Reasoning PYQs

The least possible Venn diagram for the given statements is as follows

I. Few disk are not flip →True (Because given only a few means that only some disk are flip remaining are not flip)

II. Some flip are computers → False (Because there is no relation between flip and computers)

Hence, Only I is true.

Important Points

Only a few is the case of some + some not and only few is consider as some.

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. Some pipes being powder is a possibility →True (As we can see that no direct relationship between the two is given, so the part of pipe which is not Brick can be the part of reamining powder which is not cement).

II. Some powder being bricks is a possibility → True (The remaining portion of powder which is not cement, can be the part of bricks, the possibility is true).

Hence, Both I and II follow

Possible Venn Diagram for given

Statements:

Conclusions:

Some flowers are stem. → False (as only leaves are flowers.)

No petal is flowers. → True (as only leaves are flowers.)

Hence, Only conclusion II is true.

The Least possible venn diagram is

conclusion I → True ( As we can see that some gentlemen are women, So this statement is true)

conclusion II → False (From below figure we can see that some women can be men and still all given statements stand true, hence no women is men is possible but not definite)

 

Hence Only conclusion I follow.

The least possible Venn diagram for the given statements is as follows

 I. Some cricketers are not players → False (It is a possibility but not definite as we have not given anything about cricketers with respect to the players)

 II. Some cricketers are rich → False (It is a possibility but not definite)

Hence, Neither I nor II follows.

Given words: PED      DFR      FIK      TIS     SND

1. Changing all letters to previous alphabet as per English alphabetical series:

ODC   CEQ   EHJ   SHR   RMC

2. Clearly, 3 words ODC   CEQ   EHJ have vowels.

Note:

In English alphabetical series there are 5 vowels i.e., A, E, I, O, U and remaining alphabets all are called consonants.

Hence, three words having vowels will be formed.

Given words: PED      DFR      FIK      TIS      SND

1. Arranging words in the order as they appear in a dictionary from right to left:

Left side    TIS    SND   PED    FIK   DFR   Right side

Hence, TIS  is the fifth from right.

Given words: PED      DFR      FIK      TIS      SND

Clearly two meaningful word  ITS and SIT can be formed.

Hence, two word can be formed.

Given words: PED      DFR      FIK      TIS      SND

1. First and last letter is replaced by immediate succeeding letter as per alphabetical series:

QEE      EFS      GIL      UIT      TNE

2. Clearly, two words QEE and UIT has more than one vowel.

Note:

In English alphabetical series there are 5 vowels i.e. A, E, I, O, U remaining alphabets are consonants.

Hence, two words have more than one vowel after rearrangement.

Given words: PED      DFR      FIK      TIS      SND

Left side   PED      DFR      FIK      TIS      SND  Right side

1. Second letter of the word which is fourth from the left side: PED      DFR      FIK      TIS     

2. First letter of the word which is first from the right side: SND

3. Clearly, there are 9 letters between I and S:

I  J  K  L  M  N  O P Q R S

Hence, 9 letters are between I and S.

Odd numbers → Next digit

Even numbers → Previous digit

 

Replaced number: 2 7 4 6 1 8 5

Second digit from left end: 7

Third digit from right end: 1

Sum of both the numbers: 7 + 1 = 8

Hence, ‘8’ is the right answer.

Family tree,

1.R is male member of the family 2. L is the only son of C, who is the brother of R 3. T is the wife of L 4. Q is the daughter in law of P, who is grand mother of L. 

Two cases will be 

        

5.T is not a daughter in law of Q. hence final arrangement will be

 

Hence C is brother in law of Q.

Family tree,

1.R is male member of the family 2. L is the only son of C, who is the brother of R 3. T is the wife of L 4. Q is the daughter in law of P, who is grand mother of L. 

Two cases will be 

        

5.T is not a daughter in law of Q. hence final arrangement will be

 

L is the Nephew of R.

Family tree,

1.R is male member of the family 2. L is the only son of C, who is the brother of R 3. T is the wife of L 4. Q is the daughter in law of P, who is grand mother of L. 

