Reasoning PYQs

Given words: SUB DMU BAR APL DNA

1. If the second alphabet is changed to the next alphabet in the English alphabetical order and the last alphabet is changed to the previous alphabet in the English alphabetical order

Actual words: SUB DMU BAR APL DNA

Corresponding change: SVA DNT BBQ AQK DOZ

Hence, ‘two’ words thus formed having no vowel.

From the given instructions:

1. F got fewer marks than only two girls.

__ > __ > F > __ > __ > __

 

2. F got more marks than B. B got fewer marks than C. D got more marks than E but fewer marks than A, who does not get the highest marks. B got more marks than E. D got more marks than B. C got more marks than F. So, directly we can say,

C > A > F > D > B > E

 

3. The second highest scorer got 24 marks and the third lowest scorer got 18 marks. So, Final Arrangement,

C > A (24) > F > D ( 18 ) > B > E

D got the fourth highest marks.

From the given instructions:

1. F got fewer marks than only two girls.

__ > __ > F > __ > __ > __

 

2. F got more marks than B. B got fewer marks than C. D got more marks than E but fewer marks than A, who does not get the highest marks. B got more marks than E. D got more marks than B. C got more marks than F. So, directly we can say,

C > A > F > D > B > E

 

3. The second highest scorer got 24 marks and the third lowest scorer got 18 marks. So, Final Arrangement,

C > A (24) > F > D ( 18 ) > B > E

 

23 would be the possible marks of F.

From the given instructions:

1. F got fewer marks than only two girls.

__ > __ > F > __ > __ > __

 

2. F got more marks than B. B got fewer marks than C. D got more marks than E but fewer marks than A, who does not get the highest marks. B got more marks than E. D got more marks than B. C got more marks than F. So, directly we can say,

C > A > F > D > B > E

 

3. The second highest scorer got 24 marks and the third lowest scorer got 18 marks. So, Final Arrangement,

C > A (24) > F > D ( 18 ) > B > E

F and D girls are between A and B.

Given word: DIRECTLY

2^nd, 3^rd, 4^th and 6^th letters of the word 'DIRECTLY' is : I, R, E and T

Combining and un-jumbling the letters we get: iter, rite, tier, tire, rite

Since 4  words are possible from the letters.

Hence, the answer is X.

E lives on floor number 2 and lives above C but not in the same flat. A lives above B and both lives in the same flat. 

Case 1

Case 2

 

F lives one of the floors above C and in different flat as C. Remaining flat is occupied by D. 

Case2 

D lives one of the floor below A but not in the same flat as C. F lives west of A. 

Final arrangement will be 

D lives in Floor1 - Flat1 hence it is the correct answer.

E lives on floor number 2 and lives above C but not in the same flat. A lives above B and both lives in the same flat. 

Case 1

Case 2

 

F lives one of the floors above C and in different flat as C. Remaining flat is occupied by D. 

Case2 

D lives one of the floor below A but not in the same flat as C. F lives west of A. 

Final arrangement will be 

A lives in Flat2 on the 3^rd floor is the correct statement.

E lives on floor number 2 and lives above C but not in the same flat. A lives above B and both lives in the same flat. 

Case 1

Case 2

 

F lives one of the floors above C and in different flat as C. Remaining flat is occupied by D. 

Case2 

D lives one of the floor below A but not in the same flat as C. F lives west of A. 

Final arrangement will be 

After interchanging the position of F and C we get. 

Hence B is the correct answer.

E lives on floor number 2 and lives above C but not in the same flat. A lives above B and both lives in the same flat. 

Case 1

Case 2

 

F lives one of the floors above C and in different flat as C. Remaining flat is occupied by D. 

Case2 

D lives one of the floor below A but not in the same flat as C. F lives west of A. 

Final arrangement will be 

Both A and F lives in top floor.

E lives on floor number 2 and lives above C but not in the same flat. A lives above B and both lives in the same flat. 

Case 1

Case 2

 

F lives one of the floors above C and in different flat as C. Remaining flat is occupied by D. 

Case2 

D lives one of the floor below A but not in the same flat as C. F lives west of A. 

Final arrangement will be 

B lives in flat 2 of 2^nd floor.

According to the given information,

Names given: G, H, I, J, Q, R, S and T

Facing direction: G,H, I and J are sitting in row 1 facing South. Q, R, S and T are sitting in row 2 facing North.

1. Only one person is sitting between J and I, who is sitting to the left of J.

(Here two cases exists, Case - 1: J is sitting at the extreme left end of the row and one person is sitting between J and I. Case - 2: J is sitting second from the left end of the row and one person is sitting between J and I.) 

2. S is facing the immediate neighbours of both J and I. 3. T is not the immediate neighbour of S. 4. Only one person is sitting between Q and R, who is not facing I. 5. H is not sitting to the right of G. 6. One of the immediate neighbour of J is facing T.

(Here case 1 gets eliminated. As one of the immediate neighbour of J, i.e G is not facing T.)

Hence, R is sitting to the immediate left of S.

According to the given information,

Names given: G, H, I, J, Q, R, S and T

Facing direction: G,H, I and J are sitting in row 1 facing South. Q, R, S and T are sitting in row 2 facing North.

1. Only one person is sitting between J and I, who is sitting to the left of J.

(Here two cases exists, Case - 1: J is sitting at the extreme left end of the row and one person is sitting between J and I. Case - 2: J is sitting second from the left end of the row and one person is sitting between J and I.) 

