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Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1345 Total Questions41 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 981–1000 of 1345Page 50 of 68
SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 981

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer

I. x2 – 7x + 12 = 0

II. 2y2 – 19y + 44 = 0

  1. AOption (a)

    x < y

  2. BOption (b)

    x ≤ y

  3. COption (c)

    x > y

  4. DOption (d)

    x ≥ y

  5. EOption (e)

    x = y or no relationship can be obtained

View answer & explanation

Correct answer

Answer: (b)B.

x ≤ y

Why this answer is correct

Here,

⇒ P(x) = x2 - 7x + 12 = 0

⇒ P(y) = 2y2 - 19y + 44 = 0

Factorization of P(x) and P(y);

⇒ P(x) = x2 - 3x - 4x + 12 = 0

⇒ x(x - 3) - 4(x - 3) = 0

⇒ (x - 3) (x - 4) = 0

⇒ x = 3 or x = 4

⇒ P(y) = 2y2 - 8y - 11y + 44 = 0

⇒ 2y(y - 4) - 11(y - 4) = 0

⇒ (y - 4)(2y - 11) = 0

⇒ y = 4 or y = 11/2

⇒ x ≤ y

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 982

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

In the following question two equations numbered I and II are given. You have to solve both the equations and give the answer:

I. 3x2 - 13x + 12 = 0

II. 2y2 - 15y + 28 = 0

  1. AOption (a)

    x < y

  2. BOption (b)

    x ≤ y

  3. COption (c)

    x > y

  4. DOption (d)

    x ≥ y

  5. EOption (e)

    x = y or no relationship can be obtained

View answer & explanation

Correct answer

Answer: (a)A.

x < y

Why this answer is correct

Here,

P(x) = 3x2 - 13x + 12 = 0

P(y) = 2y2 - 15y + 28 = 0

Factorization of P(x) and P(y);

⇒ P(x) = 3x2 - 9x - 4x + 12 = 0

⇒ 3x(x - 3) - 4(x - 3) = 0

⇒ (x - 3) (3x - 4) = 0

⇒ x = 3 or x = 4/3

⇒ P(y) = 2y2 - 8y - 7y + 28 = 0

⇒ 2y(y - 4) - 7(y - 4) = 0

⇒ (y - 4)(2y - 7) = 0

⇒ y = 4 or y = 7/2

Here, x < y

∴ Option 1 is the answer

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 983

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

For disc D, what is the respective ratio of used space to the available space?

  1. AOption (a)

    2:1

  2. BOption (b)

    3:1

  3. COption (c)

    1:2

  4. DOption (d)

    1:3

  5. EOption (e)

    2:3

View answer & explanation

Correct answer

Answer: (c)C.

1:2

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

Required ratio = 50: 100

⇒ 1:2

∴ The correct answer is 1:2.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 984

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

For disc A, the total space available is how much more or less than that of disc D?

  1. AOption (a)

    25% more

  2. BOption (b)

    25% less

  3. COption (c)

    35% more

  4. DOption (d)

    40% more

  5. EOption (e)

    75% less

View answer & explanation

Correct answer

Answer: (b)B.

25% less

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

Required % = [(100 - 75)/100] × 100

⇒ 25% less

∴ The correct answer is 25% less.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 985

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

If another Disc E, has 20% more total storage than Disc C, and total used space in Disc E is same as DISC C, Then find out the available space in Disc E?

  1. AOption (a)

    70 GB

  2. BOption (b)

    60 GB

  3. COption (c)

    80 GB

  4. DOption (d)

    90 GB

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

80 GB

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

 

Total storage in the disc E = 120% of 125

⇒ 150 GB

Total used space in the disc E = 70 GB

Total available space in the disc E = 150 - 70 = 80 GB

∴ The correct answer is 80 GB.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 986

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

which of the following option has maximum available space?

  1. AOption (a)

    Disk (A+C)

  2. BOption (b)

    Disk (A+B)

  3. COption (c)

    Disk (D+C)

  4. DOption (d)

    Disk (B+D)

  5. EOption (e)

    Disk (B+C)

View answer & explanation

Correct answer

Answer: (d)D.

