Reasoning PYQs

1. Q purchases three before S. 2. At most two individuals purchase between Q and R, who purchases before Q. 

Here, we have 3 Cases, i.e., Case 1, Case 2, and Case 3.

 

3. Only one individual purchases between R and P, who purchase immediately after X. 

Here, we have 6 cases, i.e., 2 more subcases of Case 1 and 1 more subcase of Case 3.

 

4. As many individuals purchase between Q and R as between X and Y.

Now, we can eliminate Case 3. (Because there is no vacant place for Y)

 

5. Z purchases three after Y.

Now, we can eliminate Case 1b and Case 2.

 

6. More than three individuals purchase between T and U, who purchase after T.

Now, we can eliminate Case 1 and Case 3a.

This is our final arrangement,

 

Hence, the correct answer is T.

1. Q purchases three before S. 2. At most two individuals purchase between Q and R, who purchases before Q. 

Here, we have 3 Cases, i.e., Case 1, Case 2, and Case 3.

 

3. Only one individual purchases between R and P, who purchase immediately after X. 

Here, we have 6 cases, i.e., 2 more subcases of Case 1 and 1 more subcase of Case 3.

 

4. As many individuals purchase between Q and R as between X and Y.

Now, we can eliminate Case 3. (Because there is no vacant place for Y)

 

5. Z purchases three after Y.

Now, we can eliminate Case 1b and Case 2.

 

6. More than three individuals purchase between T and U, who purchase after T.

Now, we can eliminate Case 1 and Case 3a.

This is our final arrangement,

 

Hence, the correct answer is Y.

People: J, K, L, M, N, & O.

1. J is older than only one person.

2. M is younger than only one person.

3. O is the oldest in the family.

O > M > ___ > ___ > J > __

4. N is younger than K and M but not as young as J.

O > M > K > N > J > ___

Thus, we get the final arrangement as:

O > M > K > N > J > L

Hence, O is the oldest among the above-given options.

People: J, K, L, M, N, & O.

1. J is older than only one person.

2. M is younger than only one person.

3. O is the oldest in the family.

O > M > ___ > ___ > J > __

4. N is younger than K and M but not as young as J.

O > M > K > N > J > ___

Thus, we get the final arrangement as:

O > M > K > N > J > L

Hence, L is the youngest.

People: J, K, L, M, N, & O.

1. J is older than only one person.

2. M is younger than only one person.

3. O is the oldest in the family.

O > M > ___ > ___ > J > __

4. N is younger than K and M but not as young as J.

O > M > K > N > J > ___

Thus, we get the final arrangement as:

O > M > K > N > J > L

Hence, 3 persons are younger than K.

1. The person who wears Diamond sits at an extreme end. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 2. Z sits three places away from the one who wears Diamond. 3. B and Z sit immediately next to each other. 4. B sits second to the right of M, who sits immediately right of the person who wears Amethyst. 5. D wears Topaz and sits immediately right of the person who wears Ruby.

Here, we have one more subcase of Case 2, i.e., Case 2a. 6. Neither X nor T wears Amethyst or Ruby. 

Now, we can eliminate Case 2a. (Because there is no vacant place for X and T)

7. T sits third to the left of the person who wears Emerald.
8. The person who wears Opal sits second to the right of the person who wears Sapphire. 

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is B and Z.

1. The person who wears Diamond sits at an extreme end. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 2. Z sits three places away from the one who wears Diamond. 3. B and Z sit immediately next to each other. 4. B sits second to the right of M, who sits immediately right of the person who wears Amethyst. 5. D wears Topaz and sits immediately right of the person who wears Ruby.

Here, we have one more subcase of Case 2, i.e., Case 2a. 6. Neither X nor T wears Amethyst or Ruby. 

Now, we can eliminate Case 2a. (Because there is no vacant place for X and T)

7. T sits third to the left of the person who wears Emerald.
8. The person who wears Opal sits second to the right of the person who wears Sapphire. 

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is The person who wears Amethyst.

