IBPS PO Mains Memory Based Paper (Held On: 30 November 2024 Shift 1) (Previous Year Paper)

Given: Certain number of persons are sitting in a linear row all of them facing towards north direction. Few persons like some colors and they are working in an company either at the post of manager or at the post of assistant. The persons who are working as an manager is sitting at even numbered places and the persons who are working as an assistant are sitting at odd numbered position when counted from the right end of the row. 

Based on the given conditions, we get the following possibilities:

1. Five persons are sitting between L and E from either side.

The person who like white color is sitting fourth to the right of L.

J is sitting immediate left the person who like white color.

K is sitting third to the right if E and also like black color.

Combining these, we get-

2. The number of persons sitting left to L is same as number of person sitting right of J. 

The number of managers sitting between the person who like red color and E is more the number of associates sitting between them and also not more than two manager sitting between them.

The above condition eliminates Case 2 from the above and we get-

3. Two managers are sitting left to N.

N is not a manager.

The person who like blue color is sitting immediate left of N.

From these, we get-

4. The person who like red color is sitting right to both M and K.

Not more than two assistant sit between M and J.

H is sitting second to the left of M and like pink color.

The person who is sitting immediate left of M likes green color.

J is not an immediate neighbor of H.

L doesn't like green color.

Combining these, we get the final arrangement as follows:

Note that in the above diagram M stands for Manager and A stands for Assistant.

Therefore, from the above final arrangement, we see that M sits seventh to the right of L.  

Hence, M sits seventh to the right of L.

​

Given: Certain number of persons are sitting in a linear row all of them facing towards north direction. Few persons like some colors and they are working in an company either at the post of manager or at the post of assistant. The persons who are working as an manager is sitting at even numbered places and the persons who are working as an assistant are sitting at odd numbered position when counted from the right end of the row. 

Based on the given conditions, we get the following possibilities:

1. Five persons are sitting between L and E from either side.

The person who like white color is sitting fourth to the right of L.

J is sitting immediate left the person who like white color.

K is sitting third to the right if E and also like black color.

Combining these, we get-

2. The number of persons sitting left to L is same as number of person sitting right of J. 

The number of managers sitting between the person who like red color and E is more the number of associates sitting between them and also not more than two manager sitting between them.

The above condition eliminates Case 2 from the above and we get-

3. Two managers are sitting left to N.

N is not a manager.

The person who like blue color is sitting immediate left of N.

From these, we get-

4. The person who like red color is sitting right to both M and K.

Not more than two assistant sit between M and J.

H is sitting second to the left of M and like pink color.

The person who is sitting immediate left of M likes green color.

J is not an immediate neighbor of H.

L doesn't like green color.

Combining these, we get the final arrangement as follows:

Note that in the above diagram M stands for Manager and A stands for Assistant.

Therefore, from the above final arrangement, we see that the color liked by the person who sits between H and J is white.  

Hence, the color liked by the person who sits between H and J is white.

Given: Certain number of persons are sitting in a linear row all of them facing towards north direction. Few persons like some colors and they are working in an company either at the post of manager or at the post of assistant. The persons who are working as an manager is sitting at even numbered places and the persons who are working as an assistant are sitting at odd numbered position when counted from the right end of the row. 

Based on the given conditions, we get the following possibilities:

1. Five persons are sitting between L and E from either side.

The person who like white color is sitting fourth to the right of L.

J is sitting immediate left the person who like white color.

K is sitting third to the right if E and also like black color.

Combining these, we get-

2. The number of persons sitting left to L is same as number of person sitting right of J. 

The number of managers sitting between the person who like red color and E is more the number of associates sitting between them and also not more than two manager sitting between them.

The above condition eliminates Case 2 from the above and we get-

(Here M stands for Manager and A stands fro Assistant.)

3. Two managers are sitting left to N.

N is not a manager.

The person who like blue color is sitting immediate left of N.

From these, we get-

4. The person who like red color is sitting right to both M and K.

Not more than two assistant sit between M and J.

H is sitting second to the left of M and like pink color.

The person who is sitting immediate left of M likes green color.

J is not an immediate neighbor of H.

L doesn't like green color.

Combining these, we get the final arrangement as follows:

Note that in the above diagram M stands for Manager and A stands for Assistant.

Therefore, from the above final arrangement, we see that there are 18 persons seated in the row. 18 multiplied by 5 is 90. 

Hence, the required product is 90.

Given: Certain number of persons are sitting in a linear row all of them facing towards north direction. Few persons like some colors and they are working in an company either at the post of manager or at the post of assistant. The persons who are working as an manager is sitting at even numbered places and the persons who are working as an assistant are sitting at odd numbered position when counted from the right end of the row. 

Based on the given conditions, we get the following possibilities:

1. Five persons are sitting between L and E from either side.

The person who like white color is sitting fourth to the right of L.

J is sitting immediate left the person who like white color.

K is sitting third to the right if E and also like black color.

