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Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1495 Total Questions38 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 301–320 of 1495Page 16 of 75
SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 301

SBI Clerk 2025• Numerical Ability• Numerical Ability

The line graph given below shows the number of boys participating in a sports event on four different days of a week. Study the graph carefully and answer the following questions. 

If 20% of the boys participating on Monday and 30% of the boys participating on Wednesday were selected for the final round, then how many boys were not selected from these two days together?

  1. AOption (a)

    504

  2. BOption (b)

    528

  3. COption (c)

    582

  4. DOption (d)

    516

  5. EOption (e)

    540

View answer & explanation

Correct answer

Answer: (c)C.

582

Why this answer is correct

Boys not selected from Monday = 80% of 360 = 288

Boys not selected from Wednesday = 70% of 420 = 294

Total not selected = 288 + 294 = 582

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 302

SBI Clerk 2025• Numerical Ability• Numerical Ability

The line graph given below shows the number of boys participating in a sports event on four different days of a week. Study the graph carefully and answer the following questions. 

The number of boys participating on Sunday is what percentage less than the number of boys participating on Wednesday?

  1. AOption (a)

    35%

  2. BOption (b)

    40%

  3. COption (c)

    42.85%

  4. DOption (d)

    45%

  5. EOption (e)

    50%

View answer & explanation

Correct answer

Answer: (c)C.

42.85%

Why this answer is correct

Difference between the number of boys participating = 420 – 240 = 180

Required Percentage = (180/420) ×100 = 42.85%

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 303

SBI Clerk 2025• Numerical Ability• Numerical Ability

The ratio of A to B is 4 : 5 and the ratio of A to C is 4 : 6. If the sum of B and C is 66, find the sum of A and B.

  1. AOption (a)

    45

  2. BOption (b)

    48

  3. COption (c)

    54

  4. DOption (d)

    60

  5. EOption (e)

    50

View answer & explanation

Correct answer

Answer: (c)C.

54

Why this answer is correct

Shortcut Trick

Since A is common in both ratios and has the same value (4), we can combine them directly.

Ratio A : B : C = 4 : 5 : 6.

Sum of B + C = 5 + 6 = 11 units → 66. So, 1 unit = 6.

Sum of A + B = 4 + 5 = 9 units → 9 × 6 = 54.

∴ The correct answer is 54.

Alternate Method

Given:

Ratio A : B = 4 : 5

Ratio A : C = 4 : 6

Sum of B and C = 66

Calculations:

⇒ Since A is 4 in both ratios, A : B : C = 4 : 5 : 6

⇒ Let A = 4x, B = 5x, and C = 6x

⇒ B + C = 5x + 6x = 11x

⇒ 11x = 66

⇒ x = 66 ÷ 11 = 6

⇒ A + B = 4x + 5x = 9x

⇒ A + B = 9 × 6 = 54

∴ The correct answer is 54.

Additional Information

Combining Ratios

To combine ratios like A:B and B:C, make the common term (B) equal by multiplying the ratios by suitable constants.

Compound Ratio

The compound ratio of a:b and c:d is (ac):(bd), found by multiplying the corresponding terms.

Proportion Rule

If a:b = c:d, then the product of extremes equals the product of means: a × d = b × c.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 304

SBI Clerk 2025• Numerical Ability• Numerical Ability

A shopkeeper marks an article 50% above its cost price and then gives a discount of ₹360. If the difference between the cost price and the profit earned in this transaction is ₹960, find the cost price of the article.

  1. AOption (a)

    ₹1000

  2. BOption (b)

    ₹1200

  3. COption (c)

    ₹1500

  4. DOption (d)

    ₹900

  5. EOption (e)

    ₹1100

View answer & explanation

Correct answer

Answer: (b)B.

₹1200

Why this answer is correct

Shortcut Trick

Let Cost Price (CP) = 100x. Then Marked Price (MP) = 150x.

Selling Price (SP) = 150x − 360. Profit = SP − CP = 50x − 360.

Given: CP − Profit = 960 ⇒ 100x − (50x − 360) = 960.

50x + 360 = 960 ⇒ 50x = 600 ⇒ 100x = 1200.

∴ The correct answer is ₹1200.

Alternate Method

Given: Markup = 50%, Discount = ₹360, CP − Profit = ₹960.

Formula: Profit = SP − CP; SP = MP − Discount.

⇒ Let Cost Price (CP) = C.

⇒ Marked Price (MP) = 1.5C.

⇒ Selling Price (SP) = 1.5C − 360.

