Official Paper

RRB Clerk Prelims Memory Based Paper (Held On: 6 Dec 2025 Shift 2) (Previous Year Paper)

80 questions · 45 minutes · with answers · free

Reasoning (40 questions)

Directions: Read the information and answer the given questions.

Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

Box Q is placed below box T. Box P is placed immediately above box R. Box S is placed immediately above box U. The box just below box S is placed three positions below box V. Exactly two boxes are placed between box R and box S. Box U occupies an even prime-numbered position.

Which among the following box is placed at the bottom-most position?

((a))
V
((b))
U
((c))
Q
((d))
T
((e))
R

Show Answer

Answer: ((c))

Given: Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

Box U occupies an even prime-numbered position.

Box no.	Boxes
7
6
5
4
3
2	U
1

2. Box S is placed immediately above box U.

Box no.	Boxes
7
6
5
4
3	S
2	U
1

3. Exactly two boxes are placed between box R and box S.

Box no.	Boxes
7
6	R
5
4
3	S
2	U
1

Box P is placed immediately above box R.

Box no.	Boxes
7	P
6	R
5
4
3	S
2	U
1

The box just below box S is placed three positions below box V.

Box no.	Boxes
7	P
6	R
5	V
4
3	S
2	U
1

Box Q is placed below box T.

This is our final arrangement,

Box no.	Boxes
7	P
6	R
5	V
4	T
3	S
2	U
1	Q

Hence, the correct answer is Q.

How many boxes are placed between box T and box V?

((a))
Same as boxes kept below V
((b))
Same as boxes between S and U
((c))
Same as boxes between T and R
((d))
Same as boxes kept above Q
((e))
None of these

Show Answer

Answer: ((b))

Same as boxes between S and U

Given: Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

1. Box U occupies an even prime-numbered position.

Box no.	Boxes
7
6
5
4
3
2	U
1

2. Box S is placed immediately above box U.

Box no.	Boxes
7
6
5
4
3	S
2	U
1

3. Exactly two boxes are placed between box R and box S.

Box no.	Boxes
7
6	R
5
4
3	S
2	U
1

Box P is placed immediately above box R.

Box no.	Boxes
7	P
6	R
5
4
3	S
2	U
1

The box just below box S is placed three positions below box V.

Box no.	Boxes
7	P
6	R
5	V
4
3	S
2	U
1

Box Q is placed below box T.

This is our final arrangement,

Box no.	Boxes
7	P
6	R
5	V
4	T
3	S
2	U
1	Q

Hence, the correct answer is Same as boxes between S and U.

Which of the following statements regarding box P is true?

((a))
Box T is placed two boxes below box P.
((b))
Two boxes are placed between P and U.
((c))
Box Q is placed above P.
((d))
P is placed in an odd-numbered position.
((e))
All are true.

Show Answer

Answer: ((d))

P is placed in an odd-numbered position.

Given: Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

1. Box U occupies an even prime-numbered position.

Box no.	Boxes
7
6
5
4
3
2	U
1

2. Box S is placed immediately above box U.

Box no.	Boxes
7
6
5
4
3	S
2	U
1

3. Exactly two boxes are placed between box R and box S.

Box no.	Boxes
7
6	R
5
4
3	S
2	U
1

Box P is placed immediately above box R.

Box no.	Boxes
7	P
6	R
5
4
3	S
2	U
1

The box just below box S is placed three positions below box V.

Box no.	Boxes
7	P
6	R
5	V
4
3	S
2	U
1

Box Q is placed below box T.

This is our final arrangement,

Box no.	Boxes
7	P
6	R
5	V
4	T
3	S
2	U
1	Q

Hence, the correct answer is P is placed in an odd-numbered position.

Four of the following five form a group based on a certain pattern. Which one does NOT belong?

((a))
S
((b))
Q
((c))
P
((d))
R
((e))
V

Show Answer

Answer: ((d))

Given: Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

1. Box U occupies an even prime-numbered position.

Box no.	Boxes
7
6
5
4
3
2	U
1

2. Box S is placed immediately above box U.

Box no.	Boxes
7
6
5
4
3	S
2	U
1

3. Exactly two boxes are placed between box R and box S.

Box no.	Boxes
7
6	R
5
4
3	S
2	U
1

Box P is placed immediately above box R.

Box no.	Boxes
7	P
6	R
5
4
3	S
2	U
1

The box just below box S is placed three positions below box V.

Box no.	Boxes
7	P
6	R
5	V
4
3	S
2	U
1

Box Q is placed below box T.

This is our final arrangement,

Box no.	Boxes
7	P
6	R
5	V
4	T
3	S
2	U
1	Q

Except for R, all others are placed in an odd-numbered position.

Hence, the correct answer is R.

What is the position of box U with respect to box R?

((a))
Three boxes below
((b))
Immediately below
((c))
Two boxes above
((d))
Two boxes below
((e))
Four boxes below

Show Answer

Answer: ((e))

Four boxes below

Given: Seven boxes, namely, P, Q, R, S, T, U, and V, are stacked vertically, where position 1 is the bottom and position 7 is the top.

1. Box U occupies an even prime-numbered position.

Box no.	Boxes
7
6
5
4
3
2	U
1

2. Box S is placed immediately above box U.

Box no.	Boxes
7
6
5
4
3	S
2	U
1

3. Exactly two boxes are placed between box R and box S.

Box no.	Boxes
7
6	R
5
4
3	S
2	U
1

Box P is placed immediately above box R.

Box no.	Boxes
7	P
6	R
5
4
3	S
2	U
1

The box just below box S is placed three positions below box V.

Box no.	Boxes
7	P
6	R
5	V
4
3	S
2	U
1

Box Q is placed below box T.

This is our final arrangement,

Box no.	Boxes
7	P
6	R
5	V
4	T
3	S
2	U
1	Q

Hence, the correct answer is Four boxes below.

How many pairs of letters are there in the word 'COVALENT" which have as many letters between them as in the English alphabetical series (both in backward and inward direction)?

((a))
One
((b))
Three
((c))
None
((d))
Two
((e))
More than three

Show Answer

Answer: ((d))

Two

Given word: COVALENT.

Forward pair: LN

Backward pair: LO

Thus, there are two such pairs of letters in the word "COVALENT" which have as many letters between them as in the English alphabetical series (both in backward and forward directions).

Hence, the correct answer is two.

Direction: Read the following information carefully and answer the questions based on given information.

A certain number of persons sit on a linear row facing towards north direction. Q sits four places away from K. Two persons sit between S and M who sits to the right of S. Three persons sit between R and F. R sits three places away from V who sits at the one of the end position. One person sits between F and M who sits to the left of F. S sits third to the right of Q. The number of persons sit to the left of Q is two less than that of to the right of F. K and S do not sit adjacent to each other.

How many persons sit between K and M?

((a))
Four persons
((b))
Six persons
((c))
Eight persons
((d))
Five persons
((e))
Nine persons

Show Answer

Answer: ((e))

Nine persons

Given: A certain number of persons sit on a linear row facing towards north direction.

R sits three places away from V who sits at the one of the end position.
Three persons sit between R and F.
One person sits between F and M who sits to the left of F.

Two persons sit between S and M who sits to the right of S.
S sits third to the right of Q. Therefore, case 1 is eliminated.
The number of persons sit to the left of Q is two less than that of to the right of F.

