Let's check each option,
1) 7 and 6
→ 27 × 3 – (6)2 + 19 + (69 ÷ 23) × 7 – 15 = 70
→ 27 × 3 – (6)2 + 19 + 3 × 7 – 15 = 70
→ 81 – (6)2 + 19 + 21 – 15 = 70
→ 121 – (6)2 – 15 = 70
→ 85 – 15 = 70
→ 70 = 70
→ LHS = RHS ⇒ Satisfies the equation.
2) 19 and 15
→ 27 × 3 – (7)2 + 15 + (69 ÷ 23) × 6 – 19 = 70
→ 27 × 3 – 49 + 15 + 3 × 6 – 19 = 70
→ 81 – 49 + 15 + 18 – 19 = 70
→ 114 – 49 – 19 = 70
→ 46 ≠ 70
→ LHS ≠ RHS
3) 3 and 7
→ 27 × 7 – (3)2 + 19 + (69 ÷ 23) × 6 – 15 = 70
→ 27 × 7 – 9 + 19 + 3 × 6 – 15 = 70
→ 189 – 9 + 19 + 18 – 15 = 70
→ 127 – 9 – 15 = 70
→ 103 ≠ 70
→ LHS ≠ RHS
4) 3 and 6
→ 27 × 6 – (7)2 + 19 + (69 ÷ 23) × 3 – 15 = 70
→ 27 × 6 – (7)2 + 19 + 3 × 3 – 15 = 70
→ 162 – 49 + 19 + 9 – 15 = 70
→ 190 – 49 – 15 = 70
→ 126 ≠ 70
→ LHS ≠ RHS
Here, we can see that only Option 1 satisfies the logic.
Hence, the correct answer is "7 and 6".