Reasoning PYQs

Given: Six persons, namely, A, B, C, D, E, and F, like different colors: Red, Blue, Green, Yellow, Black, and White, and they are showcasing their work in a painting exhibition on two different dates, either 9 or 16, of three different months: March, June, and August of the same year, but not necessarily in the same order.

1. A showcases in the month that has an even number of days. 

Here, we have 2 Cases i.e., Case 1 and Case 2.

 

2. A showcases two persons after the one who likes Red. 

 

3. F showcases on an odd-numbered date, but after A. 

 

4. C showcases three persons before the one who showcases immediately after the one who likes Black. 5. C does not showcase on an even-numbered date. 

Here, we have one more subcase of Case 2.

 

6. A does not like Black. 

Now, we can eliminate Case 1.

 

7. The one who likes Green showcases in the same month as E. 8. E likes neither Red nor Green. 

Now, we can eliminate Case 2a, but we have a new subcase of Case 2.

 

9. The one who likes Yellow showcases immediately before D.
10. Neither C nor B likes Yellow and White.

Now, we can eliminate Case 2(i).

 

This is our final arrangement,

 

Hence, the correct answer is D.

Given: Six persons, namely, A, B, C, D, E, and F, like different colors: Red, Blue, Green, Yellow, Black, and White, and they are showcasing their work in a painting exhibition on two different dates, either 9 or 16, of three different months: March, June, and August of the same year, but not necessarily in the same order.

1. A showcases in the month that has an even number of days. 

Here, we have 2 Cases i.e., Case 1 and Case 2.

 

2. A showcases two persons after the one who likes Red. 

 

3. F showcases on an odd-numbered date, but after A. 

 

4. C showcases three persons before the one who showcases immediately after the one who likes Black. 5. C does not showcase on an even-numbered date. 

Here, we have one more subcase of Case 2.

 

6. A does not like Black. 

Now, we can eliminate Case 1.

 

7. The one who likes Green showcases in the same month as E. 8. E likes neither Red nor Green. 

Now, we can eliminate Case 2a, but we have a new subcase of Case 2.

 

9. The one who likes Yellow showcases immediately before D.
10. Neither C nor B likes Yellow and White.

Now, we can eliminate Case 2(i).

 

This is our final arrangement,

 

Hence, the correct answer is 9 August.

Given: Six persons, namely, A, B, C, D, E, and F, like different colors: Red, Blue, Green, Yellow, Black, and White, and they are showcasing their work in a painting exhibition on two different dates, either 9 or 16, of three different months: March, June, and August of the same year, but not necessarily in the same order.

1. A showcases in the month that has an even number of days. 

Here, we have 2 Cases i.e., Case 1 and Case 2.

 

2. A showcases two persons after the one who likes Red. 

 

3. F showcases on an odd-numbered date, but after A. 

 

4. C showcases three persons before the one who showcases immediately after the one who likes Black. 5. C does not showcase on an even-numbered date. 

Here, we have one more subcase of Case 2.

 

6. A does not like Black. 

Now, we can eliminate Case 1.

 

7. The one who likes Green showcases in the same month as E. 8. E likes neither Red nor Green. 

Now, we can eliminate Case 2a, but we have a new subcase of Case 2.

 

9. The one who likes Yellow showcases immediately before D.
10. Neither C nor B likes Yellow and White.

Now, we can eliminate Case 2(i).

 

This is our final arrangement,

 

Hence, the correct answer is White.

Given: Six persons, namely, A, B, C, D, E, and F, like different colors: Red, Blue, Green, Yellow, Black, and White, and they are showcasing their work in a painting exhibition on two different dates, either 9 or 16, of three different months: March, June, and August of the same year, but not necessarily in the same order.

1. A showcases in the month that has an even number of days. 

Here, we have 2 Cases i.e., Case 1 and Case 2.

