Reasoning PYQs

Eight persons - Paro, Runa, Sona, Kim, Harry, Ram, Geet and Monu

1. Harry goes in the month of August.

2. Sona goes in the month which has odd number of days.

3. Geet goes just after the month in which Sona goes.

4. Three persons goes between Monu and Sona.

Case 1:

 

Case 2:

 

Case 3:

 

5. Runa goes in the month which has even number of days but not in February.

6. Two persons goes between Kim and Ram, who does not go in the month which have odd number of days.

7. Ram does not go in February.

8. Paro does not go after Kim.

Case 1a:

 

In this case, Paro goes after Kim. Hence, this case fails to satisfy the requirement.

Case 1b:

 

In this case, all conditions became satisfied.

Case 2a:

 

In this case there is no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 3a:

 

 

In this case, no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 1b:

 

Case 1b is the correct solution of this puzzle.

Hence, Paro goes in the month of March.

Eight persons - Paro, Runa, Sona, Kim, Harry, Ram, Geet and Monu

1. Harry goes in the month of August.

2. Sona goes in the month which has odd number of days.

3. Geet goes just after the month in which Sona goes.

4. Three persons goes between Monu and Sona.

Case 1:

 

Case 2:

 

Case 3:

 

5. Runa goes in the month which has even number of days but not in February.

6. Two persons goes between Kim and Ram, who does not go in the month which have odd number of days.

7. Ram does not go in February.

8. Paro does not go after Kim.

Case 1a:

 

In this case, Paro goes after Kim. Hence, this case fails to satisfy the requirement.

Case 1b:

 

In this case, all conditions became satisfied.

Case 2a:

 

In this case there is no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 3a:

 

In this case, no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 1b:

 

Hence, Three persons goes between Geet and Runa.

Eight persons - Paro, Runa, Sona, Kim, Harry, Ram, Geet and Monu

1. Harry goes in the month of August.

2. Sona goes in the month which has odd number of days.

3. Geet goes just after the month in which Sona goes.

4. Three persons goes between Monu and Sona.

Case 1:

 

Case 2:

 

Case 3:

 

5. Runa goes in the month which has even number of days but not in February.

6. Two persons goes between Kim and Ram, who does not go in the month which have odd number of days.

7. Ram does not go in February.

8. Paro does not go after Kim.

Case 1a:

 

In this case, Paro goes after Kim. Hence, this case fails to satisfy the requirement.

Case 1b:

 

In this case, all conditions became satisfied.

Case 2a:

 

In this case there is no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 3a:

 

In this case, no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 1b:

 

Hence, in May Monu goes on holiday.

Eight persons - Paro, Runa, Sona, Kim, Harry, Ram, Geet and Monu

1. Harry goes in the month of August.

2. Sona goes in the month which has odd number of days.

3. Geet goes just after the month in which Sona goes.

4. Three persons goes between Monu and Sona.

Case 1:

 

Case 2:

 

Case 3:

 

5. Runa goes in the month which has even number of days but not in February.

6. Two persons goes between Kim and Ram, who does not go in the month which have odd number of days.

7. Ram does not go in February.

8. Paro does not go after Kim.

Case 1a:

 

In this case, Paro goes after Kim. Hence, this case fails to satisfy the requirement.

Case 1b:

 

In this case, all conditions became satisfied.

Case 2a:

 

In this case there is no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 3a:

 

In this case, no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 1b:

 

Hence, in July month Kim goes on holiday.

Eight persons - Paro, Runa, Sona, Kim, Harry, Ram, Geet and Monu

1. Harry goes in the month of August.

2. Sona goes in the month which has odd number of days.

3. Geet goes just after the month in which Sona goes.

4. Three persons goes between Monu and Sona.

Case 1:

 

Case 2:

 

Case 3:

 

5. Runa goes in the month which has even number of days but not in February.

6. Two persons goes between Kim and Ram, who does not go in the month which have odd number of days.

7. Ram does not go in February.

8. Paro does not go after Kim.

Case 1a:

 

In this case, Paro goes after Kim. Hence, this case fails to satisfy the requirement.