Q sits four places away from K.
K and S do not sit adjacent to each other. Hence, the final arrangement is as follows

Hence, nine persons sit between K and M.

Which of the following statement(s) is/are correct?

I. K sits to the right of Q.

II. Prime number of persons sit to the left of Q.

III. S sits exactly between M and Q.

((a))
Only I and III
((b))
Only II and III
((c))
Only I and II
((d))
All of these
((e))
Only I

Show Answer

Answer: ((b))

Only II and III

Given: A certain number of persons sit on a linear row facing towards north direction.

R sits three places away from V who sits at the one of the end position.
Three persons sit between R and F.
One person sits between F and M who sits to the left of F.

Two persons sit between S and M who sits to the right of S.
S sits third to the right of Q. Therefore, case 1 is eliminated.
The number of persons sit to the left of Q is two less than that of to the right of F.

Q sits four places away from K.
K and S do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, K sits to the left of Q not to the right. Therefore, statement I is incorrect.

Five persons which is a prime number sit to the left of Q. Therefore, statement II is correct.

S sits exactly between M and Q. Therefore, statement III is correct.

Hence, the correct answer is only II and III.

What is the position of F with respect to S?

((a))
Second to the left
((b))
Second to the right
((c))
Fifth to the right
((d))
Third to the left
((e))
Immediate right

Show Answer

Answer: ((c))

Fifth to the right

Given: A certain number of persons sit on a linear row facing towards north direction.

R sits three places away from V who sits at the one of the end position.
Three persons sit between R and F.
One person sits between F and M who sits to the left of F.

Two persons sit between S and M who sits to the right of S.
S sits third to the right of Q. Therefore, case 1 is eliminated.
The number of persons sit to the left of Q is two less than that of to the right of F.

Q sits four places away from K.
K and S do not sit adjacent to each other. Hence, the final arrangement is as follows

Hence, F sits fifth to the right of S.

Direction: In the question below are given two statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statement:

All whatsapp is facebook.

All facebook is instagram.

Only a few instagram is twitter.

Conclusion:

I. No twitter is facebook.

II. Some twitter is facebook.

((a))
Only I follows
((b))
Only II follows
((c))
Either I or II follows
((d))
Neither I nor II follows
((e))
Both I and II follow

Show Answer

Answer: ((c))

Either I or II follows

The least possible diagram for the given statements is as follows

Conclusions:

I. No twitter is facebook. → False (It is possible but not definite)

II. Some twitter is facebook. → False (It is possible but not definite)

Both are complementary conclusions.

Hence, either I or II follows

Directions: In the question below is given three statements followed by two conclusions I and II. You have to take the given statements to be true even if they seem to be at variances from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding the commonly known facts.

Statements:

No rat is a cat.

Some cats are dogs.

Some dogs are horses.

Conclusions:

I. Some cats are not horses is a possibility.

II. Some dogs are not rats.

((a))
If only conclusion I follows.
((b))
If only conclusion II follows.
((c))
If either conclusion I or II follows.
((d))
If neither conclusion I nor II follows.
((e))
If both conclusions I and II follows.

Show Answer

Answer: ((e))

If both conclusions I and II follows.

The least possible Venn diagram is as follows,

A picture containing objectDescription automatically generated

Conclusions:

I. Some cats are not horses is a possibility → Possibility is true.

II. Some dogs are not rats → True.

Hence, both conclusions I and II follows.

Statements:

All Gold are Green.

Some Green are Black.

Some Black are White.

Conclusions:

I. Some White are Gold.

II. Some Gold are Black.

((a))
If neither conclusion I nor II follows
((b))
If only conclusion II follows
((c))
If either conclusion I or II follows
((d))
If only conclusion I follows
((e))
If both conclusions I and II follows

Show Answer

Answer: ((a))

If neither conclusion I nor II follows

The least possible Venn diagram is as follows:

Conclusions:

I. Some White are Gold → False (As there is no direct relation between White and Gold. It is possible but not definite. So, it is false)

II. Some Gold are Black → False (As there is no direct relation between Black and Gold. It is possible but not definite. So, it is false)

Hence, Neither conclusion I nor II follows.

Direction: In the question given below statements are followed by some conclusions. You have to take the given statements to be True even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions definitely does not follow from the given statements disregarding commonly known facts.

Statements:

Some Rabbit are not Mouse.

All Mouse are Bird.

No Bird is Nest.

Conclusions:

Some Nest is Mouse.
Some Mouse is Bird.
All Rabbit is Mouse is possible.

((a))
Only 1 and 3
((b))
Only 2
((c))
Only 2 and 3
((d))
All of the above
((e))
None of the above

Show Answer

Answer: ((a))

Only 1 and 3

Some Nest is Mouse → False (As All Bird is Nest, all part of Bird means Mouse is Nest. So, it is false)
Some Mouse is Bird → True (As All Mouse is Bird → Some Mouse is Bird. So, it is true)
All Rabbit is Mouse is possible → False (Some rabbit are not mouse. So, All Rabbit will not be Mouse. so, it is false)

Hence, Only conclusions 1 and 3 does not follow here.

Direction: Study the following information carefully to answer the given questions:

¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 ©

Which of the following is the fifth to the left of the ninth element from the left end of the above arrangement?

((a))
((b))
9
((c))
%
((d))
E
((e))
None of these

Show Answer

Answer: ((a))

Given series:

Left side ¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 © right side

As, left – left = left

9^th from the left – 5^th from the left = 4^th from the left

Clearly, 4^th from the left is #.

How many such symbols are there in the above arrangement each of which are immediately preceded by a number and followed by an alphabet?

((a))
Four
((b))
Two
((c))
One
((d))
Three
((e))
More than three

Show Answer

Answer: ((c))

One

Given series:

Left Side ¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 © Right Side

Symbols which are immediately preceded by a number and followed by an alphabet:

¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 ©

Hence, there is 1 symbol which is immediately preceded by number and followed by an alphabet: 6 # J

After removing the alphabets and symbols arrange the remaining numbers in ascending order. Which of the set of numbers will be correct in the given option?

((a))
97 6 5 4 1
((b))
1 4 5 6 7 9
((c))
1 5 4 6 7 9
((d))
1 4 5 7 6 9
((e))
9 7 5 6 4 1

Show Answer

Answer: ((b))

1 4 5 6 7 9

Given series:

Left Side ¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 © Right Side

After removing the alphabets and symbols will get the series as 6 4 5 7 1 9

The ascending order is 1 4 5 6 7 9. Hence option 2 is correct.

If all the symbols in the above arrangement are dropped, then which of the following will be the tenth from the right end?

((a))
2
((b))
8
((c))
I
((d))
9
((e))
None of these

Show Answer

Answer: ((e))

None of these

Given series:

Left Side ¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 © Right Side

1) If all the symbols are dropped:

R 6 J K 4 5 L 7 1 M N J H G 9

10^th letter/number from the right end is 5.

Then, letter/ number that is tenth from right end is ‘5’.

How many such symbols are there in the above arrangement each of which is immediately followed by a number and also preceded by a number?

((a))
Four
((b))
One
((c))
Two
((d))
Three
((e))
Five

Show Answer

Answer: ((c))

Two

Given series:

Left Side ¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 © Right Side

Symbols which are immediately followed by a number and preceded by a number:

¥ R 6 # J K 4 @ 5 L 7 * 1 M N $ J H £ G 9 ©.

