Reasoning PYQs

Given series is: X L 5 I € V O 7 % R G $ M 4 J D # P 8 K @ 1 0 E U 2 α 6 X 9 H

Arrangement required: Consonant → Number → Consonant

(Left)   X L 5 I € V O 7 % R G $ M 4 J D # P 8 K @ 1 0 E U 2 α 6 X 9 H           (Right)

Hence, three such pairs are there i.e. M 4 J, P 8 K and X 9 H

Arrangement required: Number → Consonant → Vowel

Given series is: X L 5 I € V O 7 % R G $ M 4 J D # P 8 K @ 1 0 E U 2 α 6 X 9 H

Clearly no such pair is there.

Hence, none is the correct answer$.

The least possible Venn diagram for the given statements is as follows,

Conclusions:

 I. Some pagers are not laptop → it is definitely true.

II. All laptop being pagers is a possibility → its possibility is true as shown in the diagram below.

Thus, both conclusion I and II follows.

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. All chairs are tables → it’s possible but not definite, hence false.

II. All beds being table is a possibility → its possibility is true when all the three coincide as shown in the diagram below.

Thus, only conclusion II follows.

The least possible Venn diagram is as follows:

Conclusions:

I. Some folders are not paper → True (because no paper is a file and all files are folder. Therefore Some folder are not paper)

II. Some files are data → False (It is possible but not definite)

Hence, only conclusions I follows.

According to the given information:

Since, from the above diagram it is clear the 'Rony' is coded as 'qm' and 'brings' is coded as 'wt'.

Hence, the words for the code 'wt qm' is 'Rony brings'.

According to the given information:

Since, the code for the word 'snowfalls' can be 'fl' and the word for the code 'za' can be either 'good' or 'luck'. Therefore, the possible words for the code 'fl za' can be either 'snowfalls good' or 'luck snowfalls'.

Hence, the correct answer is either 2 or 4.

According to the given information:

Since, from the given figure it is clear the code for the word 'winter' is 'oc'.

Hence, the correct answer is 'oc'.

According to the given information:

Since, the possible code for 'snowfalls' can be 'fl' and the word 'sleet' is not given in the coded information so its code will be different from the given codes.

Hence, the possible code for the words 'Snowfalls sleet' is 'fl ut'.

According to the given information:

Since, 'likes a snow' is coded as 'sk al js' then the possible code for 'makes' can be 'vs' and code for 'season' is 'bp'

Hence, the possible code for the word 'makes season' is 'vs bp'.

Since, the first letters are added by 2 with the previous first letter of the given clusters, the second letters of clusters are added by 4 with the previous second letter of clusters and number are arranged in prime number series.

Hence, the correct answer is XS13.

Here, persons are A, B, C, D, E and F; months June, September and December; dates 15 and 28.

1. Two persons join between E and D who joins after E.

2. B and C join company on same month.

3. B and D join company immediate next to each other.

 

4. A joins the company before F.

5. C joins company before F. Therefore, case 2 is eliminated. Hence, the final arrangement is as follows

 

Hence, C joins company on 15^th September.

Here, persons are A, B, C, D, E and F; months June, September and December; dates 15 and 28.

1. Two persons join between E and D who joins after E.

2. B and C join company on same month.

3. B and D join company immediate next to each other.

 

4. A joins the company before F.

5. C joins company before F. Therefore, case 2 is eliminated. Hence, the final arrangement is as follows

 

Since, in each pair one person joins company between them except AE where both of them joins company immediate next to each other.

Hence, the odd one is AE.

Here, persons are A, B, C, D, E and F; months June, September and December; dates 15 and 28.

1. Two persons join between E and D who joins after E.

2. B and C join company on same month.

3. B and D join company immediate next to each other.

 

4. A joins the company before F.

5. C joins company before F. Therefore, case 2 is eliminated. Hence, the final arrangement is as follows

 

Since, A joins the company in the on 15^th June. Therefore, statement I is correct.

D and F joins company in the December month. Therefore, statement II is correct.

E joins company on 28^th June not 15^th June. Therefore, statement III is incorrect.

Hence, the correct answer is only I and II.

Here, persons are A, B, C, D, E and F; months June, September and December; dates 15 and 28.

1. Two persons join between E and D who joins after E.

2. B and C join company on same month.

3. B and D join company immediate next to each other.

 

4. A joins the company before F.

5. C joins company before F. Therefore, case 2 is eliminated. Hence, the final arrangement is as follows

 

Since, C joins company just before not after B. Therefore, statement I is incorrect.

B joins company in the month of September not December. Therefore, statement II is incorrect.

D joins company after B not before. Therefore, statement III is incorrect.

Hence, the incorrect statement is all of these.

Here, persons are A, B, C, D, E and F; months June, September and December; dates 15 and 28.

1. Two persons join between E and D who joins after E.

2. B and C join company on same month.

3. B and D join company immediate next to each other.

 

4. A joins the company before F.

5. C joins company before F. Therefore, case 2 is eliminated. Hence, the final arrangement is as follows

 

Hence, E joins the company just before C.

Here, family members are K, M, O, P, W, X and Y.

1. O is the father – in – law of X.

2. P is the brother – in – law of X.

3. P is unmarried.

4. Y is the uncle of W.

5. K is the brother – in – law of Y.

6. M has two sons. Therefore, case 2 is eliminated.

7. K has one son. Hence, the final arrangement is as follows

Since, each person except X is a male member whereas X is a female member.

Hence, the odd one X.

Here, family members are K, M, O, P, W, X and Y.

1. O is the father – in – law of X.

2. P is the brother – in – law of X.

3. P is unmarried.

4. Y is the uncle of W.

5. K is the brother – in – law of Y.

6. M has two sons. Therefore, case 2 is eliminated.

7. K has one son. Hence, the final arrangement is as follows

Since, Y is the brother of X who is the sister - in - law of P. Therefore, statement I is incorrect.

K is the husband of X. Therefore, statement II is correct.

O is the grandfather of W. Therefore, statement III is correct.

Hence, the correct answer is only II and III.

Here, family members are K, M, O, P, W, X and Y.

1. O is the father – in – law of X.

2. P is the brother – in – law of X.

3. P is unmarried.

4. Y is the uncle of W.

5. K is the brother – in – law of Y.

6. M has two sons. Therefore, case 2 is eliminated.

7. K has one son. Hence, the final arrangement is as follows

Hence, K is the son of M.

Forward pair: CG

Backward pair: AC

Thus, there are two such pairs formed which have as many letters between them as in the English alphabetical series in the given word "CHANGE".

Hence, the correct answer is two such pairs.