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Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 761–780 of 1495Page 39 of 75
SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 761

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following direction and answer the following questions:

The below given pie chart shows the number of male and female who visited park on different days of  week.

The total number of males and females that visited the park  is 500

The total number of males and females who visited the park on Thursday is 1/4th of total males and females.

If the number of males and females visiting parks on Wednesday is considered a pie chart, find the degree value of the number of males and females who visited the park on Wednesday.

  1. AOption (a)

    54°

  2. BOption (b)

    105°

  3. COption (c)

    90°

  4. DOption (d)

    120°

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

54°

Why this answer is correct

Solution:

The total number of males and females visited the park = 500

Number of males and females who visited the park on Thursday is 1/4th of the total number of males and females who visited the parks on five different days

Number of males and females  visited the park on Thursday (Y) = 500/4 = 125

To find the value of X

(X + 20)/100 ×  500 + (2X)/100 ×  500 + X/100 ×  500 + (X + 5)/100×  500 + 125 = 500

(5X + 100) + (10X) + 5X + (5X + 25) + 125 = 500

25X + 250 = 500

25X = 250

X = 10

The Number of males and females the visited park on Sunday = (10 + 20) = 30% = 30/100 ×  500 = 150

The Number of males and females visited the park on Monday = 2×  10 = 20% = 20/100 ×  500 = 100

The Number of males and females visited the park on Tuesday = 10/100 ×  500 = 50

The Number of males and females visited the park on Wednesday = (10 + 5) = 15/100 ×  500 = 75

The Number of males and female visited the park on Thursday = 125 

Number of males and females visiting parks on Wednesday = (X + 5) = (10 + 5)% = 15/100 ×  500 = 75

To find the required degree = 75/500 ×  360 = 54°

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 762

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following direction and answer the following questions:

The below given pie chart shows the number of male and female who visited park on different days of  week.

The total number of males and females that visited the park  is 500

The total number of males and females who visited the park on Thursday is 1/4th of total males and females.

If the total number of males who visited park on Monday and Sunday is 100 and the number of females visited park on Sunday is 50% more than the number of females visited park on Monday. Find the number of males who visited the park on Sunday.

  1. AOption (a)

    80

  2. BOption (b)

    60

  3. COption (c)

    50

  4. DOption (d)

    100

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

60

Why this answer is correct

Solution:

The total number of males and females visited the park = 500

The number of males and females who visited the park on Thursday is 1/4th of the total number of males and females who visited the parks on five different days

Number of males and females who visited the park on Thursday (Y) = 500/4 = 125

To find the value of X

(X + 20)/100 ×  500 + (2X)/100 ×  500 + X/100 ×  500 + (X + 5)/100×  500 + 125 = 500

(5X + 100) + (10X) + 5X + (5X + 25) + 125 = 500

25X + 250 = 500

25X = 250

X = 10

The Number of males and females the visited park on Sunday = (10 + 20) = 30% = 30/100 ×  500 = 150

The Number of males and females visited the park on Monday = 2×  10 = 20% = 20/100 ×  500 = 100

The Number of males and females who visited the park on Tuesday = 10/100 ×  500 = 50

The Number of males and females visited the park on Wednesday = (10 + 5) = 15/100 ×  500 = 75

The Number of males and females visited the park on Thursday = 125 

The number of males who visited the park on Monday and Sunday = 100

Number of females visited park on Monday and Sunday = (150 + 100) - 100 = 150

The number of females who visited the park on Sunday is 50% more than the number of females who visited the park on Monday, So

⇒ The number of females who visited the park on Sunday = 150% of number of females who visited the park on Monday

⇒ 150% of the number of females visited the park on Monday + the number of females visited park on Monday = 150

⇒ 250% of number of females visited the park on Monday = 150

⇒ The number of females visited the park on Monday = 60

Number of male visited the park on Monday = (100 - 60) = 40

Number of males who visited the park on Sunday = 100 - 40 = 60

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 763

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following direction and answer the following questions:

The below given pie chart shows the number of male and female who visited park on different days of  week.

The total number of males and females that visited the park  is 500

The total number of males and females who visited the park on Thursday is 1/4th of total males and females.

The combined total of males and females on Friday is 20% higher than that of Thursday. If the total number of males on Friday equals the total count of males and females on Tuesday, determine how many females there are on Friday.