Hence, there are two sets which are immediately followed by number and preceded by number.

Directions: Read the information and answer the given questions.

Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

There are two people between P and Y. Two people travel between R and L. R travels in a month that has 31 days. T travels immediately after L. P travels earlier than R. X does not travel before P. X does not travel in a month that has 30 days. Exactly three people travel between R and Y.

Who among the following travels immediately before X?

((a))
Y
((b))
M
((c))
P
((d))
R
((e))
L

Show Answer

Answer: ((d))

Given: Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R
April (30)
May (31)		R
June (30)
July (31)			R
August (31)				R
September (30)

2. Exactly three people travel between R and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)				Y
May (31)		R
June (30)
July (31)	Y		R
August (31)				R
September (30)		Y

3. There are two people between P and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)	P			Y
May (31)		R
June (30)		P	P
July (31)	Y		R	P
August (31)				R
September (30)		Y

P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)		Y
May (31)
June (30)	P
July (31)	R	P
August (31)		R
September (30)

Two people travel between R and L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)		L
June (30)	P
July (31)	R	P
August (31)		R
September (30)

T travels immediately after L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)		R
September (30)

7. X does not travel in a month that has 30 days.

Months	Persons
Case 3	Case 4
March (31)	Y	X
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)	X	R
September (30)

X does not travel before P.

Now, we can eliminate Case 4.

This is our final arrangement,

Months	Persons
Case 3
March (31)	Y
April (30)	L
May (31)	T
June (30)	P
July (31)	R
August (31)	X
September (30)	M

Hence, the correct answer is R.

Who among the following travels in April?

((a))
L
((b))
R
((c))
T
((d))
M
((e))
Y

Show Answer

Answer: ((a))

Given: Seven individuals, namely, X, P, L, R, M, T, and Y, are planning a vacation to Canada, each traveling in a different month among March, April, May, June, July, August, and September, but not necessarily in this order.

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R
April (30)
May (31)		R
June (30)
July (31)			R
August (31)				R
September (30)

2. Exactly three people travel between R and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)				Y
May (31)		R
June (30)
July (31)	Y		R
August (31)				R
September (30)		Y

3. There are two people between P and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)	P			Y
May (31)		R
June (30)		P	P
July (31)	Y		R	P
August (31)				R
September (30)		Y

P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)		Y
May (31)
June (30)	P
July (31)	R	P
August (31)		R
September (30)

Two people travel between R and L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)		L
June (30)	P
July (31)	R	P
August (31)		R
September (30)

T travels immediately after L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)		R
September (30)

7. X does not travel in a month that has 30 days.

Months	Persons
Case 3	Case 4
March (31)	Y	X
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)	X	R
September (30)

X does not travel before P.

Now, we can eliminate Case 4.

This is our final arrangement,

Months	Persons
Case 3
March (31)	Y
April (30)	L
May (31)	T
June (30)	P
July (31)	R
August (31)	X
September (30)	M

Hence, the correct answer is L.

In which of the following months does R take the trip?

((a))
June
((b))
July
((c))
August
((d))
March
((e))
May

Show Answer

Answer: ((b))

July

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R
April (30)
May (31)		R
June (30)
July (31)			R
August (31)				R
September (30)

2. Exactly three people travel between R and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)				Y
May (31)		R
June (30)
July (31)	Y		R
August (31)				R
September (30)		Y

3. There are two people between P and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)	P			Y
May (31)		R
June (30)		P	P
July (31)	Y		R	P
August (31)				R
September (30)		Y

P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)		Y
May (31)
June (30)	P
July (31)	R	P
August (31)		R
September (30)

Two people travel between R and L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)		L
June (30)	P
July (31)	R	P
August (31)		R
September (30)

T travels immediately after L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)		R
September (30)

7. X does not travel in a month that has 30 days.

Months	Persons
Case 3	Case 4
March (31)	Y	X
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)	X	R
September (30)

X does not travel before P.

Now, we can eliminate Case 4.

This is our final arrangement,

Months	Persons
Case 3
March (31)	Y
April (30)	L
May (31)	T
June (30)	P
July (31)	R
August (31)	X
September (30)	M

Hence, the correct answer is July.

How many individuals travel between M and X?

((a))
One
((b))
Two
((c))
None
((d))
Four
((e))
More than four

Show Answer

Answer: ((c))

None

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R
April (30)
May (31)		R
June (30)
July (31)			R
August (31)				R
September (30)

2. Exactly three people travel between R and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)				Y
May (31)		R
June (30)
July (31)	Y		R
August (31)				R
September (30)		Y

3. There are two people between P and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)	P			Y
May (31)		R
June (30)		P	P
July (31)	Y		R	P
August (31)				R
September (30)		Y

P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)		Y
May (31)
June (30)	P
July (31)	R	P
August (31)		R
September (30)

Two people travel between R and L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)		L
June (30)	P
July (31)	R	P
August (31)		R
September (30)

T travels immediately after L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)		R
September (30)

7. X does not travel in a month that has 30 days.

Months	Persons
Case 3	Case 4
March (31)	Y	X
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)	X	R
September (30)

X does not travel before P.

Now, we can eliminate Case 4.

This is our final arrangement,

Months	Persons
Case 3
March (31)	Y
April (30)	L
May (31)	T
June (30)	P
July (31)	R
August (31)	X
September (30)	M

Hence, the correct answer is None.

Four of the following five letters are similar in a certain way. Identify the one that does not belong to the group.

((a))
Y
((b))
X
((c))
R
((d))
L
((e))
T

Show Answer

Answer: ((d))

1. R travels in a month that has 31 days.

Here, we have 3 Cases, i.e., Case 1, Case 2, Case 3, and Case 4.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R
April (30)
May (31)		R
June (30)
July (31)			R
August (31)				R
September (30)

2. Exactly three people travel between R and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)				Y
May (31)		R
June (30)
July (31)	Y		R
August (31)				R
September (30)		Y

3. There are two people between P and Y.

Months	Persons
Case 1	Case 2	Case 3	Case 4
March (31)	R		Y
April (30)	P			Y
May (31)		R
June (30)		P	P
July (31)	Y		R	P
August (31)				R
September (30)		Y

P travels earlier than R.

Now, we can eliminate Case 1 and Case 2.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)		Y
May (31)
June (30)	P
July (31)	R	P
August (31)		R
September (30)

Two people travel between R and L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)		L
June (30)	P
July (31)	R	P
August (31)		R
September (30)

T travels immediately after L.

Months	Persons
Case 3	Case 4
March (31)	Y
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)		R
September (30)

7. X does not travel in a month that has 30 days.

Months	Persons
Case 3	Case 4
March (31)	Y	X
April (30)	L	Y
May (31)	T	L
June (30)	P	T
July (31)	R	P
August (31)	X	R
September (30)

X does not travel before P.

Now, we can eliminate Case 4.

This is our final arrangement,

Months	Persons
Case 3
March (31)	Y
April (30)	L
May (31)	T
June (30)	P
July (31)	R
August (31)	X
September (30)	M

Except for L, all others travel in a 31-day month.

Hence, the correct answer is L.

Directions: In the question, relationship between different elements is shown in the statements. The statements are followed by two conclusions.