⇒ Profit (P) = (1.5C − 360) − C = 0.5C − 360.

⇒ According to the question: C − (0.5C − 360) = 960.

⇒ 0.5C + 360 = 960.

⇒ 0.5C = 600.

⇒ C = 600 ÷ 0.5 = 1200.

∴ The correct answer is ₹1200.

Additional Information

Marked Price and Discount

Marked Price is the price listed on the product. Discount is always calculated on the Marked Price: SP = MP × (100 − Discount%)/100.

Profit and Loss Basics

Profit = SP − CP. Profit percentage is always calculated on the Cost Price: Profit% = (Profit/CP) × 100.

Markup Percentage

Markup is the extra amount added to the CP to fix the MP. Markup% = [(MP − CP)/CP] × 100.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 305

SBI Clerk 2025• Numerical Ability• Numerical Ability

A and B enter into a partnership. A invests ₹X and B invests ₹2500. After 4 months, A withdraws 50% of his investment. At the end of the year, the profit is shared between A and B in the ratio 4 : 3. Find the value of X.

  1. AOption (a)

    ₹4000

  2. BOption (b)

    ₹5000

  3. COption (c)

    ₹6000

  4. DOption (d)

    ₹4500

  5. EOption (e)

    ₹5500

View answer & explanation

Correct answer

Answer: (b)B.

₹5000

Why this answer is correct

Shortcut Trick

Profit Ratio = (CapitalA × TimeA) : (CapitalB × TimeB)

A's effective investment = (X × 4) + (0.5X × 8) = 4X + 4X = 8X

B's effective investment = 2500 × 12 = 30000

Ratio 8X : 30000 = 4 : 3 ⇒ 2X : 7500 = 4 : 3 ⇒ X = 5000

∴ The correct answer is ₹5000.

Alternate Method

Given:

Investment of A = ₹X for 4 months, then 0.5X for 8 months.

Investment of B = ₹2500 for 12 months.

Profit Ratio A : B = 4 : 3.

Calculations:

⇒ Total investment of A = (X × 4) + (X/2 × 8) = 4X + 4X = 8X

⇒ Total investment of B = 2500 × 12 = 30000

⇒ Ratio of Profits = 8X / 30000 = 4 / 3

⇒ 8X × 3 = 30000 × 4

⇒ 24X = 120000

⇒ X = 120000 ÷ 24

⇒ X = 5000

∴ The correct answer is ₹5000.

Additional Information

Partnership Profit Sharing Rule

The profit shared between partners is directly proportional to the product of their capital and the time period for which the capital is invested: P1 : P2 = C1T1 : C2T2.

Variable Investment

If a partner changes their investment during the period, the total investment is calculated as the sum of (Amount × Duration) for each interval.

Active vs Sleeping Partner

An active partner may receive an additional commission or salary from the profit before the remaining profit is divided according to the investment ratio.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 306

SBI Clerk 2025• Numerical Ability• Numerical Ability

A person's monthly income is ₹45,000. He spends 10% on groceries, 20% on rent, and ₹3,500 on others. He saves the remaining amount. Find the difference between his monthly savings and his expenditure on groceries.

  1. AOption (a)

    ₹24,000

  2. BOption (b)

    ₹22,500

  3. COption (c)

    ₹23,500

  4. DOption (d)

    ₹25,000

  5. EOption (e)

    ₹23,000

View answer & explanation

Correct answer

Answer: (c)C.

₹23,500

Why this answer is correct

Shortcut Trick

Groceries = 10% of 45,000 = ₹4,500

Rent = 20% of 45,000 = ₹9,000

Savings = 45,000 − (4,500 + 9,000 + 3,500) = ₹28,000

Difference = Savings − Groceries = 28,000 − 4,500 = ₹23,500

∴ The correct answer is ₹23,500.

Alternate Method

Given:

Monthly Income = ₹45,000

Groceries = 10% | Rent = 20% | Others = ₹3,500

Calculations:

⇒ Expenditure on Groceries = 10/100 × 45,000 = ₹4,500

⇒ Expenditure on Rent = 20/100 × 45,000 = ₹9,000

⇒ Total Expenditure = 4,500 + 9,000 + 3,500 = ₹17,000

⇒ Monthly Savings = Total Income − Total Expenditure

⇒ Monthly Savings = 45,000 − 17,000 = ₹28,000

⇒ Required Difference = Savings − Groceries

⇒ Difference = 28,000 − 4,500 = ₹23,500

∴ The correct answer is ₹23,500.

