Official Paper

RRB Clerk Prelims Memory Based Paper (Held On: 7 Dec 2025 Shift 1) (Previous Year Paper)

80 questions · 45 minutes · with answers · free

Reasoning (40 questions)

Directions: Read the information and answer the given question.

Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

There is exactly one box between M and R. There are three boxes separating S and K. The number of boxes placed above box M is exactly the same as the number of boxes placed below box M. Box S is positioned immediately above box R. The number of boxes lying between K and M is equal to the number of boxes lying between L and P. Box P is not placed at the bottommost position.

How many boxes are placed between box S and box M?

((a))
One
((b))
Two
((c))
None
((d))
Three
((e))
Four

Show Answer

Answer: ((b))

Two

Given: Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

The number of boxes placed above box M is exactly the same as the number of boxes placed below box M.

Boxes



M

There is exactly one box between M and R.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Boxes
Case 1	Case 2

R

M	M

	R

Box S is positioned immediately above box R.

Boxes
Case 1	Case 2
S
R

M	M
	S
	R

There are three boxes separating S and K.

Boxes
Case 1	Case 2
S	K
R

M	M
K	S
	R

The number of boxes lying between K and M is equal to the number of boxes lying between L and P.

Now, we can eliminate Case 2.

Boxes
Case 1
S
R

M
K
L/P
P/L

Box P is not placed at the bottommost position.

Boxes
Case 1
S
R

M
K
P
L

This is our final arrangement,

Boxes
Case 1
S
R
N
M
K
P
L

Hence, the correct answer is Two.

Which among the following box is placed immediately above box K?

((a))
P
((b))
R
((c))
L
((d))
M
((e))
N

Show Answer

Answer: ((d))

Given: Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

The number of boxes placed above box M is exactly the same as the number of boxes placed below box M.

Boxes



M

There is exactly one box between M and R.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Boxes
Case 1	Case 2

R

M	M

	R

3. Box S is positioned immediately above box R.

Boxes
Case 1	Case 2
S
R

M	M
	S
	R

There are three boxes separating S and K.

Boxes
Case 1	Case 2
S	K
R

M	M
K	S
	R

The number of boxes lying between K and M is equal to the number of boxes lying between L and P.

Now, we can eliminate Case 2.

Boxes
Case 1
S
R

M
K
L/P
P/L

Box P is not placed at the bottommost position.

Boxes
Case 1
S
R

M
K
P
L

This is our final arrangement,

Boxes
Case 1
S
R
N
M
K
P
L

Hence, the correct answer is M.

Which among the following box is placed at the bottom-most position?

((a))
K
((b))
L
((c))
M
((d))
N
((e))
R

Show Answer

Answer: ((b))

Given: Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

The number of boxes placed above box M is exactly the same as the number of boxes placed below box M.

Boxes



M

There is exactly one box between M and R.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Boxes
Case 1	Case 2

R

M	M

	R

3. Box S is positioned immediately above box R.

Boxes
Case 1	Case 2
S
R

M	M
	S
	R

There are three boxes separating S and K.

Boxes
Case 1	Case 2
S	K
R

M	M
K	S
	R

The number of boxes lying between K and M is equal to the number of boxes lying between L and P.

Now, we can eliminate Case 2.

Boxes
Case 1
S
R

M
K
L/P
P/L

Box P is not placed at the bottommost position.

Boxes
Case 1
S
R

M
K
P
L

This is our final arrangement,

Boxes
Case 1
S
R
N
M
K
P
L

Hence, the correct answer is L.

The number of boxes between R and M is equal to the number of boxes between:

((a))
L and P
((b))
S and R
((c))
M and P
((d))
K and S
((e))
S and M

Show Answer

Answer: ((c))

M and P

Given: Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

The number of boxes placed above box M is exactly the same as the number of boxes placed below box M.

Boxes



M

There is exactly one box between M and R.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Boxes
Case 1	Case 2

R

M	M

	R

3. Box S is positioned immediately above box R.

Boxes
Case 1	Case 2
S
R

M	M
	S
	R

There are three boxes separating S and K.

Boxes
Case 1	Case 2
S	K
R

M	M
K	S
	R

The number of boxes lying between K and M is equal to the number of boxes lying between L and P.

Now, we can eliminate Case 2.

Boxes
Case 1
S
R

M
K
L/P
P/L

Box P is not placed at the bottommost position.

Boxes
Case 1
S
R

M
K
P
L

This is our final arrangement,

Boxes
Case 1
S
R
N
M
K
P
L

Hence, the correct answer is M and P.

Find the odd one pair.

((a))
R - M
((b))
S - N
((c))
R - P
((d))
N - K
((e))
K - L

Show Answer

Answer: ((c))

R - P

Given: Seven boxes, namely, K, L, M, N, P, R, and S are arranged one above another in a vertical stack, but not necessarily in the same order.

The number of boxes placed above box M is exactly the same as the number of boxes placed below box M.

Boxes



M

There is exactly one box between M and R.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Boxes
Case 1	Case 2

R

M	M

	R

3. Box S is positioned immediately above box R.

Boxes
Case 1	Case 2
S
R

M	M
	S
	R

There are three boxes separating S and K.

Boxes
Case 1	Case 2
S	K
R

M	M
K	S
	R

The number of boxes lying between K and M is equal to the number of boxes lying between L and P.

Now, we can eliminate Case 2.

Boxes
Case 1
S
R

M
K
L/P
P/L

Box P is not placed at the bottommost position.

Boxes
Case 1
S
R

M
K
P
L

This is our final arrangement,

Boxes
Case 1
S
R
N
M
K
P
L

Except for R - P, in all other pairs, only one box is placed between them.

Hence, the correct answer is R - P.

Direction: Study the following information carefully and answer the given questions.

In a certain code language

‘make good finance plans’ is written as ‘zt mn lo xy’

‘good economy helps finance’ is written as ‘dn oj mn zt’

‘make good progress now’ is written as ‘xy fs zt br’

’progress helps develop country’ means ‘oj rt cl br’.

What does the code ‘rt cl lo zt dn’ stand for in the given code language?

((a))
develop country plans good progress.
((b))
plans now develop good economy.
((c))
develop country plans good economy.
((d))
economy make good country progress.
((e))
develop country progress good economy.

Show Answer

Answer: ((c))

develop country plans good economy.