Case 1b:

 

In this case, all conditions became satisfied.

Case 2a:

 

In this case there is no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 3a:

 

In this case, no month is left which has even number of days in which Ram goes. Hence, this case also fails.

Case 1b:

 

Hence, Three persons go on holiday before Ram.

Persons: A, B, C, D, P, Q, R and S.

Floor: 1 to 4.

Flats: flat-1 and flat-2.

1)  B does not live in flat-2. 

2) Both R and B live in the same flat number.

It means both R and B live inn flat-1.

So, the possible arrangements are as follows,

3) R and A live on the same floor.

4) There is one floor between Q and S.

5. Both Q and S do not live in the same flat.

6) Q lives on an odd-numbered floor but not on floor number 1. Therefore case 2 is wrong.

7) C lives immediately below D on the same flat. Imply that C and D leaves in flat-2. 

So, the final arrangement is as follows,

Hence, A lives in flat-2 of 4^th floor.

Persons: A, B, C, D, P, Q, R and S.

Floor: 1 to 4.

Flats: flat-1 and flat-2.

1)  B does not live in flat-2. 

2) Both R and B live in the same flat number.

It means both R and B live inn flat-1.

So, the possible arrangements are as follows,

3) R and A live on the same floor.

4) There is one floor between Q and S.

5. Both Q and S do not live in the same flat.

6) Q lives on an odd-numbered floor but not on floor number 1. Therefore case 2 is wrong.

7) C lives immediately below D on the same flat. Imply that C and D leaves in flat-2. 

So, the final arrangement is as follows,

Hence, D lives in the same floor with Q.

Persons: A, B, C, D, P, Q, R and S.

Floor: 1 to 4.

Flats: flat-1 and flat-2.

1)  B does not live in flat-2. 

2) Both R and B live in the same flat number.

It means both R and B live inn flat-1.

So, the possible arrangements are as follows,

3) R and A live on the same floor.

4) There is one floor between Q and S.

5. Both Q and S do not live in the same flat.

6) Q lives on an odd-numbered floor but not on floor number 1. Therefore case 2 is wrong.

7) C lives immediately below D on the same flat. Imply that C and D leaves in flat-2. 

So, the final arrangement is as follows,

Hence, there are one floor between R and P.

Persons: A, B, C, D, P, Q, R and S.

Floor: 1 to 4.

Flats: flat-1 and flat-2.

1)  B does not live in flat-2. 

2) Both R and B live in the same flat number.

It means both R and B live inn flat-1.

So, the possible arrangements are as follows,

3) R and A live on the same floor.

4) There is one floor between Q and S.

5. Both Q and S do not live in the same flat.

6) Q lives on an odd-numbered floor but not on floor number 1. Therefore case 2 is wrong.

7) C lives immediately below D on the same flat. Imply that C and D leaves in flat-2. 

So, the final arrangement is as follows,

Hence, D lives in floor 3 of flat-2.

Persons: A, B, C, D, P, Q, R and S.

Floor: 1 to 4.

Flats: flat-1 and flat-2.

1)  B does not live in flat-2. 

2) Both R and B live in the same flat number.

It means both R and B live inn flat-1.

So, the possible arrangements are as follows,

3) R and A live on the same floor.

4) There is one floor between Q and S.

5. Both Q and S do not live in the same flat.

6) Q lives on an odd-numbered floor but not on floor number 1. Therefore case 2 is wrong.

7) C lives immediately below D on the same flat. Imply that C and D leaves in flat-2. 

So, the final arrangement is as follows,

R, Q, P and B are lives in flat-1 but S lives in flat-2.

Hence, S is does not belong to that group.