1. The person who wears Diamond sits at an extreme end. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 2. Z sits three places away from the one who wears Diamond. 3. B and Z sit immediately next to each other. 4. B sits second to the right of M, who sits immediately right of the person who wears Amethyst. 5. D wears Topaz and sits immediately right of the person who wears Ruby.

Here, we have one more subcase of Case 2, i.e., Case 2a. 6. Neither X nor T wears Amethyst or Ruby. 

Now, we can eliminate Case 2a. (Because there is no vacant place for X and T)

7. T sits third to the left of the person who wears Emerald.
8. The person who wears Opal sits second to the right of the person who wears Sapphire. 

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is B - Ruby.

1. The person who wears Diamond sits at an extreme end. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 2. Z sits three places away from the one who wears Diamond. 3. B and Z sit immediately next to each other. 4. B sits second to the right of M, who sits immediately right of the person who wears Amethyst. 5. D wears Topaz and sits immediately right of the person who wears Ruby.

Here, we have one more subcase of Case 2, i.e., Case 2a. 6. Neither X nor T wears Amethyst or Ruby. 

Now, we can eliminate Case 2a. (Because there is no vacant place for X and T)

7. T sits third to the left of the person who wears Emerald.
8. The person who wears Opal sits second to the right of the person who wears Sapphire. 

Now, we can eliminate Case 2.

This is our final arrangement,

Except for D and the person who wears Diamond, in all other pairs, the first person is second to the left of the second person.

Hence, the correct answer is D and the person who wears Diamond.

1. The person who wears Diamond sits at an extreme end. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 2. Z sits three places away from the one who wears Diamond. 3. B and Z sit immediately next to each other. 4. B sits second to the right of M, who sits immediately right of the person who wears Amethyst. 5. D wears Topaz and sits immediately right of the person who wears Ruby.

Here, we have one more subcase of Case 2, i.e., Case 2a. 6. Neither X nor T wears Amethyst or Ruby. 

Now, we can eliminate Case 2a. (Because there is no vacant place for X and T)

7. T sits third to the left of the person who wears Emerald.
8. The person who wears Opal sits second to the right of the person who wears Sapphire. 

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is Z wears Emerald.

1. X born in a month which have odd number of days but not on even date of a month.

2. Only one person born between X and O.

3. More than three person born between E and the person who lives in Delhi.

 

4. J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5. Person who lives in Mumbai born immediately after O.

 

6. Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7. Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

 

Hence, M ​lives in Mumbai.

1. X born in a month which have odd number of days but not on even date of a month.

2. Only one person born between X and O.

3. More than three person born between E and the person who lives in Delhi.

 

4. J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5. Person who lives in Mumbai born immediately after O.

 

6. Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7. Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

 

Since, J born on 9 May and R born on 26 March.

Hence, two person born between them which are O and M.

1. X born in a month which have odd number of days but not on even date of a month.

2. Only one person born between X and O.

3. More than three person born between E and the person who lives in Delhi.

 

4. J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5. Person who lives in Mumbai born immediately after O.

 

6. Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7. Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

 

Since, on 9^th May J was born and just before him M was born.

1. X born in a month which have odd number of days but not on even date of a month.

2. Only one person born between X and O.

3. More than three person born between E and the person who lives in Delhi.

 

4. J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5. Person who lives in Mumbai born immediately after O.

 

6. Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7. Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

 

Hence, all except O born in the month which have odd number of days.

1. X born in a month which have odd number of days but not on even date of a month.

2. Only one person born between X and O.

3. More than three person born between E and the person who lives in Delhi.

 

4. J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5. Person who lives in Mumbai born immediately after O.

 

6. Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7. Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

 

Since, O born on 9^th April and J and E both born in May.

Hence, More than one option is correct.

Given, the persons are O, P, Q, R, S, T, U, V.

1. Only two person sits between U and V.

2. R sits second to the left of U.                        

3. R and P sits opposite to each other and facing opposite direction.

4. As many person sits between S and O as many person sits between S and Q, who sits third to the left of S. So case 1 and case 2 further divided into two more cases.

5. The immediate neighbour of Q faces in opposite direction. So if U faces outside (or inside) the other immediate neighbour of Q faces inside (or outside).