Disk (B+D)

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

Available space in Disk (A+C) = 75 + 55 = 130

Available space in Disk (A+B) = 75 + 70 = 145

Available space in Disk (D+C) = 100 + 55 = 155

Available space in Disk (B+D) = 70 + 100 = 170

Available space in Disk (B+C) = 70 + 55 = 125

Here, Disk (B+D) has maximum available space

∴ The correct answer is Disk (B+D).

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 987

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

Total used space in Disc B is how much percentage of the total used space in Disc A and disc D?

  1. AOption (a)

    20%

  2. BOption (b)

    30%

  3. COption (c)

    40%

  4. DOption (d)

    50%

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

30%

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

 

Required % = [30/(50+50)] × 100 

⇒ 30%

∴ The correct answer is 30%.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 988

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

Find the percentage of total used space in Disc C with respect to total available space in Disc C?

  1. AOption (a)

    120.27%

  2. BOption (b)

    110.27%

  3. COption (c)

    125.27%

  4. DOption (d)

    127.27%

  5. EOption (e)

    130.27%

View answer & explanation

Correct answer

Answer: (d)D.

127.27%

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

Required % = [70/55] × 100 

⇒ 127.27%

∴ The correct answer is 127.27%.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 989

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following information to answer the given questions.

Pie chart 1 shows the percentage distribution of total storage in four disc A, B, C, and D respectively.

Pie chart 2 shows the percentage distribution of total used space in four disc A, B, C and D respectively.

Find the difference between the sum of total storage in Disc B and Disc D to the sum of disc A and disc C?

  1. AOption (a)

    0 GB

  2. BOption (b)

    5 GB

  3. COption (c)

    15 GB

  4. DOption (d)

    10 GB

  5. EOption (e)

    20 GB

View answer & explanation

Correct answer

Answer: (a)A.

0 GB

Why this answer is correct

From the data given in the pie chart, we have:

DiskTotal storage in the disc (500 GB)Total used space in the disc (200 GB)Total available space in the disc
A25% of 500 = 12525% of 200 = 50125 - 50 = 75
B20% of 500 = 10015% of 200 = 30100 - 30 = 70
C25% of 500 = 12535% of 200 = 70125 - 70 = 55
D30% of 500 = 15025% of 200 = 50150 - 50 = 100
Total500200300

Required difference = (100 + 150) - (125 + 125) = 0 GB

∴ The correct answer is 0 GB.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 990

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Pipe A fills twice as fast as pipe B and pipe B fills twice as fast as pipe C. Pipe C can fill a tank in 20 hours. In how many hours will the tank fill if all the pipes are opened?

  1. AOption (a)

    \(2\frac{5}{7};{\text{hr}}\)

  2. BOption (b)

    \(3\frac{6}{7};{\text{hr}}\)

  3. COption (c)

    \(2\frac{6}{14};{\text{hr}}\)

  4. DOption (d)

    \(2\frac{6}{7};{\text{hr}}\)

  5. EOption (e)

    \(4\frac{6}{7};{\text{hr}}\)

View answer & explanation

Correct answer

Answer: (d)D.

\(2\frac{6}{7};{\text{hr}}\)

Why this answer is correct

Shortcut Trick

Ratio of efficiencies of Pipe A : Pipe B : Pipe C is 4 : 2 :

  1. Total Work = Efficiency of C × Time of C = 1 × 20 = 20 units.

Combined Efficiency = 4 + 2 + 1 = 7 units/hr.

Time Taken = 20 ÷ 7 = 2(6/7) hr.

∴ The correct answer is 2(6/7) hr.

Alternate Method

Given:

Time taken by Pipe C = 20 hours.

Efficiency of Pipe B = 2 × Efficiency of Pipe C.

Efficiency of Pipe A = 2 × Efficiency of Pipe B.

Formula Used:

Total Work = Efficiency × Time

PersonEfficiency (Ratio)Total WorkTime (hr)
Pipe C120 units20
Pipe B210
Pipe A45

Calculations:

⇒ Efficiency of Pipe C = 1 unit/hr

⇒ Efficiency of Pipe B = 2 × 1 = 2 units/hr

⇒ Efficiency of Pipe A = 2 × 2 = 4 units/hr

⇒ Total capacity of tank = 20 × 1 = 20 units

⇒ Combined efficiency of (A + B + C) = 4 + 2 + 1 = 7 units/hr

⇒ Total time required = 20 ÷ 7 hours

⇒ Time = 2(6/7) hours

∴ The correct answer is 2(6/7) hr.

