SBI Clerk · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude

Showing questions 521–540 of 1495Page 27 of 75

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 521

SBI Clerk 2025• Numerical Ability• Numerical Ability

Read the following information carefully and answer the questions given below.

A school has three classes A, B and C. Class A has a total of 250 students, out of which 84% were present. The total number of students in Class B is 28% more than the total number of students in Class A, and 30 students were absent in Class B. The total number of absent students in Class A and Class B together is 70. The number of students present in Class C is 10 more than the number present in Class B, and 60 students were absent in Class C.

What is the total number of students in Class C?

AOption (a)
360
BOption (b)
330
COption (c)
340
DOption (d)
350
EOption (e)
320

View answer & explanation

Correct answer

360

Why this answer is correct

Common Calculation

Class A:

Given: Total = 250, Present = 84%

⇒ Present = 250 × (84 / 100) = 210

⇒ Absent = 250 − 210 = 40

∴ Total = 250, Present = 210, Absent = 40

Class B:

Given: Total = 28% more than Class A, Absent = 30

⇒ Total = 250 + (28 / 100) × 250 = 320

⇒ Present = 320 − 30 = 290

∴ Total = 320, Present = 290, Absent = 30

Class C:

Given: Present = 10 more than Class B, Absent = 60

⇒ Present = 290 + 10 = 300

⇒ Total = 300 + 60 = 360

∴ Total = 360, Present = 300, Absent = 60

Given:

Present students in Class B = 290, Absent students in Class C = 60

Formula Used:

Total Students = Present Students + Absent Students

Calculation:

⇒ Present students in Class C = 290 + 10 = 300

⇒ Total students in Class C = 300 + 60 = 360

∴ The correct answer is 360.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 522

SBI Clerk 2025• Numerical Ability• Numerical Ability

Read the following information carefully and answer the questions given below.

The number of absent students in Class A is what percent of the number of absent students in Class C?

AOption (a)
60%
BOption (b)
75%
COption (c)
72%
DOption (d)
66 2/3 %
EOption (e)
0.56

View answer & explanation

Correct answer

66 2/3 %

Why this answer is correct

Common Calculation

Class A:

Given: Total = 250, Present = 84%

⇒ Present = 250 × (84 / 100) = 210

⇒ Absent = 250 − 210 = 40

∴ Total = 250, Present = 210, Absent = 40

Class B:

Given: Total = 28% more than Class A, Absent = 30

⇒ Total = 250 + (28 / 100) × 250 = 320

⇒ Present = 320 − 30 = 290

∴ Total = 320, Present = 290, Absent = 30

Class C:

Given: Present = 10 more than Class B, Absent = 60

⇒ Present = 290 + 10 = 300

⇒ Total = 300 + 60 = 360

∴ Total = 360, Present = 300, Absent = 60

Given:

Absent students in Class A = 40, Absent students in Class C = 60

Formula Used:

Required Percentage = (Value / Base Value) × 100

Calculation:

⇒ Required Percentage = (40 / 60) × 100

⇒ Required Percentage = (2 / 3) × 100

⇒ Required Percentage = 66 2 / 3 %

∴ The correct answer is 66 2/3 %.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 523

SBI Clerk 2025• Numerical Ability• Numerical Ability

Read the following information carefully and answer the questions given below.

What is the total number of students present in all three classes together?