 

2. A showcases two persons after the one who likes Red. 

 

3. F showcases on an odd-numbered date, but after A. 

 

4. C showcases three persons before the one who showcases immediately after the one who likes Black. 5. C does not showcase on an even-numbered date. 

Here, we have one more subcase of Case 2.

 

6. A does not like Black. 

Now, we can eliminate Case 1.

 

7. The one who likes Green showcases in the same month as E. 8. E likes neither Red nor Green. 

Now, we can eliminate Case 2a, but we have a new subcase of Case 2.

 

9. The one who likes Yellow showcases immediately before D.
10. Neither C nor B likes Yellow and White.

Now, we can eliminate Case 2(i).

 

This is our final arrangement,

 

Hence, the correct answer is None.

Given: Six persons, namely, A, B, C, D, E, and F, like different colors: Red, Blue, Green, Yellow, Black, and White, and they are showcasing their work in a painting exhibition on two different dates, either 9 or 16, of three different months: March, June, and August of the same year, but not necessarily in the same order.

1. A showcases in the month that has an even number of days. 

Here, we have 2 Cases i.e., Case 1 and Case 2.

 

2. A showcases two persons after the one who likes Red. 

 

3. F showcases on an odd-numbered date, but after A. 

 

4. C showcases three persons before the one who showcases immediately after the one who likes Black. 5. C does not showcase on an even-numbered date. 

Here, we have one more subcase of Case 2.

 

6. A does not like Black. 

Now, we can eliminate Case 1.

 

7. The one who likes Green showcases in the same month as E. 8. E likes neither Red nor Green. 

Now, we can eliminate Case 2a, but we have a new subcase of Case 2.

 

9. The one who likes Yellow showcases immediately before D.
10. Neither C nor B likes Yellow and White.

Now, we can eliminate Case 2(i).

 

This is our final arrangement,

 

Except for E, all others showcase on even dates.

Hence, the correct answer is E.

Given number: 613955

Forward: (6, 9), (3, 5), (1, 5)

Hence, we can see that 3 such pairs are there.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, were born in different years: 1966, 1976, 1982, 1989, 1997, 1998, 2006, and 2012, but not necessarily in the same order. Their ages are calculated with respect to the year 2025.

1. Q’s age is a perfect cube.
2. Q is not the youngest among the group. 

 

3. There is exactly one person born between U and Q. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. There are exactly two people born between U and W. 

 

5. W is older than 20 years of age.

 

6. V was born in the year immediately before P. 7. Both P and V are younger than 45 years. 

 

8. The age difference between T and S is at most 10 years, with S being younger.

 

9. The age of R is at most 20 years less than S’s age. 

Now, we can eliminate Case 1.

 

Hence, the correct answer is T - 49 years.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, were born in different years: 1966, 1976, 1982, 1989, 1997, 1998, 2006, and 2012, but not necessarily in the same order. Their ages are calculated with respect to the year 2025.

1. Q’s age is a perfect cube.
2. Q is not the youngest among the group. 

 

3. There is exactly one person born between U and Q. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. There are exactly two people born between U and W. 

 

5. W is older than 20 years of age.

 

6. V was born in the year immediately before P. 7. Both P and V are younger than 45 years. 

 

8. The age difference between T and S is at most 10 years, with S being younger.

 

9. The age of R is at most 20 years less than S’s age. 

Now, we can eliminate Case 1.

 

Except for R, all others have odd ages.

Hence, the correct answer is R.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, were born in different years: 1966, 1976, 1982, 1989, 1997, 1998, 2006, and 2012, but not necessarily in the same order. Their ages are calculated with respect to the year 2025.

1. Q’s age is a perfect cube.
2. Q is not the youngest among the group. 

 

3. There is exactly one person born between U and Q. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. There are exactly two people born between U and W. 

 

5. W is older than 20 years of age.

 

6. V was born in the year immediately before P. 7. Both P and V are younger than 45 years. 

 

8. The age difference between T and S is at most 10 years, with S being younger.

 

9. The age of R is at most 20 years less than S’s age. 

Now, we can eliminate Case 1.