Additional Information

Efficiency and Time Relation

Efficiency is inversely proportional to the time taken to complete a work. If efficiency ratio is x:y, then time ratio is y:x.

Pipes and Cisterns

Inlet pipes have positive efficiency while outlet/leakage pipes have negative efficiency in calculations.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 991

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Anu, Taru and Daksh started a business. Taru invested 1/ 6 of the total money, while investments of Anu and Daksh are equal. If the profit on the end of the year is Rs. 7200, find the difference between the profit of Taru and Daksh.

  1. AOption (a)

    Rs. 1305

  2. BOption (b)

    Rs. 1000

  3. COption (c)

    Rs. 1205

  4. DOption (d)

    Rs. 1105

  5. EOption (e)

    None of these 

View answer & explanation

Correct answer

Answer: (e)E.

None of these 

Why this answer is correct

Shortcut Trick

Assume Total Investment is 6 units.

Taru investment = 1/6 × 6 = 1 unit.

Remaining investment = 6 − 1 = 5 units, divided equally between Anu and Daksh.

Anu = 2.5 units, Daksh = 2.5 units.

Difference between Taru and Daksh = 2.5 − 1 = 1.5 units.

Profit difference = (1.5 ÷ 6) × 7200 = 1800.

∴ The correct answer is Rs. 1800.

Alternate Method

Given: Total Profit = Rs. 7200, Taru investment = 1/6 of Total, Anu = Daksh.

Formula: Profit Share ∝ Investment × Time period.

⇒ Let Total Investment be x. Taru = x/6.

⇒ Anu + Daksh = x − x/6 = 5x/6.

⇒ Since Anu = Daksh, each invested (5x/6) ÷ 2 = 5x/12.

⇒ Ratio of Profit (Taru : Anu : Daksh) = 1/6 : 5/12 : 5/12 = 2 : 5 : 5.

⇒ Taru Profit = (2/12) × 7200 = 1200.

⇒ Daksh Profit = (5/12) × 7200 = 3000.

⇒ Difference = 3000 − 1200 = 1800.

∴ The correct answer is Rs. 1800.

Additional Information

Partnership Profit Distribution

Profit is divided in the ratio of the product of Capital and Time. If time is constant, Profit Ratio = Capital Ratio.

Ratio Balancing

To simplify fractions like 1/6 and 5/12, multiply all terms by the LCM of denominators (12) to get whole numbers.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 992

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

Ratio of present age of Ranjan and Sanjay is 3 : 2. Sanjay's age 8 years hence will be equal to Ranjan's age 8 years ago. If Irfan is 12 years older than Sanjay, What is the present age of Irfan ?

  1. AOption (a)

    60

  2. BOption (b)

    44

  3. COption (c)

    42

  4. DOption (d)

    32

  5. EOption (e)

    52

View answer & explanation

Correct answer

Answer: (b)B.

44

Why this answer is correct

Shortcut Trick

Ratio of Ranjan : Sanjay = 3 : 2.

Difference in ratio parts = 3 − 2 = 1 unit.

Age difference = 8 + 8 = 16 years.

1 unit = 16 years ⇒ Sanjay (2 units) = 32 years.

Irfan = 32 + 12 = 44 years.

∴ The correct answer is 44 years.

Alternate Method

Given: Ratio of ages = 3 : 2; Irfan = Sanjay + 12.

Formula: Age after n years = Age + n; Age n years ago = Age − n.

⇒ Let Ranjan = 3x and Sanjay = 2x.

⇒ According to question: 2x + 8 = 3x − 8

⇒ 3x − 2x = 8 + 8

⇒ x = 16

⇒ Sanjay present age = 2 × 16 = 32 years.

⇒ Irfan present age = 32 + 12 = 44 years.

∴ The correct answer is 44 years.

Additional Information

Age Difference Invariability

The difference between the ages of two persons remains constant throughout their lives regardless of the number of years passed.

Ratio and Proportion in Ages

If the ratio of ages is a : b, their actual ages can be assumed as ax and bx. The value of x is found using the given linear conditions.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 993

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

The ratio between the monthly salary of P and Q is 20 : 21. The ratio between the expenditure of P and Q is 5 : 7. The difference between the salary of Q and P is Rs.2000 and the savings of Q is Rs.14000. Find the ratio between the savings of P and Q.