AOption (a)
820
BOption (b)
780
COption (c)
800
DOption (d)
760
EOption (e)
740

View answer & explanation

Correct answer

800

Why this answer is correct

Common Calculation

Class A:

Given: Total = 250, Present = 84%

⇒ Present = 250 × (84 / 100) = 210

⇒ Absent = 250 − 210 = 40

∴ Total = 250, Present = 210, Absent = 40

Class B:

Given: Total = 28% more than Class A, Absent = 30

⇒ Total = 250 + (28 / 100) × 250 = 250 + 70 = 320

⇒ Present = 320 − 30 = 290

∴ Total = 320, Present = 290, Absent = 30

Class C:

Given: Present = 10 more than Class B, Absent = 60

⇒ Present = 290 + 10 = 300

⇒ Total = 300 + 60 = 360

∴ Total = 360, Present = 300, Absent = 60

Given:

Students present in Class A = 210, Class B = 290, Class C = 300

Formula Used:

Total Present Students = Present in Class A + Present in Class B + Present in Class C

Calculation:

⇒ Total Present = 210 + 290 + 300

⇒ Total Present = 800

∴ The correct answer is 800.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 524

SBI Clerk 2025• Numerical Ability• Numerical Ability

Read the following information carefully and answer the questions given below.

What is the ratio of the total number of students in Class A to that in Class C?

AOption (a)
20 : 29
BOption (b)
25 : 36
COption (c)
5 : 7
DOption (d)
25 : 34
EOption (e)
22 : 25

View answer & explanation

Correct answer

25 : 36

Why this answer is correct

Common Calculation

Class A:

Given: Total = 250, Present = 84%

⇒ Present = 250 × (84 / 100) = 210

⇒ Absent = 250 − 210 = 40

∴ Total = 250, Present = 210, Absent = 40

Class B:

Given: Total = 28% more than Class A, Absent = 30

⇒ Total = 250 + (28 / 100) × 250 = 250 + 70 = 320

⇒ Present = 320 − 30 = 290

∴ Total = 320, Present = 290, Absent = 30

Class C:

Given: Present = 10 more than Class B, Absent = 60

⇒ Present = 290 + 10 = 300

⇒ Total = 300 + 60 = 360

∴ Total = 360, Present = 300, Absent = 60

Given:

Total students in Class A = 250

Total students in Class C = 360

Formula Used:

Ratio = Total students in Class A : Total students in Class C

Calculation:

⇒ Ratio = 250 : 360

⇒ Ratio = 25 : 36

∴ The correct answer is 25 : 36.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 525

SBI Clerk 2025• Numerical Ability• Numerical Ability

Read the following information carefully and answer the questions given below.

What is the average number of absent students in the three classes?

AOption (a)
40
BOption (b)
41 2/3
COption (c)
43 1/3
DOption (d)
45
EOption (e)
48

View answer & explanation

Correct answer

43 1/3

Why this answer is correct

Common Calculation

Class A:

Given: Total = 250, Present = 84%

⇒ Present = 250 × (84 / 100) = 210

⇒ Absent = 250 − 210 = 40

∴ Total = 250, Present = 210, Absent = 40

Class B:

Given: Total = 28% more than Class A, Absent = 30

⇒ Total = 250 + (28 / 100) × 250 = 250 + 70 = 320

⇒ Present = 320 − 30 = 290

∴ Total = 320, Present = 290, Absent = 30

Class C:

Given: Present = 10 more than Class B, Absent = 60

⇒ Present = 290 + 10 = 300

⇒ Total = 300 + 60 = 360

∴ Total = 360, Present = 300, Absent = 60

Given:

Absent students in Class A = 40

Absent students in Class B = 30

Absent students in Class C = 60

Formula Used:

Average = Sum of values / Total number of values

Calculation:

⇒ Total absent students = 40 + 30 + 60 = 130

⇒ Average absent students = 130 / 3

⇒ Average absent students = 43 1/3

∴ The correct answer is 43 1/3.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 526

SBI Clerk 2025• Numerical Ability• Numerical Ability

A started a business with an investment of Rs.13500 and B joined after y months with an investment of Rs.16000. At the end of the year, the profit ratio of A and B is 81: 56 respectively. Find the value of y.

