SBI PO Mains Memory Based Paper (Held on:29 January 2021) (Previous Year Paper)

There are 6 persons A, B, C, D, E, and F are sitting around a circular table.

All the persons are married and there is an equal number of husbands and wives in the group.

They are of different ages viz. 36, 51, 48, 33, 41, and 28 but not necessarily in the same order.

1. The youngest person sits to the immediate right of the oldest person.

The age of the youngest person is 28 and the age of the oldest person is 51. 

2. D is married to F, who is the oldest person.

(The age of husband is greater than the age of wife)

So, F is the husband of D.

3. Only two persons sit between A, the female person and the person whose age is 41.
4. A is not the youngest person.

(No two even/odd aged persons are sitting together)

5. B, an even-aged person is sitting second to the left of a person whose age is 48.

The following are the possibilities we get,

6. C, whose age lies between 30 and 40 is sitting second to the right of A’s husband.

The possible age of C is 33 or 36.

As no two even/odd aged persons are sitting together. So, the age of C is 33.

Filling the missing data,

In case I:

As D is married to F, A’s husband will be E and is sitting opposite A.

In case II:

As D is married to F, A’s husband will be E and is sitting opposite A.

No couple sits together is violated. So, Case II is eliminated.

The final arrangement is,

 

 

 

 

 

 

Hence, the sum of the ages of A’s husband and F’s wife is 89.

There are 6 persons A, B, C, D, E, and F are sitting around a circular table.

All the persons are married and there is an equal number of husbands and wives in the group.

They are of different ages viz. 36, 51, 48, 33, 41, and 28 but not necessarily in the same order.

1. The youngest person sits to the immediate right of the oldest person.

The age of the youngest person is 28 and the age of the oldest person is 51. 

2. D is married to F, who is the oldest person.

(The age of husband is greater than the age of wife)

So, F is the husband of D.

3. Only two persons sit between A, the female person and the person whose age is 41.
4. A is not the youngest person.

(No two even/odd aged persons are sitting together)

5. B, an even-aged person is sitting second to the left of a person whose age is 48.

The following are the possibilities we get,

6. C, whose age lies between 30 and 40 is sitting second to the right of A’s husband.

The possible age of C is 33 or 36.

As no two even/odd aged persons are sitting together. So, the age of C is 33.

Filling the missing data,

In case I:

As D is married to F, A’s husband will be E and is sitting opposite A.

In case II:

As D is married to F, A’s husband will be E and is sitting opposite A.

No couple sits together is violated. So, Case II is eliminated.

The final arrangement is,

 

 

 

 

 

 

Hence, B is the wife of C.

There are 6 persons A, B, C, D, E, and F are sitting around a circular table.

All the persons are married and there is an equal number of husbands and wives in the group.

They are of different ages viz. 36, 51, 48, 33, 41, and 28 but not necessarily in the same order.

1. The youngest person sits to the immediate right of the oldest person.

The age of the youngest person is 28 and the age of the oldest person is 51. 

2. D is married to F, who is the oldest person.

(The age of husband is greater than the age of wife)

So, F is the husband of D.

3. Only two persons sit between A, the female person and the person whose age is 41.
4. A is not the youngest person.

(No two even/odd aged persons are sitting together)

5. B, an even-aged person is sitting second to the left of a person whose age is 48.

The following are the possibilities we get,

6. C, whose age lies between 30 and 40 is sitting second to the right of A’s husband.

The possible age of C is 33 or 36.

As no two even/odd aged persons are sitting together. So, the age of C is 33.

Filling the missing data,

In case I:

As D is married to F, A’s husband will be E and is sitting opposite A.

In case II:

As D is married to F, A’s husband will be E and is sitting opposite A.

No couple sits together is violated. So, Case II is eliminated.

The final arrangement is,

 

 

 

 

 

 

Hence, C is sitting exactly opposite with respect to his/her spouse.

There are 6 persons A, B, C, D, E, and F are sitting around a circular table.

All the persons are married and there is an equal number of husbands and wives in the group.

They are of different ages viz. 36, 51, 48, 33, 41, and 28 but not necessarily in the same order.

1. The youngest person sits to the immediate right of the oldest person.

The age of the youngest person is 28 and the age of the oldest person is 51. 

2. D is married to F, who is the oldest person.

(The age of husband is greater than the age of wife)

So, F is the husband of D.

3. Only two persons sit between A, the female person and the person whose age is 41.
4. A is not the youngest person.

(No two even/odd aged persons are sitting together)

5. B, an even-aged person is sitting second to the left of a person whose age is 48.

The following are the possibilities we get,

6. C, whose age lies between 30 and 40 is sitting second to the right of A’s husband.

The possible age of C is 33 or 36.

As no two even/odd aged persons are sitting together. So, the age of C is 33.

Filling the missing data,

In case I:

As D is married to F, A’s husband will be E and is sitting opposite A.

In case II:

As D is married to F, A’s husband will be E and is sitting opposite A.

No couple sits together is violated. So, Case II is eliminated.

The final arrangement is,

 

 

 

 

 

 

Hence, four persons are sitting between F and the person aged 28.

Given:

P 17@ Q means P is 14 m north to the point Q

P 15$ Q means P is 20 m east to the point Q

P 13% Q means P is 10 m south to the point Q

P 12& Q means P is 17 m west to the point Q

A 15& B, B 27% C, C 17& D, L 18% A, M 33$L, N 28@ M, O 15$ N, K 17@ O.

By observing the given data, we concluded that in the case of @ and %, we have to subtract 3 from the given position. While in case of $ and & we have to add 5 in the given position.

Now by decoding the given statement according to the given conditions:

A 15& B: A is 20 m west to point B.

B 27% C: B is 24 m south to point C.

C 17& D: C is 22 m west to point D.

L 18% A: L is 15 m south to point A.

M 33$ L: M is 38 m east to point L.

N 28@ M: N is 25 m north to point M.

O 15$ N: O is 20 m east to point N.

K 17@ O: K is 14 m north to point O.

The following diagram is the 

As Y is in the south with respect to D and in the west with respect to O, Y will be at the following position:

Now, we can see that Y would be closest to N.

Hence, N  is the correct answer.

Given:

P 17@ Q means P is 14 m north to the point Q

P 15$ Q means P is 20 m east to the point Q

P 13% Q means P is 10 m south to the point Q

P 12& Q means P is 17 m west to the point Q

A 15& B, B 27% C, C 17& D, L 18% A, M 33$L, N 28@ M, O 15$ N, K 17@ O.

By observing the given data, we concluded that in the case of @ and %, we have to subtract 3 from the given position. While in case of $ and & we have to add 5 in the given position.

Now by decoding the given statement according to the given conditions:

A 15& B: A is 20 m west to point B.

B 27% C: B is 24 m south to point C.

C 17& D: C is 22 m west to point D.

L 18% A: L is 15 m south to point A.

M 33$ L: M is 38 m east to point L.

