Reasoning PYQs

Given: Fourteen individuals are seated in two parallel rows, with seven persons in each row. The distance between adjacent seats is equal. In Row 1, namely, H, I, J, K, L, M, and N are seated, all facing north, while in Row 2, namely, O, P, Q, R, S, T, and U are seated, all facing south.

Each person in Row 1 faces exactly one person in Row 2.

1. Q sits third to the right of the person who is facing L, who sits immediately to the left of K.
2. There are exactly three persons between K and M. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 3. M sits immediately to the right of I, and I sits second to the left of N. 4. The number of persons between I and K is the same as between P and T, where T is facing I. 5. J sits to the right of H. 6. Exactly two persons sit between S and R, and R is facing neither J nor N. 7. S is not adjacent to either P or U.

Now, we can eliminate Case 2.

This is our final arrangement,

Hence, the correct answer is L.

Given: Six boxes, J, K, L, M, N, and O, are arranged in a sequence from first to last.

Each box is associated with a different dry fruit, namely, Almond, Cashew, Raisin, Pistachio, Walnut, and Dates, but not necessarily in the same order.

No two boxes have the same dry fruit.

1. Exactly one box lies between the box containing Almond and O, which contains Raisin.
2. The box containing Pistachio is placed three positions before the box containing Raisin.

 

3. The number of boxes before J is the same as the number of boxes after K, and K is placed two positions before the box containing Cashew.

 

4. The box containing Walnuts is placed before L, and L is placed after M, while M contains Dates.
5. The box containing Walnuts is placed after M. 

Now, we can eliminate Case 1.

 

6. At least one box comes after N, and N does not contain Walnuts.

Now, we can eliminate Case 3.

This is our final arrangement,

 

Hence, the correct answer is Cashews is in the last position.

Given: Six boxes, J, K, L, M, N, and O, are arranged in a sequence from first to last.

Each box is associated with a different dry fruit, namely, Almond, Cashew, Raisin, Pistachio, Walnut, and Dates, but not necessarily in the same order.

No two boxes have the same dry fruit.

1. Exactly one box lies between the box containing Almond and O, which contains Raisin.
2. The box containing Pistachio is placed three positions before the box containing Raisin.

 

3. The number of boxes before J is the same as the number of boxes after K, and K is placed two positions before the box containing Cashew.

 

4. The box containing Walnuts is placed before L, and L is placed after M, while M contains Dates.
5. The box containing Walnuts is placed after M. 

Now, we can eliminate Case 1.

 

6. At least one box comes after N, and N does not contain Walnuts.

Now, we can eliminate Case 3.

This is our final arrangement,

 

Hence, the correct answer is N - Pistachios.

Given: Six boxes, J, K, L, M, N, and O, are arranged in a sequence from first to last.

Each box is associated with a different dry fruit, namely, Almond, Cashew, Raisin, Pistachio, Walnut, and Dates, but not necessarily in the same order.

No two boxes have the same dry fruit.

1. Exactly one box lies between the box containing Almond and O, which contains Raisin.
2. The box containing Pistachio is placed three positions before the box containing Raisin.

 

3. The number of boxes before J is the same as the number of boxes after K, and K is placed two positions before the box containing Cashew.

 

4. The box containing Walnuts is placed before L, and L is placed after M, while M contains Dates.
5. The box containing Walnuts is placed after M. 

Now, we can eliminate Case 1.

 

6. At least one box comes after N, and N does not contain Walnuts.

Now, we can eliminate Case 3.

This is our final arrangement,

 

Hence, the correct answer is Three.

Given: Six boxes, J, K, L, M, N, and O, are arranged in a sequence from first to last.

Each box is associated with a different dry fruit, namely, Almond, Cashew, Raisin, Pistachio, Walnut, and Dates, but not necessarily in the same order.

No two boxes have the same dry fruit.

1. Exactly one box lies between the box containing Almond and O, which contains Raisin.
2. The box containing Pistachio is placed three positions before the box containing Raisin.

 

3. The number of boxes before J is the same as the number of boxes after K, and K is placed two positions before the box containing Cashew.

 

4. The box containing Walnuts is placed before L, and L is placed after M, while M contains Dates.
5. The box containing Walnuts is placed after M. 

Now, we can eliminate Case 1.

 

6. At least one box comes after N, and N does not contain Walnuts.

Now, we can eliminate Case 3.

This is our final arrangement,

 

Hence, the correct answer is Pistachios.

Given: Six boxes, J, K, L, M, N, and O, are arranged in a sequence from first to last.

Each box is associated with a different dry fruit, namely, Almond, Cashew, Raisin, Pistachio, Walnut, and Dates, but not necessarily in the same order.

