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IBPS RRB Office Assistant (Clerk) · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1935 Total Questions49 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 41–60 of 1935Page 3 of 97
SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 41

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Out of total number of item brought by A in 2016, 2/7th item is plastic item. Find the number of plastic items brought by A in 2016?

  1. AOption (a)

    10

  2. BOption (b)

    20

  3. COption (c)

    60

  4. DOption (d)

    80

  5. EOption (e)

    40

View answer & explanation

Correct answer

Answer: (e)E.

40

Why this answer is correct

Calculations:

Total number of items brought by A in 2016 = 140 

Number of plastic items brought by A = 140 × 2 /7 = 40

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 42

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Find the ratio between total number of items brought by A and B together in the year 2015 and 2016?

  1. AOption (a)

    5:6

  2. BOption (b)

    2:3

  3. COption (c)

    4:5

  4. DOption (d)

    4:9

  5. EOption (e)

    8:7

View answer & explanation

Correct answer

Answer: (a)A.

5:6

Why this answer is correct

Calculations:

Total number of items brought by A and B in 2015 = 120 + 130 = 250

Total number of items brought by A and B in 2016 = 140 + 160 = 300

Required ratio = 250 : 300 = 5:6

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 43

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Number of items brought by C in the year 2016 is 45 more than the average number of items brought by A and B in same year. Find the number of items brought by C in the year 2016?

  1. AOption (a)

    215

  2. BOption (b)

    205

  3. COption (c)

    235

  4. DOption (d)

    195

  5. EOption (e)

    265

View answer & explanation

Correct answer

Answer: (d)D.

195

Why this answer is correct

Calculations:

Total number of items brought by A and B in 2016 = 140 + 160 = 300

Average number of items brought by A and B in 2016 = 300/2 = 150

Number of items brought by C in the year 2016:

= 150 + 45 = 195

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 44

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Number of items brought by A and B in 2018 is 25% and 20% more than the previous year respectively. Find the total item brought by A and B together in the year 2018?

  1. AOption (a)

    205

  2. BOption (b)

    405

  3. COption (c)

    415

  4. DOption (d)

    395

  5. EOption (e)

    385

View answer & explanation

Correct answer

Answer: (b)B.

405

Why this answer is correct

Calculations:

Number of items brought by A in 2017 = 180

Number of items brought by B in 2017 = 150

Total item brought by A and B together in the year 2018 is:

[180 × 125/100] + [150 ×120/100] = 225 + 180 = 405

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 45

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Total number of items brought by A in the year 2015 and 2016 together is how much less than the number of item brought by B in same year?

  1. AOption (a)

    68

  2. BOption (b)

    66

  3. COption (c)

    30

  4. DOption (d)

    45

  5. EOption (e)

    48

View answer & explanation

Correct answer

Answer: (c)C.

30

Why this answer is correct

Calculations:

Total number of items brought by A in the year 2015 and 2016 together = 120 + 140 = 260

Total number of items brought by B in the year 2015 and 2016 together = 130 + 160 = 290

So, required difference is 290 – 260 = 30

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 46

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The given bar graphs shows the number of items brought by A and B in the year 2015, 2016 and 2017.

Difference between number of items brought by B and A in the year 2015 is x - 5. Find the value of x?

  1. AOption (a)

    10

  2. BOption (b)

    32

  3. COption (c)

    35

  4. DOption (d)

    15

  5. EOption (e)

    25

View answer & explanation

Correct answer

Answer: (d)D.

15

Why this answer is correct

Calculations:

Total number of items brought by A in the year 2015 = 120

Total number of items brought by B in the year 2015 = 130

Difference between number items brought by B and A is 130 - 120 = 10

So, x – 5 = 10 ⇒  x = 15.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 47

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Find the value of x.

125 ÷ 5 ×  171 ÷ 27 ÷ 249 ×  9 = x ÷ 83

  1. AOption (a)

    525

  2. BOption (b)

    425

  3. COption (c)

    475

  4. DOption (d)

    325

  5. EOption (e)

    400

View answer & explanation

Correct answer

Answer: (c)C.

475

Why this answer is correct

Solution:

125 ÷ 5 ×  171 ÷ 27 ÷ 249 ×  9 = x ÷ 83

25 ×  (171/27) ×  (1/249) ×  9 = x/83

25 ×  (19/3) ×  (3/83) = x/83

x = 25 ×  19

x = 475

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 48

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

Find the value of x.