N 28@ M: N is 25 m north to point M.

O 15$ N: O is 20 m east to point N.

K 17@ O: K is 14 m north to point O.

The following diagram is the 

Option 4)  D 11& K

D 11& K → D is 16 m west to the K.

As we can see in the diagram that D is 16 m west to the point K.

Hence, D 11& K is the correct answer.

Given:

P 17@ Q means P is 14 m north to the point Q

P 15$ Q means P is 20 m east to the point Q

P 13% Q means P is 10 m south to the point Q

P 12& Q means P is 17 m west to the point Q

A 15& B, B 27% C, C 17& D, L 18% A, M 33$L, N 28@ M, O 15$ N, K 17@ O.

By observing the given data, we concluded that in the case of @ and %, we have to subtract 3 from the given position. While in case of $ and & we have to add 5 in the given position.

Now by decoding the given statement according to the given conditions:

A 15& B: A is 20 m west to point B.

B 27% C: B is 24 m south to point C.

C 17& D: C is 22 m west to point D.

L 18% A: L is 15 m south to point A.

M 33$ L: M is 38 m east to point L.

N 28@ M: N is 25 m north to point M.

O 15$ N: O is 20 m east to point N.

K 17@ O: K is 14 m north to point O.

The following diagram is the 

1. C 33& K: C is 38 m west to the point K  True

2. N 15& O: N is 20 m west to the point O.  True

3. O 17% K: O is 14 m south to point K.   True

4) A 18@ L: A is 15 m north to the point L. True

Hence, none of these is the answer.

Given:

P 17@ Q means P is 14 m north to the point Q

P 15$ Q means P is 20 m east to the point Q

P 13% Q means P is 10 m south to the point Q

P 12& Q means P is 17 m west to the point Q

A 15& B, B 27% C, C 17& D, L 18% A, M 33$L, N 28@ M, O 15$ N, K 17@ O.

By observing the given data, we concluded that in the case of @ and %, we have to subtract 3 from the given position. While in case of $ and & we have to add 5 in the given position.

Now by decoding the given statement according to the given conditions:

A 15& B: A is 20 m west to point B.

B 27% C: B is 24 m south to point C.

C 17& D: C is 22 m west to point D.

L 18% A: L is 15 m south to point A.

M 33$ L: M is 38 m east to point L.

N 28@ M: N is 25 m north to point M.

O 15$ N: O is 20 m east to point N.

K 17@ O: K is 14 m north to point O.

The following diagram is the 

Point Z is such that, Z 15& C

By decoding it, we get, point Z is 20 m to the west of point C.

Now, we can see that Z is 24 m north to the point A or we can say that A is 24 m south to the point Z.

By decoding all the options:

1) A 21% Z: A is 18 m to the south of Z.   False

2) Z 21@ A: Z is 18 m to the north of A.   False

3) Z 27@ A: Z is 24 m to the north of A.   True

4) A 27% Z: A is 24 m to the south of Z.    True

Hence, both 3) and 4) is the correct answer.

Given:

P 17@ Q means P is 14 m north to the point Q

P 15$ Q means P is 20 m east to the point Q

P 13% Q means P is 10 m south to the point Q

P 12& Q means P is 17 m west to the point Q

A 15& B, B 27% C, C 17& D, L 18% A, M 33$L, N 28@ M, O 15$ N, K 17@ O.

By observing the given data, we concluded that in the case of @ and %, we have to subtract 3 from the given position. While in case of $ and & we have to add 5 in the given position.

Now by decoding the given statement according to the given conditions:

A 15& B: A is 20 m west to point B.

B 27% C: B is 24 m south to point C.

C 17& D: C is 22 m west to point D.

L 18% A: L is 15 m south to point A.

M 33$ L: M is 38 m east to point L.

N 28@ M: N is 25 m north to point M.

O 15$ N: O is 20 m east to point N.

K 17@ O: K is 14 m north to point O.

The following diagram is the 

As we can see in the diagram,

C is 38 m to the west of the point K, or it can be said as K is 38 m to the east to point C.

If we decode all the options, we will get:

1. C 41& K: C is 46 m to the west of K.   False

2. C 33$ K: C is  38 m to the east of K.   False

3) K 33$ C: K is 38 m to the east of C.    True

Hence, K 33$ C is true.

Given: Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7. 

1. E is sitting opposite to J who is sitting second to one of the extreme ends. 2. H is sitting second to the left of J and is facing the one who has 6 chocolates.

3. J has the highest number of chocolates.  4. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row.

5. Neither D nor C is sitting at the extreme ends. 6. D is sitting at the right side of C.

7. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. 8.  A is sitting diagonally opposite to I who has even number of chocolates.  

9. The one who is sitting third to the left end of the first row has a prime number of chocolates.

As we can see that the only prime number left is 7, hence the number of chocolates owned by the one who is sitting third to the left end of the first row which is C would be 7.

10. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G. 

We know that 1 + 8 = 9(perfect square)

So, F and H must have 1 and 8 chocolates.

11. F has an odd number of chocolates.

This proves that F would have 1 chocolate while H would have 8 chocolates.

Only numbers which are left now are 9 and 4 and persons whose number of chocolates are still to find out are E and I.

But as it is already given in the question that I owns even number of chocolates, hence I would have 4 while E would have 9 chocolates.

So, the final arrangement would be:

All F, A, B, I are sitting at the corners while J is not.

Hence, F is the odd one.

Given: Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7. 

1. E is sitting opposite to J who is sitting second to one of the extreme ends. 2. H is sitting second to the left of J and is facing the one who has 6 chocolates.

3. J has the highest number of chocolates.  4. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row.

5. Neither D nor C is sitting at the extreme ends. 6. D is sitting at the right side of C.

7. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. 8.  A is sitting diagonally opposite to I who has even number of chocolates.  

9. The one who is sitting third to the left end of the first row has a prime number of chocolates.

As we can see that the only prime number left is 7, hence the number of chocolates owned by the one who is sitting third to the left end of the first row which is C would be 7.

10. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G. 

We know that 1 + 8 = 9(perfect square)

So, F and H must have 1 and 8 chocolates.

11. F has an odd number of chocolates.

This proves that F would have 1 chocolate while H would have 8 chocolates.

Only numbers which are left now are 9 and 4 and persons whose number of chocolates are still to find out are E and I.

But as it is already given in the question that I owns even number of chocolates, hence I would have 4 while E would have 9 chocolates.

So, the final arrangement would be:

The person who is sitting second to the left of the person who is sitting opposite to G is B.

Hence, B has 11 number of chocolates.

Given: Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7. 

1. E is sitting opposite to J who is sitting second to one of the extreme ends. 2. H is sitting second to the left of J and is facing the one who has 6 chocolates.

3. J has the highest number of chocolates.  4. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row.

5. Neither D nor C is sitting at the extreme ends. 6. D is sitting at the right side of C.

7. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. 8.  A is sitting diagonally opposite to I who has even number of chocolates.  

