Reasoning PYQs

According to the given information:

Hence, 'ti' is coded for 'colour'.

According to the given information-

Hence, ‘moon’ is coded as either ‘ja’ or ‘pa’.

According to the given information-

Code ‘bi’ corresponds to ‘sky’,

Code ‘ma’ corresponds to ‘is’,

 Code ‘ko’ corresponds to ‘ocean’,

Code ‘di’ corresponds to 'blue'.

Hence, the only possible answer is ‘sky is ocean blue’.

According to the given information-

Hence 'ko' is coded for 'ocean'.

The given word can be represented as follows,

Hence, we get 1 such pair “RU”.

Given: Seven sports -  Football, Cricket, Kabaddi, Squash, Hockey, Archery, and Tennis are played in an indoor stadium in a week, starting from Monday to Sunday, not necessarily in the same order. 

Based on the given conditions, we get the following possiblities:

1.  Cricket is played on the last day of the week. Hockey is played on Thursday. 

Squash is played five days before the day Cricket is played. Tennis is played three days before Hockey. 

Hockey is played one of the days before Kabaddi is played. 

Combining these, we get-

 

2. Football is played one of the days after Archery. 

 

3.More than two sports are played in between Squash and Football.  Hence case 2 gets eliminated. 

So, the final arrangement will be:

 

From the above arrangement, we see that four sports are played after Archery. 

Hence, four sports are played after Archery.

Given: Seven sports -  Football, Cricket, Kabaddi, Squash, Hockey, Archery, and Tennis are played in an indoor stadium in a week, starting from Monday to Sunday, not necessarily in the same order. 

Based on the given conditions, we get the following possiblities:

1.  Cricket is played on the last day of the week. Hockey is played on Thursday. 

Squash is played five days before the day Cricket is played. Tennis is played three days before Hockey. 

Hockey is played one of the days before Kabaddi is played. 

Combining these, we get-

 

2. Football is played one of the days after Archery. 

 

3.More than two sports are played in between Squash and Football.  Hence case 2 gets eliminated. 

So, the final arrangement will be:

 

From the above arrangement, we see that Football is played immediately after Kabaddi. 

Hence,  Football is played immediately after Kabaddi.

Given: Seven sports -  Football, Cricket, Kabaddi, Squash, Hockey, Archery, and Tennis are played in an indoor stadium in a week, starting from Monday to Sunday, not necessarily in the same order. 

Based on the given conditions, we get the following possiblities:

1.  Cricket is played on the last day of the week. Hockey is played on Thursday. 

Squash is played five days before the day Cricket is played. Tennis is played three days before Hockey. 

Hockey is played one of the days before Kabaddi is played. 

Combining these, we get-

 

2. Football is played one of the days after Archery. 

 

3.More than two sports are played in between Squash and Football.  Hence case 2 gets eliminated. 

So, the final arrangement will be:

 

From the above arrangement, we see that Hockey is played three days before Cricket. 

Hence, Hockey is played three days before Cricket.

Given: Seven sports -  Football, Cricket, Kabaddi, Squash, Hockey, Archery, and Tennis are played in an indoor stadium in a week, starting from Monday to Sunday, not necessarily in the same order. 

Based on the given conditions, we get the following possiblities:

1.  Cricket is played on the last day of the week. Hockey is played on Thursday. 

Squash is played five days before the day Cricket is played. Tennis is played three days before Hockey. 

Hockey is played one of the days before Kabaddi is played. 

Combining these, we get-

 

2. Football is played one of the days after Archery. 

 

3.More than two sports are played in between Squash and Football.  Hence case 2 gets eliminated. 

So, the final arrangement will be:

 

From the above arrangement, we see that Football is played on a Saturday. 

Hence, Football is played on a Saturday.

Given: Seven sports -  Football, Cricket, Kabaddi, Squash, Hockey, Archery, and Tennis are played in an indoor stadium in a week, starting from Monday to Sunday, not necessarily in the same order. 

Based on the given conditions, we get the following possiblities:

1.  Cricket is played on the last day of the week. Hockey is played on Thursday. 

Squash is played five days before the day Cricket is played. Tennis is played three days before Hockey. 

Hockey is played one of the days before Kabaddi is played. 

Combining these, we get-

 

2. Football is played one of the days after Archery. 

 

3.More than two sports are played in between Squash and Football.  Hence case 2 gets eliminated. 

So, the final arrangement will be:

 

From the above arrangement, we see that Kabaddi was played on Friday and not Saturday. 