Code ‘rt and cl’ corresponds to ‘country and develop’,

Code ‘lo’ corresponds to ‘plans’,

Code ‘zt’ corresponds to ‘good’,

Code ‘dn’ corresponds to ‘economy’.

Thus the ‘rt cl lo zt dn’ stands for ‘develop country plans good economy’.

What is the code for ‘finance’ in the given code language?

((a))
lo
((b))
xy
((c))
dn
((d))
mn
((e))
zt

Show Answer

Answer: ((d))

Thus, the code for ‘finance’ is ‘mn’.

Which of the following represents the code for ‘make good plans now’?

((a))
xy zt mn fs
((b))
xy dn mn fs
((c))
xy zt lo br
((d))
zt mn lo fs
((e))
xy zt lo fs

Show Answer

Answer: ((e))

xy zt lo fs

Code for ‘make’ is ‘xy’.

Code for ‘good’ is ‘zt’.

Code for ‘plans’ is ‘lo’.

Code for ‘now’ is ‘fs’.

Hence, ‘xy zt lo fs’ represents the code for ‘make good plans now’.

What does the code ‘cl’ stand for in the given code language?

((a))
Either ‘country’ or ‘helps’
((b))
develop
((c))
helps
((d))
Either ‘develop’ or ‘country’
((e))
country

Show Answer

Answer: ((d))

Either ‘develop’ or ‘country’

Thus, code ‘cl’ stand for either ‘develop’ or ‘country’ in the given code language.

Which of the following means ‘develop’ in that code language?

((a))
oj
((b))
cl
((c))
rt
((d))
Either (2) or (3)
((e))
br

Show Answer

Answer: ((d))

Either (2) or (3)

Thus ‘develop’ is coded as either ‘cl’ or ‘rt’.

Direction: In the question below are given two statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statements:

All numbers are figures.

Only a few figures are digits.

Conclusions:

I. No number is digit.

II. Some numbers are figures.

((a))
Only I follow
((b))
Only II follow
((c))
Either I or II follow
((d))
Neither I nor II follows
((e))
All follows

Show Answer

Answer: ((b))

Only II follow

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. No number is digit → False (It is possible but not definite)

II. Some numbers are figures → True (As it is given in the statement that All numbers are figures, some numbers are figures is definitely true)

Thus, conclusion II follows.

Statements:

No book is a letter.

Only a few letters are words.

Conclusions:

I. Some words are not book.

II. No book is a word.

((a))
Only I follow
((b))
Only II follow
((c))
Either I or II follow
((d))
Neither I nor II follows
((e))
All follows

Show Answer

Answer: ((a))

Only I follow

The least possible Venn diagram for the given statements is as follows

Conclusions:

I. Some words are not book → True (As No book is letter given so that the word which are letter they will never be the book.)

II. No book is a word → False (As it is the definite conclusion and no direct relation given between book and word so the we cannot define it.)

Thus, only conclusion I follows.

Statement:

All even are numbers.

Only numbers are odd.

Conclusion:

I. Some numbers are odd.

II. No odd is even.

((a))
Only I follows
((b))
Only II follows
((c))
Either I or II follows
((d))
Neither I nor II follows
((e))
Both I and II follow

Show Answer

Answer: ((e))

Both I and II follow

The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. Some numbers are odd → True (As shown in the above diagram).

II. No odd is even → True (As in the given statement only numbers are odd and no other entity can become an odd).

Hence, both conclusions I and II follow.

Directions: Study the information given below carefully and answer the questions that follow.

Seven cars are parked in a parking lot numbers from C1 to C7. Further, it is known that C3 is 10 m towards the South of C1. C6 is 7 m towards the North of C7, which is 10 m towards the South of C5. C4 is 10 m towards the East of C6, which is 3 m towards the West of C1. C2 is 3 m towards the East of C5.

If a car C8 is parked exactly between C1 and C3, then what is the minimum distance between C6 and C8?

((a))
8.07 km
((b))
5 m
((c))
5.83 m
((d))
7.83 m
((e))
8 km

Show Answer

Answer: ((c))

5.83 m

We have drawn the figure according to the information given in the question,

Now, the distance between C6 and C8 = √ $({3^2} + {5^2})$ = 5.83 km

Hence, the distance between C6 and C8 is 5.83 km.

If a car C8 is parked exactly between C5 and C7, then how far is C6 with respect to C8?

((a))
5 m
((b))
4 m
((c))
1 m
((d))
2 m
((e))
3 m

Show Answer

Answer: ((d))

2 m

We have drawn the figure according to the information given in the question,

From the figure, the distance between C6 and C8 is 2 m.

Hence, the distance between C6 and C8 is 2 m.

Which among following cars are collinear?

((a))
C5, C2, C1
((b))
C1, C4, C6
((c))
C1, C4, C3
((d))
C1, C6, C7
((e))
None of the above

Show Answer

Answer: ((b))

C1, C4, C6

We have drawn the figure according to the information given in the question,

From the figure, it is clear that C1, C4 and C6 are collinear.

Hence, C1, C4 and C6 are collinear.

If it is possible to make a meaningful word from the second, fifth, seventh and tenth letters of the word "CAPITULATE", then which of the following letter is the second letter of the word? If more than one such word can be made, then give "X" as the answer and if no such word can be formed then give "Z" as the answer.

((a))
L
((b))
A
((c))
E
((d))
X
((e))
Z

Show Answer

Answer: ((d))

Given word:- CAPITULATE

The second letter is 'A', the fifth letter is 'T', the seventh letter is 'L' and the tenth letter is 'E'

The possible meaningful word can be formed by using the words A, T, L, E are Late, Tale and Teal.

Hence, the correct answer is X.

Direction: Following questions are based on the five words given below, Study the following words and answer.

WON DAD RAW BAT HAT

(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)

If in each of the given words, each of the consonants is changed to its previous letter and each vowel is changed to its next letter in the English alphabetical series, then in how many words thus formed will at least one vowel appear?

((a))
Two
((b))
Only one
((c))
More than three
((d))
Three
((e))
None

Show Answer

Answer: ((b))

Only one

Given group of words:

WON DAD RAW BAT HAT

If in each of the given words, each of the consonants is changed to its previous letter and each vowel is changed to its next letter in the English alphabetical series, After the arrangement, the new words formed are:

Required arrangement: consonants → previous letter, vowel → next letter

At least one vowel after rearrangement is -

WON → VPM

DAD → CBC

RAW → QBV

BAT → ABS

HAT → GBS

Thus, ABS is the newly formed word with at least one vowel in it.