9. The one who is sitting third to the left end of the first row has a prime number of chocolates.

As we can see that the only prime number left is 7, hence the number of chocolates owned by the one who is sitting third to the left end of the first row which is C would be 7.

10. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G. 

We know that 1 + 8 = 9(perfect square)

So, F and H must have 1 and 8 chocolates.

11. F has an odd number of chocolates.

This proves that F would have 1 chocolate while H would have 8 chocolates.

Only numbers which are left now are 9 and 4 and persons whose number of chocolates are still to find out are E and I.

But as it is already given in the question that I owns even number of chocolates, hence I would have 4 while E would have 9 chocolates.

So, the final arrangement would be:

Hence, J is sitting second to the right of H.

Given: Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7. 

1. E is sitting opposite to J who is sitting second to one of the extreme ends. 2. H is sitting second to the left of J and is facing the one who has 6 chocolates.

3. J has the highest number of chocolates.  4. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row.

5. Neither D nor C is sitting at the extreme ends. 6. D is sitting at the right side of C.

7. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. 8.  A is sitting diagonally opposite to I who has even number of chocolates.  

9. The one who is sitting third to the left end of the first row has a prime number of chocolates.

As we can see that the only prime number left is 7, hence the number of chocolates owned by the one who is sitting third to the left end of the first row which is C would be 7.

10. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G. 

We know that 1 + 8 = 9(perfect square)

So, F and H must have 1 and 8 chocolates.

11. F has an odd number of chocolates.

This proves that F would have 1 chocolate while H would have 8 chocolates.

Only numbers which are left now are 9 and 4 and persons whose number of chocolates are still to find out are E and I.

But as it is already given in the question that I owns even number of chocolates, hence I would have 4 while E would have 9 chocolates.

So, the final arrangement would be:

Hence, G has 10 chocolates.

Given: Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7. 

1. E is sitting opposite to J who is sitting second to one of the extreme ends. 2. H is sitting second to the left of J and is facing the one who has 6 chocolates.

3. J has the highest number of chocolates.  4. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row.

5. Neither D nor C is sitting at the extreme ends. 6. D is sitting at the right side of C.

7. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. 8.  A is sitting diagonally opposite to I who has even number of chocolates.  

9. The one who is sitting third to the left end of the first row has a prime number of chocolates.

As we can see that the only prime number left is 7, hence the number of chocolates owned by the one who is sitting third to the left end of the first row which is C would be 7.

10. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G. 

We know that 1 + 8 = 9 (perfect square)

So, F and H must have 1 and 8 chocolates.

11. F has an odd number of chocolates.

This proves that F would have 1 chocolate while H would have 8 chocolates.

Only numbers which are left now are 9 and 4 and persons whose number of chocolates are still to find out are E and I.

But as it is already given in the question that I owns even number of chocolates, hence I would have 4 while E would have 9 chocolates.

So, the final arrangement would be:

Hence, F is sitting third to the left of J.

In the given Input;

Logic:

Step I: Numbers are arranged in ascending order and words are arranged in English Alphabetical order alternatively.

Step II: Half of the numbers and +1 in the first letter of each word.

Step III: Multiplication of resultant number within the digit and +1 in the second letter of each word.

Step IV: Digital Sum of resultant number and +1 in the third letter of each word.

Step V: Square of resultant number and +1 in the fourth letter(if any) of the word.

Input: Maps 114 Code 92 126 Yawn Ice 78 Sip 106

Step I: 78 Code 92 Ice 106 Maps 114 Sip 126 Yawn

Step II: 39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn

Step III: 27 Dpde 24 Jde 15 Nbps 35 Tjp 18 Zbwn

Step IV: 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn

Step V: 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo

Step V is the last step.

Penultimate Step means second last step.

The Penultimate step is 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn.

In the given Input;

Logic:

Step I: Numbers are arranged in ascending order and words are arranged in English Alphabetical order alternatively.

Step II: Half of the numbers and +1 in the first letter of each word.

Step III: Multiplication of resultant number within the digit and +1 in the second letter of each word.

Step IV: Digital Sum of resultant number and +1 in the third letter of each word.

Step V: Square of resultant number and +1 in the fourth letter(if any) of the word.

Input: Maps 114 Code 92 126 Yawn Ice 78 Sip 106

Step I: 78 Code 92 Ice 106 Maps 114 Sip 126 Yawn

Step II: 39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn

Step III: 27 Dpde 24 Jde 15 Nbps 35 Tjp 18 Zbwn

Step IV: 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn

Step V: 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo

Step V is the last step.

Maps is the correct answer.

In the given Input;

Logic:

Step I: Numbers are arranged in ascending order and words are arranged in English Alphabetical order alternatively.

Step II: Half of the numbers and +1 in the first letter of each word.

Step III: Multiplication of resultant number within the digit and +1 in the second letter of each word.

Step IV: Digital Sum of resultant number and +1 in the third letter of each word.

Step V: Square of resultant number and +1 in the fourth letter(if any) of the word.

Input: Maps 114 Code 92 126 Yawn Ice 78 Sip 106

Step I: 78 Code 92 Ice 106 Maps 114 Sip 126 Yawn

Step II: 39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn

Step III: 27 Dpde 24 Jde 15 Nbps 35 Tjp 18 Zbwn

Step IV: 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn

Step V: 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo

Step V is the last step.

39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn is Step II.

In the given Input;

Logic:

Step I: Numbers are arranged in ascending order and words are arranged in English Alphabetical order alternatively.

Step II: Half of the numbers and +1 in the first letter of each word.

Step III: Multiplication of resultant number within the digit and +1 in the second letter of each word.

Step IV: Digital Sum of resultant number and +1 in the third letter of each word.

Step V: Square of resultant number and +1 in the fourth letter(if any) of the word.

Input: Maps 114 Code 92 126 Yawn Ice 78 Sip 106

Step I: 78 Code 92 Ice 106 Maps 114 Sip 126 Yawn

Step II: 39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn

Step III: 27 Dpde 24 Jde 15 Nbps 35 Tjp 18 Zbwn

Step IV: 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn

Step V: 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo

Step V is the last step.

 35 is the 4**^th** element from the right end in Step III.

In the given Input;

Logic:

Step I: Numbers are arranged in ascending order and words are arranged in English Alphabetical order alternatively.

Step II: Half of the numbers and +1 in the first letter of each word.

Step III: Multiplication of resultant number within the digit and +1 in the second letter of each word.

Step IV: Digital Sum of resultant number and +1 in the third letter of each word.

Step V: Square of resultant number and +1 in the fourth letter(if any) of the word.

Input: Maps 114 Code 92 126 Yawn Ice 78 Sip 106

Step I: 78 Code 92 Ice 106 Maps 114 Sip 126 Yawn

Step II: 39 Dode 46 Jce 53 Naps 57 Tip 63 Zawn

Step III: 27 Dpde 24 Jde 15 Nbps 35 Tjp 18 Zbwn

Step IV: 9 Dpee 6 Jdf 6 Nbqs 8 Tjq 9 Zbxn

Step V: 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo

Step V is the last step.

