We need to find the day for 18 March 2020.
Completed years (2000 years + 19 years) + period from 1 January 2020 to 18 March 2020.
1. Odd days in 2000 years:
As 2000 is a multiple of 400 ⇒ 0 odd days.
2. Odd days in the remaining 19 years (2001 to 2019):
In 19 years, number of leap years = 19/4 = 4 (2004, 2008, 2012, 2016).
Number of ordinary years = 19 − 4 = 15.
Odd days = (4 × 2) + (15 × 1) = 8 + 15 = 23 days.
23 days = (23 ÷ 7) ⇒ 3 weeks + 2 odd days.
3. Odd days in 2020 (up to 18 March):
2020 is a leap year (divisible by 4).
January = 31 days
February = 29 days
March = 18 days
Total days = 31 + 29 + 18 = 78 days.
78 days = (78 ÷ 7) ⇒ 11 weeks + 1 odd day.
4. Total odd days:
Total odd days = 0 (from 2000 years) + 2 (from 19 years) + 1 (from 2020) = 3 odd days.
5. Mapping of the day:
According to the odd days count: 0 = Sunday, 1 = Monday, 2 = Tuesday, 3 = Wednesday, 4 = Thursday, 5 = Friday, 6 = Saturday.
Since the total number of odd days is 3, the day was Wednesday.
The day on 18 March 2020 is Wednesday.
Hence, the correct answer is “Option 2”.

Alternate Method
Using the formula: Day = (Date + Month Code + Century Code + Year + Year/4) ÷ 7
For 18 March 2020:
Date = 18
Month Code (March) = 4
Century Code (2000) = 6
Year = 20
Leap Year (20 ÷ 4) = 5
Total = 18 + 4 + 6 + 20 + 5 = 53
53 ÷ 7 ⇒ Remainder = 4
In this system (where 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday), the code 4 corresponds to Wednesday.
Hence, the correct answer is Wednesday.