Reasoning PYQs

1. D sits adjacent to R.

2. R has only one neighbour.

3. Only two persons sit between M and D. 

4. B sits third to the left of M. Therefore, case 1 is eliminated.

5. Four persons sit between Z and B.

6. Q sits two places away from O and adjacent to Z.

7. Three persons sit between O and F.

8. O sits second position from the end position. Therefore, case 2(a) is eliminated.

9. Not more than one person sits between Q and F. Hence, the final arrangement is as follows

Since, Q sits immediate right to Z not left. Therefore, statement first is incorrect.

More than two persons sit to the right of F. Therefore, statement second is incorrect.

R sits extreme right end not left end. Therefore, statement third is incorrect.

O sits second from the left end. Therefore, statement fourth is correct. 

Hence, the correct statement is O sits second from the left end.

1. D sits adjacent to R.

2. R has only one neighbour.

3. Only two persons sit between M and D. 

4. B sits third to the left of M. Therefore, case 1 is eliminated.

5. Four persons sit between Z and B.

6. Q sits two places away from O and adjacent to Z.

7. Three persons sit between O and F.

8. O sits second position from the end position. Therefore, case 2(a) is eliminated.

9. Not more than one person sits between Q and F. Hence, the final arrangement is as follows

Hence, B sits second to the right of F.

Consider series: 6 6 2 6 6 6 2 2 5 5 6 2 2 2 4 6 6 4 4 2 2 5 6 6 6 5 5 4 4 2 2

Hence, only three times 2 is preceded by 6 in the series.

Consider series: 6 6 2 6 6 6 2 2 5 5 6 2 2 2 4 6 6 4 4 2 2 5 6 6 6 5 5 4 4 2 2

the two 5’s are followed by 6 in the series.

Consider series: 6 6 2 6 6 6 2 2 5 5 6 2 2 2 4 6 6 4 4 2 2 5 6 6 6 5 5 4 4 2 2

5 pairs of 2’s and 4’s are added

Original frequency of 6’s are 11

Hence the total frequency of 6’s are: 16

Consider series: 6 6 2 6 6 6 2 2 5 5 6 2 2 2 4 6 6 4 4 2 2 5 6 6 6 5 5 4 4 2 2

In 2 2 2 there are 2 consecutive pairs of 2’s together

hence total number of consecutive pairs of 2 are 5.

Consider series: 6 6 2 6 6 6 2 2 5 5 6 2 2 2 4 6 6 4 4 2 2 5 6 6 6 5 5 4 4 2 2

Number of 6’s: 11

Number of 2’s: 10

Number of 4’s: 5

Number of 5’s: 5

thus 6 has highest frequency.

The logic followed here is:-

Thus, out of all the options, 'MPSV' is the odd one out as the common difference between the position value according to the English alphabet

​Hence, "MPSV" is the correct answer.

Here, boxes are A, B, C, D, E, F, G and H.

1. Four boxes are placed between Box A and Box E which is placed below the box A.

2. Box G is above Box A.

3. Box F is placed four boxes above Box E.  

 

4. Three boxes are placed between Box G and Box B which is placed just above Box D.

5. Box C is below the box H.

6. Box H is below the box A. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, Box H is placed two boxes above the box D.

Here, boxes are A, B, C, D, E, F, G and H.

1. Four boxes are placed between Box A and Box E which is placed below the box A.

2. Box G is above Box A.

3. Box F is placed four boxes above Box E.  

 

4. Three boxes are placed between Box G and Box B which is placed just above Box D.

5. Box C is below the box H.

6. Box H is below the box A. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, two boxes are placed between Box B and Box C.

Here, boxes are A, B, C, D, E, F, G and H.

1. Four boxes are placed between Box A and Box E which is placed below the box A.

2. Box G is above Box A.

3. Box F is placed four boxes above Box E.  

 

4. Three boxes are placed between Box G and Box B which is placed just above Box D.

5. Box C is below the box H.

6. Box H is below the box A. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, Box A is placed just below Box G. Therefore, statement A is incorrect.

