 140 D 7 A 30 = 25 B ? D 8 

Decoding the given information :

Now, replacing the sign from left to right and using BODMAS rule, we get :

New equation : 140 ÷ 7 + 30 = 25 × ? ÷ 8 

Calculation :

⇒ 140 ÷ 7 + 30 = 25 × ? ÷ 8 

⇒ 20 + 30 = 25 × ? ÷ 8

⇒ 50 = 25 × ? ÷ 8

⇒ ? = 50 × 8 ÷ 25 = 16.

Hence, the correct answer is "Option 1".

The logic followed here is:

Logic: **(**3^rd number - 2^nd number) × 5 = 1^st number.

Now,

For (75, 55, 70)

→ (70 - 55) × 5

→ 15 × 5 = 75.

For (65, 55, 68) 

→ (68 - 55) × 5

→ 13 × 5 = 65.

Similarly, for (95, 85, 104)

→ (104 - 85) × 5

→ 19 × 5 = 95.

Hence, the correct answer is "Option 2".

Given: I, J, K, L, M, N and O are seven friends having different ages.

1. I is elder than K but younger than J.

J > I > K

2. K is elder than N but younger than I.

J > I > K > N 

3. J is elder than I but younger than 2 persons.

__ > __ > J > I > K > N 

4. L is elder than J.

5. M is not the eldest and O is the youngest.

L > M > J > I > K > N > O

There are '1 person' who's age is between I and N.

Hence, the correct answer is "Option 4".

The logic followed here is:

Logic: Alphabet are rotating one place in clockwise direction.

Symbols are rotated alternatively.

So, 'Option 4' will replace the question mark.

Hence, the correct answer is "Option 4".

The logic followed here is:

Logic: Sum of the place value of all numbers = Code of the word.

'FUTURE' is coded as ‘91'

⇒ 6 + 21 + 20 + 21 + 18 + 5 ⇒ 91.

'MONEY’ is coded as ‘72'

⇒ 13 + 15 + 14 + 5 + 25 ⇒ 72.

Similarly, for 'SECURE'

⇒ 19 + 5 + 3 + 21 + 18 + 5 ⇒ 71.

So, 'SECURE' will be coded as '71'.

Hence, the correct answer is "Option 3".

The logic followed here is:

Logic: Step I: Symbol 'Arrow' are getting shifted one place in clockwise direction.

Step II: Symbol 'Rectangle' are getting rotated and shifted one place in clockwise direction.

Step III: Symbol 'Diamond' are getting shifted one place in anti-clockwise direction.

 

The complete series will be:

So, 'Option 1' will replace the question mark.

Hence, the correct answer is "Option 1".