  1. AOption (a)

    100

  2. BOption (b)

    120

  3. COption (c)

    80

  4. DOption (d)

    125

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

100

Why this answer is correct

Solution:

The total number of males and females visited the park = 500

Number of males and females who visited the park on Thursday is 1/4th of the total number of males and females who visited the parks on five different days

Number of males and females  visited the park on Thursday (Y) = 500/4 = 125

To find the value of X

(X + 20)/100 ×  500 + (2X)/100 ×  500 + X/100 ×  500 + (X + 5)/100×  500 + 125 = 500

(5X + 100) + (10X) + 5X + (5X + 25) + 125 = 500

25X + 250 = 500

25X = 250

X = 10

The Number of males and females the visited park on Sunday = (10 + 20) = 30% = 30/100 ×  500 = 150

The Number of males and females visited the park on Monday = 2×  10 = 20% = 20/100 ×  500 = 100

The Number of males and females visited the park on Tuesday = 10/100 ×  500 = 50

The Number of males and females visited the park on Wednesday = (10 + 5) = 15/100 ×  500 = 75

The Number of males and female visited the park on Thursday = 125 

Number of males and females visited the park on Thursday = 125

Number of males and females visited the park on the Friday = 125 ×  120/100 = 150

Number of males visited the park on Friday is equal to the total males and females visited the park on Tuesday

Number of males and females visited park on Tuesday = 50

So, number of females visited the park on Friday = (150 - 50) = 100

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 764

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following direction and answer the following questions:

The below given pie chart shows the number of male and female who visited park on different days of  week.

The total number of males and females that visited the park  is 500

The total number of males and females who visited the park on Thursday is 1/4th of total males and females.

If the ratio between the number of males and females visited the park on Monday is 3: 2 and the number of males and females visited the park on Wednesday is 2: 1 respectively. Find the ratio between the number of males visited Monday and Wednesday to the number of females visited Monday and Wednesday..

  1. AOption (a)

    22: 13

  2. BOption (b)

    21: 19

  3. COption (c)

    22: 17

  4. DOption (d)

    19: 17

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

22: 13

Why this answer is correct

Solution:

The total number of males and females visited the park = 500

Number of males and females who visited the park on Thursday is 1/4th of the total number of males and females who visited the parks on five different days

Number of males and females  visited the park on Thursday (Y) = 500/4 = 125

To find the value of X

(X + 20)/100 ×  500 + (2X)/100 ×  500 + X/100 ×  500 + (X + 5)/100×  500 + 125 = 500

(5X + 100) + (10X) + 5X + (5X + 25) + 125 = 500

25X + 250 = 500

25X = 250

X = 10

The Number of males and females the visited park on Sunday = (10 + 20) = 30% = 30/100 ×  500 = 150

The Number of males and females visited the park on Monday = 2×  10 = 20% = 20/100 ×  500 = 100

The Number of males and females visited the park on Tuesday = 10/100 ×  500 = 50

The Number of males and females visited the park on Wednesday = (10 + 5) = 15/100 ×  500 = 75

The Number of males and female visited the park on Thursday = 125 

Number of males and females visited parks on Monday = 100

Number of males visited parks on Monday = 100/5 × 3 = 60

Number of females visited parks on Monday = (100 - 60) = 40

Number of males and females visited parks on Wednesday = 75

Number of males visited parks on Wednesday = 75/3 × 2 = 50

Number of females visited parks on Wednesday = (75 - 50) = 25

Required ratio = (60 + 50): (40 + 25) = 110: 65 = 22: 13

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 765

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions: Read the following direction and answer the following questions:

The below given pie chart shows the number of male and female who visited park on different days of  week.

The total number of males and females that visited the park  is 500

The total number of males and females who visited the park on Thursday is 1/4th of total males and females.

The total number of males and females visited park on Saturday to Sunday are in the ratio of 1:2 respectively. The total number of females visited on Saturday is 70% of the total number of males and females visited the park on Tuesday. Find the number of males who visited the park Saturday.