42 ÷ 6 ×  3 + 5 – (8 + 7) + 123 = x

  1. AOption (a)

    128

  2. BOption (b)

    134

  3. COption (c)

    126

  4. DOption (d)

    122

  5. EOption (e)

    118

View answer & explanation

Correct answer

Answer: (b)B.

134

Why this answer is correct

Solution:

42 ÷ 6 ×  3 + 5 – (8 + 7) + 123 = x

7 ×  3 + 5 – (15) + 123 = x

21 + 5 – 15 + 123 = x

x = 134

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 49

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What value will come in the place of the question mark ‘?’ in the following question?

5265 ÷ 117 + 67 × 85 - 1172 + 289 + 263 - 120 = (?)

  1. AOption (a)

    5000

  2. BOption (b)

    5500

  3. COption (c)

    5100

  4. DOption (d)

    5198

  5. EOption (e)

    5200

View answer & explanation

Correct answer

Answer: (a)A.

5000

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved second, and following BODMAS rule in the bracket

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Calculations:

5265 ÷ 117 + 67 × 85 - 1172 + 289 + 263 - 120 = (?)

⇒ 45 + 5695 - 1172 + 289 + 263 - 120 = (?)

⇒  45 + 5695 - 1172 + 289 + 263 - 120 = (?)

⇒ 6292 - 1292 = (?)

⇒ ? = 5000

Hence, the correct answer is 5000.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 50

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What value will come in the place of the question mark ‘?’ in the following question?

(159 + 321) ÷ 4 + (7250/50) + (4130 – 1270) ÷ 110 + 33 = ?2

  1. AOption (a)

    19

  2. BOption (b)

    18

  3. COption (c)

    16

  4. DOption (d)

    14

  5. EOption (e)

    20

View answer & explanation

Correct answer

Answer: (b)B.

18

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved second, and following BODMAS rule in the bracket

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Calculations:

(159 + 321) ÷ 4 + (7250/50) + (4130 – 1270) ÷ 110 + 33 = ?2

⇒ 480 ÷ 4 + 145 + 2860 ÷ 110 + 33 = ?2

⇒ 120 + 145 + 26 + 33 = ?2

⇒ 324 = ?2

⇒ √324 = ?

⇒ 18 = ?

Hence, the correct answer is 18.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 51

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

18 + 27 - 14 = ? + 10 + 20

  1. AOption (a)

    4

  2. BOption (b)

    5

  3. COption (c)

    1

  4. DOption (d)

    -1

  5. EOption (e)

    None of these.

View answer & explanation

Correct answer

Answer: (c)C.

1

Why this answer is correct

Given:

18 + 27 - 14 = ? + 10 + 20

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

18 + 27 - 14 = ? + 10 + 20

⇒ 45 - 14 = ? + 30

⇒ 31 = ? + 30

⇒ ? = 31 - 30 = 1

∴ The value of ? is 1

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 52

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

(√1024 + 19 × 12) ÷ √676 - 4 + 4680 ÷ ? = 474

  1. AOption (a)

    10

  2. BOption (b)

    8

  3. COption (c)

    16

  4. DOption (d)

    3

  5. EOption (e)

    11

View answer & explanation

Correct answer

Answer: (a)A.

10

Why this answer is correct

Given:

(√1024 + 19 × 12) ÷ √676 - 4 + 4680 ÷ ? = 474

Concept Used:

​

Calculation:

(√1024 + 19 × 12) ÷ √676 - 4 + 4680 ÷ ? = 474

⇒ (32 + 228) ÷ 26 - 4 + 4680 ÷ ? = 474

⇒ 10 - 4 + 4680 ÷ ? = 474

⇒ 4680 ÷ ? = 468

⇒ 4680 ÷ 468 = ?

⇒ ? = 10

∴ The value of (?) is 10.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 53

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

(14)2 × 10 ÷ 4 - (15)2 + 16 = ?2 + 52

  1. AOption (a)

    4

  2. BOption (b)

    16

  3. COption (c)

    8

  4. DOption (d)

    10

  5. EOption (e)

    14

View answer & explanation

Correct answer

Answer: (b)B.

