Shortcut Trick
Net deviation when 15 persons (60 kg) leave = 15 × (70 − 60) = +150 kg (distributed among remaining n − 15 persons).
Net deviation when 15 persons (87.5 kg) join = 15 × (87.5 − 70) = +262.5 kg (distributed among total n + 15 persons).
Since new averages are equal, deviations added to the base average must be equal: 150 ÷ (n − 15) = 262.5 ÷ (n + 15).
⇒ (n + 15) ÷ (n − 15) = 262.5 ÷ 150 = 7 ÷ 4
⇒ 4n + 60 = 7n − 105 ⇒ 3n = 165 ⇒ n = 55.
∴ The correct answer is 55.
Alternate Method
Given:
Initial average of n persons = 70 kg
Case 1: 15 persons leave (Avg = 60 kg)
Case 2: 15 persons join (Avg = 87.5 kg)
Formula Used:
Total Weight = Average × Number of persons
New Average = (Initial Total Weight ± Weight Change) ÷ (Initial Number ± Change in Number)
Calculations:
⇒ Case 1 Average = (70n − 15 × 60) ÷ (n − 15)
⇒ Case 1 Average = (70n − 900) ÷ (n − 15)
⇒ Case 2 Average = (70n + 15 × 87.5) ÷ (n + 15)
⇒ Case 2 Average = (70n + 1312.5) ÷ (n + 15)
Equating both cases:
⇒ (70n − 900) ÷ (n − 15) = (70n + 1312.5) ÷ (n + 15)
⇒ (70n − 900)(n + 15) = (70n + 1312.5)(n − 15)
⇒ 70n2 + 1050n − 900n − 13500 = 70n2 − 1050n + 1312.5n − 19687.5
⇒ 150n − 13500 = 262.5n − 19687.5
⇒ 262.5n − 150n = 19687.5 − 13500
⇒ 112.5n = 6187.5
⇒ n = 6187.5 ÷ 112.5 = 55
∴ The correct answer is 55.
Additional Information
Average and Deviation
Net deviation from the average is always zero. If new members join, the new average = Old Avg + (Total Deviation ÷ New Total Number).
Weighted Average
When two groups are combined, the combined average is Aavg = (n1A1 + n2A2) ÷ (n1 + n2).
Case of Leaving Persons
If members leave with weight less than the average, the average of the remaining group increases.