  1. AOption (a)

    40

  2. BOption (b)

    60

  3. COption (c)

    50

  4. DOption (d)

    70

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

40

Why this answer is correct

Solution:

The total number of males and females visited the park = 500

Number of males and females who visited the park on Thursday is 1/4th of the total number of males and females who visited the parks on five different days

Number of males and females  visited the park on Thursday (Y) = 500/4 = 125

To find the value of X

(X + 20)/100 ×  500 + (2X)/100 ×  500 + X/100 ×  500 + (X + 5)/100×  500 + 125 = 500

(5X + 100) + (10X) + 5X + (5X + 25) + 125 = 500

25X + 250 = 500

25X = 250

X = 10

The Number of males and females the visited park on Sunday = (10 + 20) = 30% = 30/100 ×  500 = 150

The Number of males and females visited the park on Monday = 2×  10 = 20% = 20/100 ×  500 = 100

The Number of males and females visited the park on Tuesday = 10/100 ×  500 = 50

The Number of males and females visited the park on Wednesday = (10 + 5) = 15/100 ×  500 = 75

The Number of males and female visited the park on Thursday = 125 

Solution:

The number of males and females visited the park on Sunday = 150

The number of males and females visited the park on Saturday = 150/2 = 75

The total number of males and females visited on Tuesday = 50

The Number of females visited the park on Saturday = (70/100) × 50 = 35

The Number of male visited the park on Saturday = (75 - 35) = 40

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 766

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Direction: The line chart given below shows the number of people visiting 5 pubs in two years 2010 and 2015.

In 2010, if the number of females visiting pub A is thrice the number of females visiting pub E and the total number of males visiting pub A is more than the total number of males visiting pub E in the same year, which of the following value cannot be the number of males visiting pub A?

  1. AOption (a)

    27

  2. BOption (b)

    39

  3. COption (c)

    33

  4. DOption (d)

    36

  5. EOption (e)

    Both options 1) and 2)

View answer & explanation

Correct answer

Answer: (a)A.

27

Why this answer is correct

From the line chart:

Pubs20102015
A6035
B8050
C7080
D9035
E4060

In 2010,

Let the total number of females in pub E be X,

So the number of males in pub E is 40 - X.

The number of females visiting pub A is thrice the number of females visiting pub E,

So the number of females in pub A = 3X,

So the number of males in pub A = 60 - 3X.

The total number of males visiting pub A is more than the total number of males visiting pub E,

So,

60 -3X > 40 - X

So,

20 > 2X

So,

X < 10.

Multiply both sides by 3,

3X < 30,

Subtract both LHS and RHS from 60,

60 - 3X < 60 - 30

60 - 3X < 30

The number of males in pub A is 60 - 3X

So the number of males in pub A must not be less than 30.

And from the given options only 27 < 30,

Hence only 27 cannot be the value.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 767

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Direction: The line chart given below shows the number of people visiting 5 pubs in two years 2010 and 2015.

In pub C, the total number of males visiting the pub in 2010 is 5 times the difference between the total number of males and females visiting pub D in the same year. Find the percentage of males who went to pub D in the same year if 3 females in pub C were charged extra fees for coming late which is 15% of the total number of females in pub C?

Assume: The total number of males in pub D is more than the total number of females in the same pub.

  1. AOption (a)

    55.55%

  2. BOption (b)

    66.66%

  3. COption (c)

    46.66%

  4. DOption (d)

    33.33%

  5. EOption (e)

    None of the above

View answer & explanation

Correct answer

Answer: (a)A.

55.55%

Why this answer is correct

From the line chart:

Pubs20102015
A6035
B8050
C7080
D9035
E4060

In 2010,

In pub C,

15% of females were charged extra fees for coming late and the total number of females who were charged were 3,

So,

(3/Total number females) x 100 = 15

So,

the total number of females in pub C = 20.

The total number of people in pub C is 70,

So the number of males in pub C = 70 - 20 = 50.

the total number of males visiting pub C is 5 times the difference between the total number of males and females visiting pub D in the same year,

So the difference between the total number of males and females in pub D = 50/5 = 10.

The total number of people visiting pub D = 90 and the number of males is greater than the number of females in pub D,

So,

the total number of males in pub D = (10 + 90)/2 = 50

and the total number of females in pub D = 90 - 50 = 40.

So the percentage of males who went to pub D in the same year = 50/90 x 100 = 55.55%.

Hence the percentage of males who went to pub D in 2010 is 55.55%.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 768

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Direction: The line chart given below shows the number of people visiting 5 pubs in two years 2010 and 2015.

If the ratio of males and females visiting all the pubs in the years 2010 and 2015 is 9:8 and 8:5 respectively and in 2010 and 2015 only 12.5% and 16% of females were fined extra fees for coming late, find the ratio of females in the year 2010 and 2015 who were not fined with any extra fees for not coming late? 