  1. AOption (a)

    2 : 7

  2. BOption (b)

    12 : 7

  3. COption (c)

    5 : 2

  4. DOption (d)

    7 : 12

  5. EOption (e)

    10 : 7

View answer & explanation

Correct answer

Answer: (e)E.

10 : 7

Why this answer is correct

Shortcut Trick

Difference in salary ratio parts = 21 − 20 = 1 unit.

Given 1 unit = ₹2000 ⇒ Salary of P = 20 × 2000 = ₹40,000; Salary of Q = 21 × 2000 = ₹42,000.

Expenditure of Q = Salary − Savings = 42,000 − 14,000 = ₹28,000.

Expenditure ratio P:Q is 5:7 → 7 units = 28,000 ⇒ 5 units (P) = ₹20,000.

Savings of P = 40,000 − 20,000 = ₹20,000.

Savings Ratio P:Q = 20,000 : 14,000 = 10 : 7.

∴ The correct answer is 10 : 7.

Alternate Method

Given: Salary ratio P:Q = 20:21, Expenditure ratio P:Q = 5:7.

Formula: Savings = Income − Expenditure

⇒ Let Salary of P = 20x and Q = 21x.

⇒ Difference = 21x − 20x = x = ₹2000.

⇒ Salary P = 20 × 2000 = ₹40,000; Salary Q = 21 × 2000 = ₹42,000.

⇒ Expenditure of Q = Salary Q − Savings Q = 42,000 − 14,000 = ₹28,000.

⇒ Let Expenditure of P = 5y and Q = 7y. Since 7y = 28,000 ⇒ y = 4,000.

⇒ Expenditure of P = 5 × 4,000 = ₹20,000.

⇒ Savings of P = 40,000 − 20,000 = ₹20,000.

⇒ Required Ratio = Savings P : Savings Q = 20,000 : 14,000 = 10 : 7.

∴ The correct answer is 10 : 7.

Additional Information

Income and Savings Relation

Income = Expenditure + Savings. If any two variables are known or their ratios are provided with a fixed difference, the third can be calculated.

Ratio and Proportion

If a:b is the ratio and the difference between quantities is d, then the actual values are [a/(b−a)]×d and [b/(b−a)]×d.

Cross Multiplication Method

Used when initial ratio, changes (savings), and final ratio (expenditure) are given: (Initial Ratio × Final Ratio parts) − (Savings × Ratio parts).

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 994

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

A certain amount was to be distributed among A, B and C in the ratio 3 ∶ 4 ∶ 5 respectively, but was erroneously distributed in the ratio 9 ∶ 4 ∶ 7 respectively. As a result of this B got Rs. 60 less. What is the amount?

  1. AOption (a)

    Rs. 480

  2. BOption (b)

    Rs. 460

  3. COption (c)

    Rs. 450

  4. DOption (d)

    Rs. 440

  5. EOption (e)

    Rs. 640

View answer & explanation

Correct answer

Answer: (c)C.

Rs. 450

Why this answer is correct

Shortcut Trick

Equate the total sum of ratios: Original (3+4+5 = 12) and New (9+4+7 = 20).

LCM of 12 and 20 is 60. Multiply Original ratio by 5 and New ratio by 3.

Original B = 4 × 5 = 20 units; New B = 4 × 3 = 12 units.

Difference in B = 20 − 12 = 8 units → ₹60. Total amount (60 units) = (60/8) × 60 = ₹450.

∴ The correct answer is ₹450.

Alternate Method

Given: Original ratio A:B:C = 3:4:5 | New ratio A:B:C = 9:4:7 | Loss for B = ₹60

Formula: Share = (Individual Ratio / Total Ratio) × Total Amount (X)

⇒ Original share of B = (4 / (3+4+5)) × X = 4X / 12 = X / 3

⇒ New share of B = (4 / (9+4+7)) × X = 4X / 20 = X / 5

⇒ Difference = (X / 3) − (X / 5) = 60

⇒ (5X − 3X) / 15 = 60

⇒ 2X / 15 = 60

⇒ 2X = 900

⇒ X = 450

∴ The correct answer is ₹450.

