SBI Clerk · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 581–600 of 1495Page 30 of 75
SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 581

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions : The following line graph shows the number of employees (Officers + Assistant) working in five different companies A, B, C, D,  and E.

 

Number of officers working in company D and E is what percentage of total assistants working in all the companies A, B, C, D and E.

  1. AOption (a)

    56.7%

  2. BOption (b)

    53.6%

  3. COption (c)

    51.6%

  4. DOption (d)

    43.8%

  5. EOption (e)

    57.8%

View answer & explanation

Correct answer

Answer: (c)C.

51.6%

Why this answer is correct

Solution:

Number of officers working in D and E = (150 + 160) = 310

Total number of assistants working in all companies = (100 + 110 + 70 + 140 + 180) = 600

Required percentage = 310/600 × 100 = 51.6%

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 582

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions : The following line graph shows the number of employees (Officers + Assistant) working in five different companies A, B, C, D,  and E.

 

1/3rd of the officers working in Company C and 3/7th of the assistants working in company C are females. Find the number of males working in the company C.

  1. AOption (a)

    180

  2. BOption (b)

    100

  3. COption (c)

    120

  4. DOption (d)

    150

  5. EOption (e)

    80

View answer & explanation

Correct answer

Answer: (b)B.

100

Why this answer is correct

Solution:

Number of female officers working in company C = 90 × 1/3 = 30

Number of males officers working in company C = (90 - 30) = 60

Number of female assistants working in company C = 70 × 3/7 = 30

Number of male assistants working in company C = (70 - 30) = 40

Required sum = (60 + 40) = 100

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 583

SBI Clerk 2024• Numerical Ability• Numerical Ability

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, then find the number of valid votes that the other candidate got

  1. AOption (a)

    2500

  2. BOption (b)

    1700

  3. COption (c)

    2600

  4. DOption (d)

    2800

  5. EOption (e)

    2700

View answer & explanation

Correct answer

Answer: (e)E.

2700

Why this answer is correct

Shortcut Trick

Total Votes = 7500

Valid Votes = 80% of 7500 = 6000

Winner got 55% of valid votes → Loser got 45% of valid votes

Other candidate votes = 45% of 6000 = 0.45 × 6000 = 2700

∴ The correct answer is 2700.

Alternate Method

Given:

Total number of votes = 7500

Percentage of invalid votes = 20%

Calculations:

⇒ Percentage of valid votes = 100% − 20% = 80%

⇒ Total valid votes = 80% of 7500 = (80/100) × 7500 = 6000

⇒ One candidate got 55% of valid votes.

⇒ The other candidate got = 100% − 55% = 45% of valid votes

⇒ Number of votes for the other candidate = 45% of 6000

⇒ Other candidate votes = (45/100) × 6000 = 45 × 60 = 2700

∴ The correct answer is 2700.

Additional Information

Election Base Values

In election problems, winner/loser percentages are usually calculated on Valid Votes unless specified as a percentage of Total Votes.

Successive Percentage Method

Required Value = Total × (Valid % / 100) × (Required Candidate % / 100). Here: 7500 × 0.80 × 0.45 = 2700.

Majority Margin

The margin of victory is the difference between winner and loser votes: (55% − 45%) = 10% of valid votes.

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 584

SBI Clerk 2024• Numerical Ability• Numerical Ability

A and B invested their capitals in the ratio of 3 :

  1. After "x" months, A leaves and C joins with some capital. If they share the annual profit equally, then the capital invested by C was what % of the capital invested by A?
  1. AOption (a)

    50%

  2. BOption (b)

    40%

  3. COption (c)

    60%

  4. DOption (d)

    45%

  5. EOption (e)

    55%

View answer & explanation

Correct answer

Answer: (a)A.

50%

Why this answer is correct

Shortcut Trick

Ratio of Profit is Investment × Time.

Let A investment be 3 and B investment be 1.

Annual profit is shared equally, so Profit A = Profit B = Profit C.

Profit B = 1 × 12 = 12 units. Thus, Profit C = 12 units.

C joins after x months, so C stays for (12 − x) months. Also A stays for x months.

Profit A = 3 × x = 12 ⇒ x = 4. Time for C = 12 − 4 = 8 months.

Investment C × 8 = 12 ⇒ C = 1.5. % of A = (1.5 ÷ 3) × 100 = 50%.

∴ The correct answer is 50%.

Alternate Method

Given → Investment ratio A : B = 3 : 1, Annual profit ratio A : B : C = 1 : 1 : 1.
Formulas: Profit = Investment × Time | Investment = Profit ÷ Time.