Step V is 81 Dpef 36 Jdf 36 Nbqt 64 Tjq 81 Zbxo.

 

AA = $2 #1 @3 #3 = B 15 19 P

Since, the string has equal number of alphabet and numbers, hence it satisfies condition 2.

Final value = 34 – 18 = 16

BB = @1 %4 @3 %3 = 9 2 19 7

Since the string has one even number, hence it satisfies condition 3.

Final value = 9 + 2 + 19 + 7 = 37

The sum of AA and BB = 16 + 37 = 53 = 8 (5 + 3)

Hence, 8 is the correct answer.

 

CC = $4 @2 #4 %1 = 2 10 16 I

Since, the string has one vowel, hence it satisfies condition 4.

Final value = alphabetical position of I = 9

Hence, the PC will hang.

                                           

AA = $2 #1 @3 #3 = B 15 19 P

Since, the string has equal number of alphabet and numbers, hence it satisfies condition 2.

Final value = 34 – 18 = 16

DD = %4 @2 @4 #2 = 2 10 S 1

Since the given string doesn’t follow any condition, hence the value of the input will be the difference between the highest and lowest number.

Final value = 10 – 1 = 9

Sum of AA and DD = 16 + 9 = 25 = 7 (2 + 5)

Hence, the program will be executed.

 

Let’s observe all the given string

A. @1 %4 @3 %3 = 9 2 19 7

Since, the given string contains only 1 even number, hence it satisfies condition 3.

Final value = 9 + 2 + 19 + 7 = 37 = 10 = 1 (1 + 0)

B. #3 @4 @2 %3 = P S 10 7

Since, the string has equal number of alphabet and numbers, hence it satisfies condition 2.

Final value = 35 – 17 = 18 = 9 (1 + 8)

C. @1 %4 @3 $4 = 9 2 19 2

Since the string has equal number of odd and even numbers, hence it satisfies condition 1.

Final value = (9 + 19) – (2 + 2) = 28 – 4 = 24 = 6 (2 + 4)

D. #4 $3$2 #4 = 16 0 B 16

Since, the given string doesn’t follow any condition, hence the value of the input will be the difference between the highest and lowest number.

Final value = 16 – 2 = 14 = 5 (1 + 4)

Hence, none of these is the answer as the required input should have been 2 for the program to be executed with an error.

 

AA = $2 #1 @3 #3 = B 15 19 P

Since, the string has equal number of alphabet and numbers, hence it satisfies condition 2.

Final value = 34 – 18 = 16

BB = @1 %4 @3 %3 = 9 2 19 7

Since, the given string contains only 1 even number, hence it satisfies condition 3.

Final value = 9 + 2 + 19 + 7 = 37

CC = $4 @2 #4 %1 = 2 10 16 I

Since, the string has one vowel, hence it satisfies condition 4.

Final value = alphabetical position of I = 9

DD = %4 @2 @4 #2 = 2 10 S 1

Since, the given string doesn’t follow any condition, hence the value of the input will be the difference between the highest and lowest number.

Final value = 10 – 1 = 9

Now, add all the strings

16 + 37 + 9 + 9 = 71 = 8 (7 + 1)

Hence, 8 is the correct answer.

Given:

Floors : 1 to 8

Persons : P, Q, R, S, T, U, V and W

Colors : Red, Violet, Pink, Yellow, Black, Purple, Blue and White.

Years : 1954, 1969, 1983, 1989, 1995, 1997, 1999 and 2001.

Therefore ages are :1954 (65), 1969 (50), 1983 (36), 1989 (30), 1995 (24), 1997 (22), 1999 (20) and 2001 (18).

1) Person whose birth year is 1997 is lives on bottom most floor and likes Violet color.

2)  The age of S, who likes Violet color is multiple of 11. Imply that S was born on 1997 and lives on 1st floor, as multiple of 11 is only 22 years and therefore birth year is 1997.

3) W lives immediately above S.

4. The difference between the age of W and R is 20 years. There are only Two years 1989 (30) and 1969 (50).

5. W is older than R. Therefore age of W is 50 years and R is 20 years.

The possible arrangement is as follows.

6) V lives on floor numbered four.

7) There are two floor between V and R.

8) R neither lives on floor numbered one and nor likes Pink color.

9) There are at least five floor between S and U.

10. U lives somewhere above S but not immediately above S.

11) Q lives on the even numbered floor but not on the topmost floor.

12) Birth year of Q is even number.

13) There is one floor between the floor on which U, who likes Red color and Q lives.

14)  Person likes Black color lives immediately above the person who likes Purple color and and immediately below the person who likes White color.

15) T, who likes Yellow color lives immediately above the who likes White color. Therefore, T must be lives on 5th floor because below there are persons who likes Black and White color.

16) The age of P is two times the age of V. Imply that age of P is 36 and year is 1983 and age of V is 18 and year is 2001. 

17) U is not 20 years old. Imply that age of U is 24 years and birth year is 1995.

The final arrangement is as follows:

 

 

 

 

 

 

 

 

 

 

Hence, P - Black - 1983 is the correct.

Given:

Floors : 1 to 8

Persons : P, Q, R, S, T, U, V and W

Colors : Red, Violet, Pink, Yellow, Black, Purple, Blue and White.

Years : 1954, 1969, 1983, 1989, 1995, 1997, 1999 and 2001.

Therefore ages are :1954 (65), 1969 (50), 1983 (36), 1989 (30), 1995 (24), 1997 (22), 1999 (20) and 2001 (18).

1) Person whose birth year is 1997 is lives on bottom most floor and likes Violet color.

2)  The age of S, who likes Violet color is multiple of 11. Imply that S was born on 1997 and lives on 1st floor, as multiple of 11 is only 22 years and therefore birth year is 1997.

3) W lives immediately above S.

4. The difference between the age of W and R is 20 years. There are only Two years 1989 (30) and 1969 (50).

5. W is older than R. Therefore age of W is 50 years and R is 20 years.

The possible arrangement is as follows.

6) V lives on floor numbered four.

7) There are two floor between V and R.

8) R neither lives on floor numbered one and nor likes Pink color.

9) There are at least five floor between S and U.

10. U lives somewhere above S but not immediately above S.

11) Q lives on the even numbered floor but not on the topmost floor.

12) Birth year of Q is even number.

13) There is one floor between the floor on which U, who likes Red color and Q lives.

14)  Person likes Black color lives immediately above the person who likes Purple color and and immediately below the person who likes White color.

15) T, who likes Yellow color lives immediately above the who likes White color. Therefore, T must be lives on 5th floor because below there are persons who likes Black and White color.

16) The age of P is two times the age of V. Imply that age of P is 36 and year is 1983 and age of V is 18 and year is 2001. 

17) U is not 20 years old. Imply that age of U is 24 years and birth year is 1995.