Combining these, we get-

2. The number of persons sitting left to L is same as number of person sitting right of J. 

The number of managers sitting between the person who like red color and E is more the number of associates sitting between them and also not more than two manager sitting between them.

The above condition eliminates Case 2 from the above and we get-

(Here M stands for Manager and A stands fro Assistant.)

3. Two managers are sitting left to N.

N is not a manager.

The person who like blue color is sitting immediate left of N.

From these, we get-

4. The person who like red color is sitting right to both M and K.

Not more than two assistant sit between M and J.

H is sitting second to the left of M and like pink color.

The person who is sitting immediate left of M likes green color.

J is not an immediate neighbor of H.

L doesn't like green color.

Combining these, we get the final arrangement as follows:

Note that in the above diagram M stands for Manager and A stands for Assistant.

Therefore, from the above final arrangement, we see that three managers sit between N and J. 

Hence, three managers sit between N and J.

The least possible Venn diagram from the given statements is as follows:

Statement I:

Conclusions:

I. Some Peons are Clerks. - False (Since, there is clearly given no clerks are specialist and all peons are specialist. Hence, does not follow.)

II. Some Specialist being Manager is a possibility. - True (Since, there is no direct relation between the two is given so it can be possible but not definite. Hence, follows.)

Therefore, statement I do not give the desired conclusions.

Statement II: 

Conclusions:

I. Some Peons are Clerks. - False (Since, there is no direct relation between the two is given so it can be possible but certain. Hence, does not follow.)

II. Some Specialist being Manager is a possibility. - True(Since, there is no direct relation between the two is given so it can be possible but not definite. Hence, follows.)

Therefore, statement II do not give the desired conclusions.

Statement III:

Conclusions:

I. Some Peons are Clerks. - True (Since, it is clear from the above diagram. Hence, follows.)

II. Some Specialist being Manager is a possibility. - True (Since, there is no direct relation between the two is given so it can be possible but not definite. Hence, follows.)

Therefore, statement III alone gives the desired conclusions.

Hence, the correct answer is only statement III follows.

The logic followed here is as follows:

In Step I, the word which starts with the highest letter as per alphabetical series rewritten as the vowel is replaced with the next letter comes and consonant replaced with the previous letter comes as per alphabetical series and new letters will be written in alphabetical order and write at extreme left end and at the same time the lowest number if it is an odd number then write in reverse order at the extreme right end. For example, the highest letter started word is nut which is rewritten as n = m, u = v and t = s and collectively written as msv and lowest number is 13 which is changed into 31.

Step I: msv 37 den kit 58 can 24 met 78 83 any 51

In Step II, the second lowest number will be written at the extreme left end if it is even number then subtracted by 3 if the odd number then just as in step I reverse order. At the same time the word started with the second highest letter will be rearranged as in step I but this time written at extreme right end.

Step II: 21 msv 37 den kit 58 can 78 83 any 51 fls

In Step III, repeat the process as in Step I newly formed letter cluster written at extreme left end and next lowest number written at extreme right end.

Step III: jjs 21 msv den 58 can 78 83 any 51 fls 73

In Step IV, repeat the step 2 letter cluster at the right end and number at the left end.

Step IV: 55 jjs 21 msv can 78 83 any 51 fls 73 cfm

In Step V, repeat the process as in Step I.

Step V: bbm 55 jjs 21 msv 83 any 51 fls 73 cfm 75

In Step VI, repeat the process as in Step II.

Step VI: 38 bbm 55 jjs 21 msv 51 fls 73 cfm 75 bmx

Input: 23 fan 64 ten jar 51 nip 48 lit 89 hut 76

Step I: fms fan 64 jar 51 nip 48 lit 89 hut 76 32

Step II: 45 fms fan 64 jar 51 lit 89 hut 76 32 jmo

Step III: jks 45 fms fan 64 jar 89 hut 76 32 jmo 15

Step IV: 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq

Step V: gsv 61 jks 45 fms fan 89 32 jmo 15 biq 73

Step VI: 98 gsv 61 jks 45 fms 32 jmo 15 biq 73 bem

Since, second element from the left end in Step III is 45 and fourth element from the right side in Step IV is 32.

Therefore, their sum = 45 + 32 = 77.

Hence, the correct answer is 77.

The logic followed here is as follows:

In Step I, the word which starts with the highest letter as per alphabetical series rewritten as the vowel is replaced with the next letter comes and consonant replaced with the previous letter comes as per alphabetical series and new letters will be written in alphabetical order and write at extreme left end and at the same time the lowest number if it is an odd number then write in reverse order at the extreme right end. For example, the highest letter started word is nut which is rewritten as n = m, u = v and t = s and collectively written as msv and lowest number is 13 which is changed into 31.

Step I: msv 37 den kit 58 can 24 met 78 83 any 51

In Step II, the second lowest number will be written at the extreme left end if it is even number then subtracted by 3 if the odd number then just as in step I reverse order. At the same time the word started with the second highest letter will be rearranged as in step I but this time written at extreme right end.

Step II: 21 msv 37 den kit 58 can 78 83 any 51 fls

In Step III, repeat the process as in Step I newly formed letter cluster written at extreme left end and next lowest number written at extreme right end.