⇒ Profit of B = 1 (investment) × 12 (months) = 12 units.
⇒ Since profits are equal, Profit of A = 12 units and Profit of C = 12 units.
⇒ For A: 3 × x = 12 ⇒ x = 4 months.
⇒ Time for C = 12 − x = 12 − 4 = 8 months.
⇒ Investment of C × 8 = 12 ⇒ Investment of C = 1.5 units.
⇒ Required % = (Investment of C ÷ Investment of A) × 100 = (1.5 ÷ 3) × 100 = 50%.

∴ The correct answer is 50%.

Additional Information

Partnership Ratio

In a partnership, the profit is distributed in the ratio of the product of capital and the time period for which the capital is invested.

Annual Profit Calculation

Annual profit implies a total time frame of 12 months. If a person joins after x months, their money is invested for (12 − x) months.

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 585

SBI Clerk 2024• Numerical Ability• Numerical Ability

An alloy contains silver, aluminium and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contain silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?

  1. AOption (a)

    10 kg

  2. BOption (b)

    15 kg

  3. COption (c)

    20 kg

  4. DOption (d)

    50 kg

  5. EOption (e)

    30 kg

View answer & explanation

Correct answer

Answer: (c)C.

20 kg

Why this answer is correct

Shortcut Trick

Initial Ratio of Silver : Aluminium : Copper = 5 : 4 : 7

Total units in initial mixture = 5 + 4 + 7 = 16 units

Given, 16 units = 320 kg → 1 unit = 20 kg

New Ratio = 5 : 4 : 8 (Only Copper units change from 7 to 8)

Change in Copper = 8 − 7 = 1 unit → 20 kg

∴ The correct answer is 20 kg.

Alternate Method

Given: Initial weight = 320 kg, Initial Ratio = 5 : 4 : 7, Final Ratio = 5 : 4 : 8

⇒ Sum of ratio parts = 5 + 4 + 7 = 16

⇒ Quantity of 1 unit = 320 ÷ 16 = 20 kg

⇒ Initial Copper = (7 ÷ 16) × 320 = 140 kg

⇒ In new alloy, Silver (100 kg) and Aluminium (80 kg) remain constant.

⇒ Ratio 5 : 4 : 8 matches the constant parts (5 units = 100 kg, 4 units = 80 kg).

⇒ New Copper quantity = 8 units × 20 kg = 160 kg

⇒ Copper added = 160 − 140 = 20 kg

∴ The correct answer is 20 kg.

Additional Information

Constant Part Rule

When one component is added to a mixture, the quantities (or ratios) of the other components must remain constant. If the ratio values differ, multiply by a factor to equalize them.

Ratio to Quantity Conversion

Total Quantity = (Sum of ratio parts) × (Value of 1 unit). This is the fastest way to map weights to ratio differences.

Alligation in Mixtures

For two-component mixtures, the Alligation rule (Quantity 1 / Quantity 2 = Difference 2 / Difference 1) can also be used to find addition amounts.

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 586

SBI Clerk 2024• Numerical Ability• Numerical Ability

A shopkeeper purchase some Onion of Rs. 200 per kg. 20% of Onion is rotten, At what price (per kg) should he sell the remaining Onion so as to earn a profit of 25% ?

  1. AOption (a)

    Rs. 340

  2. BOption (b)

    Rs. 312.5

  3. COption (c)

    Rs. 302.5

  4. DOption (d)

    Rs. 315

  5. EOption (e)

    Rs. 300

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 312.5

Why this answer is correct

Shortcut Trick

Let total quantity be 100 kg. Total CP = 100 × 200 = Rs. 20,000.

Desired SP = 20,000 × 1.25 = Rs. 25,000.

Remaining quantity = 80% of 100 = 80 kg.

Required SP per kg = 25,000 ÷ 80 = Rs. 312.5.

∴ The correct answer is Rs. 312.5.

Alternate Method

Given: CP = Rs. 200/kg, Rotten = 20%, Desired Profit = 25%.

Formulas: Total SP = Total CP × (100 + P%) ÷ 100 | Selling Price per kg = Total SP ÷ Available Quantity.

⇒ Let purchase be 1 kg. Total CP = Rs. 200.

⇒ Target Total Revenue = 200 × (125 ÷ 100) = Rs. 250.

⇒ Remaining usable weight = 1kg − (20% of 1kg) = 0.8 kg.

⇒ Selling Price per kg = 250 ÷ 0.8 = Rs. 312.5.

