A constant force acts on an object of mass \( 4 \text{ kg} \) for a duration of \( 2 \text{ s} \), increasing its velocity from \( 2 \text{ m/s} \) to \( 8 \text{ m/s} \). If the same force is applied for a duration of \( 4 \text{ s} \), then what would be the final velocity of the object?
- AOption (a)
\( 20 \text{ m/s} \)
- BOption (b)
\( 12 \text{ m/s} \)
- COption (c)
\( 10 \text{ m/s} \)
- DOption (d)
\( 14 \text{ m/s} \)
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Correct answer
\( 14 \text{ m/s} \)
Why this answer is correct
The correct answer is 14 m/s.
Key Points
- The problem involves Newton's Second Law of Motion and the Equations of Motion to determine how a constant force affects an object's velocity over time.
- In the first scenario, an object of mass 4 kg has an initial velocity (u) of 2 m/s and reaches a final velocity (v) of 8 m/s in a time duration (t) of 2 s.
- We first calculate the acceleration (a) using the formula: a = (v - u) / t. Plugging in the values: a = (8 m/s - 2 m/s) / 2 s = 6 / 2 = 3 m/s². This means the constant force produces a steady acceleration of 3 m/s².
- The magnitude of the force (F) can be found using F = m * a. Thus, F = 4 kg * 3 m/s² = 12 N.
- In the second scenario, the same force is applied for a duration of 4 s. Assuming it starts from the same initial velocity of 2 m/s, we calculate the new final velocity using v = u + at.
- Calculation: v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s. Hence, the final velocity is 14 m/s.
Additional Information
- Newton's Second Law of Motion: This law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. The formula is F = ma.
- Force: It is defined as a push or pull upon an object resulting from the object's interaction with another object. The SI unit of force is the Newton (N), named after Sir Isaac Newton. One Newton is equal to 1 kg.m/s².
- Acceleration: This is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. The SI unit for acceleration is m/s².
- Equations of Motion: These equations relate the displacement, velocity, acceleration, and time of a moving object. The three primary equations for constant acceleration are v = u + at, s = ut + 0.5at², and v² = u² + 2as.
Important Points
- Constant Force: When a constant force acts on a body of constant mass, it results in a constant acceleration. This allows for the use of the linear equations of motion.
- Mass vs. Weight: Mass is a fundamental property of an object (measured in kg) and does not change based on location, while weight is the force of gravity acting on that mass. In this problem, the mass is 4 kg.
- Initial and Final Velocity: Initial velocity is the velocity at which motion begins (at t = 0), and final velocity is the velocity after a specific time interval has elapsed.
- Relationship with Time: If the acceleration is constant, the change in velocity is directly proportional to the time for which the force is applied. Doubling the time from 2 s to 4 s (if starting from rest) would double the velocity change, but since there is an initial velocity, we must add it to the total change.