  1. AOption (a)

    6:7

  2. BOption (b)

    5:7

  3. COption (c)

    5:3

  4. DOption (d)

    10:7

  5. EOption (e)

    10:3

View answer & explanation

Correct answer

Answer: (c)C.

5:3

Why this answer is correct

From the line chart:

Pubs20102015
A6035
B8050
C7080
D9035
E4060

In 2010,

The total number of people visiting all the pubs = 60 + 80 + 70 + 90 + 40 = 340

The ratio of males and females is 9:8,

So the total number of males and females is 180 and 160 respectively.

In 2015,

The total number of people visiting all the pubs = 35 + 50 + 80 + 35 + 60 = 260

The ratio of males and females is 8:5,

So the total number of males and females is 160 and 100 respectively.

So the total number of females not charged with late fees in 2010 = (100 - 12.5)% of 160 = 87.5% of 160 = 140.

And the total number of females not charged with late fees in 2015 = (100 - 16)% of 100 = 84% of 100 = 84.

So the ratio of females not charged in 2010 and 2015 is 140:84 = 5:3.

Hence the required ratio is 5:3.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 769

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Direction: The line chart given below shows the number of people visiting 5 pubs in two years 2010 and 2015.

In 2015, the total number of males visiting pub C is thrice the difference between the total number of people visiting pubs A and B in the same year. Find the percentage by which the total number of females in pub C in year 2015 is more/less than the difference between the total number of people visiting pubs D and E in the year 2010.

  1. AOption (a)

    10%

  2. BOption (b)

    20%

  3. COption (c)

    33.33%

  4. DOption (d)

    30%

  5. EOption (e)

    50%

View answer & explanation

Correct answer

Answer: (d)D.

30%

Why this answer is correct

From the line chart:

Pubs20102015
A6035
B8050
C7080
D9035
E4060

In 2015,

The total number of people visiting pubs A and B is 35 and 50 respectively,

So the difference between the people is 50 - 35 = 15.

The total number of males visiting pub C is thrice the difference between the total number of people visiting pubs A and B in the same year,

So the total number of males visiting pub C = 3 x 15 = 45.

So the total number of females visiting pub C = 80 - 45 = 35.

the difference between the total number of people visiting pubs D and E in the year 2010 = 90 - 40 = 50.

So,

By ((50 - 35)/50) x 100 = 30%, the percentage of the total number of females in pub C is more/less than the difference between the total number of people visiting pubs D and E in the year 2010.

Hence by 30%, the percentage of the total number of females in pub C is more/less than the difference between the total number of people visiting pubs D and E in the year 2010.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 770

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Direction: The line chart given below shows the number of people visiting 5 pubs in two years 2010 and 2015.

Pub D charged extra fees for latecomers in the pub in the year 2015. If the total number of males visiting the pub is 2/5th of the total number of people visiting the same pub in the same year and 500/7% of males and 600/7% of females were charged with extra fines, find the total number of people who were not charged with extra fees?

  1. AOption (a)

    14

  2. BOption (b)

    7

  3. COption (c)

    21

  4. DOption (d)

    6

  5. EOption (e)

    1

View answer & explanation

Correct answer

Answer: (b)B.

7

Why this answer is correct

From the line chart:

Pubs20102015
A6035
B8050
C7080
D9035
E4060

In 2015,

The total number of people visiting Pub D is 35.

The total number of males visiting the pub is 2/5th of the total number of people visiting the same pub,

So the total number of males visiting the pub is 2/5 x 35 = 14,

and the total number of females visiting the pub is 3/5 x 35 = 21.

500/7% of males were charged with extra fines,

So the total number of males = 5/7 x 14 = 10,

and 600/7% of females were charged with extra fines,

So the total number of females charged with extra fines is 6/7 x 21 = 18,

So, the total number of people who were not charged with extra fees = (14 - 10) + (21 - 18) = 7.

Hence the total number of people who were on time were 7.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 771

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The table given below shows the number of students in two different streams (X and Y), % of students in X and % of students in Y in four different colleges.

Some value are missing.

CollegesTotal Students (X + Y)% of students in X% of students in Y
A96850%--
B--65%--
C--44%504
D900----

In college D, if the percentage range of students in X stream lies within 15 ≤ X < 30 and X is an even multiple by the sequence of 6 and 8 then find the number of students in stream Y in college D?