AOption (a)
6
BOption (b)
5
COption (c)
4
DOption (d)
8
EOption (e)
7

View answer & explanation

Correct answer

Why this answer is correct

Solution:

Amount invested by A = Rs.13500

Amount invested by B = Rs.16000

A invested for 12 months and B invested for (12 – y) months

Let x = 12 − y

(13500 × 12)/ (16000 × x) = 81/56

((13500 × 12) × 56)/81 = (16000 × x)

112,000 = 16000 × x

7 = x

y = (12 – 7) = 5

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 527

SBI Clerk 2025• Numerical Ability• Numerical Ability

Rishi invested an amount of Rs. 14440 for two years at compound interest and recieved an amount of Rs. 16810 on maturity. what is the rate of interest.

AOption (a)
6.13%
BOption (b)
6.31%
COption (c)
7.13%
DOption (d)
7.89%
EOption (e)
7.5%

View answer & explanation

Correct answer

7.89%

Why this answer is correct

Shortcut Trick

For a 2-year period, the ratio of Amount (A) to Principal (P) is the square of the 1-year multiplier.

√(A/P) = √(16810/14440) = √(1681/1444) = 41/38

Interest for 1 unit of time = 41 − 38 = 3 units on 38 units.

Rate % = (3/38) × 100 = 150/19 ≈ 7.89%

∴ The correct answer is 7.89%.

Alternate Method

Given: Principal (P) = ₹14440, Amount (A) = ₹16810, Time (n) = 2 years.

Formula Used: A = P(1 + R/100)ⁿ

⇒ 16810 = 14440(1 + R/100)²

⇒ 16810 / 14440 = (1 + R/100)²

⇒ 1681 / 1444 = (1 + R/100)²

⇒ √(1681 / 1444) = 1 + R/100

⇒ 41 / 38 = 1 + R/100

⇒ R/100 = (41 / 38) − 1

⇒ R/100 = 3 / 38

⇒ R = 300 / 38 = 7.8947...

∴ The correct answer is 7.89%.

Additional Information

Compound Interest Formula

The amount A is calculated as A = P(1 + r/n)^nt, where P is principal, r is annual rate, and t is time in years.

Annual vs Half-Yearly Compounding

For half-yearly, the rate is halved (R/2) and the time period is doubled (2n). For quarterly, rate is R/4 and time is 4n.

Effective Rate of Interest

It is the actual interest rate earned over a year due to compounding: Effective Rate = (1 + r/n)ⁿ − 1.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 528

SBI Clerk 2025• Numerical Ability• Numerical Ability

The average age of A and B is 20 years. If A is replaced by C, the average age becomes 19 years, and if B is replaced by C, the average age becomes 21 years. Find the age of A.

AOption (a)
20 years
BOption (b)
22 years
COption (c)
18 years
DOption (d)
16 years
EOption (e)
None of these

View answer & explanation

Correct answer

22 years

Why this answer is correct

Given:

The average age of A and B is 20 years

The average age of B and C is 19 years

The average age of A and C is 21 years

Concept Used:

Average (A) = S/N

Where, S = sum of observations, and N = number of observations

Calculation:

The sum of the ages of A and B = 20 × 2 = 40 years

The sum of the ages of B and C = 19 × 2 = 38 years

The sum of the ages of A and C = 21 × 2 = 42 years

So, 2 × (A + B + C) = 120

Then, the total ages of A, B, and C = 120/2 = 60 years

Age of A = 60 - 38 = 22 years

∴ The correct answer is option 2

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 529

SBI Clerk 2025• Numerical Ability• Numerical Ability

A boat can go 68 km downstream and 52 km upstream in 8 hours. Also, it can go 65 km upstream and 34 km downstream in 7 hours. What is the speed of boat in km/hr ?

