Reasoning PYQs

Persons: M, N, O, P, Q, R, S and T.

1. T sits third to the right of N.

2. P sits opposite to R and both sit on the corners. 

3. S sits second to the right of R.  

4. Q is adjacent to neither T nor N. 

5. M sits second to the left of O, who does not sit opposite to T. So, case 2 would be invalid. 

Hence, Q sits second to the left of N.

Persons: M, N, O, P, Q, R, S and T.

1. T sits third to the right of N.

2. P sits opposite to R and both sit on the corners. 

3. S sits second to the right of R.  

4. Q is adjacent to neither T nor N. 

5. M sits second to the left of O, who does not sit opposite to T. So, case 2 would be invalid. 

Hence, two persons sit between R and O when counted from left of O.

Persons: M, N, O, P, Q, R, S and T.

1. T sits third to the right of N.

2. P sits opposite to R and both sit on the corners. 

3. S sits second to the right of R.  

4. Q is adjacent to neither T nor N. 

5. M sits second to the left of O, who does not sit opposite to T. So, case 2 would be invalid. 

Hence, S sits opposite to T.

Persons: M, N, O, P, Q, R, S and T.

1. T sits third to the right of N.

2. P sits opposite to R and both sit on the corners. 

3. S sits second to the right of R.  

4. Q is adjacent to neither T nor N. 

5. M sits second to the left of O, who does not sit opposite to T. So, case 2 would be invalid. 

Hence, only statement 4) is correct.

Persons: M, N, O, P, Q, R, S and T.

1. T sits third to the right of N.

2. P sits opposite to R and both sit on the corners. 

3. S sits second to the right of R.  

4. Q is adjacent to neither T nor N. 

5. M sits second to the left of O, who does not sit opposite to T. So, case 2 would be invalid. 

Hence, S sits second to the left of P.

1. M weighs more than only two peoples

>> M >>

2) M weighs more than L but less than P. here we have 4 cases.

Case 1: P > ____ > M > L > ____

Case 2: ____ > P > M > L > ____

Case 3: P > ____ > M > _____ > L

Case 4: ____ > P > M > ____> L

3) N weighs less than O, whose weight is less than only one person. Here Case 2 and case 4 get eliminated.

Case 1: P > O > M > L > N

Case 3: P > O > M > N > L

Hence, We cannot determine who weighs least.

1. M weighs more than only two peoples.

>> M >>

2) M weighs more than L but less than P. here we have 4 cases.

Case 1: P > ____ > M > L > ____

Case 2: ____ > P > M > L > ____

Case 3: P > ____ > M > _____ > L

Case 4: ____ > P > M > ____> L

3) N weighs less than O, whose weight is less than only one person. Here Case 2 and case 4 get eliminated.

Case 1: P > O > M > L > N

Case 3: P > O > M > N > L

4. According to the Question If N weighs the least and M weighs 52kg then Case 3 will be cancelled. 

P > O > M > L > N

So probable weight for L will be between 45kg - 52kg

Hence, The Possible weight of L is 50Kg.

According to the given information,

The distance between point P1 and P6 = 7 + 6 = 13 km

Hence, 13 km is the correct answer.

According to the given information,

Hence, Southeast is the correct answer.

According to the given information,

Hence, Northwest is the correct answer.

1) A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not neighbour of T.

5. R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

 

Hence, T is sitting opposite to E.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not a neighbour of T.

5. R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

 

Hence, Both 1 and 2 (RC and BQ) are sitting diagonally opposite to each other.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not a neighbour of T.

5. R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

 

Here, opposite of R is B

And 3^rd to the right of B is D

Hence, D is third to the right of the one who is opposite to R.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not neighbour of T.

5. R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

 

Here, R, C, Q, B are sitting at the end of the rows except P.

Hence, P does not belong to that group.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not a neighbour of T.

5. R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

 

So,

(1) Opposite to D - True 

(2) Immediate neighbour of Q - True

(3) Second to the left of T - True

(4) Immediate left of the one who is opposite to A - True (Opposite to A is P, so S is the immediate neighbour of P)

Hence, All are correct.

The least possible Venn Diagram for the given data:

Conclusions:

I. Some stands are sticks → False (it is possible but not definite, as no direct relation between the two is given).

II. Some stands are poles → False (it is possible but not definite, as no direct relation between the two is given).

Hence, "Neither conclusion I nor II follows."

Venn diagram for the given statements are follows.

Conclusions

I. All Box being Bag is a possibility - False(Given Only Box are Pen means Pen cannot be others thus All Box being Bag is a possibility not follows)

II. Some Pen are copy - False (Because the relation between Pen and Copy is not given thus Some Pen are copy not follows)

Hence, Neither I nor II follows.

The least possible Venn diagram for the given statements is as follows:

 

 

Conclusions:

I. Some diary are earphones is a possibility → False (Because the relation of “only” is given between the elements, which implies that the element can positive relation with its object only)

II. Few laptops are books is a possibility → True (Because no definite positive or negative relation is defined between the elements)

Hence, only conclusion II follows

Additional Information

Meaning of word used in a syllogism:

1. Only means some + some not

2. Few means some 

3. If it is given only A is B then it means that the element can have relation with its object only.

The least possible Venn diagram for the given statements is as follows:

Conclusion:

I. No grapes are mango → False (as the relation of mango and apple is definite but the relation of mango is not definite with grapes)

II. Only a few mango are guava → False (as the relation between mango and apple is definite but the relation of mango and guava is not definite)

Hence, Neither I nor II follows.

According to the given information-

Hence, ‘red’ is coded as either ‘ca’ or ‘fo’.