  1. AOption (a)

    714

  2. BOption (b)

    684

  3. COption (c)

    812

  4. DOption (d)

    582

  5. EOption (e)

    722

View answer & explanation

Correct answer

Answer: (b)B.

684

Why this answer is correct

X is an even number and in between 15 to 30 so the possible value of X = 16, 18, 20, 22, 24, 26, 28

Even multiple by the sequence of 6 and 8 = 24

So, according to even multiple % range of students in X = 24%

So, Y = 76%

Therefore, Number of students in Y stream = 900 × 76/100 = 684

Hence, correct answer is option 2.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 772

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The table given below shows the number of students in two different streams (X and Y), % of students in X and % of students in Y in four different colleges.

Some value are missing.

CollegesTotal Students (X + Y)% of students in X% of students in Y
A96850%--
B--65%--
C--44%504
D900----

If the total number of students in college Z is 3 times the number of students in X stream in college A and the number of students in stream Y in college Z is 3/4th of the total students in that college. Then find the average of total number of students in X stream in college Z and the number of students in stream Y in college A ?

  1. AOption (a)

    422.5

  2. BOption (b)

    250

  3. COption (c)

    340

  4. DOption (d)

    486.2

  5. EOption (e)

    423.5

View answer & explanation

Correct answer

Answer: (e)E.

423.5

Why this answer is correct

Total number of students in college Z = 3 × 968 × 50/100 = 1452

Total number of students In college Z in stream Y = 1452 × 3/4 = 1089

Total number of students In college Z in stream X = 1452 - 1089 = 363

Required Average = (363 + 484) / 2 = 423.5 

Hence, correct answer is option 5.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 773

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The table given below shows the number of students in two different streams (X and Y), % of students in X and % of students in Y in four different colleges.

Some value are missing.

CollegesTotal Students (X + Y)% of students in X% of students in Y
A96850%--
B--65%--
C--44%504
D900----

If the number of students in stream Y in college B is 78 more than 4 times the difference between total students in college A and D, then find the sum of total number of students in college C and the number of students in stream X in college B ?

  1. AOption (a)

    1004

  2. BOption (b)

    1440

  3. COption (c)

    1550

  4. DOption (d)

    1620

  5. EOption (e)

    1450

View answer & explanation

Correct answer

Answer: (c)C.

1550

Why this answer is correct

Total number of students in stream Y in college B = 4 × (968 - 900) + 78 = 350

  total number of students in college C = 504/56 × 100 = 900

 total number of students in college B in stream X = 350/35 × 65 = 650

Required Sum = 900 + 650 = 1550

Hence, correct answer is option 3.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 774

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The table given below shows the number of students in two different streams (X and Y), % of students in X and % of students in Y in four different colleges.

Some value are missing.

CollegesTotal Students (X + Y)% of students in X% of students in Y
A96850%--
B--65%--
C--44%504
D900----

If the ratio of the total number of students in stream Y in college D and total number of students in stream Y in college A is 3 : 4. Then find the number of students in stream Y in college B, which is 33.33 % more than the number of students in college D in stream X ?

  1. AOption (a)

    650

  2. BOption (b)

    716

  3. COption (c)

    560

  4. DOption (d)

    720

  5. EOption (e)

    810

View answer & explanation

Correct answer

Answer: (b)B.

716

Why this answer is correct

Total number of students in college D in stream Y = 484 × 3/4 = 363

So, Total number of students in college D in stream X = 900 - 363 = 537

Total number of students in college B in stream Y = 537 × 4/3 = 716

Hence, correct answer is option 2.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 775

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The table given below shows the number of students in two different streams (X and Y), % of students in X and % of students in Y in four different colleges.

Some value are missing.

CollegesTotal Students (X + Y)% of students in X% of students in Y
A96850%--
B--65%--
C--44%504
D900----

Find the average of all the students in all four colleges A, B, C and D in both (X and Y) streams. If the number of students in college B in stream Y is 25% less than the number of students in college C in stream Y.

  1. AOption (a)

    962

  2. BOption (b)

    822

  3. COption (c)

    920.5

  4. DOption (d)

    850

  5. EOption (e)

    900.3

View answer & explanation

Correct answer

Answer: (a)A.

962

Why this answer is correct

Total number of students in college B in stream Y = 504 × 75/100 = 378

So, total number of students in college B = 378/35 × 100 = 1080

Total number of students in college C = 504/56 × 100 = 900

Required Average = (968 + 900 + 1080 + 900) / 4 = 3848 / 4 = 962

Hence, correct answer is option 1.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 776

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information  carefully and answer based on it.

