Reasoning PYQs

Given number - 87345691;

Sum of the first four digits - 8+7+3+4 = 22;

Sum of the last four digits - 5+6+9+1 = 21;

The difference between the sum of the digits of the first four digits and the sum of the last four digits i.e., 22 - 21 = 1.

Hence, '1' is the correct answer.

The least possible venn diagram for the given statements is

Conclusion:

I. Some north being west is a possibility → False (because the relation of “only” is given for north, so north can make positive relation with east only)

II. Some east is north → True (It is clearly concluded from the venn diagram)

Hence, Only conclusion II follows.

The least possible diagram is given below:

Conclusion:

I. Some Hat is Throne is a possibility → False (Some Hat are Throne is definite so, the case of possibility will be false)

II. No Throne is Hat → False (Some Hat are Throne and this is definite so, the statement is false)

Hence, Neither I nor II follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. some markers are pens → False (It is possible but not definite)

II. No marker is pen → False (It is possible but not definite)

Conclusion I and II is complementary pair.

Either conclusion I or conclusion II follows.

From the given information,

1. D and A are the daughter and son of K respectively and both are married. 

2. E is the sister of H whose father is C.

3) M and G are of 3^rd generation and  M is the son-in-law of E.

4. K is the brother-in-law of H.

Hence, K is the father of A.

From the given information,

1. D and A are the daughter and son of K respectively and both are married. 

2. E is the sister of H whose father is C.

3) M and G are of 3^rd generation and  M is the son-in-law of E.

4. K is the brother-in-law of H.

Hence, K is the son-in-law of C.

From the given information,

1. D and A are the daughter and son of K respectively and both are married. 

2. E is the sister of H whose father is C.

3) M and G are of 3^rd generation and  M is the son-in-law of E.

4. K is the brother-in-law of H.

Hence, C belongs to the first generation.

7 boxes – P, Q, R, S, T, U and V

1. Box U is placed third from either of the ends.

From this, we get the following possible arrangements.    

2. Box P is placed adjacent to box U.
3. Three boxes are placed between boxes P and S.

 

4. Number of boxes placed above box S is two more than the number of boxes placed below box V.

From this case 2 is eliminated as we cannot place box V. In the case of 1, the number of boxes above box S is 5, hence the number of boxes below box V is 3.

6. Box Q is placed above box R, which is not placed below box S.

    From this we get the final arrangement as follows.

Hence, two boxes are placed between boxes R and P.

7 boxes – P, Q, R, S, T, U and V

1. Box U is placed third from either of the ends.

    From this we get the following possible arrangements.    

2. Box P is placed adjacent to box U.
3. Three boxes are placed between boxes P and S.

4. Number of boxes placed above box S is two more than the number of boxes placed below box V.

    From this case 2 is eliminated as we cannot place box V. In case of 1, the number of boxes above box S is 5, hence the number of boxes below box V is 3.

6. Box Q is placed above box R, which is not placed below box S.

    From this we get the final arrangement as follows.

Hence box S is placed three boxes below box U.

7 boxes – P, Q, R, S, T, U and V

1. Box U is placed third from either of the ends.

    From this we get the following possible arrangements.    

2. Box P is placed adjacent to box U.
3. Three boxes are placed between boxes P and S.

4. Number of boxes placed above box S is two more than the number of boxes placed below box V.

    From this case 2 is eliminated as we cannot place box V. In case of 1, the number of boxes above box S is 5, hence the number of boxes below box V is 3.

6. Box Q is placed above box R, which is not placed below box S.

    From this we get the final arrangement as follows.

The number of boxes placed below box Q is six which is same as the number of boxes placed above box T.

7 boxes – P, Q, R, S, T, U and V

1. Box U is placed third from either of the ends.

    From this we get the following possible arrangements.    

2. Box P is placed adjacent to box U.
3. Three boxes are placed between boxes P and S.

4. Number of boxes placed above box S is two more than the number of boxes placed below box V.

    From this case 2 is eliminated as we cannot place box V. In case of 1, the number of boxes above box S is 5, hence the number of boxes below box V is 3.