Additional Information

Ratio Balancing

When the total quantity remains constant across two different ratio distributions, multiply each ratio by the total sum of the other ratio to balance them.

Compound Ratio

The compound ratio of (a : b) and (c : d) is (ac : bd), used when multiple factors influence a final share.

Inverse Ratio Property

If an amount is distributed inversely to original values, the new share of x is proportional to 1/x.

SBI PO Prelims Memory Based Paper (Held on: 17th Dec 2022 Shift 2) (Previous Year Paper)·Quantitative Aptitude
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Question 995

SBI Probationary Officer (PO) 2022• Quantitative Aptitude• Quantitative Aptitude

A shopkeeper marks up the worth of his product by 40%. If he increases the discount from 10% to 15%, his profit will be decreased by Rs. 21. How much profit/loss would he get, if he offered a 20% discount on the marked price?

  1. AOption (a)

    115

  2. BOption (b)

    36

  3. COption (c)

    54

  4. DOption (d)

    125

  5. EOption (e)

    250

View answer & explanation

Correct answer

Answer: (b)B.

36

Why this answer is correct

Shortcut Trick

Let Cost Price (CP) = 100 units. Marked Price (MP) = 140 units.

Difference in Discount = 15% − 10% = 5% of MP.

5% of 140 = 7 units. Given, 7 units = Rs. 21 ⇒ 1 unit = Rs. 3. For 20% discount: Selling Price (SP) = 140 × 80/100 = 112 units.

Profit = 112 − 100 = 12 units ⇒ 12 × 3 = Rs. 36. ∴ The correct answer is Rs. 36.

Alternate Method

Given: Markup = 40%, D1 = 10%, D2 = 15%, Profit Decrease = Rs. 21. Formulas: MP = CP × (100 + Markup%) ÷ 100 | SP = MP × (100 − D%) ÷ 100 | Profit = SP − CP

⇒ Let CP = x. Then MP = 1.4x.

⇒ Case 1 SP = 1.4x × 0.9 = 1.26x. Case 2 SP = 1.4x × 0.85 = 1.19x.

⇒ Difference in Profit = 1.26x − 1.19x = 0.07x.

⇒ 0.07x = 21 ⇒ x = 21 ÷ 0.07 = 300.

⇒ For 20% discount: SP = 1.4 × 300 × 0.8 = 336.

⇒ Profit = 336 − 300 = Rs. 36. ∴ The correct answer is Rs. 36.

Additional Information

Marked Price & Markup

Markup is the extra price added to the CP to arrive at MP. Markup% = (MP − CP) ÷ CP × 100.

Relation between CP and MP

CP ÷ MP = (100 − Discount%) ÷ (100 + Profit%). This ratio is very useful when both D% and P% are given.

SBI PO Prelims Memory Based Paper (Held on: 21 Nov 2021 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 996

SBI Probationary Officer (PO) 2021• Quantitative Aptitude• Quantitative Aptitude

Instructions: Study the following information carefully and answer accordingly.

In the SSC and PO exams, among a certain number of participants (Boy + Girl), some participate in both the events of SSC and PO while some of them participate in PO or SSC alone.

The ratio of Boys to Girls who participate in SSC and PO is 4 : 3 and 8 : 13 respectively, while the ratio of Boy to Girl who participates in both the exams PO and SSC is 2 : 1 and the ratio of Boys to Girls who participate only in the PO exams is  1 : 2. The participation of boys in the SSC exam alone is 10 more than the Girls who participate in it. Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC events alone.

Find the ratio of boys who participated in SSC to Girls who participated in PO.

  1. AOption (a)

    12:13

  2. BOption (b)

    13:12

  3. COption (c)

    11:15

  4. DOption (d)

    9:25

  5. EOption (e)

    3:5

View answer & explanation

Correct answer

Answer: (a)A.