The data is given about 3 companies (A, B and C) on Monday to Friday in a week. On Monday and Tuesday A produced 20% and 25% respectively of the total production done by it on all the five days. The ratio of production by A on Friday and Thursday is 1:2. On Wednesday A produced 60 less than Friday. On Monday A produced 60 more than Friday. 2.5 times the production of A on Wednesday is 25% of total production of A on all the five days.

B produced total 2400 products on all five days and C produced 2/3rd of total production by B on all the five days. Out of the total production of B, it produced 15% of the total production each on Thursday and Friday. On Wednesday B produced 960 products. On Monday and Tuesday production of B is in the ratio of 1:2. Out of the total production of C, it produced 12% of the total production each on Tuesday and Wednesday. The sum of production of C on Thursday and Friday is 816 and the ratio of production of C on Thursday and Friday is 1:2.

Find the sum of production of A on Tuesday and B on Friday ?

  1. AOption (a)

    400

  2. BOption (b)

    660

  3. COption (c)

    590

  4. DOption (d)

    620

  5. EOption (e)

    540

View answer & explanation

Correct answer

Answer: (b)B.

660

Why this answer is correct

Let production by A on Friday = x and Thursday = 2x

Production by A on Wednesday = x - 60

Production by A on Monday = x + 60

x + 60 = 20% ...........(1)

So, x -60 + 2x + x = 55% (100% - 20% - 25%)

4x - 60 = 55% ....... (2) Solving equation 1 and 2, we get-

(x + 60) / (4x - 60) = 20% / 55%

(x + 60) / (4x - 60) = 4 / 11

So, x = 180

Production by A on Tuesday = ((180+ 60)/20%) × 25% = 300

Total Production by B = 2400

Total Production by C = 2/3 × 2400 = 1600

Production by B on Thursday = 2400 × 15/100 = 360

Production by B on Friday = 360

Production by B on Tuesday and Monday = (2400 - 960 - 360 - 360) = 720

Production by B on Monday = 720/3 × 1 = 240

Production by B on Tuesday = 720/3 × 2 = 480

Production by C on Wednesday = 1600 × 12/100 = 192

Production by C on Tuesday = 192

Production by C on Monday = 1600 - 192 - 192 - 816 = 400

Production by C on Thursday = 816 × 1/3 = 272

Production by C on Friday =  816 × 2/3 = 544

DaysABC
Monday240240400
Tuesday300480192
Wednesday120960192
Thursday360360272
Friday180360544

 

Required Sum = 300 + 360 = 660

Hence, correct answer is option 2.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 777

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information  carefully and answer based on it.

The data is given about 3 companies (A, B and C) on Monday to Friday in a week. On Monday and Tuesday A produced 20% and 25% respectively of the total production done by it on all the five days. The ratio of production by A on Friday and Thursday is 1:2. On Wednesday A produced 60 less than Friday. On Monday A produced 60 more than Friday. 2.5 times the production of A on Wednesday is 25% of total production of A on all the five days.

B produced total 2400 products on all five days and C produced 2/3rd of total production by B on all the five days. Out of the total production of B, it produced 15% of the total production each on Thursday and Friday. On Wednesday B produced 960 products. On Monday and Tuesday production of B is in the ratio of 1:2. Out of the total production of C, it produced 12% of the total production each on Tuesday and Wednesday. The sum of production of C on Thursday and Friday is 816 and the ratio of production of C on Thursday and Friday is 1:2.

What is the ratio of production of A on Friday and Monday together and the production B on Friday and Monday together ?

  1. AOption (a)

    5 : 8

  2. BOption (b)

    6 : 11

  3. COption (c)

    2 : 9

  4. DOption (d)

    7 : 10

  5. EOption (e)

    11 : 12

View answer & explanation

Correct answer

Answer: (d)D.

