Reasoning PYQs

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

 

AFTER INTERCHANGING:

 

If W and B interchange their position, then D lives immediately below B.

Hence, D is the correct option.

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

Hence, D lives below the floor on which W lives is true.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

So, in the above series only one symbol is immediately followed by a consonant and preceded by vowel i.e. O@P

Hence, one is the correct answer$

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

If all symbols are removed from the given series, we get

Left side N T I A J B B U A R Q D L O P T F Right side

Hence, 9^th from the right end is A

Hence, A is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

5^th to left + 7^th from the right = 12^th from the right i.e. A

Hence, A is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D &L O @ P T ! F Right side

There are two vowels which are immediately followed and immediately preceded by a letter i.e. I A ^ and L O @

Hence, two is the correct answer$.

Left side N T * I A ^ $ J # B * B U A R Q D & L O @ P T ! F Right side

If all symbols are replaced with a digit 5 then-new series is

N T 5 I A 5 5 J 5 B 5 B U A R Q D 5 L O 5 P T 5 F

Hence, there are six 5’s in the new series each of which is followed by a consonant.

Confusion Points There are eight symbol which changed to 5. After that condition is given that we have to make the pair of 5 - Consonant. so such type of Six pair are there$.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Hence, B scores second highest in the group.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Here either C or E is the second lowest scorer.

Hence, either option 1 or option 2 is the correct answer.

1) F is the third highest score in the group and has scored 56 marks. 

2)  D is the highest scorer in the group.

D > _____ > F (56) > _____ > _____ > _____

3) B scores the second highest mark. 

4) Marks of F is less than  D.

5) A scores fewer marks than C and E.

D > B > F (56) > C/E > C/E > A

Here either C or E is the second-lowest scorer.

If sum of F and B marks is 116 then marks of B = 116  - 56  = 60.

So the possible mark of D is 62

Hence, the Possible mark of D is 62.

According to the given information,

1. Two boxes are placed between V and Z, which is kept at an odd number position above V.

 

2. Three boxes are kept between Z and W. 3. Two boxes are kept between A and W.

 

4. B is kept immediately above U, which is not kept above V. Here case - 2 gets eliminated.

The only box left will be C, so it will be kept at 5^th place from the bottom.

 

Hence, W is the correct answer.

According to the given information,

1. Two boxes are placed between V and Z, which is kept at an odd number position above V.

 

2. Three boxes are kept between Z and W. 3. Two boxes are kept between A and W.

 

4. B is kept immediately above U, which is not kept above V. Here case - 2 gets eliminated.

The only box left will be C, so it will be kept at 5^th place from the bottom.

 

Hence, V is the correct answer.

According to the given information,

1. Two boxes are placed between V and Z, which is kept at an odd number position above V.

 

2. Three boxes are kept between Z and W. 3. Two boxes are kept between A and W.

 

4. B is kept immediately above U, which is not kept above V. Here case - 2 gets eliminated.

The only box left will be C, so it will be kept at 5^th place from the bottom.

 

Hence, Four is the correct answer.

According to the given information,

1. Two boxes are placed between V and Z, which is kept at an odd number position above V.

 

2. Three boxes are kept between Z and W. 3. Two boxes are kept between A and W.

 

4. B is kept immediately above U, which is not kept above V. Here case - 2 gets eliminated.

The only box left will be C, so it will be kept at 5^th place from the bottom.

 

Hence, Z is the correct answer.

According to the given information,

1. Two boxes are placed between V and Z, which is kept at an odd number position above V.

 

2. Three boxes are kept between Z and W. 3. Two boxes are kept between A and W.

 

4. B is kept immediately above U, which is not kept above V. Here case - 2 gets eliminated.

The only box left will be C, so it will be kept at 5^th place from the bottom.

 

 

Here two boxes B and Z remain in the same position.

Hence, Two is the correct answer.

Given

Statements:

H ≤ G ≤ J ≥ L >A >Q = Y < R

Conclusions:

I. J > Q → True (as J ≥ L >A >Q → its clear J > Q)

II. Q < R → True (as Q = Y < R → its clear Q < R)

Hence, both conclusions I and II follow.

Given

Statements:

F < H ≤ L; L < J ≤ S < A

On combining: F < H ≤ L < J ≤ S < A

Conclusions:

I. S > F → True (as F < H ≤ L < J ≤ S → therefore S > F)

II. A < H → False (as H ≤ L < J ≤ S < A → therefore H < A)

Hence, only conclusion I is True.

Given

Statements:

R < O ≤ L ≤ E; G = E ≥ S ≥ P

On combining: R < O ≤ L ≤ E = G  ≥ S ≥ P

Conclusions:

I. R < S → False (as R < O ≤ L ≤ E = G  ≥ S → relation can’t be determined)

II. O ≤ G → True (as O ≤ L ≤ E = G → therefore O ≤ G)

Hence, only conclusion II is True.

Given

Statements:

P > Q = R ≥ S; T ≥ U ≤ V = S

On combining:  P > Q = R ≥ S = V ≥ U ≤ T

Conclusions:

I. V = R → False (as R ≥ S = V → therefore V ≤ R)

II. V < R → False (as R ≥ S = V → therefore V ≤ R)

Note:

Conclusion I and II are complementary pair.

Hence, either conclusion I or II is True.

Given:

Word - ASSESSMENT

Changing each consonant of the word to its next letter and each vowel of the word with the previous letter of the English alphabetic series. we get,

 

Now, the seventh from the right is D.

Hence, the correct answer is D.