 

Hence, the correct answer is One.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, were born in different years: 1966, 1976, 1982, 1989, 1997, 1998, 2006, and 2012, but not necessarily in the same order. Their ages are calculated with respect to the year 2025.

1. Q’s age is a perfect cube.
2. Q is not the youngest among the group. 

 

3. There is exactly one person born between U and Q. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. There are exactly two people born between U and W. 

 

5. W is older than 20 years of age.

 

6. V was born in the year immediately before P. 7. Both P and V are younger than 45 years. 

 

8. The age difference between T and S is at most 10 years, with S being younger.

 

9. The age of R is at most 20 years less than S’s age. 

Now, we can eliminate Case 1.

 

The sum is = 49 + 13 = 62 years.

Hence, the correct answer is 62 years.

Given: Eight individuals, namely, P, Q, R, S, T, U, V, and W, were born in different years: 1966, 1976, 1982, 1989, 1997, 1998, 2006, and 2012, but not necessarily in the same order. Their ages are calculated with respect to the year 2025.

1. Q’s age is a perfect cube.
2. Q is not the youngest among the group. 

 

3. There is exactly one person born between U and Q. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. There are exactly two people born between U and W. 

 

5. W is older than 20 years of age.

 

6. V was born in the year immediately before P. 7. Both P and V are younger than 45 years. 

 

8. The age difference between T and S is at most 10 years, with S being younger.

 

9. The age of R is at most 20 years less than S’s age. 

Now, we can eliminate Case 1.

 

Hence, the correct answer is W.

The least possible Venn diagram for the given statements is as follows,

I. No malaria is bacteria → False (It can be possible but it is not definite)

II. Some virus is malaria → False (It is definitely false)

III. Some mosquito are not bacteria → True (It is definite)

Only conclusion III follows.

The least possible Venn diagram for the given statements is as follows,

I. Some prepositions are verbs → False (It can be possible but it is not definite)

II. All verb is noun → False (It can be possible but it is not definite)

III. Some article is noun → False (It can be possible but it is not definite)

Hence, none of the conclusion follows.

Concept 1:

• Meaning of "Some A are B" in Syllogism - there is at least one point in A which is in B.
• Meaning of "All A are B" in Syllogism - each point of A is in B.
• This explains why "some" can be considered as a subset of "all".
• Therefore, if "All A are B" is true, then "some A are B" is always true.

Keywords:

1. All and some not
2. Some and no

Conditions:

1. The same elements are used in the two conclusions. For example, in this case, the elements jungles and malls are common to both conclusions.
2. Both conclusions should be possibilities. That is, they should be false because the conclusion is possible but not definite.

Then, the pair of conclusions are considered as complementary pairs.

Concept 2: Few, Only a few, Only.

a) Only a few - means only "some" not "all".

Example1-

1. Only a few A are B implies that-

• Some A are B
• All A are B is a possibility is false because Only a few A are B. All A cannot be B

"But"

• all B can be A.

b) "Few" is same as "some".

Example2-

1. few A are B implies that-

• Some A are B
• All A are B is a possibility
• Some B are A.
• Some A are not B is a possibility.

3) Concept of Only:

c) Only "A is B" is the same as "all B are A".

Examples

• Only A are B.
• Some A are B.

The least possible Venn diagram for the given statements is as follows,

Explanation:

I. Some Boys are not Bad → False (As some Boys are Bad, and remaining part of Boys and Bad whether it is true or not. So, it is false)

II. Some Men are Good → True (As All Men are Good → some Men are Good. So, it is true) 

III. Some Bad are not Good → False (it is possible but not definite. So, it is false)

Conclusion

"Only conclusion II follows" is the correct answer.