If the third letter in each of the words is changed to the next letter in the English alphabetical order, how many words thus formed will do not have the last letter as a vowel?

((a))
One
((b))
Two
((c))
Three
((d))
None
((e))
All of these

Show Answer

Answer: ((a))

One

Given the group of letters:

WON DAD RAW BAT HAT

The new words formed after the third letter in each of the words is changed:

WOO DAE RAX BAU HAU

Clearly, the word ‘RAX’ does not have its last letter as a vowel.

If the position of the first and the third alphabet of each of the words are interchanged, which of the following will not form a meaningful word in the new arrangement?

((a))
WON
((b))
RAW
((c))
BAT
((d))
HAT
((e))
None of these

Show Answer

Answer: ((d))

HAT

Given group of letters:

WON DAD RAW BAT HAT

If arranged as per the question the new words formed will be:

NOW DAD WAR TAB TAH

Thus, the only word ‘HAT’ will not form a meaningful word in the new arrangement.

If the given words are arranged in the order as they appear in a dictionary from left to right, which of the following will be the fourth from the left end?

((a))
BAT
((b))
WON
((c))
RAW
((d))
HAT
((e))
DAD

Show Answer

Answer: ((c))

RAW

Given group of letters:

WON DAD RAW BAT HAT

After arrangement: As per the dictionary order from left to right -

BAT DAD HAT RAW WON

Thus, the word ‘RAW’ will be the fourth from the left end.

How many letters are there in the English alphabetical series between the second letter of the word which is second from the right end and the third letter of the word which is second from the left end?

((a))
Three
((b))
Two
((c))
One
((d))
More than three
((e))
None

Show Answer

Answer: ((b))

Two

Given group of letters:

WON DAD RAW BAT HAT

The word ‘BAT’ is second from the right end → the second letter of the word is A.

The word ‘DAD’ is second from the left end → the third letter of the word is D.

Thus, there are two letters between A & D i.e., B, C as per the English alphabetical series.

Directions: Read the information and answer the given questions.

Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

T is seated immediately to the left of V and is directly opposite Q. P and V occupy corner positions, but they are not facing each other. W is seated on a side of the square, immediately to the right of V. P and T are not adjacent. U is seated in a corner position, but do not face P. R does not occupy a corner seat.

Who among the following sits opposite to W?

((a))
P
((b))
Q
((c))
R
((d))
S
((e))
T

Show Answer

Answer: ((c))

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

W is seated on a side of the square, immediately to the right of V.

T is seated immediately to the left of V and is directly opposite Q.

P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

P and T are not adjacent.

Now, we can eliminate Case 2.

U is seated in a corner position, but do not face P.

R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is R.

Who among the following sits third to the right of R?

((a))
P
((b))
Q
((c))
S
((d))
T
((e))
U

Show Answer

Answer: ((a))

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, are seated around a square table, but not necessarily in the same order. Four of them occupy the corner seats and face towards the centre, while the remaining four sit on the sides and face outwards.

1. W is seated on a side of the square, immediately to the right of V.

T is seated immediately to the left of V and is directly opposite Q.

P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

P and T are not adjacent.

Now, we can eliminate Case 2.

U is seated in a corner position, but do not face P.

R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is P.

How many people sit between P and T, from the left of P?

((a))
One
((b))
Two
((c))
Three
((d))
Four
((e))
None

Show Answer

Answer: ((b))

Two

1. W is seated on a side of the square, immediately to the right of V.

T is seated immediately to the left of V and is directly opposite Q.

P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

P and T are not adjacent.

Now, we can eliminate Case 2.

U is seated in a corner position, but do not face P.

R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is Two.

Pick the odd one out.

((a))
P
((b))
Q
((c))
S
((d))
V
((e))
U

Show Answer

Answer: ((b))

1. W is seated on a side of the square, immediately to the right of V.

T is seated immediately to the left of V and is directly opposite Q.

P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

P and T are not adjacent.

Now, we can eliminate Case 2.

U is seated in a corner position, but do not face P.

R does not occupy a corner seat.

This is our final arrangement,

Except for Q, all others face inside.

Hence, the correct answer is **Q.**

Who among the following sits immediately right of the one who sits opposite to W?

((a))
P
((b))
Q
((c))
U
((d))
S
((e))
T

Show Answer

Answer: ((c))

1. W is seated on a side of the square, immediately to the right of V.

T is seated immediately to the left of V and is directly opposite Q.

P and V occupy corner positions, but they are not facing each other.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

P and T are not adjacent.

Now, we can eliminate Case 2.

U is seated in a corner position, but do not face P.

R does not occupy a corner seat.

This is our final arrangement,

Hence, the correct answer is U.

Directions: Read the information and answer the given questions.

Six pencils, P, L, S, G, Z, and Q, have different lengths. Z is just shorter than S but just longer than P. L is shorter than S. Q is longer than at least three pencils, but not the longest pencil.

Which of the following pencils is the second longest?

((a))
Q
((b))
Z
((c))
G
((d))
L
((e))
S

Show Answer

Answer: ((a))

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Q.

If pencil Q is 15 cm and Z is 10 cm then what could be the length of L?

((a))
16 cm
((b))
19 cm
((c))
17 cm
((d))
14 cm
((e))
Can’t be determined

Show Answer

Answer: ((e))

Can’t be determined

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

1. Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Can't be determined.

How many pencils are longer than L?

((a))
Four
((b))
Three
((c))
Five
((d))
Two
((e))
One

Show Answer

Answer: ((c))

Five

Given: Six pencils, P, L, S, G, Z, and Q, have different lengths.

1. Q is longer than at least three pencils, but not the longest pencil.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Case 1: _ > _ > Q > _ > _ > _

Case 2: _ > Q > _ > _ > _ > _

Z is just shorter than S but just longer than P.

Case 1: _ > _ > Q > S > Z > P

Case 2: _ > Q > _ > S > Z > P

Case 2a: _ > Q > S > Z > P > _

L is shorter than S.

Now, we can eliminate Case 1 and Case 2.

Case 2a: _ > Q > S > Z > P > L

This is our final arrangement,

Case 2a: G > Q > S > Z > P > L

Hence, the correct answer is Five.