Statement:

R ≤ T ≤ S = P < U > W ≥ X > Y

Conclusions:

I) T = P

II) U > R

III) S > Y

((a))
Only (I)
((b))
Only (II)
((c))
Only (III)
((d))
Both (I) and (II)
((e))
Both (II) and (III)

Show Answer

Answer: ((b))

Only (II)

Statement: R ≤ T ≤ S = P < U > W ≥ X > Y

Let us check each conclusion one by one.

I) T = P But T ≤ P → False

II) U > R → True

III) S > Y → No relation between S and Y can be established.

Hence, only conclusion II follows.

Directions: In the following question, relationship between different elements is shown in the statement. The statement is followed by conclusions, give answer.

Statements:

R ≥ P = O > U ≤ M = B

Conclusions:

I. B ≥ O

II. R > M

III. P = B

((a))
Only conclusion I is true
((b))
Only conclusion III is true
((c))
Either conclusion I or II is true
((d))
All are true
((e))
None is true

Show Answer

Answer: ((e))

None is true

Statements:

R ≥ P = O > U ≤ M = B

Conclusions:

I. B ≥ O → O > U and U ≤ B → Relation between B and O is not clear. Hence false.

II. R > M →R > U and U ≤ M→ Relation between R and M is not clear. Hence false.

III. P = B → P > U and U ≤ B → Relation between P and B is not clear. Hence false.

Hence none of the given conclusions are true.

Directions: In the following question, relationship between different elements is shown in the statements. These statements are followed by two conclusions.

Statements:

P ≥ M > T > A = C > S

Conclusions:

P > C
T < S

((a))
Only conclusion I follows
((b))
Only conclusion II follows
((c))
Either conclusion I or II follows
((d))
Neither conclusion I nor II follows
((e))
Both conclusions I and II follow

Show Answer

Answer: ((a))

Only conclusion I follows

Conclusion:

P > C → P > T and T > C → P > C

T < S → T > C and C > S → T > S

Hence, only conclusions I follow.

Directions: The following questions are based on the three digits five numbers given below.

545 644 784 527 898

What will be the number obtained if 2^nd digit of the largest number is multiplied with 3^rddigit of the smallest number?

((a))
64
((b))
57
((c))
63
((d))
54
((e))
44

Show Answer

Answer: ((c))

Given series: 545 644 784 527 898

Largest no is in the series: 898

Smallest no is in the series: 527

2^nd digit of largest no: 9

3^rd digit of smallest no: 7

After multiplying this: 9*7 = 63

If in each number 1^st and 3^rd digits are interchanged, then how many even numbers are there?

((a))
1
((b))
2
((c))
3
((d))
4
((e))
5

Show Answer

Answer: ((b))

Given series: 545 644 784 527 898

Interchanging the 1^st and 3^rd digits: 545 446 487 725 898

hence 2 even number, which came from 644, 898

If 2 is subtracted from the 2^nd digit of each number and then the positions of the 1^st and the 3^rd digit are interchanged, which of the following will be the lowest number?

((a))
545
((b))
527
((c))
898
((d))
784
((e))
644

Show Answer

Answer: ((e))

644

Given series: 545 644 784 527 898

Subtracting 2 from the 2^nd digit: 525 624 764 507 878

interchanging the 1^st and the 3^rd digit: 525 426 467 705 878

So 426 is the lowest number, which came from 644.

If 4 is added to the 1^st digit of each number and then the positions of the 2^nd and the 3^rd digits are interchanged, which of the following will be the highest number?

((a))
545
((b))
527
((c))
898
((d))
784
((e))
644

Show Answer

Answer: ((c))

898

Given series: 545 644 784 527 898

Adding 4 to the 1^st digit: 945 1044 1184 927 1298

interchanging the 2^nd and the 3^rd digit: 954 1404 1814 972 1928

So, 1928 is highest number which came from 898.

If the 1^st and 3^rd digit of each of the number are multiplied then the resultant of which of the following numbers will be divisible by 5?

((a))
644
((b))
545 and 527
((c))
527 and 898
((d))
545
((e))
644 and 784

Show Answer

Answer: ((b))

545 and 527

Given series: 545 644 784 527 898

on multiplying 1st and last digits:

545: 5*5 = 25

644: 6*4 = 24

784: 7*4 = 28

527: 5*7 = 35

898: 8*8 = 64

here 35 and 25 are only divisible by 5.

Hence answer is 527 and 545.

Direction: Read the following information carefully and answer the questions based on given information.

Seven persons A, B, C, D, E, F and G sit around a circular table and facing towards the centre but not necessarily in same order. C is not a neighbour of E. G sits three places away from A. Two persons sit between B and E. F is a neighbour of both C and B. D sits third to the right of C. A and B do not sit adjacent to each other.

Who among the following person sits third to the left of E?

((a))
G
((b))
B
((c))
C
((d))
F
((e))
A

Show Answer

Answer: ((d))

Here, persons are A, B, C, D, E, F and G.

Two persons sit between B and E.
F is a neighbour of both C and B.
C is not a neighbour of E.

D sits third to the right of C.
G sits three places away from A. Therefore, case 1 is eliminated.
A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Hence, F sits third to the left of E.

Which of the following statement(s) is/are incorrect?

I. B sits second to the right of D.

II. C sits immediate right to F.

III. A sits second to the left of D.

((a))
Only I and II
((b))
Only I and III
((c))
All of these
((d))
Only II and III
((e))
None of these

Show Answer

Answer: ((e))

None of these

Here, persons are A, B, C, D, E, F and G.

Two persons sit between B and E.
F is a neighbour of both C and B.
C is not a neighbour of E.

D sits third to the right of C.
G sits three places away from A. Therefore, case 1 is eliminated.
A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, B sits second to the right of D. Therefore, statement I is correct.

C sits immediate right to F. Therefore, statement II is correct.

A sits second to the left of D. Therefore, statement III is correct.

Therefore, the correct answer is none of these.

In a certain way four of the five are alike find the one which does not follow the same pattern?

((a))
FD
((b))
DC
((c))
GC
((d))
BE
((e))
AF

Show Answer

Answer: ((e))

Here, persons are A, B, C, D, E, F and G.

Two persons sit between B and E.
F is a neighbour of both C and B.
C is not a neighbour of E.

D sits third to the right of C.
G sits three places away from A. Therefore, case 1 is eliminated.
A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, each pair represents number of persons sitting between them is either two or three but between A and F either one or four persons sit.

Hence, the odd one is AF.

Which of the following statement(s) is/are correct?

I. A sits immediate right to C.

II. E sits second to the left of A.

III. G is a immediate neighbour of D and C.

((a))
Only I and II
((b))
Only II
((c))
Only II and III
((d))
Only I
((e))
Only I and III

Show Answer

Answer: ((d))

Only I

Here, persons are A, B, C, D, E, F and G.

Two persons sit between B and E.
F is a neighbour of both C and B.
C is not a neighbour of E.

D sits third to the right of C.
G sits three places away from A. Therefore, case 1 is eliminated.
A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, A sits immediate right to C. Therefore, statement I is correct.

E sits immediate right to A not second left. Therefore, statement II is incorrect.

III. G is a immediate neighbour of D and B not C. Therefore, statement III is incorrect.

Hence, the correct answer is only I.

Who among the following person sits third to the right of the one who sits second to the right of B?

((a))
C
((b))
G
((c))
A
((d))
D
((e))
E

Show Answer

Answer: ((d))

Here, persons are A, B, C, D, E, F and G.

Two persons sit between B and E.
F is a neighbour of both C and B.
C is not a neighbour of E.