12:13

Why this answer is correct

Ratio of Boys to Girls who participate in SSC = 4 : 3

Ratio of Boys to Girls who participate in PO = 8 : 13

Ratio of Boy to Girl who participates in both the events of PO and SSC = 2 : 1

Ratio of Boys to Girls who participate only in the PO exam = 1 : 2

participation of boys in the SSC exam alone is 10 more than the Girls participation in SSC alone

Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC exam alone

Concept:

 

Total participant in SSC = participate only in SSC + participate in both SSC and PO

Total participant in PO = participate only in PO + participate in both SSC and PO

Calculation:

Let number of Girl participate only in SSC = x

So, Number of Boys participate only in SSC = x + 10

Number of Boys participate in both SSC and PO = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both SSC and PO = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in SSC/Number of girls participate in SSC = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in SSC = 40

Number of Boys participate only in PO = 40 + 10

⇒ 50

Number of Boys participate in both SSC and PO = (40 + 10)/5

⇒ 10

Number of Girls participate in both SSC and PO = (40 + 10)/10

⇒ 5

 

Number of Boys participate in SSC = 50 + 10

⇒ 60

Number of girls participate in SSC = 40 + 5

⇒ 45

 

Number of Boys in PO/Number of Girls in po = 8/13

8/13 = (10 + y)/(5 + 2y)

⇒ 40 + 16y = 130 + 13y

⇒ 3y = 90

⇒ y = 30

Number of Boys in PO only = 30

Number of Girls in PO only = 2 × 30

⇒ 60

 

Number of Boys in PO = 30 + 10

⇒ 40

Number of Girls in PO = 60 + 5

⇒ 65

Ratio of boy who participated in SSC to Girls who participated in PO = 60 : 65

⇒ 12 : 13

∴ Ratio of boy who participated in SSC to Girls who participated in PO is 12 : 13.

SBI PO Prelims Memory Based Paper (Held on: 21 Nov 2021 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 997

SBI Probationary Officer (PO) 2021• Quantitative Aptitude• Quantitative Aptitude

Instructions: Study the following information carefully and answer accordingly.

In the SSC and PO exams, among a certain number of participants (Boy + Girl), some participate in both the events of SSC and PO while some of them participate in PO or SSC alone.

The ratio of Boys to Girls who participate in SSC and PO is 4 : 3 and 8 : 13 respectively, while the ratio of Boy to Girl who participates in both the exams PO and SSC is 2 : 1 and the ratio of Boys to Girls who participate only in the PO exams is  1 : 2. The participation of boys in the SSC exam alone is 10 more than the Girls who participate in it. Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC events alone.

How many participants were there in the competition?

  1. AOption (a)

    190

  2. BOption (b)

    199

  3. COption (c)

    250

  4. DOption (d)

    195

  5. EOption (e)

    205

View answer & explanation

Correct answer

Answer: (d)D.

195

Why this answer is correct

Ratio of Boys to Girls who participate in SSC = 4 : 3

Ratio of Boys to Girls who participate in PO = 8 : 13

Ratio of Boy to Girl who participates in both the events of PO and SSC = 2 : 1

Ratio of Boys to Girls who participate only in the PO event = 1 : 2

participation of boys in the SSC event alone is 10 more than the Girls participation in PO alone

Boys who participate in both SSC and PO is 20% of the Boys who participate in Dancing events alone

Concept:

 

Total participant in SSC = participate only in SSC + participate in both SSC and PO

Total participant in PO = participate only in PO + participate in both SSC and PO

Total participant in competition = participate only in SSC + participate in both SSC and PO + participate only in PO

Calculation:

Let number of Girl participate only in SSC = x

So, Number of Boys participate only in SSC = x + 10

Number of Boys participate in both SSC and PO = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both SSC and PO = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in SSC/Number of girls participate in SSC = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in SSC = 40

Number of Boys participate only in SSC = 40 + 10

⇒ 50

Number of Boys participate in both SSC and PO = (40 + 10)/5

⇒ 10

Number of Girls participate in both SSC PO= (40 + 10)/10

⇒ 5

 

Number of Boys participate in SSC = 50 + 10

⇒ 60

Number of girls participate in SSC = 40 + 5

⇒ 45

 

Number of Boys in PO/Number of Girls in PO = 8/13

8/13 = (10 + y)/(5 + 2y)

⇒ 40 + 16y = 130 + 13y

⇒ 3y = 90

⇒ y = 30

Number of Boys in PO only = 30

Number of Girls in PO only = 2 × 30

⇒ 60

 

Number of Boys in PO = 30 + 10

⇒ 40

Number of Girls in PO = 60 + 5

⇒ 65

Total participant in competition = (50 + 40) +(10 + 5) + (30 + 60)

⇒ 90 + 15 + 90

⇒ 195

∴ Total 195 participants were there in the competition.