Directions: In the following question assuming the given statements to be true, find which of the conclusion among given two conclusions is/are definitely true and then give your answers accordingly.

Statements:

Y < U ≤ Q ≥ S >T = O > P

Conclusions:

I. P < Q

II. Y < S

((a))
Conclusion I is true.
((b))
Conclusion II is true.
((c))
Either conclusion I or II is true.
((d))
Neither conclusion I nor II is true.
((e))
Both conclusions I and II are true

Show Answer

Answer: ((a))

Conclusion I is true.

Given statement: Y < U ≤ Q ≥ S >T = O > P

Conclusions:

I. P < Q → True as Q ≥ S >T = O > P, thus Q > P.

II. Y < S → False as Y < U ≤ Q ≥ S, thus there is no definite relation between them.

Hence, only conclusion I is true.

Statements:

C < P ≤ M = U = S < E ≥ T

Conclusions:

I. C > E

II. E < P

((a))
Conclusion I is true.
((b))
Conclusion II is true.
((c))
Either conclusion I or II is true.
((d))
Neither conclusion I nor II is true.
((e))
Both conclusion I and II are true.

Show Answer

Answer: ((d))

Neither conclusion I nor II is true.

Given statement is: C < P ≤ M = U = S < E ≥ T

Conclusion:

I. C > E → FalseasC < P ≤ M = U = S < E, thusC < E.

II. E < P → False as P ≤ M = U = S < E, P < E.

Hence, neither conclusion I nor II is true.

Directions: In the following question assuming the given statements to be true, find which of the conclusion among given conclusions is /are definitely true and then give your answers accordingly.

Statement: A > K ≤ D; D < B; B > K ≤ C

Conclusions:

I. A < C

II. A = C

((a))
Both I and II are true
((b))
Only II
((c))
Only I is true
((d))
Either I or II is true
((e))
Neither I nor II is true

Show Answer

Answer: ((e))

Neither I nor II is true

Given: A > K ≤ D; D < B; B > K ≤ C

On combining: A > K ≤ D = C < B

I. A < C ⇒ False (as A > K ≤ D = C relation between A and C can’t be established)

II. A = C ⇒ (as A > K ≤ D = C relation between A and C can’t be established)

Hence, Neither I nor II is true.

How many pairs of letters are there in the word "MISTAKE" which have as many letters between them as in the English alphabetical series (both in forward and backward direction)?

((a))
None
((b))
Three
((c))
Two
((d))
One
((e))
More than three

Show Answer

Answer: ((d))

One

Forward pair: ST

Backward pair: None

Thus, there are one such pair of letters in the word "MISTAKE" which have as many letters between them as in the English alphabetical series (both in forward and backward direction).

Hence, the correct answer is one such pair.

Directions: Read the information and answer the given question.

Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

There is exactly one day between E and G. The number of reservations before B is one less than the number of reservations after D. E has a reservation on Wednesday. D's reservation is after B but before F. There are exactly two days between G and B.

Who has the reservation on Monday?

((a))
C
((b))
B
((c))
E
((d))
G
((e))
D

Show Answer

Answer: ((a))

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

E has a reservation on Wednesday.

Days	Persons
Monday
Tuesday
Wednesday	E
Thursday
Friday
Saturday

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday
Wednesday	E	E
Thursday
Friday	G
Saturday

There are exactly two days between G and B.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B
Wednesday	E	E
Thursday		B
Friday	G
Saturday

The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B	D
Wednesday	E	E
Thursday	D	B
Friday	G
Saturday

D's reservation is after B but before F.

Now, we can eliminate Case 2.

Days	Persons
Case 1
Monday
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

This is our final arrangement,

Days	Persons
Case 1
Monday	C
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

Hence, the correct answer is C.

On which day D reserved the bus?

((a))
Monday
((b))
Tuesday
((c))
Wednesday
((d))
Thursday
((e))
Friday

Show Answer

Answer: ((d))

Thursday

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

E has a reservation on Wednesday.

Days	Persons
Monday
Tuesday
Wednesday	E
Thursday
Friday
Saturday

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday
Wednesday	E	E
Thursday
Friday	G
Saturday

There are exactly two days between G and B.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B
Wednesday	E	E
Thursday		B
Friday	G
Saturday

The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B	D
Wednesday	E	E
Thursday	D	B
Friday	G
Saturday

D's reservation is after B but before F.

Now, we can eliminate Case 2.

Days	Persons
Case 1
Monday
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

This is our final arrangement,

Days	Persons
Case 1
Monday	C
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

Hence, the correct answer is Thursday.

Who among the following is scheduled immediately after C?

((a))
B
((b))
D
((c))
E
((d))
F
((e))
G

Show Answer

Answer: ((a))

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

E has a reservation on Wednesday.

Days	Persons
Monday
Tuesday
Wednesday	E
Thursday
Friday
Saturday

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday
Wednesday	E	E
Thursday
Friday	G
Saturday

There are exactly two days between G and B.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B
Wednesday	E	E
Thursday		B
Friday	G
Saturday

The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B	D
Wednesday	E	E
Thursday	D	B
Friday	G
Saturday

D's reservation is after B but before F.

Now, we can eliminate Case 2.

Days	Persons
Case 1
Monday
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

This is our final arrangement,

Days	Persons
Case 1
Monday	C
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

Hence, the correct answer is B.

How many persons are scheduled between C and G?

((a))
None
((b))
One
((c))
Two
((d))
Three
((e))
Four

Show Answer

Answer: ((d))

Three

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

E has a reservation on Wednesday.

Days	Persons
Monday
Tuesday
Wednesday	E
Thursday
Friday
Saturday

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday
Wednesday	E	E
Thursday
Friday	G
Saturday

There are exactly two days between G and B.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B
Wednesday	E	E
Thursday		B
Friday	G
Saturday

The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B	D
Wednesday	E	E
Thursday	D	B
Friday	G
Saturday

D's reservation is after B but before F.

Now, we can eliminate Case 2.

Days	Persons
Case 1
Monday
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

This is our final arrangement,

Days	Persons
Case 1
Monday	C
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

Hence, the correct answer is Three.

Which among the following combination is correct?

((a))
B - Thursday
((b))
C - Tuesday
((c))
D - Friday
((d))
G - Monday
((e))
F - Saturday

Show Answer

Answer: ((e))

F - Saturday

Given: Six people, namely, B, C, D, E, F, and G, have bus reservations on six different days of the same week, Monday to Saturday, one person per day, but not necessarily in the same order.