AOption (a)
30
BOption (b)
15
COption (c)
13
DOption (d)
17
EOption (e)
20

View answer & explanation

Correct answer

Why this answer is correct

Given:

A boat can go 68 km downstream and 52 km upstream in 8 hours

it can go 65 km upstream and 34 km downstream in 7 hours

Formula used:

Distance = Speed × Time

Speed of the boat = (Downstream + Upstream)/2

Calculation:

According to the question,

Let U and D be the upstream and downstream,

\(\frac{68}{D}+\frac{52}{U}=8 \) --------(1)

\(\frac{34}{D}+\frac{65}{U}=7 \) --------(2)

by performing this [(1) ÷ 4] - [(2) ÷ 2]

We get,

\(\frac{68}{4\times D}+\frac{52}{4 \times U} -\frac{34}{2 \times D}-\frac{65}{2 \times U} =\frac{8}{4} -\frac{7}{2} \)

\(\frac{17}{ D}+\frac{13}{U} -\frac{17}{ D}-\frac{32.5}{U} =2 -3.5\)

\(\frac{13}{U} -\frac{32.5}{U} =-1.5 \)

\( -\frac{19.5}{U} =-1.5 \)

U = 19.5/1.5

Upstream = 13 km/hr ------(3)

Substitute (3) in equation (1),

\(\frac{68}{D}+\frac{52}{13}=8 \)

\(\frac{68}{D}+4=8 \)

Downstream = 68/4

= 17 km/hr

Speed of boat = (17 + 13)/2

= 30/2

= 15 km/hr

Answer is 15.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 530

SBI Clerk 2025• Numerical Ability• Numerical Ability

In order to pass in exam a student required to get 540 minimum marks. Subham got 432 marks and was declared fail by 12%. What are the maximum aggregate marks a student can get in the examination?

AOption (a)
800
BOption (b)
300
COption (c)
900
DOption (d)
600
EOption (e)
None of these

View answer & explanation

Correct answer

900

Why this answer is correct

Given:

Minimum Aggregate marks to pass in the exam = 540

Marks obtained by Subham = 432

Formula:

Minimum passing marks = Subham’s marks + 12% of the total marks

Calculation:

Let the maximum or total marks = x

Subham failed by 12% marks

⇒ 12% of total marks = minimum passing marks – Subham’s marks

⇒ 12% of x = 540 – 432

⇒ (12/100) × x = 108

⇒ x = 108 × 100/12

⇒ x = 900

∴ Maximum aggregate or total marks is 900.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 531

SBI Clerk 2025• Numerical Ability• Numerical Ability

The table shows the number of employees in the HR, Sales and Marketing departments of three companies X, Y and Z.

Company	HR	Sales	Marketing
X	48	36	40
Y	40	32	44
Z	42	38	32

What is the total number of employees in the Sales department across all three companies X, Y and Z?

AOption (a)
100
BOption (b)
102
COption (c)
104
DOption (d)
106
EOption (e)
108

View answer & explanation

Correct answer

106

Why this answer is correct

Given:

Sales employees in Company X = 36

Sales employees in Company Y = 32

Sales employees in Company Z = 38

Formula Used:

Total Sales employees = Sales(X) + Sales(Y) + Sales(Z)

Calculation:

⇒ Total = 36 + 32 + 38

⇒ Total = 106

∴ The correct answer is 106.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 532

SBI Clerk 2025• Numerical Ability• Numerical Ability

The table shows the number of employees in the HR, Sales and Marketing departments of three companies X, Y and Z.

Company	HR	Sales	Marketing
X	48	36	40
Y	40	32	44
Z	42	38	32

What is the average number of employees in the Marketing department of companies X and Z?

AOption (a)
32
BOption (b)
34
COption (c)
36
DOption (d)
38
EOption (e)
40

View answer & explanation

Correct answer

Why this answer is correct

Given:

Marketing employees in Company X = 40

Marketing employees in Company Z = 32

Formula Used:

Average = (Marketing(X) + Marketing(Z)) / 2

Calculation:

⇒ Average = (40 + 32) / 2

⇒ Average = 72 / 2

⇒ Average = 36

∴ The correct answer is 36.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 533

SBI Clerk 2025• Numerical Ability• Numerical Ability

The table shows the number of employees in the HR, Sales and Marketing departments of three companies X, Y and Z.