D sits third to the right of C.
G sits three places away from A. Therefore, case 1 is eliminated.
A and B do not sit adjacent to each other. Hence, the final arrangement is as follows

Since, C sits second to the right of B and D sits third to the right of C.

Hence, the correct answer is D.

Direction: Read the following information carefully and answer the question that follow:

P, S, T, W, X, Y, and Z are family members related to each other. X is the father of Y, who is the son of Z. Z is the daughter of S, who is the husband of P. X is the brother of T. W is the mother of T. W has only one daughter.

Who is the father-in-law of X?

((a))
P
((b))
W
((c))
Y
((d))
S
((e))
T

Show Answer

Answer: ((d))

From the given information,

X is the father of Y, who is the son of Z. (means Y is the son of Z).
Z is the daughter of S, who is the husband of P. (means S is the husband of P).
X is the brother of T.
W is the mother of T. W has only one daughter. (Means T is the sister of X).

S is the father-in-law of X.

How T related to Z?

((a))
Sister
((b))
Grandmother
((c))
Sister-in-law
((d))
Mother
((e))
Aunty

Show Answer

Answer: ((c))

Sister-in-law

From the given information,

X is the father of Y, who is the son of Z. (means Y is the son of Z).
Z is the daughter of S, who is the husband of P. (means S is the husband of P).
X is the brother of T.
W is the mother of T. W has only one daughter. (Means T is the sister of X).

Hence, T is the sister-in-law of Z.

How is S related to Y?

((a))
Brother
((b))
Grandfather
((c))
Father-in-law
((d))
Father
((e))
Uncle

Show Answer

Answer: ((b))

Grandfather

From the given information,

X is the father of Y, who is the son of Z. (means Y is the son of Z).
Z is the daughter of S, who is the husband of P. (means S is the husband of P).
X is the brother of T.
W is the mother of T. W has only one daughter. (Means T is the sister of X).

Hence, S is the grandfather of Y.

If in the number "743625814", the odd digits are added by 1 and even digits are subtracted by 1 then what is the product of second digit from the left end and third digits from the right end?

((a))
6
((b))
24
((c))
27
((d))
21
((e))
15

Show Answer

Answer: ((d))

Given number: 743625814

Operation: Even digits are subtracted by 1 and odd digits are added by 1

Given number	7	4	3	6	2	5	8	1	4
Operations	+1	-1	+1	-1	-1	+1	-1	+1	-1
Resultant	8	3	4	5	1	6	7	2	3

Since, second digit from from left end is '3' and third digit from the right end is '7'.

Therefore, their product is 7×3 = 21.

Hence, the correct answer is 21.

Numerical Ability (40 questions)

What should come in place of the question mark '?' in the following number series?

332, 331, 323, 296, 232, ?

((a))
103
((b))
101
((c))
105
((d))
107
((e))
108

Show Answer

Answer: ((d))

107

The series follows the following pattern:

332 – 1³ = 331

331 – 2³ = 323

323 – 3³ = 296

296 – 4³ = 232

232 – 5³ = 107

∴ The missing term in the series is 107.

What should come in place of the question mark '?' in the following number series?

728, 716, 692, ?, 608, 548

((a))
635
((b))
642
((c))
656
((d))
649
((e))
663

Show Answer

Answer: ((c))

656

The series follows the following pattern:

728 – (12 × 1) = 716

716 – (12 × 2) = 692

692 – (12 × 3) = 656

656 – (12 × 4) = 608

608 – (12 × 5) = 548

∴ The missing term in the series is 656.

What should come in place of the question mark '?' in the following number series?

1, 5, 13, 29, ?, 125

((a))
60
((b))
61
((c))
62
((d))
63
((e))
64

Show Answer

Answer: ((b))

The given series follows the pattern shown below:

1 × 2 + 3 = 5

5 × 2 + 3 = 13

13 × 2 + 3 = 29

29 × 2 + 3 = 61

61 × 2 + 3 = 125

What should come in place of the question mark '?' in the following number series?

3, 7, ?, 27, -37, 63

((a))
12
((b))
-18
((c))
15
((d))
-9
((e))
-12

Show Answer

Answer: ((d))

-9

The given series follows the pattern shown below:

3 + 2² = 7

7 – 4² = –9

–9 + 6² = 27

27 – 8² = –37

–37 + 10² = 63

What should come in place of the question mark '?' in the following number series?

25, 30, 40, 55, 75, ?

((a))
90
((b))
100
((c))
110
((d))
120
((e))
105

Show Answer

Answer: ((b))

100

The series follows the following pattern:

25 + 5 = 30

30 + 10 = 40

40 + 15 = 55

55 + 20 = 75

75 + 25 = 100

A man marks an article 25% above the cost price of an article. if he gives 20% discount on markup price what will be his loss or gain percentage?

((a))
5% gain.
((b))
5% loss.
((c))
10% loss.
((d))
no gain no loss.
((e))
10% gain.

Show Answer

Answer: ((d))

no gain no loss.

Given:

Discount percentage = 20%

And markup price = 25% above the cost price

Formula used:

Mark up price = cost price × [(100 + markup percentage)/100]

Selling price = markup price × [(100 - discount percentage)/100]

Calculation:

Let the cost price of an article be Rs. x

Markup price = x × [(100 + 25)/100]

⇒ 125x/100

⇒ 1.25x

Selling price = 1.25x × [(100 - 20)/100]

⇒ 1.25x × (80/100)

⇒ 100x/100

⇒ x

We can see the cost price and the selling price of an article are the same ie. equal to Rs. x.

∴ There will be no loss or gain percentage on an article.

Train A of length 100 m crosses a platform of length 20 m in 5 sec. It crosses another train B of length 80 m running in opposite direction in 4 sec. Find the speed of train B.

((a))
26 m/s
((b))
25 m/s
((c))
21 m/s
((d))
30 m/s
((e))
None of these

Show Answer

Answer: ((c))

21 m/s

GIVEN :

Train A of length 100 m crosses a platform of length 20 m in 5 sec.

It crosses another train B of length 80 m running in opposite direction in 4 sec.

CALCULATION :

1st case

Total distance = 100 + 20 = 120 m

Speed of train A = 120/5 = 24 m/s

2^nd case

Total distance = 100 + 80 = 180 m

Let speed of train B = x m/s

Relative speed = (24 + x)m/s

According to question,

24 + x = 180/4

⇒ 24 + x = 45

⇒ x = 21 m/s

∴ Speed of train B = 21 m/s

Study the following information carefully and answer the questions given below:

The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.

Subjects (Maximum marks)	English (100)	Quantitative Aptitude (125)	Reasoning Ability (175)
Aman	63%	88%	76%
Bharat	78%	64%	68%
Chetan	52%	72%	92%
Dheeraj	84%	56%	52%
Elvish	92%	48%	84%

What is the difference between highest and lowest Reasoning scores?

((a))
60
((b))
90
((c))
70
((d))
55
((e))
65

Show Answer

Answer: ((c))

Calculations:

⇒ Chetan = 92 × 175 ÷ 100 = 161

⇒ Dheeraj = 52 × 175 ÷ 100 = 91

Highest = 161

Lowest = 91

⇒ Difference = 161 − 91 = 70

∴ Difference between highest and lowest Reasoning marks = 70.

If Chetan improves their English score by 25% of their previous English score, what will be the approximate percentage change in their total marks across all three subjects?

