Reasoning PYQs

The logic followed here is,

Thus, the missing term in the series is 124.

Hence, the correct answer is 'Option 1';

The logic followed here is,

Thus, the missing term in the series is −23693.

Hence, the correct answer is 'Option 1';

The logic followed in this pattern is a combination of alphabetical shifts and opposite letter relationships.

For 'EN' related to 'YM':

For 'DP' related to 'XK':

Applying the same logic to find the cluster related to 'DJ':

Thus, JQ is related to DJ.

Hence, the correct answer is 'Option 2'.

The logic followed in this pattern is a consistent alphabetical shift between consecutive letter clusters within each set.

Each subsequent cluster is formed by adding +2 to the first letter and +5 to the second letter of the preceding cluster.

For the set '(PO, RT, TY)':

For the set '(TQ, VV, XA)':

Applying the same logic to the group '(BQ, DV, FA)':

Thus, the group (BQ, DV, FA) follows the same logic as the given sets.

Hence, the correct answer is 'Option 4'.

Given: 21 July 1999 was a Wednesday.

Target Date: 21 November 1999.

Calculating the total number of days from 21 July 1999 to 21 November 1999:

Days remaining in July: 31 − 21 = 10 days

Days in August: 31 days

Days in September: 30 days

Days in October: 31 days

Days in November: 21 days (up to the 21^st)

Total number of days = 10 + 31 + 30 + 31 + 21 = 123 days

To find the number of odd days, we divide the total number of days by 7:

123 ÷ 7 = 17 weeks and 4 days remainder.

So, there are 4 odd days.

Now, count 4 days forward from Wednesday:

1 day after Wednesday = Thursday

2 days after Wednesday = Friday

3 days after Wednesday = Saturday

4 days after Wednesday = Sunday

Therefore, the day on 21 November 1999 was Sunday.

Hence, the correct answer is “Option 1”.

Given that there are 5 cars A, B, M, S and T with different speeds.

From the clues, we can deduce the following relationships:

1. Speed of only three cars is more than A.

→ A is faster than only one car, so A is the 2^nd slowest.

→ _ > _ > _ > A > _

2. Speed of S is more than at least four cars.

→ Since there are only 5 cars, S is faster than all the other four cars.

→ S is the fastest.

→ S > _ > _ > A > _

3. Speed of T is less than M and S.

→ M > T and S > T. 4. Speed of T is not the least.

→ T cannot be the slowest. Since A is already the 2^nd slowest, T must be above A.

→ S > M > T > A > B

Thus, the final order from fastest to slowest is:

→ S > M > T > A > B

Thus, the least speed is of Car B.

Hence, the correct answer is "Option 1".

7 children P, Q, R, S, T, U and V are sitting around a circular table facing towards the centre (not necessarily in the same order).

1. V is second to the right of R.
2. S and T are next to each other.
3. S is not the immediate neighbour of R or V.
4. Q is third to the left of P.
5. T is third to the right of U.
6. Q is the immediate neighbour of T.

P is immediate left of R.

Hence, the correct answer is “Option 1”.

Given word: ENDANGERED

(1) DECREE → Can not be formed as it requires the letter "C", which is not present in the given word. (2) EARNED → Can be formed as all the letters are present in the given word in the required quantity. (3) GARDENS → Can not be formed as it requires the letter "S", which is not present in the given word. (4) DANGEROUS → Can not be formed as it requires the letters "O, U" and "S", which are not present in the given word.

Hence, the correct answer is "Option 2".

Given word: CALENDAR

(1) LEND → Can be formed as all the letters (L, E, N, D) are present in the given word. (2) CARD → Can be formed as all the letters (C, A, R, D) are present in the given word.

(3) DENTAL → Can not be formed as the letter "T" is not present in the given word.

(4) CARNAL → Can be formed as all the required letters are present in the given word (A appears twice in CALENDAR).

Hence, the correct answer is “Option 3”.

The logic followed here is,

1. Temperature on Day 1 = 24.0

2. Temperature on Day 2 = 24.0 + 1.5 = 25.5

3. Temperature on Day 3 = 25.5 + 1.7 = 27.2

4. Temperature on Day 4 = 27.2 + 1.9 = 29.1

5. Temperature on Day 5 = 29.1 + (1.9 + 0.2) = 29.1 + 2.1 = 31.2

6. Temperature on Day 6 = 31.2 + (2.1 + 0.2) = 31.2 + 2.3 = 33.5

Thus, the expected temperature on the 6^th day in the series is 33.5 degreeC.

Hence, the correct answer is 'Option 3';

Pattern followed here is,

Similarly,

Hence, the correct answer is “Option 1”.

Pattern followed here is,

Similarly,

Hence, the correct answer is “Option 2”.

For, AL220 : MB240

For, JK330 : LK350

Similarly,

ST110 : ?

 

Hence, the correct answer is 'Option 1'.

DZ155 : GG355

BK605 : ER805

Similarly,

? : DZ445

Hence, the correct answer is 'Option 4'.

The logic followed here is:

Logic: Second Number = First Number + 54

For the third and fourth numbers 5191 : 5245

⇒ 5191 + 54 = 5245.

For the fifth and sixth numbers 8259 : 8313

⇒ 8259 + 54 = 8313.

Applying the same logic to the first and second numbers

7084 : ?

⇒ 7084 + 54 = 7138.

Hence, the correct answer is 'Option 2'.

The logic followed here is:

Logic: Second Number = (First Number − 2)³

For the first pair 14 : 1728

⇒ (14 − 2)³

⇒ 12³ = 1728.

For the second pair 19 : 4913

⇒ (19 − 2)³

⇒ 17³ = 4913.

Applying the same logic to the third pair

29 : ?

⇒ (29 − 2)³

⇒ 27³ = 19683.

Hence, the correct answer is 'Option 3'.

FIRE is coded as IMNZ →

POLE is coded as SSHZ →

Similarly,

let us find the code for HIYA:

Hence, the correct answer is “Option 4”.

Given:

Therefore, 'teach prime' be coded in that code language as "xl ta".

Hence, the correct answer is “Option 1”.

Pattern followed here is,

Hence, the correct answer is “Option 3”.

According to the problem:

The clock gains 6 minutes every hour.

The duration of time elapsed is 18 hours.

The time currently shown on the clock is 8 PM.

Total gain = 18 × 6 minutes

Total gain = 108 minutes

Next, we convert this gain from minutes into hours and minutes:

108 minutes = 60 minutes + 48 minutes

108 minutes = 1 hour 48 minutes

The actual time is determined by subtracting this total gain from the displayed time (8 PM):

Actual time = 8:00 PM − 1 hour 48 minutes

Step 1: 8:00 PM − 1 hour = 7:00 PM

Step 2: 7:00 PM − 48 minutes = 6:12 PM

Therefore, the actual time is 6:12.

Hence, the correct answer is “Option 1”.