Company	HR	Sales	Marketing
X	48	36	40
Y	40	32	44
Z	42	38	32

What is the difference between the total number of employees in the HR department and the total number of employees in the Marketing department, considering all three companies together?

AOption (a)
10
BOption (b)
12
COption (c)
14
DOption (d)
16
EOption (e)
18

View answer & explanation

Correct answer

Why this answer is correct

Given:

HR employees:

X = 48, Y = 40, Z = 42

Marketing employees:

X = 40, Y = 44, Z = 32

Formula Used:

Difference = Total HR employees − Total Marketing employees

Calculation:

⇒ Total HR employees = 48 + 40 + 42 = 130

⇒ Total Marketing employees = 40 + 44 + 32 = 116

⇒ Difference = 130 − 116 = 14

∴ The correct answer is 14.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 534

SBI Clerk 2025• Numerical Ability• Numerical Ability

The table shows the number of employees in the HR, Sales and Marketing departments of three companies X, Y and Z.

Company	HR	Sales	Marketing
X	48	36	40
Y	40	32	44
Z	42	38	32

The number of employees in the Marketing department of Company Y is what percent more than that of Company X?

AOption (a)
5%
BOption (b)
8%
COption (c)
10%
DOption (d)
12%
EOption (e)
15%

View answer & explanation

Correct answer

10%

Why this answer is correct

Given:

Marketing employees in Company Y = 44

Marketing employees in Company X = 40

Formula Used:

Percentage more = [(Value 1 − Value 2) / Value 2] × 100

Calculation:

⇒ Difference = 44 − 40 = 4

⇒ Percentage more = (4 / 40) × 100

⇒ Percentage more = (1 / 10) × 100 = 10%

∴ The correct answer is 10%.

SBI Clerk Prelims Memory Based Paper (Held On: 21 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability

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Question 535

SBI Clerk 2025• Numerical Ability• Numerical Ability

The table shows the number of employees in the HR, Sales and Marketing departments of three companies X, Y and Z.

Company	HR	Sales	Marketing
X	48	36	40
Y	40	32	44
Z	42	38	32

The number of employees in the HR department of Company X is what percent of the combined number of employees in the Sales department of Company Y and the Marketing department of Company Z? (Which ratio does this percentage correspond to?)

AOption (a)
65% (13:20)
BOption (b)
70% (7:10)
COption (c)
75% (3:4)
DOption (d)
80% (4:5)
EOption (e)
85% (17:20)

View answer & explanation

Correct answer

75% (3:4)

Why this answer is correct

Given:

Employees in HR of Company X = 48

Employees in Sales of Company Y = 32

Employees in Marketing of Company Z = 32

Formula Used:

Percentage = (Target Value / Reference Sum) × 100

Calculation:

⇒ Combined Reference Employees = 32 + 32 = 64

⇒ Required Percentage = (48 / 64) × 100

⇒ Required Ratio = 48 : 64 = 3 : 4

⇒ Required Percentage = (3 / 4) × 100 = 75%

∴ The correct answer is 75% (3:4).

SBI Clerk Prelims Memory Based Paper (Held On: 12 January 2024 Shift 1) (Previous Year Paper)·Numerical Ability

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Question 536

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions: Study the following directions shows the number of non vegetarian and number of vegetarians living in five different cities A, B, C D and E.

If 2/5^th of the vegetarians in city A and 1/4^th of the non vegetarians in city A are females then find the total number of male vegetarian and male non vegetarian in city A.