16

Why this answer is correct

Given:  

(14)2 × 10 ÷ 4 - (15)2 + 16 = ?2 + 52

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

(14)2 × 10 ÷ 4 - (15)2 + 16 = ?2 + 52

⇒ 196 × 10 × 1/4 - 225 + 16 = ?2 + 25

⇒ 98 × 5 - 225 + 16 = ?2 + 25

⇒ 490 - 225 + 16 = ?2 + 25

⇒ 490 - 225 + 16 - 25 = ?2 

⇒  ?2 = 506 - 250 = 256

⇒ ? = √256 = 16

∴ 16 will come in place of the question mark '?'.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 54

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

(72 × 6 - 36 × 6) ÷ 12 = 288 ÷ ?

  1. AOption (a)

    12

  2. BOption (b)

    26

  3. COption (c)

    16

  4. DOption (d)

    14

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (c)C.

16

Why this answer is correct

Concept used:

Follow the BODMAS rule according to the table given below:

 

Calculation:

⇒ (72 × 6 - 36 × 6) ÷ 12 = 288 ÷ ?

⇒ (432 - 216) ÷ 12 = 288 ÷ ?

⇒ 216 ÷ 12 = 288 ÷ ?

⇒ ? = 288 ÷ 18 = 16

∴ The value of ? is 16.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 55

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

53 × 3 + 85 ÷ 5 - √(?) × 6 = 356

  1. AOption (a)

    25

  2. BOption (b)

    36

  3. COption (c)

    49

  4. DOption (d)

    64

  5. EOption (e)

    81

View answer & explanation

Correct answer

Answer: (b)B.

36

Why this answer is correct

Given:

53 × 3 + 85 ÷ 5 - √(?) × 6 = 356

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

53 × 3 + 85 ÷ 5 - √(?) × 6 = 356

⇒ 125 × 3 + 17 - √(?) × 6 = 356

⇒ 375 + 17 - √(?) × 6 = 356

⇒ √(?) × 6 = 36

⇒ √(?) = 6

⇒ ? = 62

⇒ ? = 36

∴ 36 should come in place of the question mark (?).

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 56

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

328 ÷ 8 + 25 × 2.4 + ? = (11)2

  1. AOption (a)

    21

  2. BOption (b)

    22

  3. COption (c)

    20

  4. DOption (d)

    23

  5. EOption (e)

    24

View answer & explanation

Correct answer

Answer: (c)C.

20

Why this answer is correct

Given:

328 ÷ 8 + 25 × 2.4 + ? = (11)2

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

328 ÷ 8 + 25 × 2.4 + ? = (11)2

⇒ 41 + 60 + ? = 121

⇒ 101 + ? = 121

⇒ ? = 20

∴ 20 should come in place of the question mark (?).

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 57

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

15 × 678 - 10 × 802 + 60 ÷ 6 = ? × 50 ÷ 5

  1. AOption (a)

    216

  2. BOption (b)

    179

  3. COption (c)

    185

  4. DOption (d)

    246

  5. EOption (e)

    175

View answer & explanation

Correct answer

Answer: (a)A.

216

Why this answer is correct

Given:

15 × 678 - 10 × 802 + 60 ÷ 6 = ? × 50 ÷ 5

Concept Used:

Calculation:

15 × 678 - 10 × 802 + 60 ÷ 6 = ? × 50 ÷ 5

⇒ 10170 - 8020 + 10 = ? × 10

⇒ 2160 = ? × 10

⇒ 2160/10 = ?

⇒ ? = 216

∴ The value of ? is 216

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 58

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

What will come in the place of the question mark ‘?’ in the following question?

549 ÷ 3 × 54 - 25 × 321 + 31 = ?

  1. AOption (a)

    1888

  2. BOption (b)

    1886

  3. COption (c)

    1866

  4. DOption (d)

    1898

  5. EOption (e)

    1889

View answer & explanation

Correct answer

Answer: (a)A.

1888

Why this answer is correct

Calculation:

We use the BODMAS rule as follows:

According to the rule ‘division’ should be solved first

⇒ 549 ÷ 3 × 54 - 25 × 321 + 31 = ?

⇒ 183 × 54 - 25 × 321 + 31 = ?

⇒ 9882 - 8025 + 31 = ?

⇒ 9913 - 8025 = ?

⇒ ? = 1888

∴ required answer is 1888.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 59

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

The ratio of the speed of stream to the speed of the boat in still water is 5 : 16. A boat goes 33 km in 90 minutes upstream, find the time taken by boat to cover the distance of 35 km downstream.