∴ The correct answer is Rs. 312.5.

Additional Information

Effective Cost Price

When goods are lost or rotten, the effective CP per unit increases. Effective CP = Total CP ÷ Net usable quantity.

Profit Calculation

Profit is always calculated on the initial Total Investment, regardless of how much quantity is lost or wasted during the process.

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 587

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following equation?

75% of 500 + 40% of 650 = ?

  1. AOption (a)

    625

  2. BOption (b)

    630

  3. COption (c)

    640

  4. DOption (d)

    635

  5. EOption (e)

    645

View answer & explanation

Correct answer

Answer: (d)D.

635

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

75% of 500 + 40% of 650 = ?

⇒ (75/100) × 500 + (40/100) × 650 = ?

⇒ 375 + 260 = ?

∴ ? = 635

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 588

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following question?

256 × 2-5 × ? = (2/25) of 50 × 75

  1. AOption (a)

    25

  2. BOption (b)

    37.5

  3. COption (c)

    22.5

  4. DOption (d)

    50

  5. EOption (e)

    16

View answer & explanation

Correct answer

Answer: (b)B.

37.5

Why this answer is correct

256 × 2-5 × ? = (2/25) of 50 × 75

⇒ 28 × 2-5 × ? = (2/25) of 50 × 75

⇒ 28 × 2-5 × ? = (2/25) ×  50 × 75

⇒ 28 × 2-5 × ? = 2 ×  2 × 75

⇒ 28/25 × ? = 4 × 75

⇒ 8 × ? = 4 × 75

⇒ ? = 75/2

⇒ ? = 37.5

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 589

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following question?

37% of 700 - 39% of 400 = ? - 31% of 300

  1. AOption (a)

    187

  2. BOption (b)

    168

  3. COption (c)

    196

  4. DOption (d)

    202

  5. EOption (e)

    205

View answer & explanation

Correct answer

Answer: (c)C.

196

Why this answer is correct

37% of 700 - 39% of 400 = ? - 31% of 300

⇒ 37 × 7 - 39 × 4 = ? - 31 × 3

As all unit digits in options are different, hence we can reach to answer by only calculating unit digits

⇒ 7 × 7 - 9 × 4 = ? - 1 × 3

⇒ ? = 9 - 6 + 3 = 6

Hence, answer will be 196

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 590

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following question?

150% of 220 + 83 + 10% of ? = 302

  1. AOption (a)

    58

  2. BOption (b)

    80

  3. COption (c)

    360

  4. DOption (d)

    580

  5. EOption (e)

    630

View answer & explanation

Correct answer

Answer: (d)D.

580

Why this answer is correct

150% of 220 + 83 + 10% of ? = 302

⇒ 330 + 512 + ?/10 = 900

⇒ ?/10 = 900 - 330 - 512

⇒ ?/10 = 58

⇒ ? = 580

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 591

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following question?

? + 308 - 25% of 4036 = 182

  1. AOption (a)

    325

  2. BOption (b)

    525

  3. COption (c)

    725

  4. DOption (d)

    1025

  5. EOption (e)

    1225

View answer & explanation

Correct answer

Answer: (d)D.

1025

Why this answer is correct

? + 308 - 25% of 4036 = 182​

⇒ ? + 308 - 4036/4 = 324

⇒ ? + 308 - 1009 = 324

⇒ ? = 1009 + 324 - 308

⇒ ? = 1025

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 592

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following question?

20% of (28 × 40) - √? = 156 × 30 ÷ 26

  1. AOption (a)

    144

  2. BOption (b)

    784

  3. COption (c)

    1296

  4. DOption (d)

    1936

  5. EOption (e)

    2116

View answer & explanation

Correct answer

Answer: (d)D.

1936

Why this answer is correct

20% of (28 × 40) - √? = 156 × 30 ÷ 26

⇒ 28 × 40/5 - √? = 6 × 30

⇒ 224 - √? = 180

⇒ √? = 224 - 180

⇒ √? = 44

⇒ ? = 1936

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 593

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following equation?

80 – 42 ÷ 14 – 19 × 3 = ?

  1. AOption (a)

    18

  2. BOption (b)

    12

  3. COption (c)

    15

  4. DOption (d)

    20

  5. EOption (e)

    25

View answer & explanation

Correct answer

Answer: (d)D.

20

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

80 – 42 ÷ 14 – 19 × 3 = ?

⇒ 80 – 3 – 19 × 3 = ?

⇒ 80 – 3 – 57 = ?

⇒ 80 – 60 = ?