E has a reservation on Wednesday.

Days	Persons
Monday
Tuesday
Wednesday	E
Thursday
Friday
Saturday

2. There is exactly one day between E and G.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday
Wednesday	E	E
Thursday
Friday	G
Saturday

There are exactly two days between G and B.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B
Wednesday	E	E
Thursday		B
Friday	G
Saturday

The number of reservations before B is one less than the number of reservations after D.

Now, we can eliminate Case 2.

Days	Persons
Case 1	Case 2
Monday		G
Tuesday	B	D
Wednesday	E	E
Thursday	D	B
Friday	G
Saturday

D's reservation is after B but before F.

Now, we can eliminate Case 2.

Days	Persons
Case 1
Monday
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

This is our final arrangement,

Days	Persons
Case 1
Monday	C
Tuesday	B
Wednesday	E
Thursday	D
Friday	G
Saturday	F

Hence, the correct answer is F - Saturday.

In a certain way four of the five are alike find the one which does not follow the same pattern?

((a))
DGI
((b))
HEK
((c))
MPR
((d))
VOZ
((e))
NSA

Show Answer

Answer: ((c))

MPR

Since, each letter cluster contains a vowel except MPR which contain only consonants.

Hence, the odd one is MPR.

Numerical Ability (40 questions)

The table shows the number of red and green balls in five different bags.

Bag	Number of red ball	Number of green balls
A	34	44
B	42	38
C	64	22
D	28	62
E	72	28

Difference between number of green balls in Bag D and C is 5t. Find the value of t?

((a))
1
((b))
8
((c))
6
((d))
4
((e))
3

Show Answer

Answer: ((b))

Calculations:

Difference between green balls in Bag D and Bag C:

Bag D green = 62

Bag C green = 22

Difference = 62 – 22 = 40 =5t

So, t = 40 / 5 = 8

Find the ratio between number of red balls in bag A and number of green balls in Bag B?

((a))
5:9
((b))
7:11
((c))
17:19
((d))
7:9
((e))
11:19

Show Answer

Answer: ((c))

17:19

Calculations:

Ratio of red balls in Bag A to green balls in Bag B:

Red in A = 34

Green in B = 38

Ratio = 34 : 38 = 17 : 19

Find the total number of balls in bag E?

((a))
95
((b))
180
((c))
185
((d))
100
((e))
120

Show Answer

Answer: ((d))

100

Calculations:

Total number of balls in Bag E:

Red = 72

Green = 28

Total = 72 + 28 = 100

Find the difference between number of red balls in bag B and number of red balls in Bag E?

((a))
74
((b))
62
((c))
55
((d))
30
((e))
32

Show Answer

Answer: ((d))

Calculations:

Bag E red = 72

Bag B red = 42

Difference = 72 – 42 = 30

Find the average number of green balls in Bag A, B and E?

((a))
46.67
((b))
45.69
((c))
36.67
((d))
32.67
((e))
39.67

Show Answer

Answer: ((c))

36.67

Calculations:

Average green balls in Bags A, B, and E:

Green in A = 44

Green in B = 38

Green in E = 28

Total = 44 + 38 + 28 = 110

Average = 110 ÷ 3 = 36.67

A running train crosses a stationary pole in 4 seconds and a platform 75m long in 9 seconds. what will be the speed and length of the train respectively?

((a))
45 km/hr. and 100m
((b))
30 km/hr. and 150m
((c))
54 km/hr. and 60m
((d))
63 km/hr. and 225m
((e))
none of these

Show Answer

Answer: ((c))

54 km/hr. and 60m

Given:

Time to cross the pole = 4 seconds

Time to cross the 75m platform = 9 seconds

Calculation:

Let the speed of train be x m/sec.

And length of train = L m

When train crosses the pole:

L = 4x

When train crosses the platform:

L + 75 = 9x

Put L = 4x

4x + 75 = 9x

5x = 75

x = 15 m/sec = 15 × 18/5 = 54 km/hr

L = 4 × 15 = 60 m

∴The speed and length of train is 54 km/hr. and 60m respectively.

12 men and 15 women can complete a work in 24 days. If the efficiency of a woman is 75% of a man, then to complete the work in 12 days how many men are required?

((a))
105/2
((b))
89/2
((c))
57/2
((d))
79/2
((e))
93/2

Show Answer

Answer: ((e))

93/2

Given:

12 men and 15 women can complete a work in 24 days

The efficiency of a woman is 75% of a man

Concept Used:

Work done = efficiency × time

Calculation:

Let, the efficiency of a man = 4

The efficiency of a woman = 4 × 3/4 = 3

Total work = [(12 × 4) + (15 × 3)] × 24 = (93 × 24) unit

To complete the work in 12 days number of men required are

⇒ (93 × 24)/(12 × 4)

⇒ 93/2

∴ The correct answer is option 5

Find out the wrong term in the following series.

74, 99, 50, 125, 10, 179

((a))
74
((b))
125
((c))
10
((d))
179
((e))
50

Show Answer

Answer: ((b))

125

Calculation:

The series is

74 + 25= 99

99 – 49 = 50

50 + 81 = 131

131 – 121 = 10

10 + 169 = 179

∴ 125 is the wrong number in the series.

Find out the wrong term in the following series.

38, 38, 57, 114, 284, 855

((a))
284
((b))
114
((c))
57
((d))
855
((e))
None of these

Show Answer

Answer: ((a))

284

Calculation:

The series is

38 × 1 = 38

38 × 1.5 = 57

57 × 2 = 114

114 × 2.5 = 285

285 × 3 = 855

∴ 284 is wrong number in the series.

In each of the following number series, the wrong number is given, find out that number.

65, 126, 219, 347, 517, 735

((a))
219
((b))
347
((c))
735
((d))
126
((e))
517

Show Answer

Answer: ((d))

126

The series follows the following pattern:

43 + 1 = 65

53 + 2 = 127

63 + 3 = 219

73 + 4 = 347

83 + 5 = 517

93 + 6 = 735

∴ The wrong term in the series is 126.

In each of the following number series, the wrong number is given, find out that number.