2. S is facing the immediate neighbours of both J and I. 3. T is not the immediate neighbour of S. 4. Only one person is sitting between Q and R, who is not facing I. 5. H is not sitting to the right of G. 6. One of the immediate neighbour of J is facing T.

(Here case 1 gets eliminated. As one of the immediate neighbour of J, i.e G is not facing T.)

Hence, G and I sits at the extreme ends of row 1.

According to the given information,

Names given: G, H, I, J, Q, R, S and T

Facing direction: G,H, I and J are sitting in row 1 facing South. Q, R, S and T are sitting in row 2 facing North.

1. Only one person is sitting between J and I, who is sitting to the left of J.

(Here two cases exists, Case - 1: J is sitting at the extreme left end of the row and one person is sitting between J and I. Case - 2: J is sitting second from the left end of the row and one person is sitting between J and I.) 

2. S is facing the immediate neighbours of both J and I. 3. T is not the immediate neighbour of S. 4. Only one person is sitting between Q and R, who is not facing I. 5. H is not sitting to the right of G. 6. One of the immediate neighbour of J is facing T.

(Here case 1 gets eliminated. As one of the immediate neighbour of J, i.e G is not facing T.)

Hence, I sits to the immediate left of the person facing S.

According to the given information,

Names given: G, H, I, J, Q, R, S and T

Facing direction: G,H, I and J are sitting in row 1 facing South. Q, R, S and T are sitting in row 2 facing North.

1. Only one person is sitting between J and I, who is sitting to the left of J.

(Here two cases exists, Case - 1: J is sitting at the extreme left end of the row and one person is sitting between J and I. Case - 2: J is sitting second from the left end of the row and one person is sitting between J and I.) 

2. S is facing the immediate neighbours of both J and I. 3. T is not the immediate neighbour of S. 4. Only one person is sitting between Q and R, who is not facing I. 5. H is not sitting to the right of G. 6. One of the immediate neighbour of J is facing T.

(Here case 1 gets eliminated. As one of the immediate neighbour of J, i.e G is not facing T.)

Hence, T and Q sits at the extreme ends of row 2.

According to the given information,

Names given: G, H, I, J, Q, R, S and T

Facing direction: G,H, I and J are sitting in row 1 facing South. Q, R, S and T are sitting in row 2 facing North.

1. Only one person is sitting between J and I, who is sitting to the left of J.

(Here two cases exists, Case - 1: J is sitting at the extreme left end of the row and one person is sitting between J and I. Case - 2: J is sitting second from the left end of the row and one person is sitting between J and I.) 

2. S is facing the immediate neighbours of both J and I. 3. T is not the immediate neighbour of S. 4. Only one person is sitting between Q and R, who is not facing I. 5. H is not sitting to the right of G. 6. One of the immediate neighbour of J is facing T.

(Here case 1 gets eliminated. As one of the immediate neighbours of J, i.e G is not facing T.)

Final Arrangement:

If all the people are made to sit in alphabetical order from the left of the rows, then the arrangement will be.

As we can see H**, R** and S will remain in the same position.

Hence, Three persons H, R, and S remain in the same position after all the people are made to sit in alphabetical order from the left of both rows.

 

Here we have two types of arrangement:

Second last arrangement is according to the given condition and the Last arrangement is according to the question given.

LKMJ → L – 1 = K, K + 2 = M, M – 3 = J.

FEGD → F – 1 = E, E + 2 = G, G – 3 = D.

SRTQ → S – 1 = R, R + 2 = T, T – 3 = Q.

ONPM → O – 1 = N, N + 2 = P, P – 3 = M.

RQTR → R – 1 = Q, Q + 3 = T, T – 2 = R.

Hence, RQTR is the odd one out.

The pattern for the code is as follows:

 There are different code for each alphabet

Hence, CURRENT will be written as 'ABWWLDZN'

Given series:

Left Side G % 4 F L # 2 1 V & W 5 4 @ $ X + 4 € 6 3 Q © 7 5 Right Side

Symbols which are immediately preceded by an even number or followed by an odd number:

Possible combination can be either (Even number - Symbol) or (Symbol - Odd number)

 

G % 4 F L # 2 1 V & W 5 4 @ $ X + 4 € 6 3 Q © 7 5

Hence, there are three symbols which are preceded by an even number or followed by an odd number i.e. 4 @, 4 € and © 7.

NOTE: Consider ‘or’ and ‘and’ in the question.

Given series:

Left Side G % 4 F L # 2 1 V & W 5 4 @ $ X + 4 € 6 3 Q © 7 5 Right Side

Pattern: The second and the third element is second to the right and second to the left of the first element respectively. The next set of elements is taken at a gap of three elements to the right of the first set of elements.

Next set of elements: 3©€

Hence, 3©€ is the next set of elements in the series$.

Given series:

Left Side G % 4 F L # 2 1 V & W 5 4 @ $ X + 4 € 6 3 Q © 7 5 Right Side

Reversed series:

Left Side 5 7 © Q 3 6 € 4 + X $ @ 4 5 W & V 1 2 # L F 4 % G Right Side

The fourth element to the right of the tenth element from the left end:

Tenth element from the left end: X

Now, the Fourth element to the right of &: 5

Hence, 5 is the fourth element to the right of the tenth element from the left end.

TRICK:

If the question is asked in such a manner that the element asked in a particular position with respect to the position of the elements in the different directions (i.e. right and left or left and right) then we can get it by simply adding the respective positions from the later direction.

For Example: Fourth to the right of the tenth element from the left end.

There are different directions given (i.e. right and left).

So, we will simply add the positions and get the answer from the later direction.

Fourth + Tenth = the Fourteenth element from the left end.