The final arrangement is as follows:

 

 

 

 

 

 

 

 

 

 

Hence, one whose age is 20 years lives on 5th floor.

Given:

Floors : 1 to 8

Persons : P, Q, R, S, T, U, V and W

Colors : Red, Violet, Pink, Yellow, Black, Purple, Blue and White.

Years : 1954, 1969, 1983, 1989, 1995, 1997, 1999 and 2001.

Therefore ages are :1954 (65), 1969 (50), 1983 (36), 1989 (30), 1995 (24), 1997 (22), 1999 (20) and 2001 (18).

1) Person whose birth year is 1997 is lives on bottom most floor and likes Violet color.

2)  The age of S, who likes Violet color is multiple of 11. Imply that S was born on 1997 and lives on 1st floor, as multiple of 11 is only 22 years and therefore birth year is 1997.

3) W lives immediately above S.

4. The difference between the age of W and R is 20 years. There are only Two years 1989 (30) and 1969 (50).

5. W is older than R. Therefore age of W is 50 years and R is 20 years.

The possible arrangement is as follows.

6) V lives on floor numbered four.

7) There are two floor between V and R.

8) R neither lives on floor numbered one and nor likes Pink color.

9) There are at least five floor between S and U.

10. U lives somewhere above S but not immediately above S.

11) Q lives on the even numbered floor but not on the topmost floor.

12) Birth year of Q is even number.

13) There is one floor between the floor on which U, who likes Red color and Q lives.

14)  Person likes Black color lives immediately above the person who likes Purple color and and immediately below the person who likes White color.

15) T, who likes Yellow color lives immediately above the who likes White color. Therefore, T must be lives on 5th floor because below there are persons who likes Black and White color.

16) The age of P is two times the age of V. Imply that age of P is 36 and year is 1983 and age of V is 18 and year is 2001. 

17) U is not 20 years old. Imply that age of U is 24 years and birth year is 1995.

The final arrangement is as follows:

 

 

 

 

 

 

 

 

 

 

Sum of the age of R and Q is = 30 + 65 = 95

Hence, sum of the age of R and Q is 95 years.

Given:

Floors : 1 to 8

Persons : P, Q, R, S, T, U, V and W

Colors : Red, Violet, Pink, Yellow, Black, Purple, Blue and White.

Years : 1954, 1969, 1983, 1989, 1995, 1997, 1999 and 2001.

Therefore ages are :1954 (65), 1969 (50), 1983 (36), 1989 (30), 1995 (24), 1997 (22), 1999 (20) and 2001 (18).

1) Person whose birth year is 1997 is lives on bottom most floor and likes Violet color.

2)  The age of S, who likes Violet color is multiple of 11. Imply that S was born on 1997 and lives on 1st floor, as multiple of 11 is only 22 years and therefore birth year is 1997.

3) W lives immediately above S.

4. The difference between the age of W and R is 20 years. There are only Two years 1989 (30) and 1969 (50).

5. W is older than R. Therefore age of W is 50 years and R is 20 years.

The possible arrangement is as follows.

6) V lives on floor numbered four.

7) There are two floor between V and R.

8) R neither lives on floor numbered one and nor likes Pink color.

9) There are at least five floor between S and U.

10. U lives somewhere above S but not immediately above S.

11) Q lives on the even numbered floor but not on the topmost floor.

12) Birth year of Q is even number.

13) There is one floor between the floor on which U, who likes Red color and Q lives.

14)  Person likes Black color lives immediately above the person who likes Purple color and and immediately below the person who likes White color.

15) T, who likes Yellow color lives immediately above the who likes White color. Therefore, T must be lives on 5th floor because below there are persons who likes Black and White color.

16) The age of P is two times the age of V. Imply that age of P is 36 and year is 1983 and age of V is 18 and year is 2001. 

17) U is not 20 years old. Imply that age of U is 24 years and birth year is 1995.

The final arrangement is as follows:

 

 

 

 

 

 

 

 

 

 

Hence, 1983 is the birth year of the person who likes Black color.

Given:

Floors : 1 to 8

Persons : P, Q, R, S, T, U, V and W

Colors : Red, Violet, Pink, Yellow, Black, Purple, Blue and White.

Years : 1954, 1969, 1983, 1989, 1995, 1997, 1999 and 2001.

Therefore ages are :1954 (65), 1969 (50), 1983 (36), 1989 (30), 1995 (24), 1997 (22), 1999 (20) and 2001 (18).

1) Person whose birth year is 1997 is lives on bottom most floor and likes Violet color.

2)  The age of S, who likes Violet color is multiple of 11. Imply that S was born on 1997 and lives on 1st floor, as multiple of 11 is only 22 years and therefore birth year is 1997.

3) W lives immediately above S.

4. The difference between the age of W and R is 20 years. There are only Two years 1989 (30) and 1969 (50).

5. W is older than R. Therefore age of W is 50 years and R is 20 years.

The possible arrangement is as follows.

6) V lives on floor numbered four.

7) There are two floor between V and R.

8) R neither lives on floor numbered one and nor likes Pink color.

9) There are at least five floor between S and U.

10. U lives somewhere above S but not immediately above S.

11) Q lives on the even numbered floor but not on the topmost floor.

12) Birth year of Q is even number.

13) There is one floor between the floor on which U, who likes Red color and Q lives.

14)  Person likes Black color lives immediately above the person who likes Purple color and and immediately below the person who likes White color.

15) T, who likes Yellow color lives immediately above the who likes White color. Therefore, T must be lives on 5th floor because below there are persons who likes Black and White color.

16) The age of P is two times the age of V. Imply that age of P is 36 and year is 1983 and age of V is 18 and year is 2001. 

17) U is not 20 years old. Imply that age of U is 24 years and birth year is 1995.

The final arrangement is as follows:

 

 

 

 

 

 

 

 

 

 

U, V, S and the one who likes blue color born in the year which is the odd number, and also their age is an even number.

Now the one who lives between R and T is Q, Q born in the year which is the even number year, and his age is also 65, which is an odd number. 

Hence this is odd one out, Correct option is 3.

Given words: PRIORITY and SECTOR

1^st, 4^th, 5^th and 7^th letter from the first word is: P, O, R, T 

3^rd, 5^th, and 6^th letter from the second word is: C, O, R

Combining and jumbling first and second word we get: PROCTOR

Hence, the first letter will, be P.

While many of their routine tasks such as document management, time & attendance records, payroll, and the like can be completed faster using HR management software, this does not imply a reduction in responsibility for HR. Instead, other strategic areas such as engaging with employees, spearheading change management as new digital systems are introduced, and finding the brightest talent to help organizations win in the digital economy require human interaction as technology is incapable of strategy, empathy, creativity, and on-spot improvising, which are all essential traits for any HR practitioner.

Therefore, action I does not follow.