((a))
4%
((b))
8%
((c))
10%
((d))
12%
((e))
6%

Show Answer

Answer: ((a))

Calculations:

⇒ Increase in English = 25% × 52

⇒ = 0.25 × 52 = 13

⇒ New English = 52 + 13 = 65

Original total = 52 + 90 + 161 = 303

New total = 65 + 90 + 161 = 316

⇒ Increase = 316 − 303 = 13

⇒ % change = 13 ÷ 303 × 100

⇒ 4.29% ≈ 4%

∴ Approximate percentage change in total marks = 4%.

If a person qualifies only if they score at least 60% in each subject, how many friends qualify?

((a))
1
((b))
0
((c))
3
((d))
2
((e))
4

Show Answer

Answer: ((d))

Calculations:

⇒ Aman: 63, 88, 76 → Qualifies

⇒ Bharat: 78, 64, 68 → Qualifies

⇒ Chetan: 52 (fails), 72, 92 → Not qualify

⇒ Dheeraj: 84, 56 (fails), 52 (fails) → Not qualify

⇒ Elvish: 92, 48 (fails), 84 → Not qualify

⇒ Total qualifiers = 2

∴ Number of friends who qualify = 2.

What is the average marks scored by person Chetan across all three subjects?

((a))
104
((b))
101
((c))
108
((d))
112
((e))
124
((5))
None of these

Show Answer

Answer: ((b))

101

Calculations:

⇒ Total = 52 + 90 + 161 = 303

⇒ Average = 303 ÷ 3

⇒ Average = 101

∴ Average marks of Chetan = 101.

Who scored the highest total marks across all three subjects?

((a))
Aman
((b))
Bharat
((c))
Elvish
((d))
Dheeraj
((e))
Chetan

Show Answer

Answer: ((a))

Aman

Calculations:

Aman:

⇒ English = 63 × 100 ÷ 100 = 63

⇒ Quant = 88 × 125 ÷ 100 = 110

⇒ Reasoning = 76 × 175 ÷ 100 = 133

Total = 63 + 110 + 133 = 306

Bharat:

⇒ English = 78

⇒ Quant = 64 × 125 ÷ 100 = 80

⇒ Reasoning = 68 × 175 ÷ 100 = 119

Total = 78 + 80 + 119 = 277

Chetan:

⇒ English = 52

⇒ Quant = 72 × 125 ÷ 100 = 90

⇒ Reasoning = 92 × 175 ÷ 100 = 161

Total = 52 + 90 + 161 = 303

Dheeraj:

⇒ English = 84

⇒ Quant = 56 × 125 ÷ 100 = 70

⇒ Reasoning = 52 × 175 ÷ 100 = 91

Total = 84 + 70 + 91 = 245

Elvish:

⇒ English = 92

⇒ Quant = 48 × 125 ÷ 100 = 60

⇒ Reasoning = 84 × 175 ÷ 100 = 147

Total = 92 + 60 + 147 = 299

∴ Aman scored the highest total marks = 306.

In a company, three persons A, B, and C share their profit in the ratio 4 : 7 : 3 respectively. B retired from the company and, A & C decided to share the profit in the ratio 4 : 3. Calculate the ratio of their gain.

((a))
3 : 4
((b))
4 : 3
((c))
3 : 5
((d))
5 : 3
((e))
4 : 5

Show Answer

Answer: ((b))

4 : 3

Given:

A, B, and C share their profit in the ratio 4 : 7 : 3 respectively

B retired from the company and, A & C decided to share the profit in the ratio 4 : 3

Calculation:

The initial profit share of A = 4/(4 + 7 + 3) = 4/14 unit

The initial profit share of C = 3/(4 + 7 + 3) = 3/14 unit

After B retired,

The profit share of A = 4/(4 + 3) = 4/7

The profit share of C = 3/(4 + 3) = 3/7

Gain of A = (4/7) - (4/14) = 28/98

Gain of C = (3/7) - (3/14) = 21/98

The respective ratio of gain of A and C = (28/98) : (21/98) = 4 : 3

∴ The correct answer is option 2

A batsman scored 90 runs in his 12^th match. Due to this, his average run is increased by 2. Find the initial average runs scored by him.

((a))
65
((b))
63
((c))
68
((d))
66
((e))
70

Show Answer

Answer: ((d))

Given:

Runs in 12^th match = 90

Calculation:

Let the average till 11^th match or initial average = x

According to the question

⇒ 11x + 90 = (x + 2) × 12

∴ x = 66

What will come in place of the question mark ‘?’ in the following question?

(8536 – √2209) × 0.3 = ?

((a))
2556.7
((b))
2456.7
((c))
2546.7
((d))
2645.7
((e))
2654.7

Show Answer

Answer: ((c))

2546.7

Follow BODMAS rule to solve this question, as per the order given below,

Step -1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step -2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step -3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step -4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

(8536 – √2209) × 0.3 = ?

⇒ ? = (8536 – 47) × 0.3

⇒ ? = (8489) × 0.3

∴ ? = 2546.7

What will come in place of question Mark ‘?’ in the following question?

81% of 2300 – 34% of 596 = ?

((a))
1060.63
((b))
1060.36
((c))
1660.36
((d))
1006.63
((e))
1600.36

Show Answer

Answer: ((c))

1660.36

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

81% of 2300 – 34% of 596 = ?

⇒ ? = (81/100 × 2300) – (34/100 × 596)

⇒ ? = (81 × 2300) – (34 × 5.96)

⇒ ? = 1863 – 202.64

∴ ? = 1660.36

What will come in place of question mark (?) in the following question?

13.6 – 1.6 – 1 + 1.3 × 2 = ?

((a))
13.6
((b))
12.6
((c))
14.6
((d))
11.6
((e))
15.6

Show Answer

Answer: ((a))

13.6

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

13.6 – 1.6 – 1 + 1.3 × 2 = ?

⇒ 13.6 – 1.6 – 1 + 2.6 = ?

⇒ 13.6 – 1.6 + 1.6 = ?

⇒ 13.6 + 0 = ?

∴ ? = 13.6

What will come in place of question mark ‘?’ in the following question?

350% of ? ÷ 50 + 278 = 1825

((a))
22200
((b))
22150
((c))
44100
((d))
22100
((e))
None of these

Show Answer

Answer: ((d))

22100

Follow BODMAS rules to solve the equation

Step -1: The part of the equation containing 'Brackets' must be solved first, and in the bracket,

Step -2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step -3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are solved

Step -4: At last, the part of the equation that contains 'Addition' and 'Subtraction' should be solved.

⇒ 350% of ? ÷ 50 + 278 = 1825

⇒ [350 × (?)] / (100 × 50) + 278 = 1825

⇒ 7/100 × ? = 1547

⇒ ? = (1547 × 100) /7

⇒ ? = 221 × 100 = 22100

∴ ? = 22100

What will come in place of ? in the following equation?

[(140)² ÷ 35 × 32] ÷ 8 = 7 × ?

((a))
32
((b))
320
((c))
160
((d))
80
((e))
None of these

Show Answer

Answer: ((b))

320

Follow these BODMAS rules to solve the question

⇒ (140 × 140 × 32) / (35 × 8) = 7 × ?

⇒ 16 × 140 = 7 × ?

⇒ ? = (16 × 140)/7

⇒ ? = 320

What will come in place of question mark ‘?’ in the following question?