No two boxes have the same dry fruit.

1. Exactly one box lies between the box containing Almond and O, which contains Raisin.
2. The box containing Pistachio is placed three positions before the box containing Raisin.

 

3. The number of boxes before J is the same as the number of boxes after K, and K is placed two positions before the box containing Cashew.

 

4. The box containing Walnuts is placed before L, and L is placed after M, while M contains Dates.
5. The box containing Walnuts is placed after M. 

Now, we can eliminate Case 1.

 

6. At least one box comes after N, and N does not contain Walnuts.

Now, we can eliminate Case 3.

This is our final arrangement,

 

Hence, the correct answer is J.

Given:

1. A person starts from point A and walks 6 km north to reach point B.
2. From point B, he turns right and walks 8 km to reach point C.
3. He then turns right and walks 5 km to reach point D.
4. From point D, he turns left and walks 3 km to reach point E.
5. He again turns left and walks 7 km to reach point F.
6. From point F, he turns right and walks 2 km to reach point G.
7. Finally, he turns right and walks 4 km to reach point H.

This is our final arrangement,

Hence, the correct answer is South-West.

Given:

1. A person starts from point A and walks 6 km north to reach point B.
2. From point B, he turns right and walks 8 km to reach point C.
3. He then turns right and walks 5 km to reach point D.
4. From point D, he turns left and walks 3 km to reach point E.
5. He again turns left and walks 7 km to reach point F.
6. From point F, he turns right and walks 2 km to reach point G.
7. Finally, he turns right and walks 4 km to reach point H.

This is our final arrangement,

Distance = 8 + 5 + 3 = 16 km.

Hence, the correct answer is 16 km.

Given:

1. A person starts from point A and walks 6 km north to reach point B. 2. From point B, he turns right and walks 8 km to reach point C. 3. He then turns right and walks 5 km to reach point D. 4. From point D, he turns left and walks 3 km to reach point E. 5. He again turns left and walks 7 km to reach point F. 6. From point F, he turns right and walks 2 km to reach point G. 7. Finally, he turns right and walks 4 km to reach point H.

This is our final arrangement,

Hence, the correct answer is North-East.

Statements:

X < Y = Z, Z ≥ W > V, U ≤ X

After combining,

U ≤ X < Y = Z ≥ W > V

Conclusions:

I. Y > V: True (Y = Z ≥ W > V; Y > V)

II. U < W: False (U ≤ X < Y = Z ≥ W; opposite signs between the elements)

Hence, the correct answer is Only conclusion I is true.

Statements:

M ≥ N > O, O = P < Q, R ≥ M

After combining,

R ≥ M ≥ N > O = P < Q

Conclusions:

I. R > Q: False (R ≥ M ≥ N > O = P < Q; opposite signs between the elements)

II. N > P: True (N > O = P; N > P)

Hence, the correct answer is Only conclusion II is true.

Statements:

A < B ≤ C, D > C = E, F ≤ D

After combining,

A < B ≤ C = E < D ≥ F

Conclusions:

I. F > A: False (A < B ≤ C = E < D ≥ F; opposite signs between the elements)

II. B < D: True (B ≤ C = E < D; B < D)

Hence, the correct answer is Only conclusion II is true.

Statements:

P > Q = R, R ≥ S < T, U ≤ P

After combining,

U ≤ P > Q = R ≥ S < T

Conclusions:

I. U > S: False (U ≤ P > Q = R ≥ S; opposite signs between the elements)

II. Q ≥ T: False (Q = R ≥ S < T; opposite signs between the elements)

Hence, the correct answer is Neither conclusion I nor II is true.

Given: Six individuals, namely, P, Q, R, S, T, and U, live in a three-storey building.

Each floor has two flats: Flat A is west of Flat B. Floors are numbered 1 as the bottom, and 3 as the top.

Each flat has exactly one person.

Each person is associated with a different month, namely, January, February, March, April, May, and June, but not necessarily in the same order.

1. Q lives in Flat A and is not on Floor 1.
2. The person associated with May lives in the same flat column as Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3.  The one associated with June lives on the top floor, but not in Flat A. 

 

4. T is associated with February and lives adjacent to U. 5. U does not live on Floor 2 and Floor 3. 

Now, we can eliminate Case 2.

 

6. The person associated with March lives on a floor immediately above P in the same flat, while P doesn't live in Flat B.

 

7. The one associated with April lives on Floor 2. 8. R lives immediately below S, and both stay in the same flat column. 

This is our final arrangement,

 

Hence, the correct answer is P.

Given: Six individuals, namely, P, Q, R, S, T, and U, live in a three-storey building.

