Reasoning PYQs

Given: Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

2.  Exactly three people travel between R and Y.

 

3. There are two people between P and Y.

 

4. P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

 

5. Two people travel between R and L.

 

6. T travels immediately after L.

 

7. X does not travel in a month that has 30 days. 

 

8. X does not travel before P. 

Now, we can eliminate Case 4.

This is our final arrangement,

 

Hence, the correct answer is July.

Given: Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

2.  Exactly three people travel between R and Y.

 

3. There are two people between P and Y.

 

4. P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

 

5. Two people travel between R and L.

 

6. T travels immediately after L.

 

7. X does not travel in a month that has 30 days. 

 

8. X does not travel before P. 

Now, we can eliminate Case 4.

This is our final arrangement,

 

Hence, the correct answer is None.

Given: Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

 

2.  Exactly three people travel between R and Y.

 

3. There are two people between P and Y.

 

4. P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

 

5. Two people travel between R and L.

 

6. T travels immediately after L.

 

7. X does not travel in a month that has 30 days. 

 

8. X does not travel before P. 

Now, we can eliminate Case 4.

This is our final arrangement,

 

Except for L, all others travel in a 31-day month.

Hence, the correct answer is L.

Statement:

R ≤ T ≤ S = P < U > W ≥ X > Y

Let us check each conclusion one by one.

I) T = P But T ≤ P → False

II) U > R → True

III) S > Y → No relation between S and Y can be established.

Hence, only conclusion II follows.

Statements:

R ≥ P = O > U ≤ M = B

Conclusions:

I. B ≥ O → O > U and U ≤ B → Relation between B and O is not clear. Hence false.

II. R > M →R > U and U ≤ M→ Relation between R and M is not clear. Hence false.

III. P = B → P > U and U ≤ B → Relation between P and B is not clear. Hence false.

Hence none of the given conclusions are true.

Conclusion:

P > C → P > T and T > C → P > C

T < S → T > C and C > S → T > S

Hence, only conclusions I follow.

Given series: 545 644 784 527 898

Largest no is in the series: 898

Smallest no is in the series: 527

2^nd digit of largest no: 9

3^rd digit of smallest no: 7

After multiplying this: 9*7 = 63

Given series: 545 644 784 527 898

Interchanging the 1^st and 3^rd digits: 545 446 487 725 898

hence 2 even number, which came from 644, 898

Given series: 545 644 784 527 898

Subtracting 2 from the 2^nd digit: 525 624 764 507 878

interchanging the 1^st and the 3^rd digit: 525 426 467 705 878

So 426 is the lowest number, which came from 644.

Given series: 545 644 784 527 898

Adding 4 to the 1^st digit: 945 1044 1184 927 1298

interchanging the 2^nd and the 3^rd digit: 954 1404 1814 972 1928

So, 1928 is highest number which came from 898.

Given series: 545 644 784 527 898

on multiplying 1^st and last digits:

545: 5*5 = 25

644: 6*4 = 24

784: 7*4 = 28

527: 5*7 = 35

898: 8*8 = 64

here 35 and 25 are only divisible by 5.

Hence answer is 527 and 545.

Here, persons are A, B, C, D, E, F and G.

1. Two persons sit between B and E.

2. F is a neighbour of both C and B.

3. C is not a neighbour of E.

4. D sits third to the right of C.

5. G sits three places away from A. Therefore, case 1 is eliminated.

6. A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Hence, F sits third to the left of E.

Here, persons are A, B, C, D, E, F and G.

1. Two persons sit between B and E.

2. F is a neighbour of both C and B.

3. C is not a neighbour of E.

4. D sits third to the right of C.

5. G sits three places away from A. Therefore, case 1 is eliminated.

6. A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, B sits second to the right of D. Therefore, statement I is correct.

C sits immediate right to F. Therefore, statement II is correct.

A sits second to the left of D. Therefore, statement III is correct.

Therefore, the correct answer is none of these.

Here, persons are A, B, C, D, E, F and G.

1. Two persons sit between B and E.

2. F is a neighbour of both C and B.

3. C is not a neighbour of E.

4. D sits third to the right of C.

5. G sits three places away from A. Therefore, case 1 is eliminated.

6. A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, each pair represents number of persons sitting between them is either two or three but between A and F either one or four persons sit.

Hence, the odd one is AF.

Here, persons are A, B, C, D, E, F and G.

1. Two persons sit between B and E.

2. F is a neighbour of both C and B.

3. C is not a neighbour of E.

4. D sits third to the right of C.

5. G sits three places away from A. Therefore, case 1 is eliminated.

6. A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, A sits immediate right to C. Therefore, statement I is correct.

E sits immediate right to A not second left. Therefore, statement II is incorrect.

III. G is a immediate neighbour of D and B not C. Therefore, statement III is incorrect.

Hence, the correct answer is only I.

Here, persons are A, B, C, D, E, F and G.

1. Two persons sit between B and E.

2. F is a neighbour of both C and B.

3. C is not a neighbour of E.

4. D sits third to the right of C.

5. G sits three places away from A. Therefore, case 1 is eliminated.

6. A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, C sits second to the right of B and D sits third to the right of C.

Hence, the correct answer is D.

From the given information,

1. X is the father of Y, who is the son of Z. (means Y is the son of Z).

2. Z is the daughter of S, who is the husband of P. (means S is the husband of P).

3. X is the brother of T.

4. W is the mother of T. W has only one daughter. (Means T is the sister of X).

S is the father-in-law of X.

From the given information,

1. X is the father of Y, who is the son of Z. (means Y is the son of Z).

2. Z is the daughter of S, who is the husband of P. (means S is the husband of P).

3. X is the brother of T.

4. W is the mother of T. W has only one daughter. (Means T is the sister of X).

Hence, T is the sister-in-law of Z.

From the given information,

1. X is the father of Y, who is the son of Z. (means Y is the son of Z).

2. Z is the daughter of S, who is the husband of P. (means S is the husband of P).

3. X is the brother of T.

4. W is the mother of T. W has only one daughter. (Means T is the sister of X).

Hence, S is the grandfather of Y.

Given number: 743625814

Operation: Even digits are subtracted by 1 and odd digits are added by 1

 

Since, second digit from from left end is '3' and third digit from the right end is '7'.

Therefore, their product is 7×3 = 21.

Hence, the correct answer is 21.