Quantitative Aptitude PYQs

The lateral surface area of a cube is 420 cm² less than lateral surface area of a cylinder and the height of cylinder is 2x cm. If radius of the cylinder is x cm and side of the cube is equal to the radius of cylinder, then find the area (approximate) of a circle which radius is (x+3) cm.

The marked price of an article is 1.45 times its cost price and the selling price of the article is Rs. 750. If profit percentage of shopkeeper on the article is 25%, then find the discount (in %) allowed by the shopkeeper.

Vessel A contains 80 liter milk and 12 liters water, while vessel B contains 156 liters mixture of milk and water are in the ratio of 10 : 3 respectively. If vessel A and B mixed into another vessel C which already contains 12 liters waters, then find the percentage of water in vessel C.

P and Q started a business together and investment of P is Rs. 2000 more than that of Q. After eight months, P left the business. At the end of a year, they get total profit of Rs. 6800 and profit share of P is Rs. 400X. Find the investment of Q (Given, 6X³ = 3090 – √324).

A man invested Rs. 6500 on compound interest at the rate of 10% p.a. for two years in scheme A. Find the total interest (approximate) received by man on investing the amount he received from scheme A again in the same scheme for two years.

Direction (96-97): Read the following paragraph carefully and answer the questions given below. The monthly income of A is 60% more than B and both A & B pay equal amount for EMI. From the remaining monthly income, A and B spends a certain amount on house rent. Total amount that B pay for EMI is 20% of his monthly income and total amount A spends on house rent are ‘n’ times of the amount he pays for EMI.

If total amount spends by A on EMI and house rent is 50% of his total monthly income and total amount pay by B for EMI is Rs. 15000, then find total saving of A (Given, A and B had only two expanses from their monthly income i.e., EMI and house rent).

Direction (96-97): Read the following paragraph carefully and answer the questions given below. The monthly income of A is 60% more than B and both A & B pay equal amount for EMI. From the remaining monthly income, A and B spends a certain amount on house rent. Total amount that B pay for EMI is 20% of his monthly income and total amount A spends on house rent are ‘n’ times of the amount he pays for EMI.

The amount spends on house rent by A is Rs. 5000 more than that of B and total amount spends on house rent paid by A is Rs. 3000 more than total amount pays by him for EMI. If house rend paid by B is 1/3 rd of the amount pays by A for EMI, then which of the following possible monthly income (in Rs.) of A.

Direction (98-102): The pie chart given below shows distribution (in degree) of total number of bookshelves manufactured by five (P, Q, R, S and T) different companies and the table given below shows percentage distribution of unsold bookshelves. Read the data carefully and answer the questions.

Note: (i) p + 25° = degree of company Q (ii) Total bookshelves manufactured by S is 975. (iii) Total manufactured bookshelves = Sold bookshelves + Unsold bookshelves

Q98. Find the value of (20X − 2p/5 − 4q/5).

Direction (98-102): The pie chart given below shows distribution (in degree) of total number of bookshelves manufactured by five (P, Q, R, S and T) different companies and the table given below shows percentage distribution of unsold bookshelves. Read the data carefully and answer the questions.

Note: (i) p + 25° = degree of company Q (ii) Total bookshelves manufactured by S is 975. (iii) Total manufactured bookshelves = Sold bookshelves + Unsold bookshelves

Q99. The selling price of each book shelve sold by P and R is Rs. 25 & Rs. 30 respectively. If total 500 bookshelves are unsold, then find total revenue generated by P and R.

Direction (98-102): The pie chart given below shows distribution (in degree) of total number of bookshelves manufactured by five (P, Q, R, S and T) different companies and the table given below shows percentage distribution of unsold bookshelves. Read the data carefully and answer the questions.

Note: (i) p + 25° = degree of company Q (ii) Total bookshelves manufactured by S is 975. (iii) Total manufactured bookshelves = Sold bookshelves + Unsold bookshelves

Q100. If difference between total unsold bookshelves of P and R is 16, then find average number of sold bookshelves of Q, S and T.

Direction (98-102): The pie chart given below shows distribution (in degree) of total number of bookshelves manufactured by five (P, Q, R, S and T) different companies and the table given below shows percentage distribution of unsold bookshelves. Read the data carefully and answer the questions.

Note: (i) p + 25° = degree of company Q (ii) Total bookshelves manufactured by S is 975. (iii) Total manufactured bookshelves = Sold bookshelves + Unsold bookshelves

Q101. If total unsold bookshelves of P and R together is 210 and total sold bookshelves of X is 15% less than that of Q, then find total number of sold bookshelves of S are what percent (approx.) less than total sold bookshelves of X.

Direction (98-102): The pie chart given below shows distribution (in degree) of total number of bookshelves manufactured by five (P, Q, R, S and T) different companies and the table given below shows percentage distribution of unsold bookshelves. Read the data carefully and answer the questions.

Note: (i) p + 25° = degree of company Q (ii) Total bookshelves manufactured by S is 975. (iii) Total manufactured bookshelves = Sold bookshelves + Unsold bookshelves

Q102. If total 1000 bookshelves are unsold, then find the difference between number of sold bookshelves of Q and the average number of sold bookshelves of S and T.

Direction (103-104): In the given questions, two quantities are given, one as ‘Quantity I’ and another as ‘Quantity II’. You have to determine relationship between two quantities and choose the appropriate option:

Quantity I: Value of ‘x’ for equation [Formula above]. Quantity II: Value of ‘y’ for equation [Formula above].

Direction (103-104): In the given questions, two quantities are given, one as ‘Quantity I’ and another as ‘Quantity II’. You have to determine relationship between two quantities and choose the appropriate option:

Given, p > 1 > q > 0. Quantity I: Value of [Formula above]. Quantity II: Value of [Formula above].

Direction (15-17): There are two equations I and II given, solve these equations and answer the following questions given below. Equation I. px² − 9x + 7 = 0 Equation II. qy² – 8y + 4 = 0 Note: (A) Both p and q are positive integers. (B) One of the roots of equation II is 2/3. (C) The ratio of highest root of equation I to the highest root of equation II is 7 : 4.

Q105. Find the ratio of smallest root of equation I to the smallest root of equation II.

Direction (15-17): There are two equations I and II given, solve these equations and answer the following questions given below. Equation I. px² − 9x + 7 = 0 Equation II. qy² – 8y + 4 = 0 Note: (A) Both p and q are positive integers. (B) One of the roots of equation II is 2/3. (C) The ratio of highest root of equation I to the highest root of equation II is 7 : 4.

Q106. Find the value of (p + q).

Direction (15-17): There are two equations I and II given, solve these equations and answer the following questions given below. Equation I. px² − 9x + 7 = 0 Equation II. qy² – 8y + 4 = 0 Note: (A) Both p and q are positive integers. (B) One of the roots of equation II is 2/3. (C) The ratio of highest root of equation I to the highest root of equation II is 7 : 4.

Q107. Find the both roots of equation [Formula above].

If X is the correct number which replace the wrong number of the series 229, 256, 320, 441, 661, 1004, then which of following statement/s is or are correct. I. X is completely divisible by 15. II. (X+2) is a prime number.

Q109. Series (A): 1332, 612, 492, Y, 462, 460 If (Y−18)/5 is a fourth term of series (B) and follow same pattern as of the series (A), then find the first term of series (B).

Q110. 49, ?, 82, 145, 269, 484, 826 If ?=A+6, then find the nearest square of A.