46 × 1536 ÷ (2√2304) = (?)³ + √49

((a))
7
((b))
8
((c))
9
((d))
6
((e))
10

Show Answer

Answer: ((c))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

46 × 1536 ÷ (2√2304) = (?)³ + √49

⇒ 46 × 1536 ÷ (2 × 48) = (?)³ + 7

⇒ 46 × 1536 ÷ 96 = (?)³ + 7

⇒ 46 × 16 – 7 = ?³

⇒ ?³= 729

⇒ ? = 9

∴ The value of ? is 9

What will come in place of question mark ‘?’ in the following question?

[(368)² ÷ (23)² × 15] ÷ 12 = ?

((a))
400
((b))
320
((c))
360
((d))
340
((e))
280

Show Answer

Answer: ((b))

320

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

[(368)² ÷ (23)² × 15] ÷ 12 = ?

⇒ [(368 ÷ 23)² × 15] ÷ 12 = ?

Applying BODMAS Rule;

⇒ [16² × 15] ÷ 12 = ?

⇒ [256 × 15] ÷ 12 = ?

⇒ 3840 ÷ 12 = ?

∴ ? = 320

What will come in place of question mark ‘?’ in the following question?

28 ÷ (√144 × 17 ÷ 51) + (?)² = 848

((a))
30
((b))
31
((c))
28
((d))
29
((e))
27

Show Answer

Answer: ((d))

Concept Used:

Follow the BODMAS rule as given in the below table:

Calculation:

28 ÷ (√144 × 17 ÷ 51) + (?)2 = 848

Applying BODMAS Rule;

⇒ 28 ÷ [12 × (1/3)] + (?)2 = 848

⇒ 28 ÷ 4 + (?)2 = 848

⇒ 7 + (?)2 = 848

⇒ (?)2 = 848 - 7 = 841

⇒ (?) = √841 = 29

∴ ? = 29

What will come in place of question mark ‘?’ in the following question?

(12/5)² × (37.5 × 56) ÷ (984/41) = ?

((a))
500
((b))
502
((c))
498
((d))
496
((e))
504

Show Answer

Answer: ((e))

504

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

(12/5)² × (37.5 × 56) ÷ (984/41) = ?

Applying BODMAS Rule;

⇒ (144/25) × 2100 ÷ 24 = ?

⇒ (144/25) × 87.5 = ?

∴ ? = 504

What will come in place of question mark (?) in the following question?

435 ÷ 7.5 – 40% of 130 = ?

((a))
7
((b))
10
((c))
12
((d))
9
((e))
6

Show Answer

Answer: ((e))

Follow the BODMAS rule to solve the question,

435 ÷ 7.5 – 40% of 130 = ?

Any mathematical 'Of' or 'Exponent' must be solved,

⇒ 435 ÷7.5 – [(40/100) × 130] = ?

The parts of the equation that contain 'Division' and 'Multiplication' are calculated,

⇒ (435 ÷ 7.5) – 52 = ?

The parts of the equation that contain 'Addition' and 'Subtraction' should be calculated,

⇒ 58 – 52 = ?

∴ ? = 6

What will come in the place of the question mark ‘?’ in the following question?

858 ÷ 39 × 74 – 1500 = (2)^?

((a))
2
((b))
5
((c))
7
((d))
9
((e))
11

Show Answer

Answer: ((c))

Given:

858 ÷ 39 × 74 – 1500 = (2)?

Concept Used:

Calculation:

858 ÷ 39 × 74 – 1500 = (2)^?

By using the BODMAS rule,

⇒ (858 ÷ 39) × 74 – 1500 = 2^?

⇒ (22 × 74) – 1500 = 2^?

⇒ 1628 – 1500 = 2^?

⇒ 128 = 2^?

⇒ 2⁷ = 2^?

∴ ? = 7

What should come in place of question mark (?) in the following questions?

120 ÷ 5 × (3)³ ÷ 9 = (?) ÷ [8 ÷ (?)]

((a))
576
((b))
24
((c))
8
((d))
256
((e))
216

Show Answer

Answer: ((b))

Follow the BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

120 ÷ 5 × (3)³ ÷ 9 = (?) ÷ [8 ÷ (?)]

⇒ 120 ÷ 5 × (3)3 ÷ 9 = (?) ÷ (8/?)

⇒ 120 ÷ 5 × (3)³ ÷ 9 = (?) × (?)/8

⇒ (?)² = 24 × 3 × 8

⇒ (?) = 24

What should come in place of question mark ‘?’ in the following question?

999 ÷ 3 – 165 = 75 + 111 - ?

((a))
20
((b))
28
((c))
18
((d))
22
((e))
24

Show Answer

Answer: ((c))

Follow BODMAS (Brackets, Of, Division, Multiplication, Addition, Subtraction) rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved inside the bracket first,

Step-2- Then any mathematical 'Of' or 'Exponent' must be solved,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

⇒ 999 ÷ 3 – 165 = 75 + 111 - ?

⇒ 333 – 165 = 186 - ?

⇒ 168 = 186 - ?

⇒ ? = 186 – 168

⇒ ? = 18

What will come in the place of the question mark ‘?’ in the following question?

67% of √676 ÷ 0.01 = ? + 577

((a))
1163
((b))
1267
((c))
1165
((d))
1168
((e))
1264

Show Answer

Answer: ((c))

1165

$\sqrt {676} \times \frac{{67}}{{100}} \div \frac{1}{{100}} = ;? + ;577$

$\Rightarrow 26 \times \frac{{67}}{{100}} \times 100 = ;?; + ;577$

⇒ 1742 = ? + 577

⇒ ? = 1742 – 577

⇒ ? = 1165

What will come in place of the question mark (?) in the following question?

(?)²÷ 4 × 5 = 180

((a))
10
((b))
14
((c))
8
((d))
12
((e))
16

Show Answer

Answer: ((d))

Given

(?)2 ÷ 4 × 5 = 180

⇒ (?)2 ÷ 4 = 36

⇒ (?)² = 36 × 4

∴ ? = 6 × 2 = 12.

In a milk tank, the quantity of milk is 40% more than water. If 31 litres of water is added to this mixture, then the final ratio of milk and water is 5 : 8. Find the initial quantity of milk.

((a))
35 litres
((b))
45 litres
((c))
30 litres
((d))
40 litres
((e))
48 litres

Show Answer

Answer: ((a))

35 litres

GIVEN:

In a milk tank the quantity of milk is 40% more than water

31 litres of water is added to this mixture

The final ratio of milk and water = 5 : 8

CALCULATION:

Initial ratio of milk and water = 7 : 5

Let the initial quantity of milk and water be 7x litres and 5x litres respectively.

Final ratio of milk and water = 5 : 8

According to question,

(5x + 31)/7x = 8/5

⇒ 56x = 25x + 155

⇒ 31x = 155

⇒ x = 5

⇒ 7x = (7 × 5) litres

∴ Initial quantity of milk = 35 litres

If the radius of a sphere increases by 5 cm then the surface area increases by 726 cm². What was the initial radius of the sphere?