Open communication between departments is essential for a company’s continued growth. A training program for HR that outlines and emphasizes the need to build employee morale, satisfaction, and engagement will help to lessen the chances of misunderstandings and potentially reduces grievances. A strong training component will not only equip HR to communicate effectively with the employees and other organizational leaders, but it will also help them understand the appropriate communication protocols.

Therefore, action II is a viable course of action.

Hence, only II follows is the correct answer.

The passage above mentions about the problems which the destitute widows, deserted women, and physically challenged men and women are facing in the villages of Gujarat and Rajasthan.

From the above information, we can determine that the next course of action will be helping those poor people who have skills but don’t have a job.

Hence Option III follows.

Option I is not a correct course of action as it is practically not possible for the Government to make everyone rich and stable.

Hence, Option I does not follow.

Option II does not follow as the issue pointed out in the statement is not the lack of shelter

Hence, Option II does not follow.

1. The company recently hired a web designer and created an interesting online clothing catalogue to take its Clothing business online.
2. As a result, the company had a huge uptick in the volume of sales in the Clothing segment. The spurt was caused due to increased orders from digitally literate clients

The two statements combinedly mean that sales increased (attracted more digitally literate customers) after the company took the Clothing business online.

In order to relate the two concepts, the underlying assumption must be the same, i.e., by taking the Electronic goods business online, the company will attract digitally literate clientele. 

Thus, Option 2 is a valid assumption.

Option 1 is an invalid assumption because it is irrelevant to the question since the question of whether other companies had online sales did not arise with the Clothing segment. If this assumption held true, then you would have to assume the same for the clothing segment. Also, the question is not what other companies do, but what this company is doing to increase sales from digitally literate clients.

By the same logic, Option 4 is invalid too.

Option 3 is an invalid assumption because it is irrelevant to the question since the web designer is not the main topic under discussion.

Option 5 is also an invalid assumption because it is Irrelevant to the question. The problem is not whether the company is looking to wind-up its brick and mortar business but its plans to increase digital sales.

Hence, Only Assumption 2 holds.

Solution: Correct option 2. 

The statement talks about the notion of loneliness until the 19th century which meant seclusion from the world and being devoid of God's love and these descriptions were used to breed fear in men.

From what is supplied we only know God's love is needed but cannot deduce that God loves all equally. Therefore, inference 1 does not follow.

Since loneliness generated fear of nonexistence, people thought of it as a condition cut off from the world and God's love we can infer that people felt scared to be deprived of God's love. Therefore, inference 2 follows.

The statement talks about the 19th century and therefore no deduction about the 20th century can be made. Therefore inference 3 does not follow.

Again the statement mentions that until the 19th-century feelings were disassociated with the notion of loneliness but we do not get clarity upon what should have been done. Therefore, inference 4 does not follow.

Hence,option 2 is correct.

From the statement, it is evident that there is a usual conflict between the residents of X and Y due to some sharing issues. But the difficulties occur when they start hampering other people and damage national properties.

The first course of action is correct as deploying policemen round the clock in the borders of X and Y will not allow the residents to create a nuisance.

Similarly, identifying the right person involved in such activities and punishing him will be a warning for others to not indulge in such activities.

Therefore, both I and II follow.

In the case of the third course of action, stopping all the transport facilities between the two states would be an extreme step taken in this regard.

Therefore, III does not follow.

Hence, 'All except III follow' is the correct answer.

Given data :

From statement I : P is given the seminar before than at least three students. M was given the seminar on Tuesday.

 

From statement II : Q is given the seminar before than at least one of them. O was given immediately after P.

 

Thus, three-person was given seminars before O.

<br>

Hence, statements I and II are sufficient to answer the question is the correct answer.

Given data : 

From statement I :  X is standing second from the left end. Z is standing third to the left of Y who is near to B.

Case I :

Case II :

From statement II : Y is not the immediate neighbour of C who does not sits any extreme end of the row.

case II is invalid.

case I : 

The C is standing between the Z and B.

Hence, 'the data in statement I and II are sufficient to answer the question, while the data in statement III are not sufficient to answer the question' is the correct answer.

Given data :

1) J is standing exactly between M and K.

2) J is standing to the right of M.

3) L is standing exactly between I and M.

Taking all together we get,

Thus, the building "I" is standing at the extreme left.

Hence, 'All statements together required to answer the question' is the correct answer.

Given data :

From statement I and II we get,

The code for love is "fr"

If the data in both statements I and II together are necessary to answer the question is the correct answer.

Given data :

Statements :

All City are Trees . No Trees is Branch . All Branch are Forest

The best possible Venn diagram is shown below - 

Conclusions :

I.All Trees being Forest is a possibility → True(There is no direct not relation between trees and forest)

II.All City being Forest is a possibility → True(There is no direct not relation between trees and forest)

Hence, 'Statement - II : All City are Trees . No Trees is Branch . All Branch are Forest' is the correct answer.

Given data :

 Only a few wells are mats. All pillows are mats.

The best possible Venn diagram is shown below - 

Conclusions :

I.some pillows are mats → True (There is a direct relation between pillows and mats)

II.All wells can never be pillows → True(As given Only a few wells are mats so, all part of wells can never be pillows)

Hence, 'Statement – I: Only a few wells are mats. All pillows are mats' is the correct answer.

Given data :

All Rose are roots. No root is a flower. Some flowers are plants.

The best possible Venn diagram is shown below -

Conclusions :

I.No Rose is a flower → True( This is the definite case from the above Venn diagram)

II.Some plants are flowers → True( This is the definite case from the above Venn diagram)

Hence, 'Statements  III : All Rose are roots. No root is a flower. Some flowers are plants' is the correct answer.

Let us first decode the given symbols and then draw a family tree.

 

Now draw family tree using following notations:

G + I % T × K + Y → G is the brother of I who is the husband of T who is the mother of K who is the brother of Y.

Clearly, G is the paternal uncle of Y.

Let us first decode the given symbols and then draw a family tree.

 

Now draw family tree using following notations:

F ÷ U $J$ V % H → F is the father of U who is the daughter of H who is the daughter of V who is the husband of H.

Clearly, F is the son-in-law of H

Let us first decode the given symbols and then draw a family tree.

 

Now draw family tree using following notations:

1. C + L ÷ N % Q $ R → C is the brother of L who is the father of N who is the husband of Q who is the daughter of R. Clearly, N is a male here. Hence, N cannot be the granddaughter in this case.

2. R % Q + L ÷ C % N → R is the husband of Q who is the brother of L who is the father of C who is the husband of N. Clearly, it is a false case as Q is the wife and the brother at the same time which is not possible.

3. Q × N $C + L$ R → Q is the mother of N who is the daughter of C who is the brother of L who is the daughter of R.

Clearly, in this case, N is the granddaughter of R.

4. C × N + R $ L ÷ Q → C is the mother of N who is the brother of R who is the daughter of L who is the father of Q. Clearly, in this case, N is the brother of R.