240, 244, 253, 276, 327, 448

((a))
244
((b))
327
((c))
253
((d))
448
((e))
276

Show Answer

Answer: ((e))

276

The series follows the following pattern:

240 + 2² = 244

244 + 3² = 253

253 + 5² = 278

278 + 7² = 327

327 + 11² = 448

∴ The wrong term in the series is 276.

In each of the following number series, the wrong number is given, find out that number.

351, 334, 300, 250, 181, 96

((a))
334
((b))
300
((c))
250
((d))
181
((e))
96

Show Answer

Answer: ((c))

250

The series follows the following pattern:

351 – 17 = 334

334 – 34 = 300

300 – 51 = 249

249 – 68 = 181

181 – 85 = 96

∴ The wrong term in the series is 250.

The ratio of the present ages of two cousins is 2 : 3 and six years back, the ratio was 1 : 3. Find the ratio of the cousins' ages after 8 years?

((a))
3 : 4
((b))
4 : 5
((c))
5 : 6
((d))
4 : 7
((e))
7 : 8

Show Answer

Answer: ((b))

4 : 5

Given:

The present ages of two cousins = 2 : 3

6 years ago

The ages of the cousins = 1 : 3

Calculation:

Let the present ages of the two Cousins be 2x and 3x respectively.

∴ According to the question:

⇒ (2x – 6)/(3x – 6) = 1/3

⇒ 6x – 18 = 3x – 6

⇒ 3x = 12

⇒ x = 4.

∴ required ratio:

(2x + 8) : (3x + 8)

⇒ 8 + 8 : 12 + 8

⇒ 16 : 20

⇒ 4 : 5.

∴ The ratio of the cousins' ages after 8 years is 4 : 5.

Two candidates appeared at an election. One of them get 9 votes more than the other and his vote was 56% of the sum of their total votes. The votes obtained by them are:

((a))
39, 30
((b))
41, 32
((c))
42, 33
((d))
43, 34
((e))
None of these

Show Answer

Answer: ((c))

42, 33

Given:

Two candidates appeared at an election. One of them get 9 votes more than the other and his vote was 56% of the sum of their total votes.

Calculation:

Let their votes be (x + 9) and x

Then, x + 9 = 56/100(x + 9 + x)

⇒ 25 (x + 9) = 14 (2x + 9)

⇒ 3x = 99

⇒ x = 33

∴ Their votes are 42 and 33

Priya, Shanu and Raj started a business by investing Rs. 10,400, Rs. 36,400 and Rs. 31,200. At the end of the first year, Shanu’s share in total profit was Rs. 11,200. What was the total profit earned by them?

((a))
Rs. 20,000
((b))
Rs. 22,000
((c))
Rs. 24,000
((d))
Rs. 26,000
((e))
None of these

Show Answer

Answer: ((c))

Rs. 24,000

Given:

Priya’s investments = Rs. 10,400

Shanu’s investment = Rs. 36,400

Raj’s investment = Rs. 31,200

Shanu’s profit share = Rs. 11,200

Formula used:

Profit share = investment × time period

Calculation:

Ratio of investments in business by Priya, Shanu and Raj = 10400 ∶ 36400 ∶ 31200

⇒ 2 ∶ 7 ∶ 6

Let the total profit is 15 unit.

Now Shanu’s profit = 7 unit = Rs. 11,200

⇒ 1 unit = Rs. 1600

Total profit = 15 units = Rs. (15 × 1600)

⇒ Rs. 24,000

∴ Total profit earned by them is Rs. 24,000

The line graph shows the number of items sold and unsold in five different months.

Difference between number of items sold in February and April is x. Find the value of 7x?

((a))
165
((b))
185
((c))
194
((d))
105
((e))
115

Show Answer

Answer: ((d))

105

Calculations:

Difference between items sold in February and April:

February sold = 65

April sold = 50

Difference = 15 = x

So, 7x = 105

Find the ratio between number of items unsold in January and number items unsold in March?

((a))
2:3
((b))
4:9
((c))
3:4
((d))
4:5
((e))
7:8

Show Answer

Answer: ((c))

3:4

Calculations:

Ratio of unsold items in January to unsold items in March:

January unsold = 15

March unsold = 20

Ratio = 3 : 4

Find the average items sold in March, April and May together?

((a))
55.27
((b))
40.27
((c))
46.67
((d))
36.55
((e))
49.27

Show Answer

Answer: ((c))

46.67

Calculations:

Average items sold in March, April and May:

30 + 50 + 60 = 140

Average = 140 ÷ 3 = 46.67 items

In which month is the number of items unsold the highest, and how many more unsold items are there compared to January?

((a))
29
((b))
25
((c))
22
((d))
12
((e))
18

Show Answer

Answer: ((b))

Calculations:

Highest unsold month and difference from January:

Highest unsold = February (40)

Difference = 40 – 15 = 25 items

Number of items sold in June is 10 more than the number of items sold in May. Find the number of items sold in June?

((a))
85
((b))
60
((c))
70
((d))
80
((e))
90

Show Answer

Answer: ((c))

Calculations:

Items sold in June (10 more than May):

May sold = 60

June sold = 60 + 10 = 70

Sandeep lent Rs. 25000 to Arvind and if Arvind returned it to him after 3 years at simple interest rate of 12%, find the amount of interest.

((a))
Rs. 10,000
((b))
Rs. 9000
((c))
Rs. 8000
((d))
Rs. 5000
((e))
None of these

Show Answer

Answer: ((b))

Rs. 9000

Given:

Arvind borrow an amount = Rs. 25000

Time period = 3 years

Rate of interest = 12%

Formula Used:

(P × R × T)/100 = S.I

Where P = Principle, R = Rate of interest, T = Time, S.I = Simple interest.

Calculation:

S.I = (P × R × T)/100

⇒ (25000 × 12 × 3)/100

⇒ 250 × 36

⇒ 9000

∴ The amount of interest is Rs. 9000.

Additional Information

Borrowed money is considered as the Principle.

Boat can do a round trip of 88 km (44 km to and fro) in 12 hours. If ratio of boat speed to stream speed is 3 ∶ 1, Find stream speed (in km/hr)

((a))
2.25
((b))
2.5
((c))
2.75
((d))
3.25
((e))
3.5

Show Answer

Answer: ((c))

2.75

Given:

Time for 44 km round trip = 12 hours.