  1. AOption (a)

    40 minutes

  2. BOption (b)

    20 minutes

  3. COption (c)

    60 minutes

  4. DOption (d)

    50 minutes

  5. EOption (e)

    30 minutes

View answer & explanation

Correct answer

Answer: (d)D.

50 minutes

Why this answer is correct

Shortcut Trick

Ratio of Boat Speed (u) : Stream Speed (v) = 16 : 5

Upstream Speed (u−v) = 11 units | Downstream Speed (u+v) = 21 units

Upstream Speed = 33 km ÷ 1.5 hours = 22 kmph ⇒ 1 unit = 2 kmph

Downstream Speed = 21 × 2 = 42 kmph

Time Downstream = (35 ÷ 42) × 60 = 50 min

∴ The correct answer is 50 min.

Alternate Method

Given: Ratio of stream speed (v) to boat speed (u) = 5 : 16. Upstream distance = 33 km, Upstream time = 90 min (1.5 hours).

Formula Used: Speed = Distance ÷ Time; Upstream Speed (Sup) = u − v; Downstream Speed (Sdown) = u + v.

⇒ Let Boat speed = 16x and Stream speed = 5x

⇒ Upstream speed = 16x − 5x = 11x

⇒ 11x = 33 km ÷ 1.5 hr = 22 kmph

⇒ x = 2 kmph

⇒ Downstream speed = 16x + 5x = 21x = 21 × 2 = 42 kmph

⇒ Time taken for 35 km downstream = (35 ÷ 42) hours

⇒ Time in minutes = (35 ÷ 42) × 60 = 5 × 10 = 50 min

∴ The correct answer is 50 min.

Additional Information

Relative Speed in Water

Downstream speed is the sum (u + v) and Upstream speed is the difference (u − v) of boat and stream speeds.

Boat Speed Calculation

Speed of boat in still water (u) = (Downstream Speed + Upstream Speed) ÷ 2.

Stream Speed Calculation

Speed of stream (v) = (Downstream Speed − Upstream Speed) ÷ 2.

SBI Clerk Prelims Memory Based Paper (Held On: 22 February 2025 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 60

IBPS RRB Office Assistant (Clerk) 2025• Numerical Ability• Numerical Ability

In a Business Vaibhav invested Rs. 32000 for ‘x’ months, after 6 months Ashish joined the business with the amount equal to Rs. 20000. If the ratio of profit received is 12 : 5, Find the duration of amount invested by Vaibhav.

  1. AOption (a)

    24 months

  2. BOption (b)

    12 months

  3. COption (c)

    9 months

  4. DOption (d)

    18 months

  5. EOption (e)

    15 months

View answer & explanation

Correct answer

Answer: (d)D.

18 months

Why this answer is correct

Shortcut Trick

Profit Ratio = (Capital1 × Time1) : (Capital2 × Time2)

Ratio of Capitals = 32000 : 20000 = 8 : 5.

Time for Vaibhav = x, Time for Ashish = (x − 6).

Ratio = (8 × x) : (5 × (x − 6)) = 12 : 5.

Solving 8x ÷ (5x − 30) = 12 ÷ 5 ⇒ 40x = 60x − 360 ⇒ 20x = 360 ⇒ x = 18.

∴ The correct answer is 18 months.

Alternate Method

Given: Vaibhav Investment = Rs. 32000, Ashish Investment = Rs. 20000, Profit Ratio = 12 : 5, Ashish joined after 6 months.

Formula: Profit = Investment × Time period

⇒ Let Vaibhav invested for x months.

⇒ Ashish joined 6 months later, so his time = (x − 6) months.

⇒ (32000 × x) ÷ (20000 × (x − 6)) = 12 ÷ 5

⇒ (32 × x) ÷ (20 × (x − 6)) = 12 ÷ 5

⇒ (8x) ÷ (5 × (x − 6)) = 12 ÷ 5

⇒ 8x ÷ (x − 6) = 12

⇒ 8x = 12x − 72

⇒ 4x = 72 ⇒ x = 18 months.

∴ The correct answer is 18 months.

Additional Information

Partnership Principle

In a partnership, the profit is distributed among partners in the ratio of the product of their investment and time duration.

Time Calculation

If a person joins 'n' months after the start, their investment duration is (Total Time − n).

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How should I prepare for Quantitative Aptitude in IBPS RRB Office Assistant (Clerk)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.