Hence, Kabaddi was played on Saturday is the incorrect option.

Given: DISGUISING

2^nd, 5^th, 7^th and 10^th letters are - I, U, S, G

Meaningful word is - No meaningful word can be formed. 

Hence, the correct answer is Y.

If the first and the third digits are interchanged within the numbers, then we get:

389 → 983

524 → 425

471 → 174

379 → 973

787 → 787

Thus, 174 is the lowest number.

Product of the first and second digit of 174 → 1 * 7 = 7

Hence, 7 is the product of the first and second digit of the lowest number.

From the given information, it can be clearly determined that:

The even number is 524.

Odd numbers are 389, 379, 471, and 787.

If 2 is subtracted from the even numbers, we get:

524 – 2 → 522

If 1 is added to the odd numbers, we get:

389 + 1 → 390

471 + 1 → 472

379 + 1 → 380

787 + 1 → 788

So, 380 < 390 < 472 < 522 < 788

Thus, among the newly formed numbers, 522 is the fourth-lowest.

The first digit of 522 is 5

The third digit of 522 is 2.

5 * 2 = 10

Hence, 10 is the resultant of the product of the first and third digit of the fourth lowest number.

If 1 is added to the even digits and 1 is subtracted from the odd digits within the numbers, then we get:

389 → 298

524 → 435

471 → 560

379 → 268

787 → 696

So, 268 < 298 < 435 < 560 < 696

Thus, 298 is the fourth-highest number and it originated from 389.

Hence, 389 will be the fourth-highest number.

If the digits are arranged in ascending order form left to right within the numbers, we get:

389 → 389

524 → 245

471 → 147

379 → 379

787 → 778

Thus, 147 is the lowest number which originated from 471.

Hence, 471 will be the lowest number.

A number is divisible by 6 only when the 6 is divisible by 2 and 3 where 2 and 3 are coprime numbers.

389 → 389 is not divisable by 2.

389 = 3 + 8 + 9 = 20 which is not divisable by 3.

471 → 471 is not divisable by 2.

471 = 4 + 7 + 1 = 12 which is divisible by 3.

379 → 379 is not divisable by 2.

379 = 3 + 7 + 9 = 19 which is not divisible by 3.

787 → 789 is not divisable by 2.

789 = 7 + 8 + 7 = 22 which is not divisible by 3.

Hence, No one number is divisible by 6.

Eight persons: A, B, C, D, E, F, G, and H

1) B sits third to the right of H. 

2) B sits third to the left of F.

3) Neither F nor H is not an immediate neighbour of D.

(Here, Two possible cases: Case1: D sits immediate right of B. Case2: D sits immediate left of B)

4) Only one person sits between D and E. 

5) C sits second to the left of A.

6. G does not sit opposite A.  

 7) G is not an immediate neighbor of D. 

(Case2: we eliminated case 2)

This will be our final arrangement.

Hence, C sits second to the right of B.

Eight persons: A, B, C, D, E, F, G, and H

1) B sits third to the right of H. 

2) B sits third to the left of F.

3) Neither F nor H is not an immediate neighbour of D.

(Here, Two possible cases: Case1: D sits immediate right of B. Case2: D sits immediate left of B)

4) Only one person sits between D and E. 

5) C sits second to the left of A.

6. G does not sit opposite A.  

 7) G is not an immediate neighbour of D. 

(Case2: we eliminated case 2)

This will be our final arrangement.

Hence, D sits opposite H.

Eight persons: A, B, C, D, E, F, G, and H

1) B sits third to the right of H. 

2) B sits third to the left of F.

3) Neither F nor H is not an immediate neighbour of D.

(Here, Two possible cases: Case1: D sits immediate right of B. Case2: D sits immediate left of B)

4) Only one person sits between D and E. 

5) C sits second to the left of A.

6. G does not sit opposite A.  

 7) G is not an immediate neighbour of D. 

(Case2: we eliminated case 2)

This will be our final arrangement.

Hence, F and H are immediate neighbours of A.

Eight persons: A, B, C, D, E, F, G, and H

1) B sits third to the right of H. 

2) B sits third to the left of F.

3) Neither F nor H is not an immediate neighbour of D.

(Here, Two possible cases: Case1: D sits immediate right of B. Case2: D sits immediate left of B)

4) Only one person sits between D and E. 

5) C sits second to the left of A.

6. G does not sit opposite A.  

 7) G is not an immediate neighbour of D. 

(Case2: we eliminated case 2)

This will be our final arrangement.

Hence, C is sitting 3^rd to the right of E.