Shortcut Trick
Length of Train A = Speed × Time = (60 × 5/18) × 15 = 250 m
Relative speed (opposite direction) = (60 + 48) × 5/18 = 108 × 5/18 = 30 m/s
Total distance (Length of Train A + Length of Train B) = Relative speed × Time = 30 × 19 = 570 m
Length of Train B = 570 − 250 = 320 m
∴ The correct answer is 320 m.
Alternate Method
Given:
Speed of Train A (SA) = 60 km/h
Time taken by Train A to cross an electric pole = 15 s
Speed of Train B (SB) = 48 km/h
Time taken by both trains to cross each other = 19 s
Formula Used:
Distance = Speed × Time
Speed in m/s = Speed in km/h × (5/18)
Relative Speed (opposite directions) = SA + SB
Calculations:
Train A
60 km/h →
Length = 250 m
Train B
← 48 km/h
Length = ?
Relative Speed = 108 km/h | Time = 19 s
⇒ Speed of Train A in m/s = 60 × 5/18 = 50/3 m/s
⇒ Length of Train A (LA) = Speed × Time = (50/3) × 15 = 250 m
⇒ Relative speed of Train A and Train B = 60 + 48 = 108 km/h
⇒ Relative speed in m/s = 108 × 5/18 = 30 m/s
⇒ Total distance covered during crossing = LA + LB
⇒ Total Distance = Relative speed × Time
⇒ 250 + LB = 30 × 19
⇒ 250 + LB = 570
⇒ LB = 570 − 250 = 320 m
∴ The correct answer is 320 m.
Additional Information
Relative Speed (Opposite Directions)
When two bodies move in opposite directions, their relative speed is the sum of their individual speeds: Relative Speed = S1 + S2
Relative Speed (Same Direction)
When two bodies move in the same direction, their relative speed is the difference of their individual speeds: Relative Speed = |S1 − S2|
Unit Conversion
To convert speed from km/h to m/s, multiply the value by 5/18. To convert speed from m/s to km/h, multiply by 18/5.
Train Crossing Concepts
When a train crosses a stationary object of negligible length (like an electric pole or a standing man), the distance traveled is equal to the length of the train itself. When crossing another train or a platform, the distance traveled is the sum of their lengths: L1 + L2.