Quantitative Aptitude PYQs

Cost of raw material = 6 × 25 = Rs. 150

Cost of labour = 5 × 35 = Rs. 175

Overhead cost = Rs. 2.5

Total cost = Rs. 150 + Rs. 175 + Rs. 2.5 = Rs. 327.50

Cost of raw material = 3 × 25 = Rs. 75

Cost of labour = 3 × 35 = Rs. 105

Overhead cost = Rs. 1

⇒ Total cost = Rs. 181

Profit = SP – CP

Profit = 200 – 181 = Rs. 19

Product D

Cost of raw material = 4 × 25 = Rs. 100

Cost of labour = 2 × 35 = Rs. 70

Total cost = Rs. 170

Product E

Cost of raw material = 5 × 25 = Rs. 125

Cost of labour = 3 × 35 = Rs. 105

⇒ Total cost = Rs. 230

⇒ Ratio of cost of product D and E = 17 : 23

Cost of raw material = 3 × 25 = Rs. 75

Cost of labour = 2 × 35 = Rs. 70

Overhead cost = Rs. 0.5

⇒ Total cost = Rs. 145.50

Cost price of 4 units = 145 × 4 = 582

SP = 582 × 1.1 = Rs. 640.2

Product C

Cost of raw material = 3 × 25 = Rs. 75

Cost of labour = 2 × 35 = Rs. 70

Overhead cost = Rs. 0.5

⇒ Total cost = Rs. 145.50

Product A

Cost of raw material = 6 × 25 = Rs. 150

Cost of labour = 5 × 35 = Rs. 175

Overhead cost = Rs. 2.5

⇒ Total cost = Rs. 327.5

⇒ Difference of cost = 327.5 – 145.5 = Rs. 182

Given

Total number of seat (Lok Sabha and Rajya Sabha) of Uttar Pradesh = 111

The number of Rajya Sabha seats of UP = 31

Calculation

Let the number of Lok Sabha seats of Uttar Pradesh be x

Hence, 31 + x = 111

⇒ x = 80

Lok Sabha seat of Tamil Nadu = 39

Now, Required percentage = [(80 – 39)/39] × 100 = (41/39) × 100 = 105.1% ≈ 105%

Given

Lok Sabha seats of West Bengal = 42

Calculation

Let the Lok Sabha and Rajya Sabha seats of West Bengal be 21x and 8x

According to the question,

21x = 42

⇒ x = 2

Now, 8x = 8 × 2 = 16

Total number of seats of West Bengal = Lok Sabha + Rajya Sabha = 42 + 16 = 58

Total number of seats of Tamil Nadu = Lok Sabha + Rajya Sabha = 39 + 18 = 57

∴ Ratio of total seats of West Bengal and Tamil Nadu = 58 : 57

Given

Lok Sabha seats of Tamil Nadu = 39

Lok sabha seats of Maharashtra = 48

Calculation

According to the question,

Rajya Sabha seats of bihar = 3 + (Lok Sabha seats of Tamil Nadu/3)

⇒ 3 + (39/3) = 16

Total seats (Lok Sabha and Rajya Sabha) of Bihar = 55

⇒ 16 + seats of Lok Sabha = 55

⇒ Seats of Lok Sabha = 39

Hence, Required percentage = (48 – 39)/48 × 100 = (9/48) × 100 = 18.75%

∴ Lok Sabha seats of Bihar is less than the Lok Sabha seats of Maharashtra by 18.75%

Given

Lok Sabha seats of Maharashtra = 48

Calculation

According to the question,

Total number of seats of Madhya Pradesh = \(33\frac{1}{3}\)% × 120 = (1/3) × 120 = 40

As, the ratio of Lok Sabha and Rajya Sabha seats of MP = 29 : 11 = 29x : 11x

Hence, 29x + 11x = 40

⇒ x = 1

So, Rajya Sabha seats of Madhya Pradesh = 11

Now, Rajya Sabha seats of Madhya Pradesh : Lok Sabha seats of Maharashtra = 11 : 48

∴ The ratio of Rajya Sabha seats of Madhya Pradesh and Lok Sabha Seats of Maharashtra is 11 : 48