Ratio of boat speed to stream speed = 3 : 1

Formula:

Speed = Distance/Time

Downstream speed = u + v

Upstream speed = u – v

u and v are speed of boat and stream respectively

Calculation:

Let speeds of boat and stream be 3x and x respectively.

44/(3x – x) + 44/(x + 3x) = 12

44/2x + 44/4x = 12

132/4x = 12

x = 2.75 km/hr

∴ The speed of stream is 2.75 km/h.

What will come in the place of question mark (?) in the given expression?

12² + 13² – 15 × 45 ÷ 5 = 89 × ?

((a))
3
((b))
2
((c))
4
((d))
1
((e))
7

Show Answer

Answer: ((b))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below

Calculations:

122 + 132 – 15 × 45 ÷ 5 = 89 × ?

⇒ 144 + 169 – 135 = 89 × ?

⇒ 178 = 89 × ?

⇒ ? = 178/89

⇒ ? = 2

∴ The value of ? is 2

What will come in the place of question mark (?) in the given expression?

30% of 150 + 2² = ?² – 50% of 30

((a))
8
((b))
6
((c))
7
((d))
9
((e))
10

Show Answer

Answer: ((a))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below

Calculations:

30% of 150 + 2² = ?2 – 50% of 30

⇒ (30/100) × 150 + 4 = ?² – (50/100) × 30

⇒ 45 + 4 = ?² – 15

⇒ ?² = 64

⇒ ? = √64 = 8

∴ The value of ? is 8

What will come in the place of ‘?’ in the following question?

90 + 9 × 42 ÷ (119 ÷ 17) = ?

((a))
154
((b))
44
((c))
144
((d))
164
((e))
None of these

Show Answer

Answer: ((c))

144

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

90 + 9 × 42 ÷ (119 ÷ 17) = ?

⇒ 90 + 9 × 42 ÷ 7 = ?

⇒ 90 + 9 × 6 = ?

⇒ 90 + 54 = ?

⇒ 144 = ?

∴ The value of ? is 144

What will come in the place of the question mark ‘?’ in the following question?

∛1728 ÷ √144 + ?² = 257

((a))
256
((b))
16
((c))
26
((d))
√258
((e))
None of these

Show Answer

Answer: ((b))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

∛1728 ÷ √144 + ?² = 257

⇒ 12 ÷ 12 + ?²= 257

⇒ 1 + ?²= 257

⇒ ?² = 257 – 1

⇒ ?² = 256

⇒ ? = √256

⇒ ? = 16

∴ The value of x is 16

What will come in the place of ‘?’ in the following question?

96 × 108 ÷ 24 + 169 ÷ 13 = ?

((a))
465
((b))
419
((c))
445
((d))
545
((e))
None of these

Show Answer

Answer: ((c))

445

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

96 × 108 ÷ 24 + 169 ÷ 13 = ?

⇒ 432 + 13 = ?

⇒ ? = 445

∴ The value of ? is 445

What should come in place of question mark (?) in the following question?

[3³ × 2⁴] ÷ 16 × 49 – 594 = ?³

((a))
7
((b))
11
((c))
8
((d))
9
((e))
None of these

Show Answer

Answer: ((d))

Concept used:

Calculation:

Considering the following given question

[3³ × 2⁴] ÷ 16 × 49 – 594 = ?³

⇒ [27 × 16] ÷ 16 × 49 – 594 = ?³

⇒ [432] ÷ 16 × 49 – 594 = ?³

⇒ 432 ÷ 16 × 49 – 594 = ?³

⇒ 27 × 49 – 594 = ?³

⇒ 1323 – 594 = ?³

⇒ ?³ = 729

⇒ ? = 9

∴ ? = 9

What will come in the place of the question mark ‘?’ in the following question?

(6.5% of 375) – (0.85% of 230) = ?

((a))
23.42
((b))
24.24
((c))
21.64
((d))
25.76
((e))
22.42

Show Answer

Answer: ((e))

22.42

Concept used:

Follow BODMAS rule to solve this question, as per the order given below

Calculation:

(6.5% of 375) – (0.85% of 230) = ?

⇒24.375 − 1.955 = ?

⇒ 22.42 = ?

∴ The value of ? is 22.42

What should come in place of question mark (?) in the following questions?

16 + √361 – 19 + √625 + 76 = ?

((a))
189
((b))
117
((c))
122
((d))
154
((e))
None of these

Show Answer

Answer: ((b))

117

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

16 + √361 – 19 + √625 + 76 = ?

⇒ 16 + 19 – 19 + 25 + 76 = ?

⇒ 16 + 25 + 76 = ?

⇒ 117 = ?

∴ Result will be 117.

What will come in the place of the question mark ‘?’ in the following question?

24 + 112 – 64 ÷ 8 + 12 ÷ 3 = ?

((a))
122
((b))
132
((c))
133
((d))
162
((e))
None of these

Show Answer

Answer: ((b))

132

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

24 + 112 – 64 ÷ 8 + 12 ÷ 3 = ?

⇒ 24 + 112 – 8 + 4 = ?

⇒ 136 – 8 + 4 = ?

⇒ 140 – 8 = ?

⇒ ? = 132

∴ Result will be 132.

What should come in place of question mark (?) in the following questions?

26 + 22 – 24 + 112 ÷ 16 × 4 = ?

((a))
51
((b))
54
((c))
52
((d))
53
((e))
None of these

Show Answer

Answer: ((c))

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

26 + 22 – 24 + 112 ÷ 16 × 4 = ?

⇒ 26 + 22 – 24 + 7 × 4 = ?

⇒ 26 + 22 – 24 + 28 = ?

⇒ 76 – 24 = ?

⇒ 52 = ?

∴ Result will be 52.

What should come in place of question mark (?) in the following questions?

1728 - √144 × 20 ÷ 2.5 + 89 – 12 = ?

((a))
1509
((b))
1609
((c))
1709
((d))
1109
((e))
None of these

Show Answer

Answer: ((c))

1709

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

1728 - √144 × 20 ÷ 2.5 + 89 – 12 = ?

⇒ 1728 – 12 × 8 + 89 – 12 = ?

⇒ 1728 – 96 + 89 – 12 = ?

⇒ 1817 – 108 = ?

⇒ 1709 = ?

∴ Result will be 1709.

What should come in place of question mark (?) in the following questions?