5. R + L $ N ÷ C × Q → R is the brother of L who is the daughter of N who is the father of C who is the mother of Q. Clearly, as N is the father of C, implies, N is a male.

Hence, Q × N $C + L$ R represents that N is the granddaughter of R.

Given:

The shopkeeper made neither profit nor loss

Formula used:

Profit = Selling price – Cost price

Loss = Cost price – Selling price

Profit percentage = (Profit/Cost price) × 100

Loss percentage = (Loss/Cost price) × 100

Calculation:

Statement I:

Let CP₁ be the cost price of the first article

Let SP₁ be the selling price of the first article

Let CP₂ be the cost price of the second article

Let SP₂ be the selling price of the second article

SP₁ = CP₁ × (5/3)

SP₂ = CP₂ × (5/7)

Statement I alone is not sufficient to answer the question

Statement II:

Let SP₁ be the selling price of the first article

Let SP₂ be the selling price of the second article

SP₁ = SP₂

Statement II alone is not sufficient to answer the question

Statement III:

Let SP₁ be the selling price of the first article

Let SP₂ be the selling price of the second article

SP₁ + SP₂ = 5000

Statement III alone is not sufficient to answer the question

Considering Statement III

We know that sum of the Cost price of both articles is equal to the sum of the Selling price of the articles, as no profit no loss condition.

SP₁ + SP₂ = 5000 = CP₁ + CP₂      ----(1)

Considering Statement I and Statement III

SP₁ = CP₁ × (5/3)  

SP₂ = CP₂ × (5/7)

⇒ {(5/3) × CP₁} + {(5/7) × CP₂} = 5000

⇒ 7CP₁ + 3CP₂ = 21000      ----(2)

Multiply equn (1) with 3 to equal CP2 in both equations, we get,

⇒ 3CP₁ + 3CP₂ = 15000      ----(3)

Subtracting equn (3) and equn (2) we get

⇒ 4CP₁ = 6000

⇒ CP₁ = 1500

∴ Both I and III statements are required to give the answer.

Formula used:

Speed = Distance/time

Statement (I):

The difference between the speeds of trains A and B is 22 km/h.

If the speed of train A is 'x' km/h.

So, the speed of train B is (x - 22) km/h.

∴ Statement (I) alone is not sufficient to answer the question.

Statement (II):

Two trains A and B running in opposite directions and cross each other in 32 seconds.

So. total time taken to cross each other is 32 seconds.

∴ Statement (II) alone is not sufficient to answer the question.

Statement (III):

The length of train A is 192 m 

The ratio of the speed of the trains is 20 : 31.

According to question,

x/(x - 22) = 20/31

So the speed of two train calculated.

So, we get the length of second train.

∴ Statement (III) alone is not sufficient to answer the question.

∴ The data in all the statements I, II and III together is necessary to answer the question.

Concept Used:

Using the unitary method.

Statement (I):

Three men worked together for 30 days to do work and all of them remained absent for few days.

One man take time to complete the work is 90 days.

In one man complete the work is 1/90 part.

Statement (I) is not sufficient to answer the question.

Statement (II):

First man was absent for 10 days more than the second man. 

Let the time taken by second man is 'x' days

Then time taken by first man is (x - 10)days.

Statement (I)  and (II) is not sufficient to answer the question.

Statement (II):

The third man completed 1/3rd of the total work.

It means third man complete 30 part of work.

Remaining work is 60 part 

Which is done by first and second and.

∴ Statement (I), (II) and (III) is not sufficient to answer the question.

Quantity I:

Given:

[(1/3) of (1/5) of a number] – 5 = (1/30) of the same number

Calculation:

Let the number be x

[(1/3) × (1/5) × x] – 5 = (1/30) × x

⇒ [(1/15) × x] – 5 = (1/30) × x

⇒ (x – 75)/15 = (1/30) × x

⇒ (x – 75) = (1/2) × x

⇒ 2x – 150 = x

⇒ x = 150

The number is 150.

Quantity II:

Given:

Denomination of notes in the bag are ₹ 50, ₹ 100 and ₹ 200

Calculation:

Let x be the number of notes in each bag

50x + 100x + 200x = 10500

⇒ 350x = 10500

⇒ x = 30

The number of notes in each bag are 30.

∴ We can deduce that Quantity I > Quantity II.

Quantity I:

Probability of picking 2 tiles such that one is green and the other one is blue

⇒ (6 × 9)/⁵⁰C₂

⇒ 54/(50 × 49/2)

⇒ 54/1225

⇒ 0.044

Quantity II:

Probability of picking 3 balls such that at least one of them is red

⇒ 1 – ⁴⁵C₃/⁵⁰C₃

⇒ 1 – (45 × 44 × 43/6)/(50 × 49 × 48/6)

⇒ 1 – (14190/19600)

⇒ 541/1960

⇒ 0.276

Quantity III:

Probability of picking 3 balls such that at least one of them is blue

⇒ 1 – ⁴¹C₃/⁵⁰C₃

⇒ 1 – (41 × 40 × 39/6)/(50 × 49 × 48/6)

⇒ 1 – (10660/19600)

⇒ 894/1960

⇒ 0.456

Quantity III > Quantity II > Quantity I

Quantity I:

Given:

Q's share of profit = ₹ 252 

Calculation:

Let the Amount invested by P is ₹ P

and the Amount invested by Q is ₹ 2P

So, the amount invested by R is ₹ 3P

P did investment for 8 months

Q did investment for 12 months

R did investment for 4 months

Profit ratio = (P × 8) : (2 × P × 12) : (3 × P × 4)

⇒ Profit ratio = 8P : 24P : 12P

⇒ Profit ratio = 2 : 6 : 3

Q share in terms of ratio = 6

The actual share of Q = 252

Profit share of R = (252/6) × 3 = 126

Quantity II:

₹ 280

∴ Quantity I < Quantity II

Given:

Duration of basic, regular and advance classes are 1 hour, 2 hours and 3 hours respectively.

Solution:

Total class hour taken by Vaibhav sir is (28/100) × 450 = 126 hours

Hours spent on the basic class by Vaibhav sir is (2/14) × 126 = 18 Hours

Number of basic classes taken by Vaibhav sir is (18/1) = 18

Total class hour taken by Sachin sir is (34/100) × 450 = 153 hours

Hours spent on the regular class by Sachin sir is (8/17) × 153 = 72 hours

Number of regular classes taken by Sachin sir is (72/2) = 36

Percentage of the number of basic class taken by Vaibhav sir to the number of regular classes taken by Sachin sir = (18/36) × 100 = 50%

∴ Required percentage is 50%

Given:

The duration of basic, regular and advance classes are 1 hour, 2 hours and 3 hours respectively.

