Reasoning PYQs

Here, persons are A, B, C, D, E, F, G and H.

1. F lives on the odd number floor below the fifth floor.

2. Three persons live between E and F.

3. G lives just below the floor of E.

 

4. One person lives between B and G.

5. A lives two floors above C.

6. H lives below the floor of C.

 

7. No two person whose names start with consecutive letters live adjacent floors. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, E lives two floors above the floor of D.

Here, persons are A, B, C, D, E, F, G and H.

1. F lives on the odd number floor below the fifth floor.

2. Three persons live between E and F.

3. G lives just below the floor of E.

 

4. One person lives between B and G.

5. A lives two floors above C.

6. H lives below the floor of C.

 

7. No two person whose names start with consecutive letters live adjacent floors. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Hence, A lives on 4^th floor.

Here, persons are A, B, C, D, E, F, G and H.

1. F lives on the odd number floor below the fifth floor.

2. Three persons live between E and F.

3. G lives just below the floor of E.

 

4. One person lives between B and G.

5. A lives two floors above C.

6. H lives below the floor of C.

 

7. No two person whose names start with consecutive letters live adjacent floors. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, B lives on eighth floor not seventh floor. Therefore, statement first is incorrect.

Two persons live between A and H. Therefore, statement second is incorrect.

G lives just above not below the floor of D. Therefore, statement third is incorrect.

H lives on first floor not second floor. Therefore, statement fourth is incorrect.

Hence, the correct statement is None of these.

Here, persons are A, B, C, D, E, F, G and H.

1. F lives on the odd number floor below the fifth floor.

2. Three persons live between E and F.

3. G lives just below the floor of E.

 

4. One person lives between B and G.

5. A lives two floors above C.

6. H lives below the floor of C.

 

7. No two person whose names start with consecutive letters live adjacent floors. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, two persons live between the floor of E and A and two persons live below the floor of F.

Hence, the correct answer is  As many persons live below the floor of F.

Here, persons are A, B, C, D, E, F, G and H.

1. F lives on the odd number floor below the fifth floor.

2. Three persons live between E and F.

3. G lives just below the floor of E.

 

4. One person lives between B and G.

5. A lives two floors above C.

6. H lives below the floor of C.

 

7. No two person whose names start with consecutive letters live adjacent floors. Therefore, case 1 is eliminated. Hence, the final arrangement is as follows

 

Since, B lives on top floor so no one lives above his floor. Therefore, the statement A is correct.

E lives just below not above the floor of B. Therefore, the statement B is incorrect.

Two persons live between D and B. Therefore, statement C is incorrect.

Hence, the correct answer is Both B and C.

Given: M > C < D = R ≤ E < A ≥ V > Y

I. R < A → True (as R ≤ E < A)

II. M < E → False (as M > C < D = R ≤ E; thus a clear relation between M and E cannot be established).

III. D ≤ E → True (as D = R ≤ E)

Hence, conclusion I and III are true.

Given:

A ≥ B > C; C ≤ D ≤ E < F

On Combining:

A ≥ B > C ≤ D ≤ E < F

Conclusions:

I. A ≥ E→ False (as A ≥ B > C ≤ D ≤ E; therefore, the relationship between A and E cannot be determined)

II. C < F→ True (as C ≤ D ≤ E < F; therefore C < F)

Hence, only conclusion II is true.

Given statements: C ≥ F; B < C > D < H = I

On combining, we get

B < C ≥ F; I = H > D < C ≥ F

Conclusions:

I. I > F → False (As I = H > D < C ≥ F, thus, the relation between I and F cannot be determined)

II. H > C → False (As H > D < C, thus, the relation between H and C cannot be determined)

Hence, none of the conclusions is true

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

 

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

 

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

 

Hence, V is the first one who purchased a gift.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

 

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

 

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

 

Hence, one person purchased gift between R and F.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

 

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

 

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

 

Since, B is the last person who purchased a gift. Therefore, statement first is correct.

H purchased a gift just before X. Therefore, statement second is correct.

K purchased a gift just after V. Therefore, statement third is correct.

Only two persons purchased gift after H. Therefore, statement fourth is incorrect.

Hence, the incorrect statement is More than three persons purchased gift after H.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

 

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

 

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

 

Since, three persons purchased gift before O and three persons purchased gift after F.

Hence, the correct answer is F.

Here, persons are B, F, H, K, O, R, V and X.

1. At least three persons purchased gift between K and X.

2. K purchased gift before X and neither of them is the first or last person.

 

3. Three persons purchased gift between V and F.

4. Only two persons purchased gift between V and O who purchased gift after V.

5. O purchased a gift two persons before H.

 

6. H purchased gift before B.

7. R does not purchase a gift adjacent to X and V. Therefore, cases 1, 2(b) and 3 are eliminated. Hence, the final arrangement is as follows

 

Since, two persons purchased gift before R and same number of persons purchased gift after H. Therefore, statement A is correct.

O purchased gift just after R. Therefore, statement B is correct.

F purchased gift after R not before R. Therefore, statement C is incorrect.

Hence, the correct statement is both A and B.

the pattern of code is as follows,

Similarly, the word PAUSED can be coded as,

Hence, the word PAUSED would be coded as UCFRYW.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

 

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

 

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

 

Hence, the correct answer is The one whose visit is on 7^th March.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

 

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

 

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

 

Hence, the correct answer is 20^th September.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

 

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

 

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

 

Hence, the correct answer is Three.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

 

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

 

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

 

Except for the Z who visited in the month which have 30 ays, all others visit in month having 31 days.

Hence, the correct answer is Z.

1. Y’s visit takes place immediately before X’s visit, and X’s visit is on 7^th March. 

 

​2. Exactly three people have their visits between X’s visit and V’s visit. 

 

3. T’s visit is in a month that has 31 days.  4. There are more than two people whose visits fall between T’s visit and S’s visit.

Here, we have 4 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

5. U’s visit is scheduled immediately after W’s visit. 

Now, we can eliminate Case 3, but we have a new subcase of Case 1.

 

6. Z’s visit is scheduled after S’s visit. 

Now, we can eliminate Case 1a and Case 2.

 

7. Not more than two people visit between T and Z.

Now, we can eliminate Case 1.

This is our final arrangement,

 

Hence, the correct answer is Five.

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. No pen is eraser → False (it is possible but not definite.)

II. Some erasers are pencil → False (as no pencil is eraser which also  means no eraser is pencil.)

III. All pen being pencils is a possibility → False (not possible as only few pens are pencils which means some pens are pencils and some pen are not pencils.)

Thus, none of the conclusions follows.