6. Box Q is placed above box R, which is not placed below box S.

    From this we get the final arrangement as follows.

 

Box T is at bottom but given is not placed so it will be false.

Box V is placed immediately above R so it will be true.

More than 4 boxes between Q and S but here exactly four boxes are there so it will be false.

Hence, only a and c is the correct answer.

1. Box U is placed third from either of the ends.

    From this we get the following possible arrangements.    

2. Box P is placed adjacent to box U.
3. Three boxes are placed between boxes P and S.

4. Number of boxes placed above box S is two more than the number of boxes placed below box V.

    From this case 2 is eliminated as we cannot place box V. In case of 1, the number of boxes above box S is 5, hence the number of boxes below box V is 3.

6. Box Q is placed above box R, which is not placed below box S.

From this we get the final arrangement as follows.

 

ALPHABETICAL ORDER:

If all the boxes are arranged to place in alphabetical order from bottom to top, then only box R remains unchanged.

Hence, only one box remains unchanged is the correct answer.

As per the given information,

Given word: UNIQUE

 

Forward pair - 0

Backward pair - 0 

No such pairs have as many letters between in the word as they have between them in the English alphabetical series

Hence, none is the correct answer.

Given

Statements:

W = B , B ≤ F ;F < R 

On Combining: W = B ≤ F < R > F

Conclusions

I. W = F → False (as W = B ≤ F → W  ≤ F )

II. W < F → False (as W = B ≤ F → W  ≤ F )

But I and II are complementary pairs.

Therefore, Either I  or II follow.

 

Key Points  

There are three conditions that should satisfy to qualify for Non-Relational Either Or case. The three conditions are as follows

1. The subject and predicate should be same i.e. the either or will only qualify if the conclusion is between two same subjects and predicates on

2. Both the individual conclusion must be false.

3) 

If we have Greater than or equal to ≥ and Lesser than or equal to ≤ relationship between the entities, Two possibilities > and = or < and = must be discussed in the conclusion.

**Given

Statements:

** F < A > B = E; D < C = G > E

On combining: F < A > B = E < G = C > D

Conclusions:

I. A > E → True ( as F > A > E; B = E)

II. E > D → False ( as E < G = C > D thus clear relation cannot be determined between E and D)

Important Points

Whenever there are different signs given between different identities, their relation cannot be determined.

Therefore, only conclusion I follow

**Given

Statements:

** J > D > A ≥ S; C > X ≤ F ≤ S

On combining: J > D > A ≥ S ≥ F ≥ X < C

Conclusions:

I. D ≥ X → False(as D > A ≥ S ≥ F ≥ X → D > X)

II. C > A → False(as A ≥ S ≥ F ≥ X < C, no clear relationship can be determined between C and A because there are opposite signs between C and A. So, it is false)

Hence, Neither I nor II is true.

The movements of Kashish are as shown in figure:

(A to B, B to C, C to D and D to E)

Kashish distance from his house at A.

AE = BE - AB

= CD - AB (BE = CD)

= (25 -15) Km = 10 km

Hence, Kashish is 10 km far from his house.

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

Hence, W lives in flat P on floor 3.

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

Hence, Y lives on the same floor with Z.

1. D lives immediately above the flat in which A lives in the same flat but not in flat Q.
2. There is two floors between the floor on which A and Z live.

    From this we get the following possibilities.

3. There is only one floor between the floors on which Z and B live.

    This implies B lives in flat Q on floor 2 in both the cases.

4. Y who lives on an even numbered floor lives above the floor on which C lives.
5. C lives below the floor on which X lives.

    From this we can say that Y lives in flat Q and flat P in case 1 and in case 2, respectively. Thus, C lives in flat Q on floor 1 in both the cases. X lives in either flat P or flat Q but lives on floor 3.

6. C and X live in the same flat but not with Z.   

    From this case 2 is eliminated as we cannot determine the flat in which X lives. Hence, in case 1 X lives in flat Q on floor 3. W lives in flat P on floor 3. From this we get the final arrangement as follows.

Except D, all the persons live on an odd numbered floor.

 Therefore, D is the odd one out.