SBI PO Prelims Memory Based Paper (Held on: 21 Nov 2021 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 998

SBI Probationary Officer (PO) 2021• Quantitative Aptitude• Quantitative Aptitude

Instructions: Study the following information carefully and answer accordingly.

In the SSC and PO exams, among a certain number of participants (Boy + Girl), some participate in both the events of SSC and PO while some of them participate in PO or SSC alone.

The ratio of Boys to Girls who participate in SSC and PO is 4 : 3 and 8 : 13 respectively, while the ratio of Boy to Girl who participates in both the exams PO and SSC is 2 : 1 and the ratio of Boys to Girls who participate only in the PO exams is  1 : 2. The participation of boys in the SSC exam alone is 10 more than the Girls who participate in it. Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC events alone.

Find the number of participants who participated in both events (SSC and PO)?

  1. AOption (a)

    10

  2. BOption (b)

    25

  3. COption (c)

    13

  4. DOption (d)

    15

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (d)D.

15

Why this answer is correct

Ratio of Boys to Girls who participate in SSC = 4 : 3

Ratio of Boys to Girls who participate in PO = 8 : 13

Ratio of Boy to Girl who participates in both the events of PO and SSC = 2 : 1

Ratio of Boys to Girls who participate only in the PO event = 1 : 2

participation of boys in the SSC exam alone is 10 more than the Girls participation in SSC alone

Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC exam alone

Concept:

 

Total participant in SSC = participate only in SSC + participate in both SSC and PO

Total participant in PO = participate only in PO + participate in both SSC and PO

Calculation:

Let number of Girl participate only in SSC = x

So, Number of Boys participate only in SSC = x + 10

Number of Boys participate in both SSC and PO = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both SSC and PO = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in SSC/Number of girls participate in SSC = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in SSC = 40

Number of Boys participate only in SSC = 40 + 10

⇒ 50

Number of Boys participate in both SSC and PO = (40 + 10)/5

⇒ 10

Number of Girls participate in both SSC and PO = (40 + 10)/10

⇒ 5

number of participants who participated in both events (SSC and PO) = 10 + 5

⇒ 15

∴ 15 participants, participated in both exams (SSC and PO).

SBI PO Prelims Memory Based Paper (Held on: 21 Nov 2021 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 999

SBI Probationary Officer (PO) 2021• Quantitative Aptitude• Quantitative Aptitude

Instructions: Study the following information carefully and answer accordingly.

In the SSC and PO exams, among a certain number of participants (Boy + Girl), some participate in both the events of SSC and PO while some of them participate in PO or SSC alone.

The ratio of Boys to Girls who participate in SSC and PO is 4 : 3 and 8 : 13 respectively, while the ratio of Boy to Girl who participates in both the exams PO and SSC is 2 : 1 and the ratio of Boys to Girls who participate only in the PO exams is  1 : 2. The participation of boys in the SSC exam alone is 10 more than the Girls who participate in it. Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC events alone.

The number of Boys who participated only in PO exam is what percent of Boys who participated only in SSC events?

  1. AOption (a)

    60%

  2. BOption (b)

    55%

  3. COption (c)

    65%

  4. DOption (d)

    35%

  5. EOption (e)

    40%

View answer & explanation

Correct answer

Answer: (a)A.

60%

Why this answer is correct

Ratio of Boys to Girls who participate in SSC = 4 : 3

Ratio of Boys to Girls who participate in PO = 8 : 13

Ratio of Boy to Girl who participates in both the exams of PO and SSC = 2 : 1

Ratio of Boys to Girls who participate only in the PO exams = 1 : 2

participation of boys in the SSC exam alone is 10 more than the Girls participation in SSC alone

Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC exam alone

Concept:

 

Total participant in SSC = participate only in SSC + participate in both SSC and PO

Total participant in PO = participate only in PO + participate in both SSC and PO

Calculation:

Let number of Girl participate only in SSC = x

So, Number of Boys participate only in SSC = x + 10

Number of Boys participate in both SSC and PO = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both SSC and PO = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in SSC/Number of girls participate in SSC = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in SSC = 40