6. The number of person faces away from centre is less than that of faces towards centre. R is not the neighbour of O. Then case 1(b) is eliminated.

8) T and Q faces in same direction but faces opposite direction of P. 

9. No three consecutive person faces in same direction. So, case 2(b) is eliminated.                                        

10. S and V sits immediate left to each other. So, case 2(a) is eliminated. Hence, final arrangement is as follows

Hence, P and U sits adjacent to O.

Given, the persons are O, P, Q, R, S, T, U, V.

1. Only two person sits between U and V.

2. R sits second to the left of U.                        

3. R and P sits opposite to each other and facing opposite direction.

4. As many person sits between S and O as many person sits between S and Q, who sits third to the left of S. So case 1 and case 2 further divided into two more cases.

5. The immediate neighbour of Q faces in opposite direction. So if U faces outside (or inside) the other immediate neighbour of Q faces inside (or outside).

6. The number of person faces away from centre is less than that of faces towards centre. R is not the neighbour of O. Then case 1(b) is eliminated.

8) T and Q faces in same direction but faces opposite direction of P. 

9. No three consecutive person faces in same direction. So, case 2(b) is eliminated.                                        

10. S and V sits immediate left to each other. So, case 2(a) is eliminated. Hence, final arrangement is as follows

When counted from clockwise direction of O only two persons sits between O and S.

Given, the persons are O, P, Q, R, S, T, U, V.

1. Only two person sits between U and V.

2. R sits second to the left of U.                        

3. R and P sits opposite to each other and facing opposite direction.

4. As many person sits between S and O as many person sits between S and Q, who sits third to the left of S. So case 1 and case 2 further divided into two more cases.

5. The immediate neighbour of Q faces in opposite direction. So if U faces outside (or inside) the other immediate neighbour of Q faces inside (or outside).

6. The number of person faces away from centre is less than that of faces towards centre. R is not the neighbour of O. Then case 1(b) is eliminated.

8) T and Q faces in same direction but faces opposite direction of P. 

9. No three consecutive person faces in same direction. So, case 2(b) is eliminated.                                        

10. S and V sits immediate left to each other. So, case 2(a) is eliminated. Hence, final arrangement is as follows

Hence, all except P faces towards the centre.

Given, the persons are O, P, Q, R, S, T, U, V.

1. Only two person sits between U and V.

2. R sits second to the left of U.                        

3. R and P sits opposite to each other and facing opposite direction.

4. As many person sits between S and O as many person sits between S and Q, who sits third to the left of S. So case 1 and case 2 further divided into two more cases.

5. The immediate neighbour of Q faces in opposite direction. So if U faces outside (or inside) the other immediate neighbour of Q faces inside (or outside).

6. The number of person faces away from centre is less than that of faces towards centre. R is not the neighbour of O. Then case 1(b) is eliminated.

8) T and Q faces in same direction but faces opposite direction of P. 

9. No three consecutive person faces in same direction. So, case 2(b) is eliminated.                                        

10. S and V sits immediate left to each other. So, case 2(a) is eliminated. Hence, final arrangement is as follows

Hence, T sits opposite to U.

Given, the persons are O, P, Q, R, S, T, U, V.

1. Only two person sits between U and V.

2. R sits second to the left of U.                        

3. R and P sits opposite to each other and facing opposite direction.

4. As many person sits between S and O as many person sits between S and Q, who sits third to the left of S. So case 1 and case 2 further divided into two more cases.

5. The immediate neighbour of Q faces in opposite direction. So if U faces outside (or inside) the other immediate neighbour of Q faces inside (or outside).

6. The number of person faces away from centre is less than that of faces towards centre. R is not the neighbour of O. Then case 1(b) is eliminated.

8) T and Q faces in same direction but faces opposite direction of P. 

9. No three consecutive person faces in same direction. So, case 2(b) is eliminated.                                        

10. S and V sits immediate left to each other. So, case 2(a) is eliminated. Hence, final arrangement is as follows

Hence, V sits immediate left of S.