AOption (a)
1150
BOption (b)
950
COption (c)
1050
DOption (d)
850
EOption (e)
1100

View answer & explanation

Correct answer

1050

Why this answer is correct

Solution:

Number of female vegetarians = 750 ×2/5 = 300

Number of male vegetarians = 750 - 300 = 450

Number of female non vegetarians = 800 × 1/4 = 200

Number of male non vegetarians = 800 - 200 = 600

Require total = (600 + 450) = 1050

SBI Clerk Prelims Memory Based Paper (Held On: 12 January 2024 Shift 1) (Previous Year Paper)·Numerical Ability

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Question 537

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions: Study the following directions shows the number of non vegetarian and number of vegetarians living in five different cities A, B, C D and E.

40% of the vegetarians from city B and 33.33% of the non-vegetarians from city B are married and the remaining are unmarried then find a difference between unmarried non-vegetarians and unmarried vegetarians in city B.

AOption (a)
120
BOption (b)
80
COption (c)
90
DOption (d)
70
EOption (e)
100

View answer & explanation

Correct answer

Why this answer is correct

Solution:

Number of married vegetarians from city B = 850 × (40/100) = 340

Number of unmarried vegetarians from city B = 850 - 340 = 510

Number of married non-vegetarians from city B = 900 ×1/3 = 300

Number of unmarried non-vegetarians from city B = 900 - 300 = 600

Required difference = (600 - 510) = 90

SBI Clerk Prelims Memory Based Paper (Held On: 12 January 2024 Shift 1) (Previous Year Paper)·Numerical Ability

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Question 538

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions: Study the following directions shows the number of non vegetarian and number of vegetarians living in five different cities A, B, C D and E.

The average number of vegetarians in the city D , E and F is 700 and the average number of non vegetarians in the city D, E and F is 600. Find the total number of vegetarian and Non vegetarian in city F.

AOption (a)
1100
BOption (b)
1200
COption (c)
1250
DOption (d)
1000
EOption (e)
1300

View answer & explanation

Correct answer

1200

Why this answer is correct

Solution:

Total number of vegetarians in city D, E and F = 700 × 3 = 2100

Number of vegetarians in city D and E = (550 + 950) = 1500

Number of vegetarians in city F = (2100 - 1500) = 600

Total number of non vegetarians in city D, E and F = 600 × 3 = 1800

Number of non vegetarians in city D and E = (500 + 700) = 1200

Number of non vegetarians in city F = (1800 - 1200) = 600

Required total = (600 + 600) = 1200

SBI Clerk Prelims Memory Based Paper (Held On: 12 January 2024 Shift 1) (Previous Year Paper)·Numerical Ability

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Question 539

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions: Study the following directions shows the number of non vegetarian and number of vegetarians living in five different cities A, B, C D and E.

Find the ratio between the number of vegetarians in D and E to the number of non-vegetarians in C and D.

AOption (a)
5: 11
BOption (b)
7: 5
COption (c)
3: 5
DOption (d)
5: 4
EOption (e)
3: 2

View answer & explanation

Correct answer

5: 4

Why this answer is correct

Solution:

Number of vegetarians in city D = 550

Number of vegetarians in city E = 950

Number of non-vegetarians in C = 700

Number of non-vegetarians in D = 500

Required ratio = (950 + 550): (700 + 500) = 1500: 1200 = 5: 4

SBI Clerk Prelims Memory Based Paper (Held On: 12 January 2024 Shift 1) (Previous Year Paper)·Numerical Ability

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Question 540

SBI Clerk 2024• Numerical Ability• Numerical Ability

Directions: Study the following directions shows the number of non vegetarian and number of vegetarians living in five different cities A, B, C D and E.

Find the difference between the average number of vegetarians from all the cities and the average number of non vegetarians from all the cities.

AOption (a)
60
BOption (b)
70
COption (c)
30
DOption (d)
40
EOption (e)
50

View answer & explanation

Correct answer

Why this answer is correct

Solution:

Average number of vegetarians from all the cities = (750 + 850 + 650 + 550 + 950)/5 = 750

Average number of non vegetarians from all the cities = (800 + 900 + 700 + 500 + 700)/5 = 720

Required difference = (750 - 720) = 30

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How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.

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