((a))
3.175 cm
((b))
3.275 cm
((c))
3.575 cm
((d))
3.725 cm
((e))
3.475 cm

Show Answer

Answer: ((b))

3.275 cm

Given:

If the radius of a sphere increases by 5 cm then the surface area increases by 726 cm²

Formula Used:

The surface area of a sphere = 4π R²

Where, R = radius of the sphere

Calculation:

Let, the initial radius of the sphere = R cm

After the radius is increased by 5 cm, the new surface area becomes = 4π (R + 5) cm²

According to the question,

4π [(R + 5)² - R²] = 726

⇒ 4π [R² + 10R + 25 - R²] = 726

⇒ 4 × (22/7) × [10R + 25] = 726

⇒ 4/7 × [10R + 25] = 33

⇒ 40R + 100 = 231

⇒ R = 131/40 = 3.275 cm

∴ The initial radius of the sphere was 3.275 cm

Study the following information carefully and answer the questions given below:

Bar graph given below shows the number of online and offline orders (in 100s) received by a food restraint in four different days (Monday, Tuesday, Wednesday and Thursday).

If difference between number of online received on Thursday and number of offline orders received on Tuesday is 'k', then find the value of (k + 5) .

((a))
34
((b))
36
((c))
35
((d))
33
((e))
32

Show Answer

Answer: ((a))

Calculation:

k = |Online (Thu) − Offline (Tue)|

Required value = k + 5

⇒ k = |25 − 54|

⇒ k = 29

⇒ k + 5 = 29 + 5

⇒ = 34

∴ The value of (k + 5) = 34.

Number of offline orders received on Tuesday is what percent more than offline orders received on Wednesday?

((a))
40%
((b))
25%
((c))
20%
((d))
30%
((e))
35%

Show Answer

Answer: ((e))

35%

Calculations:

⇒ Difference = 54 − 40 = 14

⇒ % more = 14 ÷ 40 × 100

⇒ % more = 35%

∴ Offline orders on Tuesday are 35% more than offline orders on Wednesday.

Number of offline orders received on Sunday is 40% more than the offline orders received on Thursday. If ratio of number of offline orders to that of online orders received on Sunday is 6:7. Find the number of online orders received on Sunday.

((a))
36
((b))
49
((c))
56
((d))
30
((e))
63

Show Answer

Answer: ((b))

Calculations:

⇒ Offline (Sunday) = 30 × 1.40

⇒ Offline (Sunday) = 42

⇒ 6 parts = 42

⇒ 1 part = 42 ÷ 6 = 7

⇒ Online (Sunday) = 7 parts = 7 × 7 = 49

∴ Number of online orders received on Sunday = 49.

Find the ratio of number of online orders received on Monday and Tuesday together to the number of offline orders received on Monday and Wednesday together.

((a))
18:17
((b))
17:16
((c))
13:12
((d))
17:11
((e))
19:15

Show Answer

Answer: ((d))

17:11

Calculations:

⇒ Online total = 64 + 72 = 136

⇒ Offline total = 48 + 40 = 88

⇒ Ratio = 136 : 88

⇒ Divide by 8 → 17 : 11

∴ Required ratio = 17 : 11.

Find the average number of online orders received by the restraint in all four days.

((a))
4040
((b))
5275
((c))
4060
((d))
5140
((e))
4120

Show Answer

Answer: ((b))

5275

Calculations:

⇒ Sum = 64 + 72 + 50 + 25

⇒ Sum = 211

⇒ Average = 211 ÷ 4

⇒ Average = 52.75

∴ Average online orders = 52.75 (in hundreds).

If the upstream speed of a boat is 60% of its downstream speed when travelling the same distance then find the ratio between speed of stream to boat in still water?

((a))
1 : 4
((b))
1 : 1
((c))
3 : 4
((d))
1 : 3
((e))
None of these

Show Answer

Answer: ((a))

1 : 4

GIVEN:

U_s = Upstream speed of a boat

D_s= Downstream speed of a boat

⇒ U_s : D_s = 3x : 5x ----(1)

FORMULA USED:

Downstream speed = (Speed of a boat in still water + Speed of current)/2
Upstream speed = (Speed of a boat in still water - Speed of current)/2

ASSUMPTION:

Let the speed of boat in still water and the speed of stream be (u) and (v) km/hr

CALCULATION:

⇒ u + v = 5x ----(2)

⇒ u - v = 3x ----(3)

Solving the above equations we get,

⇒ Speed of stream = v = 1x

⇒ Speed of boat in still water = u = 4x

⇒ v : u = 1 : 4

An amount becomes Rs. 1800 after 2 years and Rs. 1890 after 3 years while interest is compounded annually. Find the principal amount.(Approximate)

((a))
Rs. 1600
((b))
Rs. 1500
((c))
Rs. 1633
((d))
Rs. 1522
((e))
Rs. 1700

Show Answer

Answer: ((c))

Rs. 1633

Given:

An amount becomes Rs. 1800 after 2 years and Rs. 1890 after 3 years at CI

Concept Used:

Simple Interest (SI) = (P × R × T)/100

Compound Interest (CI) = P × (1 + R/100)T - P

Where, P = principal amount, R = rate of interest, and T = time duration

Calculation:

Interest earned on Rs. 1800 in (3 - 2) = 1 year is = 1890 - 1800 = Rs. 90

Here, P = Rs. 1800, SI (as it is for 1 year) = Rs. 90, and T = 1 year

So, R = (90 × 100)/1800 = 5%

Let, the actual principal amount = A

According to the question,

⇒ A × (1 + 5/100)² = 1800

⇒ A × 441/400 = 1800

⇒ A = (1800 × 400)/441 ≈ Rs. 1633

∴ The correct answer is option 3

Important PointsIf time duration (T) = 1 year, and the rate of interest is per annum, then the interest earned for SI or, CI will be equal. That is why the formula of SI is used to calculate the Rate (R), although the question is about CI.

Ram's age is 37.5% of Shiv's age. The ratio of their ages 6 years hence will be 9 : 19. Find the sum of their present ages.

((a))
44 years
((b))
42 years
((c))
40 years
((d))
46 years
((e))
48 years

Show Answer

Answer: ((a))

44 years

GIVEN:

Ram's age = 37.5% of Shiv's age

Ram : Shiv (6 years hence) = 9 : 19

EXPLANATION:

37.5% = 3/8

Let Ram's age be 3x and Shiv's age be 8x.

A.T.Q

(3x + 6)/(8x + 6) = 9/19

57x + 114 = 72x + 54

15 x = 60

x = 4

Sum = 3x + 8x = 11x

11x = 11 × 4 = 44 yrs

∴ The sum is 44 years.

Two Pipes X and Y can fill a cistern in 10 hrs and 15 hrs respectively. If two pipes are working simultaneously then how much time will the tank be filled?

((a))
12 hr
((b))
10 hr
((c))
6 hr
((d))
14 hr
((e))
None of these

Show Answer

Answer: ((c))

6 hr

Given:

Pipe X fills tank in 10 hours

Pipe Y fills tank in 15 hours

Formula used:

Work = LCM of time taken

Efficiency = Work ÷ Time

Time taken together = Total work ÷ (Efficiency of X + Efficiency of Y)

Calculations:

⇒ LCM of 10 and 15 = 30 units

⇒ X’s 1 hour work = 30 ÷ 10 = 3 units

⇒ Y’s 1 hour work = 30 ÷ 15 = 2 units

⇒ Total 1 hour work = 3 + 2 = 5 units

⇒ Time taken together = 30 ÷ 5 = 6 hours

∴ Both pipes together will fill the cistern in 6 hours.

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