Each floor has two flats: Flat A is west of Flat B. Floors are numbered 1 as the bottom, and 3 as the top.

Each flat has exactly one person.

Each person is associated with a different month, namely, January, February, March, April, May, and June, but not necessarily in the same order.

1. Q lives in Flat A and is not on Floor 1.
2. The person associated with May lives in the same flat column as Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3.  The one associated with June lives on the top floor, but not in Flat A. 

 

4. T is associated with February and lives adjacent to U. 5. U does not live on Floor 2 and Floor 3. 

Now, we can eliminate Case 2.

 

6. The person associated with March lives on a floor immediately above P in the same flat, while P doesn't live in Flat B.

 

7. The one associated with April lives on Floor 2. 8. R lives immediately below S, and both stay in the same flat column. 

This is our final arrangement,

 

Hence, the correct answer is R - January.

Given: Six individuals, namely, P, Q, R, S, T, and U, live in a three-storey building.

Each floor has two flats: Flat A is west of Flat B. Floors are numbered 1 as the bottom, and 3 as the top.

Each flat has exactly one person.

Each person is associated with a different month, namely, January, February, March, April, May, and June, but not necessarily in the same order.

1. Q lives in Flat A and is not on Floor 1.
2. The person associated with May lives in the same flat column as Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3.  The one associated with June lives on the top floor, but not in Flat A. 

 

4. T is associated with February and lives adjacent to U. 5. U does not live on Floor 2 and Floor 3. 

Now, we can eliminate Case 2.

 

6. The person associated with March lives on a floor immediately above P in the same flat, while P doesn't live in Flat B.

 

7. The one associated with April lives on Floor 2. 8. R lives immediately below S, and both stay in the same flat column. 

This is our final arrangement,

 

Hence, the correct answer is T.

Given: Six individuals, namely, P, Q, R, S, T, and U, live in a three-storey building.

Each floor has two flats: Flat A is west of Flat B. Floors are numbered 1 as the bottom, and 3 as the top.

Each flat has exactly one person.

Each person is associated with a different month, namely, January, February, March, April, May, and June, but not necessarily in the same order.

1. Q lives in Flat A and is not on Floor 1.
2. The person associated with May lives in the same flat column as Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3.  The one associated with June lives on the top floor, but not in Flat A. 

 

4. T is associated with February and lives adjacent to U. 5. U does not live on Floor 2 and Floor 3. 

Now, we can eliminate Case 2.

 

6. The person associated with March lives on a floor immediately above P in the same flat, while P doesn't live in Flat B.

 

7. The one associated with April lives on Floor 2. 8. R lives immediately below S, and both stay in the same flat column. 

This is our final arrangement,

 

Hence, the correct answer is January.

Given: Six individuals, namely, P, Q, R, S, T, and U, live in a three-storey building.

Each floor has two flats: Flat A is west of Flat B. Floors are numbered 1 as the bottom, and 3 as the top.

Each flat has exactly one person.

Each person is associated with a different month, namely, January, February, March, April, May, and June, but not necessarily in the same order.

1. Q lives in Flat A and is not on Floor 1.
2. The person associated with May lives in the same flat column as Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3.  The one associated with June lives on the top floor, but not in Flat A. 

 

4. T is associated with February and lives adjacent to U. 5. U does not live on Floor 2 and Floor 3. 

Now, we can eliminate Case 2.

 

6. The person associated with March lives on a floor immediately above P in the same flat, while P doesn't live in Flat B.

 

7. The one associated with April lives on Floor 2. 8. R lives immediately below S, and both stay in the same flat column. 

This is our final arrangement,

 

Hence, the correct answer is U.

Given word: ADVENTURE

2^nd, 5^th, 6^th, and 9^th letters = D, N, T, E

Meaningful words = DENT (a place where a flat surface, especially metal, has been hit and damaged but not broken) and TEND (to usually do or be something)

Hence, the correct answer is Two.

Given: A certain number of persons are standing in a straight line, all facing north.

1. P1 is standing at one of the extreme ends of the row.
2. Exactly one person stands between P1 and R3.
3. There are six people between R3 and T5.
4. T5 is third from one of the ends. 

Here, we have 2 Cases, i.e., Case 1 and Case 2. 5. There are more than six people between P1 and S4. 6. The number of persons between Q2 and S4 is the same as the number of persons between R3 and Q2. 

Here, we have subcases of Case 1 and Case 2. 7. U6 stands fifth to the right of Q2.  

Now, we can eliminate Case 2. 8. There are not more than five people between T5 and U6. 9. At least one person stands between S4 and U6.

Now, we can eliminate Case 1a and Case 2a.

This is our final arrangement,

Hence, the correct answer is R3.