Additional Information

Income and Expenditure Formula

Income = Expenditure + Savings. This fundamental identity is used to calculate any one missing component when the other two are known.

Percentage Calculation

To find x% of a value Y, use the formula: (x ÷ 100) × Y. For quick calculations, 10% is simply the value divided by 10.

Successive Percentage vs. Flat Percentage

If percentages are of the 'remaining' amount, use the multiplying factor method. If they are of the 'total' income, simply add the percentages together.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 307

SBI Clerk 2025• Numerical Ability• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

The number of students playing Cricket in Colleges B and C together is what percentage more than the number of students playing Football in Colleges A and D together? 

  1. AOption (a)

    12%

  2. BOption (b)

    18%

  3. COption (c)

    24%

  4. DOption (d)

    32%

  5. EOption (e)

    36%

View answer & explanation

Correct answer

Answer: (d)D.

32%

Why this answer is correct

Cricket players in B and C together = 300 + 360 = 660

Football players in A and D together = 180 + 320 = 500

Percentage increase = {660 – 500}/500 x 100) = 32%

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 308

SBI Clerk 2025• Numerical Ability• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

What is the average number of students playing Hockey in all the colleges?

  1. AOption (a)

    160

  2. BOption (b)

    170

  3. COption (c)

    180

  4. DOption (d)

    190

  5. EOption (e)

    200

View answer & explanation

Correct answer

Answer: (c)C.

180

Why this answer is correct

Total Hockey players = 120 + 160 + 200 + 240 = 720

Required Average = 720 ÷ 4 = 180

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 309

SBI Clerk 2025• Numerical Ability• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

What is the ratio between the number of students playing Cricket in College A and Football in College D?

  1. AOption (a)

    2:3

  2. BOption (b)

    3:4

  3. COption (c)

    4:5

  4. DOption (d)

    5:6

  5. EOption (e)

    6:7

View answer & explanation

Correct answer

Answer: (b)B.

3:4

Why this answer is correct

Cricket players in College A = 240

Football players in College D = 320

Required ratio = 240:320 = 3:4

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 310

SBI Clerk 2025• Numerical Ability• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

If 20% of Cricket players and 25% of Football players in College C participated in a competition, then what was the total number of participants from College C?

  1. AOption (a)

    120

  2. BOption (b)

    132

  3. COption (c)

    142

  4. DOption (d)

    152

  5. EOption (e)

    160

View answer & explanation

Correct answer

Answer: (c)C.

142

Why this answer is correct

Cricket players in College C = 360

No of players participated in competition = 20% of 360 = 72

Football players in College C = 280

No of players participated in competition = 25% of 280 = 70

Total participants = 72 + 70 = 142

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 311

SBI Clerk 2025• Numerical Ability• Numerical Ability

Study the following table carefully and answer the questions given below.

The table shows the number of students playing Cricket, Football and Hockey in four different colleges (A, B, C and D).

CollegeCricketFootballHockey
A240180120
B300240160
C360280200
D400320240

The sum of Cricket and Hockey players in College B is how much more than the sum of Football and Hockey players in College A?

  1. AOption (a)

    120

  2. BOption (b)

    140

  3. COption (c)

    160

  4. DOption (d)

    180

  5. EOption (e)

    200

View answer & explanation

Correct answer

Answer: (c)C.

160

Why this answer is correct

Cricket + Hockey players in College B = 300 + 160 = 460

Football + Hockey players in College A = 180 + 120 = 300

Required difference = 460 – 300 = 160

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 312

SBI Clerk 2025• Numerical Ability• Numerical Ability

A person invests ₹20,000 at 10% per annum compound interest for 2 years in Scheme 1, and separately invests ₹20,000 at 10% per annum compound interest for 3 years in Scheme 2. Find the total compound interest earned from both schemes.

  1. AOption (a)

    ₹10,000

  2. BOption (b)

    ₹9,800

  3. COption (c)

    ₹10,820

  4. DOption (d)

    ₹11,000

  5. EOption (e)

    ₹10,620

View answer & explanation

Correct answer

Answer: (c)C.

₹10,820

Why this answer is correct

Shortcut Trick

Effective rate for 2 years at 10% = 10 + 10 + (10 × 10)/100 = 21%

Effective rate for 3 years at 10% = 33.1%

Total Interest % = 21% + 33.1% = 54.1% of Principal

Total Interest = 54.1% × 20,000 = 54.1 × 200 = ₹10,820

∴ The correct answer is ₹10,820.