7 : 10

Why this answer is correct

Let production by A on Friday = x and Thursday = 2x

Production by A on Wednesday = x - 60

Production by A on Monday = x + 60

x + 60 = 20% ...........(1)

So, x -60 + 2x + x = 55% (100% - 20% - 25%)

4x - 60 = 55% ....... (2) Solving equation 1 and 2, we get-

(x + 60) / (4x - 60) = 20% / 55%

(x + 60) / (4x - 60) = 4 / 11

So, x = 180

Production by A on Tuesday = (180/20%) × 25% = 300

Total Production by B = 2400

Total Production by C = 2/3 × 2400 = 1600

Production by B on Thursday = 2400 × 15/100 = 360

Production by B on Friday = 360

Production by B on Tuesday and Monday = (2400 - 960 - 360 - 360) = 720

Production by B on Monday = 720/3 × 1 = 240

Production by B on Tuesday = 720/3 × 2 = 480

Production by C on Wednesday = 1600 × 12/100 = 192

Production by C on Tuesday = 192

Production by C on Monday = 1600 - 192 - 192 - 816 = 400

Production by C on Thursday = 816 × 1/3 = 272

Production by C on Friday =  816 × 2/3 = 544

DaysABC
Monday240240400
Tuesday300480192
Wednesday120960192
Thursday360360272
Friday180360544

Required Ratio = (180 + 240) / (360 + 240) = 420 / 600 = 7/10

Hence, correct answer is option 4.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 778

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information  carefully and answer based on it.

The data is given about 3 companies (A, B and C) on Monday to Friday in a week. On Monday and Tuesday A produced 20% and 25% respectively of the total production done by it on all the five days. The ratio of production by A on Friday and Thursday is 1:2. On Wednesday A produced 60 less than Friday. On Monday A produced 60 more than Friday. 2.5 times the production of A on Wednesday is 25% of total production of A on all the five days.

B produced total 2400 products on all five days and C produced 2/3rd of total production by B on all the five days. Out of the total production of B, it produced 15% of the total production each on Thursday and Friday. On Wednesday B produced 960 products. On Monday and Tuesday production of B is in the ratio of 1:2. Out of the total production of C, it produced 12% of the total production each on Tuesday and Wednesday. The sum of production of C on Thursday and Friday is 816 and the ratio of production of C on Thursday and Friday is 1:2.

If production of company C in Saturday increases by 16.66% from Tuesday and production of company B on Saturday decreases by 25% from Wednesday then find the sum of the production of company C and B on Saturday ?

  1. AOption (a)

    726

  2. BOption (b)

    875

  3. COption (c)

    944

  4. DOption (d)

    766

  5. EOption (e)

    926

View answer & explanation

Correct answer

Answer: (c)C.

944

Why this answer is correct

Let production by A on Friday = x and Thursday = 2x

Production by A on Wednesday = x - 60

Production by A on Monday = x + 60

x + 60 = 20% ...........(1)

So, x -60 + 2x + x = 55% (100% - 20% - 25%)

4x - 60 = 55% ....... (2) Solving equation 1 and 2, we get-

(x + 60) / (4x - 60) = 20% / 55%

(x + 60) / (4x - 60) = 4 / 11

So, x = 180

Production by A on Tuesday = (180/20%) × 25% = 300

Total Production by B = 2400

Total Production by C = 2/3 × 2400 = 1600

Production by B on Thursday = 2400 × 15/100 = 360

Production by B on Friday = 360

Production by B on Tuesday and Monday = (2400 - 960 - 360 - 360) = 720

Production by B on Monday = 720/3 × 1 = 240

Production by B on Tuesday = 720/3 × 2 = 480

Production by C on Wednesday = 1600 × 12/100 = 192

Production by C on Tuesday = 192

Production by C on Monday = 1600 - 192 - 192 - 816 = 400

Production by C on Thursday = 816 × 1/3 = 272

Production by C on Friday =  816 × 2/3 = 544

DaysABC
Monday240240400
Tuesday300480192
Wednesday120960192
Thursday360360272
Friday180360544

Production of company C on Saturday = 192 × 1/6 = 32 = 192 + 32 = 224

Production of company B on Saturday = 960 × 25/100 = 240 = 960 - 240 = 720

Total sum = 720 + 224 = 944

Hence, correct answer is option 3.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 779

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information  carefully and answer based on it.

The data is given about 3 companies (A, B and C) on Monday to Friday in a week. On Monday and Tuesday A produced 20% and 25% respectively of the total production done by it on all the five days. The ratio of production by A on Friday and Thursday is 1:2. On Wednesday A produced 60 less than Friday. On Monday A produced 60 more than Friday. 2.5 times the production of A on Wednesday is 25% of total production of A on all the five days.