∴ ? = 20

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 594

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of the question mark ‘?’ in the following question?

4532 ÷ √1936 + 524 ÷ 4 = ?

  1. AOption (a)

    210

  2. BOption (b)

    214

  3. COption (c)

    226

  4. DOption (d)

    234

  5. EOption (e)

    242

View answer & explanation

Correct answer

Answer: (d)D.

234

Why this answer is correct

Given:

4532 ÷ √1936 + 524 ÷ 4 = ?

Concept:

Calculation:

⇒ 4532 ÷ 44 + 131 = ?

⇒ 103 + 131 = ?

⇒ 234 = ?

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 595

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of the question mark ‘?’ in the following question?

√676 × 34 + 125 × 7 = ? - 41

  1. AOption (a)

    1500

  2. BOption (b)

    1600

  3. COption (c)

    1800

  4. DOption (d)

    2000

  5. EOption (e)

    2100

View answer & explanation

Correct answer

Answer: (c)C.

1800

Why this answer is correct

√676 × 34 + 125 × 7 = ? - 41

⇒ 26 × 34 + 125 × 7 = ? - 41

⇒ 884 + 875 = ? - 41

⇒ 1759 = ? - 41

⇒ ? = 1759 + 41 = 1800

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 596

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of the question mark ‘?’ in the following question?

(256 - 196 + 169 - 144) ÷ ? = 500

  1. AOption (a)

    0.17

  2. BOption (b)

    0.26

  3. COption (c)

    0.37

  4. DOption (d)

    0.47

  5. EOption (e)

    0.58

View answer & explanation

Correct answer

Answer: (a)A.

0.17

Why this answer is correct

Given:

(256 - 196 + 169 - 144) ÷ ? = 500

Concept used:

Calculation:

(256 - 196 + 169 - 144) ÷ ? = 500

⇒ (425 - 340) ÷ ? = 500

⇒ 85 ÷ ? = 500

⇒ ? = 0.17

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 597

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following equation?

65% of 400 + 35% of 600 = ?

  1. AOption (a)

    430

  2. BOption (b)

    510

  3. COption (c)

    450

  4. DOption (d)

    470

  5. EOption (e)

    490

View answer & explanation

Correct answer

Answer: (d)D.

470

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

65% of 400 + 35% of 600 = ?

⇒ 260 + 210 = ?

∴ ? = 470

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 598

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark (?) in the following equation?

40% of 600 + ∛729 – 132 = ?

  1. AOption (a)

    60

  2. BOption (b)

    120

  3. COption (c)

    80

  4. DOption (d)

    90

  5. EOption (e)

    50

View answer & explanation

Correct answer

Answer: (c)C.

80

Why this answer is correct

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

40% of 600 + ∛729 – 132 = ?

⇒ 240 + 9 – 169 = ?

⇒ 249 – 169 = ?

∴ ? = 80

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 599

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark ‘?’ in the following question?

24 × 16.67% + 36 × 11.11% + 42 × 14.28% = ?

  1. AOption (a)

    10

  2. BOption (b)

    12

  3. COption (c)

    14

  4. DOption (d)

    16

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (c)C.

14

Why this answer is correct

24 × 16.67% + 36 × 11.11% + 42 × 14.28% = ?

⇒ 24 × 1/6 + 36 × 1/9 + 42 × 1/7 = ?

⇒ 4 + 4 + 6 = ?

⇒ ? = 14

SBI Clerk Prelims Memory Based Paper (Held On: 11 January 2024 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 600

SBI Clerk 2024• Numerical Ability• Numerical Ability

What will come in place of question mark ‘?’ in the following question?

35 × 25 + 55 × 45 + 75 × 65 = ? × 5

  1. AOption (a)

    1220

  2. BOption (b)

    1330

  3. COption (c)

    1455

  4. DOption (d)

    1665

  5. EOption (e)

    1645

View answer & explanation

Correct answer

Answer: (e)E.

1645

Why this answer is correct

35 × 25 + 55 × 45 + 75 × 65 = ? × 5

⇒ (30 + 5)(30 - 5) + (50 + 5)(50 - 5) + (70 + 5)(70 - 5) = ? × 5

⇒ 302 - 52 + 502 - 52 + 702 - 52 = ? × 5

⇒ 900 - 25 + 2500 - 25 + 4900 - 25 = ? × 5

⇒ (900 + 2500 + 4900) - (25) × 3 = ? × 5

⇒ 8300 - 75 = ? × ?

⇒ ? = 8225/5 = 1645

How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.