Two cases will be 

        

5.T is not a daughter in law of Q. hence final arrangement will be

 

Hence, T is the wife of L, who is Nephew of Q.

From the given information,

Row 1: A, B, C, D and E are facing South

Row 2: P, Q, R, S and T are facing North

1. T sits third to the left of S.

Following are the possibilities we get:

Case 1:

Case 2:

2. B faces immediate neighbor of T.

3. A sit second to the right of B.

The above conditions are not satisfied in case 2. So, it will be eliminated.

Case 1:

4. Only one person sits between C and E.

Case 1 (a):

Case 1 (b):

5. R and Q are immediate neighbours.

6. Q faces neither B nor C.

7. P doesn’t face D.

The above conditions are not satisfied in case 1 (b). So, it will be eliminated.

The final arrangement will be as shown below:

Hence, two persons are sitting between C and D.

From the given information,

Row 1: A, B, C, D and E are facing South

Row 2: P, Q, R, S and T are facing North

1. T sits third to the left of S.

Following are the possibilities we get:

Case 1:

Case 2:

2. B faces immediate neighbor of T.

3. A sit second to the right of B.

The above conditions are not satisfied in case 2. So, it will be eliminated.

Case 1:

4. Only one person sits between C and E.

Case 1 (a):

Case 1 (b):

5. R and Q are immediate neighbors.

6. Q faces neither B nor C.

7. P doesn’t face D.

The above conditions are not satisfied in case 1 (b). So, it will be eliminated.

The final arrangement will be as shown below:

Hence, Q faces E.

From the given information,

Row 1: A, B, C, D and E are facing South

Row 2: P, Q, R, S and T are facing North

1. T sits third to the left of S.

Following are the possibilities we get:

Case 1:

Case 2:

2. B faces immediate neighbor of T.

3. A sit second to the right of B.

The above conditions are not satisfied in case 2. So, it will be eliminated.

Case 1:

4. Only one person sits between C and E.

Case 1 (a):

Case 1 (b):

5. R and Q are immediate neighbors.

6. Q faces neither B nor C.

7. P doesn’t face D.

The above conditions are not satisfied in case 1 (b). So, it will be eliminated.

The final arrangement will be as shown below:

Hence, none of these is correct.

From the given information,

Row 1: A, B, C, D and E are facing South

Row 2: P, Q, R, S and T are facing North

1. T sits third to the left of S.

Following are the possibilities we get:

Case 1:

Case 2:

2. B faces immediate neighbor of T.

3. A sit second to the right of B.

The above conditions are not satisfied in case 2. So, it will be eliminated.

Case 1:

4. Only one person sits between C and E.

Case 1 (a):

Case 1 (b):

5. R and Q are immediate neighbors.

6. Q faces neither B nor C.

7. P doesn’t face D.

The above conditions are not satisfied in case 1 (b). So, it will be eliminated.

The final arrangement will be as shown below:

Hence, B and R are sitting exactly in the middle of the rows.

From the given information,

Row 1: A, B, C, D and E are facing South

Row 2: P, Q, R, S and T are facing North

1. T sits third to the left of S.

Following are the possibilities we get:

Case 1:

Case 2:

2. B faces immediate neighbor of T.

3. A sit second to the right of B.

The above conditions are not satisfied in case 2. So, it will be eliminated.

Case 1:

4. Only one person sits between C and E.

Case 1 (a):

Case 1 (b):

5. R and Q are immediate neighbors.

6. Q faces neither B nor C.

7. P doesn’t face D.

The above conditions are not satisfied in case 1 (b). So, it will be eliminated.

The final arrangement will be as shown below:

All persons except Q, are sitting at the extreme ends of the lines.

Hence, Q doesn’t belong to the group.

One pair is there in the word 'OBLIGATE', each of which has as many letters between them in the word (both forward and backward direction) as they have between them in the English Alphabet.

Mistake Points In this type of question we have to count from A to Z, reverse counting Z to A is not considered. Therefore Y- A is not the correct pair