Alternate Method

Given: Principal (P) = ₹20,000, Rate (R) = 10%

Formula Used: CI = P[(1 + R/100)n − 1]

⇒ CI1 = 20,000 × [(1 + 10/100)2 − 1]

⇒ CI1 = 20,000 × [1.21 − 1] = 20,000 × 0.21 = ₹4,200

⇒ CI2 = 20,000 × [(1 + 10/100)3 − 1]

⇒ CI2 = 20,000 × [1.331 − 1] = 20,000 × 0.331 = ₹6,620

⇒ Total CI = 4,200 + 6,620 = ₹10,820

∴ The correct answer is ₹10,820.

Additional Information

Successive Percentage Rule

For two years, the effective rate of interest is calculated as x + y + (xy/100).

Compound Interest vs Simple Interest

Difference for 2 years = P(R/100)2. Difference for 3 years = P(R/100)2 × (3 + R/100).

Amount Formula

Total Amount (A) = P(1 + R/100)n, where n is the number of years.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 313

SBI Clerk 2025• Numerical Ability• Numerical Ability

A car covers a distance of 480 km in 8 hours. A bike travels for 6 hours and covers 60 km less than the car. Find the respective ratio of the speed of the car to the speed of the bike.

  1. AOption (a)

    2 : 1

  2. BOption (b)

    6 : 7

  3. COption (c)

    4 : 3

  4. DOption (d)

    5 : 3

  5. EOption (e)

    3 : 1

View answer & explanation

Correct answer

Answer: (b)B.

6 : 7

Why this answer is correct

Shortcut Trick

Car's speed = 480 ÷ 8 = 60 km/h

⇒ Bike's distance = 480 − 60 = 420 km

⇒ Bike's speed = 420 ÷ 6 = 70 km/h

⇒ Required ratio = 60 : 70 = 6 : 7

∴ The respective ratio of the speed of the car to the bike is 6 : 7.

Alternate Method

Given:

Car: Distance = 480 km, Time = 8 hours

Bike: Time = 6 hours, Distance = 60 km less than car

Formula Used:

Speed = Distance ÷ Time

Calculations:

⇒ Car's speed = 480 ÷ 8 = 60 km/h

⇒ Bike's distance = 480 − 60 = 420 km

⇒ Bike's speed = 420 ÷ 6 = 70 km/h

⇒ Car : Bike = 60 : 70

⇒ = 6 : 7

∴ The respective ratio of the speed of the car to the bike is 6 : 7.

SBI Clerk Prelims Memory Based Paper (Held On: 20 September 2025 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 314

SBI Clerk 2025• Numerical Ability• Numerical Ability

The area of a triangle is 80 cm². The ratio of its base to height is 5 : 4. If the length of the base of the triangle is equal to the side of a square, find the area of the square.

  1. AOption (a)

    100 cm²

  2. BOption (b)

    200 cm²

  3. COption (c)

    144 cm²

  4. DOption (d)

    160 cm²

  5. EOption (e)

    225 cm²

View answer & explanation

Correct answer

Answer: (b)B.

200 cm²

Why this answer is correct

Shortcut Trick

Let Base = 5x and Height = 4x.

Area = 1/2 × 5x × 4x = 10x2 = 80 cm2.

⇒ x2 = 8 ⇒ x = √8.

Base = 5√8 cm = Side of Square.

Area of Square = (5√8)2 = 25 × 8 = 200 cm2.

∴ The correct answer is 200 cm2.

Alternate Method

Given:

Area of Triangle = 80 cm2

Ratio of Base : Height = 5 : 4

Formula Used:

Area of Triangle = 1/2 × Base × Height

Area of Square = (Side)2

Calculations:

⇒ Let Base = 5x and Height = 4x

⇒ 1/2 × 5x × 4x = 80

⇒ 10x2 = 80

⇒ x2 = 8

⇒ x = √8

⇒ Base of triangle = 5 × √8 = 5√8 cm

⇒ Side of square = Base of triangle = 5√8 cm

⇒ Area of square = (5√8)2

⇒ Area of square = 25 × 8 = 200 cm2

∴ The correct answer is 200 cm2.

Additional Information

Area of Triangle

The general formula is 1/2 × base × height. For an equilateral triangle, Area = (√3/4) × side2.

Square Properties

Area = side2 or 1/2 × diagonal2. Perimeter = 4 × side.

Heron's Formula

Used when all three sides (a, b, c) are known: Area = √[s(s−a)(s−b)(s−c)], where s = (a+b+c)/2.

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How should I prepare for Quantitative Aptitude in SBI Clerk?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.