1. M sits at the extreme end.

2. R sits two places away from M.

3. Only two persons sit between X and R.

4. H sits second to the left of X.

5. E sits immediate right to H.

6. E sits exactly at middle of S and W.

7. Only three persons S and W. Therefore, case 1 is eliminated.

8. W sits to the right of X.

9. The number of persons sit to the left of S is same as to that of to the right of F.

10. F sits to the right of X.

11. Y and W sit immediate next to each other. Hence, the final arrangement is as follows

Hence, no one sits to the left of S.

1. M sits at the extreme end.

2. R sits two places away from M.

3. Only two persons sit between X and R.

4. H sits second to the left of X.

5. E sits immediate right to H.

6. E sits exactly at middle of S and W.

7. Only three persons S and W. Therefore, case 1 is eliminated.

8. W sits to the right of X.

9. The number of persons sit to the left of S is same as to that of to the right of F.

10. F sits to the right of X.

11. Y and W sit immediate next to each other. Hence, the final arrangement is as follows

Hence, Y sits fourth to the left of H.

1. M sits at the extreme end.

2. R sits two places away from M.

3. Only two persons sit between X and R.

4. H sits second to the left of X.

5. E sits immediate right to H.

6. E sits exactly at middle of S and W.

7. Only three persons S and W. Therefore, case 1 is eliminated.

8. W sits to the right of X.

9. The number of persons sit to the left of S is same as to that of to the right of F.

10. F sits to the right of X.

11. Y and W sit immediate next to each other. Hence, the final arrangement is as follows

Since, X sits second to the left of Y. Therefore, statement A is correct.

H sits immediate to S. Therefore, statement B is incorrect.

R sits second to the left of M. Therefore, statement C is incorrect.

Hence, the correct answer is option 1.

Word: EDUCATION

1^st letter = E; 2^nd letter = D; 5^th letter = A; 6^th letter = T

Letters given: EDAT.

Possible words: DATE.

Hence, only 1 such word is possible.

Clearly, the third letter of the possible word from the left end is T.

Here, boxes are J, L, N, Q, R and V and colours are Blue, Green, Pink, Red, White and Yellow.

1. Box L placed four boxes above the box which contains Pink colour.

2. The box contains Red colour and the box contains Pink colour placed adjacent to each other.  3) Box V placed just above the box which contains Red colour.

 

4. Only two boxes are placed between the box contains White colour and Box N, neither of them placed at top or bottom positions. Therefore, case 3 is eliminated.

5. As many boxes placed above the box contains Green colour as many below the box J. 

 

6. Box Q placed below the Box L but likes neither Yellow nor Blue colour. Therefore, case 1(a) is eliminated.

7. Neither V nor R likes Green or White colour. Therefore, case 1(b) and case 2(b) are eliminated.

8. The box contains Blue colour is placed below the box that contains Yellow colour. Hence, the final arrangement is as follow

 

Since, Box Q which contains White colour placed just above the box that contains Yellow colour.

Hence, the correct answer is more than one option.

Here, boxes are J, L, N, Q, R and V and colours are Blue, Green, Pink, Red, White and Yellow.

1. Box L placed four boxes above the box which contains Pink colour.

2. The box contains Red colour and the box contains Pink colour placed adjacent to each other.  3) Box V placed just above the box which contains Red colour.

 

4. Only two boxes are placed between the box contains White colour and Box N, neither of them placed at top or bottom positions. Therefore, case 3 is eliminated.

5. As many boxes placed above the box contains Green colour as many below the box J. 

 

6. Box Q placed below the Box L but likes neither Yellow nor Blue colour. Therefore, case 1(a) is eliminated.

7. Neither V nor R likes Green or White colour. Therefore, case 1(b) and case 2(b) are eliminated.

8. The box contains Blue colour is placed below the box that contains Yellow colour. Hence, the final arrangement is as follow

 

Since, two boxes placed between the Box L and the Box R and same number of boxes placed below the box that contains Red colour which is Box R.

Hence, the correct answer is As many boxes placed below the box that contains Red colour.