Reasoning PYQs

Given group of letters:

WON DAD RAW BAT HAT

After arrangement: As per the dictionary order from left to right - 

BAT  DAD  HAT  RAW  WON

Thus, the word ‘RAW’ will be the fourth from the left end.

Given group of letters:

WON DAD RAW BAT HAT

The word ‘BAT’ is second from the right end → the second letter of the word is A.

The word ‘DAD’ is second from the left end → the third letter of the word is D.

Thus, there are two letters between A & D i.e., B, C as per the English alphabetical series.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.
2. T is seated immediately to the left of V and is directly opposite Q.
3. P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2. 4. P and T are not adjacent. 

Now, we can eliminate Case 2. 5. U is seated in a corner position, but do not face P. 6. R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is R.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.
2. T is seated immediately to the left of V and is directly opposite Q.
3. P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2. 4. P and T are not adjacent. 

Now, we can eliminate Case 2. 5. U is seated in a corner position, but do not face P. 6. R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is P.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.
2. T is seated immediately to the left of V and is directly opposite Q.
3. P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2. 4. P and T are not adjacent. 

Now, we can eliminate Case 2. 5. U is seated in a corner position, but do not face P. 6. R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is Two.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.
2. T is seated immediately to the left of V and is directly opposite Q.
3. P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2. 4. P and T are not adjacent. 

Now, we can eliminate Case 2. 5. U is seated in a corner position, but do not face P. 6. R does not occupy a corner seat.

This is our final arrangement,

Except for Q, all others face inside.

Hence, the correct answer is **Q.**​

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.
2. T is seated immediately to the left of V and is directly opposite Q.
3. P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2. 4. P and T are not adjacent. 

Now, we can eliminate Case 2. 5. U is seated in a corner position, but do not face P. 6. R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is U.

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

1. Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

2. Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

3. L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Q.

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

1. Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

2. Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

3. L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Can't be determined.

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

1. Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

2. Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

3. L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Five.

Given

Statement:

Y < U ≤ Q ≥ S >T = O > P

Conclusions:

I. P < Q → True as Q ≥ S >T = O > P, thus Q > P.

II. Y < S → False as Y < U ≤ Q ≥ S, thus there is no definite relation between them.

Hence, only conclusion I is true.

Given statement is:  C < P ≤ M = U = S < E ≥ T

Conclusion:

I. C > E → FalseasC < P ≤ M = U = S < E, thusC < E.

II. E < P → False as P ≤ M = U = S < E, P < E.

Hence, neither conclusion I nor II is true.

Given: A > K ≤ D; D < B; B > K ≤ C

On combining: A > K ≤ D = C < B

I. A < C ⇒ False (as A > K ≤ D = C relation between A and C can’t be established)

II. A = C ⇒ (as A > K ≤ D = C relation between A and C can’t be established)

Hence, Neither I nor II is true.

Forward pair: ST

Backward pair: None

Thus, there are one such pair of letters in the word "MISTAKE" which have as many letters between them as in the English alphabetical series (both in forward and backward direction).

Hence, the correct answer is one such pair.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. There are exactly two days between G and B.

 

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

 

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

 

This is our final arrangement,

 

Hence, the correct answer is C.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. There are exactly two days between G and B.

 

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

 

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

 

This is our final arrangement,

 

Hence, the correct answer is Thursday.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. There are exactly two days between G and B.

 

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

 

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

 

This is our final arrangement,

 

Hence, the correct answer is B.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. There are exactly two days between G and B.

 

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

 

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

 

This is our final arrangement,

 

Hence, the correct answer is Three.

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

1. E has a reservation on Wednesday. 

 

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. There are exactly two days between G and B.

 

4. The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

 

5. D's reservation is after B but before F.

Now, we can eliminate Case 2.

 

This is our final arrangement,

 

Hence, the correct answer is F - Saturday.

Since, each letter cluster contains a vowel except MPR which contain only consonants.

Hence, the odd one is MPR.