B produced total 2400 products on all five days and C produced 2/3rd of total production by B on all the five days. Out of the total production of B, it produced 15% of the total production each on Thursday and Friday. On Wednesday B produced 960 products. On Monday and Tuesday production of B is in the ratio of 1:2. Out of the total production of C, it produced 12% of the total production each on Tuesday and Wednesday. The sum of production of C on Thursday and Friday is 816 and the ratio of production of C on Thursday and Friday is 1:2.

Find the average of total production by A on Thursday, total production by B on Tuesday, total production by C on Wednesday ?

  1. AOption (a)

    300

  2. BOption (b)

    248

  3. COption (c)

    225

  4. DOption (d)

    344

  5. EOption (e)

    322

View answer & explanation

Correct answer

Answer: (d)D.

344

Why this answer is correct

Let production by A on Friday = x and Thursday = 2x

Production by A on Wednesday = x - 60

Production by A on Monday = x + 60

x + 60 = 20% ...........(1)

So, x -60 + 2x + x = 55% (100% - 20% - 25%)

4x - 60 = 55% ....... (2) Solving equation 1 and 2, we get-

(x + 60) / (4x - 60) = 20% / 55%

(x + 60) / (4x - 60) = 4 / 11

So, x = 180

Production by A on Tuesday = (180/20%) × 25% = 300

Total Production by B = 2400

Total Production by C = 2/3 × 2400 = 1600

Production by B on Thursday = 2400 × 15/100 = 360

Production by B on Friday = 360

Production by B on Tuesday and Monday = (2400 - 960 - 360 - 360) = 720

Production by B on Monday = 720/3 × 1 = 240

Production by B on Tuesday = 720/3 × 2 = 480

Production by C on Wednesday = 1600 × 12/100 = 192

Production by C on Tuesday = 192

Production by C on Monday = 1600 - 192 - 192 - 816 = 400

Production by C on Thursday = 816 × 1/3 = 272

Production by C on Friday =  816 × 2/3 = 544

DaysABC
Monday240240400
Tuesday300480192
Wednesday120960192
Thursday360360272
Friday180360544

Required Average = (360 + 480 + 192) / 3 = 1032 / 3 = 344

Hence, correct answer is option 4.

SBI Clerk Mains Memory Based Paper (Held On: 15 Jan 2023 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 780

SBI Clerk 2023• Quantitative Aptitude• Quantitative Aptitude

Directions : Study the following information carefully and answer based on it.

The data given about number of articles sold by X, Y and Z in three different years 2016 to 2018. Total number of articles sold by X, Y and Z in 2018 is 430. Total number of articles sold in all three years by Y is 390 and that by Z is 158. Articles sold by Z in 2017 and 2018 are in the ratio of 6 : 11. The ratio of articles sold by X and Z in 2016 is 7 : 8. The number of articles sold by Z in 2016 is 20 more than the article sold by it in 2017. The number of articles sold by Y in 2018 is 5 times the number of articles sold by X in 2016. The number of articles sold by Y and Z in 2016 is 25 : 28. In 2017 X sold double the number of articles sold by it previous year.

Find the ratio of total number of articles of X in 2017  and total number of articles of Z in 2016 and 2018 together.

  1. AOption (a)

    55 : 63

  2. BOption (b)

    49 : 61

  3. COption (c)

    47 : 51

  4. DOption (d)

    42 : 53

  5. EOption (e)

    51 : 61

View answer & explanation

Correct answer

Answer: (b)B.

49 : 61

Why this answer is correct

Total number of articles sold by X, Y and Z in 2018 = 430 

Total number of articles sold in all three years by Y = 390

Total number of articles sold in all three years by Z = 158

Let, articles sold by Z in 2017 = 6x and Z in 2018 = 11x

Let, articles sold by X in 2016 = 7y and Z in 2016 = 8y

So, 8y = 6x + 20 ...............

(1) Y in 2018 = 7y × 5 = 35y

(articles sold by Y in 2016) / 8y = 25 / 28

So, articles sold by Y in 2016 = 200y/28 

X in 2017 = 14y

Now, 11x + 6x + 8y = 158

17x + 8y = 158 ................... (2) After solving equation 1 and 2, we get-

x = 6 and y = 7

YearsXYZ
2016495056
2017989536
201811924566
Total266390158

Required ratio = 98 / (56 + 66) = 98 / 122 = 49 / 61

Hence, correct answer is option 2.

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How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.