No box is placed below the Box C. Therefore, statement B is incorrect.

Three boxes are placed above Box H. Therefore, statement C is correct.

Hence, the incorrect statements are Both A and B.

Here, boxes are A, B, C, D, E, F, G and H.

1. Four boxes are placed between Box A and Box E which is placed below the box A.

2. Box G is above Box A.

3. Box F is placed four boxes above Box E.  

 

4. Three boxes are placed between Box G and Box B which is placed just above Box D.

5. Box C is below the box H.

6. Box H is below the box A. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, two boxes are placed above the box F and two boxes are placed below the box D.

Hence, the correct answer is Box D.

Here, boxes are A, B, C, D, E, F, G and H.

1. Four boxes are placed between Box A and Box E which is placed below the box A.

2. Box G is above Box A.

3. Box F is placed four boxes above Box E.  

 

4. Three boxes are placed between Box G and Box B which is placed just above Box D.

5. Box C is below the box H.

6. Box H is below the box A. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, Box H is placed four boxes above the Box C and Box D is placed two boxes below the Box H.

Hence, the correct answer is Box D.

**Given

Statements:

** N ≤ Q; M > B; Q = R < O < M

Combining: N ≤ Q = R < O < M > B

Conclusions:

I. N < O → True (as N ≤ Q = R < O → N < O)

II. Q ≤ M → False (as N ≤ Q = R < O < M → Q < M, thus Q ≤ M cannot be true)

Hence, only conclusion I follows.

**Given

Statements:

** A ≥ C ≥ D > G = I ≥ B; S ≥ M > B

Combining:  A ≥ C ≥ D > G = I ≥ B < M ≤ S

Conclusions:

I. C ≥ M → False (as C ≥ D > G = I ≥ B < M → no clear relation between C and M can be determined)

II. A > I → True (as A ≥ C ≥ D > G = I → A > I)

Hence, only conclusion II follows.

**Given

Statements:

** G < L; D ≥ G; H = L; H ≤ B

Combining: D ≥ G < L = H ≤ B

Conclusions:

I. G > B → False (as G < L = H ≤ B → G > B cannot be true)

II. B > D → False (as D ≥ G < L = H ≤ B → no relation between B and D can be determined)

Hence, neither conclusion I nor conclusion II follows.

Here, persons are S, T, U, V, W, X, Y and Z.

1. W sits third to the left of S.

2. X sits fifth to the right of T.

3. W sits immediate right of T.

4. V sits adjacent to X and Z.

5. Z sits four places away from U.

6. Y does not face towards the center. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Hence, W sits second to the left of Z.

Here, persons are S, T, U, V, W, X, Y and Z.

1. W sits third to the left of S.

2. X sits fifth to the right of T.

3. W sits immediate right of T.

4. V sits adjacent to X and Z.

5. Z sits four places away from U.

6. Y does not face towards the center. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Since, S sits opposite to T and W sits opposite to  X therefore, in the same way V sits opposite to Y.

Hence, the correct answer is Y.

Here, persons are S, T, U, V, W, X, Y and Z.

1. W sits third to the left of S.

2. X sits fifth to the right of T.

3. W sits immediate right of T.

4. V sits adjacent to X and Z.

5. Z sits four places away from U.

6. Y does not face towards the center. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Since, S and T faces away from the center. Therefore, statement A is incorrect.

W sits immediate left to Y. Therefore, statement B is incorrect.

Z faces towards the center.Therefore, statement C is incorrect.

Hence, the correct answer is None of these.

Here, persons are S, T, U, V, W, X, Y and Z.

1. W sits third to the left of S.

2. X sits fifth to the right of T.

3. W sits immediate right of T.

4. V sits adjacent to X and Z.

5. Z sits four places away from U.

6. Y does not face towards the center. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

Hence, only two persons sit between Z and Y, when counted from the left of Y.