Given

Rajya Sabha seats of Uttar Pradesh = 31

Calculation

Let the Lok Sabha seats of Uttar Pradesh be x

Rajya Sabha seats of Uttar Pradesh = 31

According to the question,

Lok Sabha seats of Uttar Pradesh – 2(Rajya Sabha seats of Uttar Pradesh) = 18

⇒ x – 2(31) = 18

⇒ x = 18 + 62 = 80

Population density = (Total Population/Number of Lok sabha seats) = 250000000/80

= 25000000/8

= 3125000

∴ The population density of Lok Sabha of Uttar Pradesh is 3125000

Follow BODMAS rule to solve this question, as per the order given below, 

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and follow BODMAS rule in the bracket,

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value,

So, we can write these values to their nearest integers.

Given expression is

√1763.98 + √1444.04 - (39.99% of 149.92) = ?

⇒ √1764 + √1444 - (40% of 150) = ?

⇒ 42 + 38 - (40/100 × 150) = ?

⇒ 42 + 38 - 60 = ?

⇒ 80 - 60 = ?

⇒ 20 = ?

Follow BODMAS rule to solve this question, as per the order given below, 

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket-

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since we need to find out the approximate value,

we can write these values to their nearest integers.

Given expression is

29.9% of 499.99 - 49.93% of 399.99 + 69.92% of 199.99 = ?

⇒ 30% of 500 - 50% of 400 + 70% of 200 = ?

⇒ (30/100) × 500 - (50/100) × 400 + (70/100) × 200 = ?

⇒ 150 - 200 + 140 = ?

⇒ 290 - 200 = ?

⇒ ? = 90

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

638.4 ÷ 22.1 + 99.7 × 20.1 - (27)² = ?

Taking the approximate values as,

638.4 ≈ 638, 22.1 ≈ 22, 99.7 ≈ 100, 20.1 ≈ 20

⇒ 638 ÷ 22 + 100 × 20 - (27)² = ?

⇒ 29 + 2000 - 729 = ?

∴ ? = 1300

Follow the BODMAS rule to solve this question, as per the order given below. 

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first and following  BODMAS rule in the bracket-

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since we need to find out the approximate value, we can write these values to their nearest integers.

Given expression is

39.98% of 699.97 = 799.98 + 59.84% of 599.99 - ?

⇒ 40% of 700 = 800 + 60% of 600 - ?

⇒ 280 = 800 + 360 - ?

⇒ ? = 1160 - 280 = 880

Follow the BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first and following BODMAS rule in the bracket-

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since we need to find out the approximate value, we can write these values to their nearest integers.

Given expression is

39.99% of 799.98 + 59.98% of 499.98 = 24.89% of ?

⇒ 40% of 800 + 60% of 500 = 25% of ?

⇒ 320 + 300 = (25/100) × ?

⇒ 620 × 100/25 = ?

⇒ ? = 2480

Calculation:

⇒ 25 + (1)³ = 26

⇒ 26 - (2)³ = 18

⇒ 18 + (3)³ = 45

⇒ 45 - (4)³ = - 19

⇒ -19 + (5)³ = 106

∴ The missing number is -19.

Calculation:

⇒  18 + 1 x 2 = 20

⇒ 20 + 2 x 3 = 26

⇒ 26 + 3 x 4 = 38

⇒ 38 + 4 x 5 = 58 

⇒ 58 + 5 x 6 = 88

∴ The required answer is 88.

Calculation:

⇒ 5 x 2 + 2 = 12

⇒ 12 x 3 - 3 = 33

⇒ 33 x 4 + 4 = 136

⇒ 136 x 5 - 5 = 675

⇒ 675 x 6 + 6 = 4056 

∴ The missing number is 4056.

Calculation:

⇒ 4 x 2 + 3 = 11

⇒ 11 x 3 + 4 = 37

⇒ 37 x 4 + 5 = 153

⇒ 153 x 5 + 6 = 771

⇒ 771 x 6 + 7 = 4633 

∴ The required answer is 771.

Calculation:

⇒ 8 x 0.5 + 0.5 = 4.5

⇒ 4.5 x 1 + 1 = 5.5

⇒ 5.5 x 2 + 2 = 13

⇒ 13 x 4 + 4 = 56

⇒ 56 x 8 + 8 = 456

∴ The required answer is 456.