1. Four persons sit between A and B.

2. Y sits immediate left of A.

3. Two persons sit between B and E.

4. S sits fourth to the left of E.

5. P sits third to the right of S.

6. More than two persons sit between B and P. Therefore, Case II and Case III will be eliminated.

7. Y sits fifth from one of the extreme ends.

8. Nine persons sit between Y and R.

9. R sits third from one of the extreme ends.

10. U sits third from one of the extreme ends but not adjacent to S. Therefore, Case I will be eliminated.

The final arrangement is

Hence, there are 17 persons sitting in the row.

1. Four persons sit between A and B.

2. Y sits immediate left of A.

3. Two persons sit between B and E.

4. S sits fourth to the left of E.

5. P sits third to the right of S.

6. More than two persons sit between B and P. Therefore, Case II and Case III will be eliminated.

7. Y sits fifth from one of the extreme ends.

 

8. Nine persons sit between Y and R.

9. R sits third from one of the extreme ends.

10. U sits third from one of the extreme ends but not adjacent to S. Therefore, Case I will be eliminated.

The final arrangement is-----------------

Hence, B sits fourth to the left of Y.

1. Four persons sit between A and B.

2. Y sits immediate left of A.

3. Two persons sit between B and E.

4. S sits fourth to the left of E.

5. P sits third to the right of S.

6. More than two persons sit between B and P. Therefore, Case II and Case III will be eliminated.

7. Y sits fifth from one of the extreme ends.

8. Nine persons sit between Y and R.

9. R sits third from one of the extreme ends.

10. U sits third from one of the extreme ends but not adjacent to S. Therefore, Case I will be eliminated.

The final arrangement is-----------------

Hence, there are 10 persons between R and A.

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. Some football are not ball → True ( as only a few football are ball which means some football are ball and some football are not ball. Hence, Some football are not ball is true).

II. All bat can be cricket → True ( as there is no relation between Bat and cricket, so it is possible. Hence, all bat can be cricket is true).

Hence, Both I and II follow.

The least possible Venn diagram for the given statements is:

Conclusions:

I. All grapes are apple → False (It is possible but not definite, because no definite relation is given between the elements, therefore we will consider it as false)

II. Some grapes are not apple→ False (It is possible but not definite, because no definite relation is given between the elements, therefore we will consider it as false)

Therefore, Conclusions I and II form a complementary pair.

Hence, Either conclusion I or II follows.

Additional Information

Conditions for complementary pair:

I. Both the conclusions must be wrong (No definite relation)

II. Subject and Predicate must be the same

III. (Some + No) or (All + Some not) pair must be in conclusions

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. Some milk is coffee → False ( as there is no relation between coffee and milk, so it is possible but it's is not definite. Hence, Some milk is coffee is false).

II. Some tea is milk → False ( as there is no relation between tea and milk, so it is possible but it's is not definite. Hence, some tea is milk is false).

Hence, Neither I nor II follows is the correct answer.

The best possible diagram is,

Conclusions:

I. Some tables are sofas: False (As no direct relation between tables and sofa, it is possible but not definite)

II. No table is sofa: False (As no direct relation between tables and sofa, it is possible but not definite)

Conclusion I and II form a complementary pair.

Hence, Either conclusion I or II follows.

Key Points

Conditions for Either - Or 

1. Subject and predicate should be the same
2. Both the individual conclusions should be false
3. One conclusion should be positive and one conclusion should be negative
4. There should either one of the following pairs present in the conclusions

• All + Some not
• Some + No

Given series: 483         396      625      834      967

Adding 2 to the last digit: 485    398   627      836      969

Interchanging first and the second digit: 845    938   267      386      699

So, 938 is the highest number which came from 396.

Given series: 483         396      625      834      967

After adding 1 to last digit and subtracting 2 from first digit

284      197      426      635      768

On rearranging the series in descending order, we get:

768      635      426      284      197

Now third number Is 426 made from 625.

Hence, 625 is correct answer.

Given series: 483         396      625      834      967

Series each number is multiplied by 2: 966    792      1250    1668    1934

Lowest number is = 792

And 1^st digit of the lowest = 7,

Largest number is = 1934.

Last digit of largest number is = 4

Multiplication = 7 × 4 = 28

Hence, 28 is correct answer.