Number of Boys participate only in SSC = 40 + 10

⇒ 50

Number of Boys participate in both SSC and PO = (40 + 10)/5

⇒ 10

Number of Girls participate in both SSC and PO = (40 + 10)/10

⇒ 5

 

 

 

 

Number of Boys participate in SSC = 50 + 10

⇒ 60

Number of girls participate in SSC = 40 + 5

⇒ 45

 

Number of Boys in PO/Number of Girls in PO = 8/13

8/13 = (10 + y)/(5 + 2y)

⇒ 40 + 16y = 130 + 13y

⇒ 3y = 90

⇒ y = 30

Let number of Boys who participated only in PO events is x% of Boys who participated only in SSC exam

x% = (30/50) × 100

⇒ 60%

∴ Number of Boys who participated only in PO exam is 60% of Boys who participated only in SSC exams.

SBI PO Prelims Memory Based Paper (Held on: 21 Nov 2021 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 1000

SBI Probationary Officer (PO) 2021• Quantitative Aptitude• Quantitative Aptitude

Instructions: Study the following information carefully and answer accordingly.

In the SSC and PO exams, among a certain number of participants (Boy + Girl), some participate in both the events of SSC and PO while some of them participate in PO or SSC alone.

The ratio of Boys to Girls who participate in SSC and PO is 4 : 3 and 8 : 13 respectively, while the ratio of Boy to Girl who participates in both the exams PO and SSC is 2 : 1 and the ratio of Boys to Girls who participate only in the PO exams is  1 : 2. The participation of boys in the SSC exam alone is 10 more than the Girls who participate in it. Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC events alone.

Find the ratio of participants who participated only in SSC to only in PO.

  1. AOption (a)

    4:3

  2. BOption (b)

    1:1

  3. COption (c)

    2:3

  4. DOption (d)

    3:4

  5. EOption (e)

    5:2

View answer & explanation

Correct answer

Answer: (b)B.

1:1

Why this answer is correct

Ratio of Boys to Girls who participate in SSC = 4 : 3

Ratio of Boys to Girls who participate in PO = 8 : 13

Ratio of Boy to Girl who participates in both the events of PO and SSC = 2 : 1

Ratio of Boys to Girls who participate only in the PO exam = 1 : 2

participation of boys in the SSC exam alone is 10 more than the Girls participation in SSC alone

Boys who participate in both SSC and PO is 20% of the Boys who participate in SSC exam alone

Concept:

 

Total participant in SSC = participate only in SSC + participate in both SSC and PO

Total participant in PO = participate only in PO + participate in both SSC and PO

 

Calculation:

Let number of Girl participate only in SSC = x

So, Number of Boys participate only in SSC = x + 10

Number of Boys participate in both SSC and PO = (20/100) × (x + 10)

⇒ (x + 10)/5

Number of Girls participate in both SSC and PO = (1/2) × {(x + 10)/5}

⇒ (x + 10)/10

Number of Boys participate in SSC/Number of girls participate in SSC = 4/3

4/3 = {(x + 10) + (x + 10)/5}/{x + (x + 10)/10}

⇒ 2/3 = (6x + 60)/(11x + 10)

⇒ 18x + 180 = 22x + 20

⇒ 4x = 160

⇒ x = 40

Number of Girl participate only in SSC = 40

Number of Boys participate only in SSC = 40 + 10

⇒ 50

Number of Boys participate in both SSC and PO = (40 + 10)/5

⇒ 10

Number of Girls participate in both SSC and PO = (40 + 10)/10

⇒ 5

 

 

 

 

Number of Boys participate in SSC = 50 + 10

⇒ 60

Number of girls participate in SSC = 40 + 5

⇒ 45

 

Number of Boys in PO/Number of Girls in PO= 8/13

8/13 = (10 + y)/(5 + 2y)

⇒ 40 + 16y = 130 + 13y

⇒ 3y = 90

⇒ y = 30

Number of Boys in PO only = 30

Number of Girls in PO only = 2 × 30

⇒ 60

Participant only in SSC = 50 + 40

⇒ 90

Participant only in PO = 30 + 60

⇒ 90

Participant only in SSC : Participant only in PO = 90 : 90

⇒ 1 : 1

∴ Ratio of participants who participated only in SSC to only in PO is 1 : 1.

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How should I prepare for Quantitative Aptitude in SBI Probationary Officer (PO)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.