[(22)² × 2 ÷ 22] ÷ 44 × 5 – 1 = ? – 124

((a))
628
((b))
738
((c))
724
((d))
728
((e))
None of these

Show Answer

Answer: ((e))

None of these

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

[(22)2 × 2 ÷ 22] ÷ 44 × 5 – 1 = ? – 124

⇒ [484 ÷ 11] ÷ 44 × 5 – 1 = ? – 124

⇒ 44 ÷ 44 × 5 – 1 = ? – 124

⇒ 1 × 5 – 1 = ? – 124

⇒ 5 – 1 = ? – 124

⇒ 4 = ? – 124

⇒ ? = 128

∴ ? = 128

What should come in place of question mark (?) in the following questions?

2000 % of 15 ÷ 5 × 12 = ?

((a))
730
((b))
620
((c))
710
((d))
720
((e))
None of these

Show Answer

Answer: ((d))

720

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

⇒ 2000 % of 15 ÷ 5 × 12 = ?

⇒ 300 ÷ 5 × 12 = ?

⇒ 60 × 12 = ?

⇒ ? = 720

∴ ? = 720

What will come in the place of the question mark ‘?’ in the following question?

81 – 9 × √49 + 21 + √225 × 2 = ?

((a))
99
((b))
79
((c))
89
((d))
69
((e))
None of these

Show Answer

Answer: ((d))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

81 – 9 × √49 + 21 + √225 × 2 = ?

⇒ 81 – 9 × 7 + 21 + 15 × 2 = ?

⇒ 81 – 63 + 21 + 30 = ?

⇒ 81 – 63 + 51 = ?

⇒ 132 – 63 = ?

⇒ 69 = ?

∴ ? = 69.

What will come in the place of the question mark ‘?’ in the following question?

81 ÷ 9 × 3 + 21 – 63 + 16 × 6 = ?

((a))
31
((b))
81
((c))
41
((d))
51
((e))
None of these

Show Answer

Answer: ((b))

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

81 ÷ 9 × 3 + 21 – 63 + 16 × 6 = ?

⇒ 9 × 3 + 21 – 63 + 16 × 6 = ?

⇒ 27 + 21 – 63 + 96 = ?

⇒ 144 – 63 = ?

⇒ 81 = ?

∴ The value of ? is 81

A shopkeeper increased the cost price by 30% and gave 30% discount and suffered a loss of Rs. 810. What was the cost price of product ?

((a))
990
((b))
1000
((c))
720
((d))
9000
((e))
None of these

Show Answer

Answer: ((d))

9000

Given:

M.R.P = 30% more than CP

Discount = 30%

Loss = Rs. 810

Formula Used:

Cost price × (100 + Profit %)/100 = Selling price

Also, Cost price × (100 - Loss %)/100 = Selling price

{(M.R.P – S.P)/M.R.P} × 100 = Discount %

Calculation:

Let the C.P of the product be 100x.

M.R.P = 100x × (130/100)

⇒ 130x

Discount = 30%

⇒ 130x × (30/100) = 39x

S.P = 130x – 39x

⇒ 91x

Loss = C.P – S.P

⇒ 100x – 91x

⇒ 9x

Value of 90x = 810

⇒ x = 810/9

⇒ x = 90

C.P = 100x

⇒ 100 × 90

⇒ 9000

∴ The cost price of the product was Rs. 9000.

Alternate Method

Let C.P be 100x.

C.P : M.R.P : Dis. : S.P : Loss

100x : 130x : 39x : 91x : 9x

Loss = 810

⇒ 9x = 810

⇒ x = 90

C.P = 100x

⇒ 100 × 90

⇒ 9000

∴ The cost price of the product is Rs. 9000.

The salaries of three friends A, B and C are in the ratio 2 ∶ 5 ∶ 7. If the increment in their salary is 5%, 20% and 30% respectively, what is the new ratio of their salaries?

((a))
40 ∶ 63 ∶ 110
((b))
35 ∶ 43 ∶ 110
((c))
21 ∶ 60 ∶ 91
((d))
29 ∶ 63 ∶ 91
((e))
35 ∶ 28 ∶ 97

Show Answer

Answer: ((c))

21 ∶ 60 ∶ 91

Given:

The ratio of Salaries of A, B and C = 2 ∶ 5 ∶ 7

Increment in salary of A = 5%

Increment in salary of B = 20%

Increment in salary of C = 30%

Formula used:

Salary after increment = old salary × [(100 + increased percent)/100]

Calculation:

Let the salary of A, B and C is 2x, 5x and 7x respectively.

New salary of A after increment = 2x × (105/100) = 210x/100

New salary of B after increment = 5x × (120/100) = 600x/100

New salary of C after increment = 7x × (130/100) = 910x/100

Now, Ratio of the salaries of A, B and C = 210x ∶ 600x ∶ 910x

⇒ 21 ∶ 60 ∶ 91

∴ The new ratio of salaries of A, B and C is 21 ∶ 60 ∶ 91 respectively.

The milk and water in a mixture are in the ratio of 7 : 5. When 15 litres of milk and 25 litres of water are added in the mixture, The mixture becomes 1 : 1. Find the quantity of Milk in the new mixture.

((a))
40 litres
((b))
35 litres
((c))
45 litres
((d))
50 litres
((e))
30 litres

Show Answer

Answer: ((d))

50 litres

Given:

Ratio of milk and water in the mixture = 7 : 5

Amount of milk added = 15 litres

Amount of water added = 25 litres

Ratio of final mixture = 1 : 1

Formula used:

∴ (Ratio of milk in the mixture + new quantity of milk added) : (Ratio of water in the mixture + new quantity of water added) = New ratio of mixture

Calculation:

Let the amount of milk and water be 7x and 5x respectively

New amount of milk added = 15 litres

Final amount of milk = (7x + 15) litres

New amount of water added = 25 litres

Final amount of water added = (5x + 25) litres

Final ratio = 1 : 1

Now, as we know that

(Ratio of milk in the mixture + new quantity of milk added) : (Ratio of water in the mixture + new quantity of water added) = New ratio of mixture

$\Rightarrow \frac{{7x + 15}}{{5x + 25}} = \frac{1}{1}$

⇒ 7x + 15 = 5x + 25

⇒ 2x = 10

⇒ x = 5 litres

Now, quantity of milk in the new mixture = (7x + 15) litres

⇒ Quantity of milk in the new mixture = (7 × 5 + 15) litres

⇒ 50 litres

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