Solution:

The total class hour taken by Vaibhav sir is (28/100) × 450 = 126 hours

Hours spent on the advance class by Vaibhav sir is (5/14) × 126 = 45 Hours

The number of advance classes taken by Vaibhav sir is (45/3) = 15

The total class hour taken by Aditya sir is (22/100) × 450 = 99 hours

Hours spent on the regular class by Aditya sir is (4/11) × 99 = 36 hours

Number of regular classes taken by Aditya sir is 36/2 = 18

The number of more regular classes taken by Aditya sir than the number of advance classes taken by Vaibhav sir = 18 - 15

⇒ 3

∴ 3 more regular classes taken by Aditya sir than the advance classes taken by Vaibhav sir.

Confusion Points

Before calculation of the number of classes, we need to divide the hours taught by each teacher by the duration of the class. 

For Basic Class, we divide by 1

For Regular Class, we divide by 2

For Advance Class, we divide by 3

Given:

Duration of basic, regular and advance classes are 1 hour, 2 hours and 3 hours respectively.

Solution:

Overall time spend by Sachin sir is (34/100) × 450 = 153 hours

Time spent on the basic level classes by Sachin sir = (6/17) × 153 = 54 hours

Time spent on the regular level classes by Sachin sir = (8/17) × 153 = 72 hours

Overall time spent by Vishnu sir is (16/100) × 4500 = 72 hours

Time spent on the basic level classes by Vishnu sir = (1/9) × 72 = 8 hours

Time spent on the regular level classes by Vishnu sir = (2/9) × 16 hours

Time spent by Sachin sir and Vishnu sir in basic level class together is (54 + 8) = 62 hours

Time spent by Sachin sir and Vishnu sir in regular level class together is (72 + 16) = 88 hours

The required ratio is 62 : 88

⇒ 31 : 44

∴ The required ratio of time spend by Sachin sir and Vishnu sir together in basic level classes to that of the regular level class through the month is 31 : 44.

Given:

Total number of class hour = 450 hours

Calculation:

The total class was taken by Vaibhav sir (28/100) × 450 = 126 hour

The ratio of 1 hour, 2 hours and 3 hours class taken by Vaibhav sir is 2 : 7 : 5

Time spend on the basic class by Vaibhav sir is (2/14) × 126 = 18

Number of basic classes taken by Vaibhav sir is 18/1 = 18

The total class was taken by Vishnu sir (16/100) × 450 = 72 hours

The ratio of 1 hour, 2 hours and 3 hours class taken by Vishnu sir is 1 : 2 : 6

Time spend on the advance class by Vishnu sir is (6/9) × 72 = 48 hours

Number of the advance class by Vishnu sir is 48/3 = 16 

The ratio of the number of the basic class of Vaibhav sir to the number of advance classes taken by Vishnu sir is 18 : 16 = 9 : 8

∴ The ratio of the number of the basic class of Vaibhav sir to the number of advance classes taken by Vishnu sir is 9 : 8

Confusion Points

Before calculation of the number of classes, we need to divide the hours taught by each teacher by the duration of the class. 

For Basic Class, we divide by 1

For Regular Class, we divide by 2

For Advance Class, we divide by 3

Formula used:

Percentage = (Part value/Original value) × 100

Calculation: 

Orders placed and delivered on Wednesday

⇒ 400 + 223 = 623

Orders placed and returned on Friday

⇒ 275 + 59.43

⇒ 334.43

Percentage

⇒ (623/334.43) × 100

⇒ 186.70% ≈ 186%

∴ The approximate percentage is 186%.

Formula used:

Average = Sum of values/number of values

Calculation:

Average of orders delivered on all days

⇒ (149 + 225 + 223 + 283 + 147 + 188)/6

⇒ 202.5

By comparing the data given in the table

The order delivered on Tuesday, Wednesday, and Thursday are more than the Average of orders delivered.

⇒ 3

∴ 3

Given:

Orders delivered on Monday = 149

Order delivered on Thursday = 283

Order returned percentage from Monday Orders delivered = 20%

Order returned percentage from Thursday Orders delivered = 21%

Calculation:

Orders delivered and not returned on Monday

⇒ 149 - 29.8

⇒ 119.2

All data is in thousands

⇒ 119.2 × 1000 = 119200

Orders delivered and not returned on Thursday

⇒ 283 - 59.43

⇒ 223.57

All data is in thousands

⇒ 223.57 × 1000 = 223570

Ratio = 119200 : 223570

⇒ 11920 : 22357

∴ 11920 : 22357

Calculation:

The difference in the order placed and returned on Tuesday = (375 - 29.8) thousand = 345200

The difference in the order placed and returned on Friday = (275 - 59.43) thousand = 215570

Required ratio = 345200 ∶ 215570

∴ 34520 ∶ 21557

Calculation:

Total items returned on Tuesday and Wednesday = (60.75 + 28.99) thousand = 89740

Average of items returned on Tuesday and Wednesday = 89740/2 = 44870

∴ 44870

Calculation:

Number of orders returned on Wednesday > Friday > Tuesday > Thursday > Monday > Saturday

∴ From the options given maximum number of orders were returned on Wednesday

Given:

Total number of books written by E = 300

Number of friends of E = 3

Number of male friends of E = 1

Number of friends of each of the friends of E = 5

Calculation:

Number of book distributed to each friend of E = 300/3 = 100

Hence, Number of book received by the only male friend of E =  100

Also, it is given that,

Male friend of E can equally distribute a maximum of 60 books to his female friends.

So, the maximum possible number of female friends of E = total number of male friends of E

Hence,  the maximum possible number of female friends of the male friend of E = 5

∴  The maximum possible number of female friends of the male friend of E is 5

Mistake Points Common Wrong Logic

1. Question asked a maximum female friend of the male friend of E.

Not the maximum female friend of E. Hence, the answer should be 3

 

2. 300/3 = 100 then 100/5 is equal to 20.

Now the maximum number of books that can be given to a female friend is 60,

So 60/20 which is equal to 3

Both the above logic are wrong.

it has been mentioned in the question that there are certain number of friends for a particular friend of A, B, C, D and E each. Hence in the solution; we divide the total number of friends of a person by the maximum of number of friends that person has to obtain the required answer.

Number of ways 1 female can distribute the books her 5 friends = 5!

So, Number of ways 2 females can distribute the books their friends = 2 × 5!

Number of ways male can distribute 1 book to his 5 friends = 5!

Difference between number of ways = (2 × 5!) - 5!

⇒ 5!

⇒ 5 × 4 × 3 × 2 × 1

⇒ 120 ways

∴ In 120 ways female friends of E can distribute 1 book to their friends more than that by the male friends.

Given:

Number of books written by C = 400

Number of books written by D = 600

Number of friends of C = 4

Number of friends of D = 6

Number of friends of each friend of C = 5

Number of friends of each friend of D = 2

Calculation:

Number of books received by each friend of C = 400/4 = 100

Number of books received by each friend of D = 600/6 = 100

When each friend of D distributes the book equally to their respective friends, 

Number of books received by each friend of the friends of D = 100/2 = 50

So, the required average = (100 + 50)/2 = 75

∴ The average of the number of books received by each of the friends of C and those received by each of the friend of the friends of D is 75