Step III: jjs 21 msv den 58 can 78 83 any 51 fls 73

In Step IV, repeat the step 2 letter cluster at the right end and number at the left end.

Step IV: 55 jjs 21 msv can 78 83 any 51 fls 73 cfm

In Step V, repeat the process as in Step I.

Step V: bbm 55 jjs 21 msv 83 any 51 fls 73 cfm 75

In Step VI, repeat the process as in Step II.

Step VI: 38 bbm 55 jjs 21 msv 51 fls 73 cfm 75 bmx

Input: 23 fan 64 ten jar 51 nip 48 lit 89 hut 76

Step I: fms fan 64 jar 51 nip 48 lit 89 hut 76 32

Step II: 45 fms fan 64 jar 51 lit 89 hut 76 32 jmo

Step III: jks 45 fms fan 64 jar 89 hut 76 32 jmo 15

Step IV: 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq

Step V: gsv 61 jks 45 fms fan 89 32 jmo 15 biq 73

Step VI: 98 gsv 61 jks 45 fms 32 jmo 15 biq 73 bem

In step II, 64 comes fifth to the left of hut.

Hence, the correct answer is fifth to the left.

The logic followed here is as follows:

In Step I, the word which starts with the highest letter as per alphabetical series rewritten as the vowel is replaced with the next letter comes and consonant replaced with the previous letter comes as per alphabetical series and new letters will be written in alphabetical order and write at extreme left end and at the same time the lowest number if it is an odd number then write in reverse order at the extreme right end. For example, the highest letter started word is nut which is rewritten as n = m, u = v and t = s and collectively written as msv and lowest number is 13 which is changed into 31.

Step I: msv 37 den kit 58 can 24 met 78 83 any 51

In Step II, the second lowest number will be written at the extreme left end if it is even number then subtracted by 3 if the odd number then just as in step I reverse order. At the same time the word started with the second highest letter will be rearranged as in step I but this time written at extreme right end.

Step II: 21 msv 37 den kit 58 can 78 83 any 51 fls

In Step III, repeat the process as in Step I newly formed letter cluster written at extreme left end and next lowest number written at extreme right end.

Step III: jjs 21 msv den 58 can 78 83 any 51 fls 73

In Step IV, repeat the step 2 letter cluster at the right end and number at the left end.

Step IV: 55 jjs 21 msv can 78 83 any 51 fls 73 cfm

In Step V, repeat the process as in Step I.

Step V: bbm 55 jjs 21 msv 83 any 51 fls 73 cfm 75

In Step VI, repeat the process as in Step II.

Step VI: 38 bbm 55 jjs 21 msv 51 fls 73 cfm 75 bmx

Input: 23 fan 64 ten jar 51 nip 48 lit 89 hut 76

Step I: fms fan 64 jar 51 nip 48 lit 89 hut 76 32

Step II: 45 fms fan 64 jar 51 lit 89 hut 76 32 jmo

Step III: jks 45 fms fan 64 jar 89 hut 76 32 jmo 15

Step IV: 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq

Step V: gsv 61 jks 45 fms fan 89 32 jmo 15 biq 73

Step VI: 98 gsv 61 jks 45 fms 32 jmo 15 biq 73 bem

Since, in Step IV third element from the right end is 'jmo' and second to the left of 'jmo' is '76'. Therefore, 'biq' comes fourth to the right of '76'.

Hence, the correct answer is 'biq'.

The logic followed here is as follows:

In Step I, the word which starts with the highest letter as per alphabetical series rewritten as the vowel is replaced with the next letter comes and consonant replaced with the previous letter comes as per alphabetical series and new letters will be written in alphabetical order and write at extreme left end and at the same time the lowest number if it is an odd number then write in reverse order at the extreme right end. For example, the highest letter started word is nut which is rewritten as n = m, u = v and t = s and collectively written as msv and lowest number is 13 which is changed into 31.

Step I: msv 37 den kit 58 can 24 met 78 83 any 51

In Step II, the second lowest number will be written at the extreme left end if it is even number then subtracted by 3 if the odd number then just as in step I reverse order. At the same time the word started with the second highest letter will be rearranged as in step I but this time written at extreme right end.

Step II: 21 msv 37 den kit 58 can 78 83 any 51 fls

In Step III, repeat the process as in Step I newly formed letter cluster written at extreme left end and next lowest number written at extreme right end.

Step III: jjs 21 msv den 58 can 78 83 any 51 fls 73

In Step IV, repeat the step 2 letter cluster at the right end and number at the left end.

Step IV: 55 jjs 21 msv can 78 83 any 51 fls 73 cfm

In Step V, repeat the process as in Step I.

Step V: bbm 55 jjs 21 msv 83 any 51 fls 73 cfm 75

In Step VI, repeat the process as in Step II.

Step VI: 38 bbm 55 jjs 21 msv 51 fls 73 cfm 75 bmx

Input: 23 fan 64 ten jar 51 nip 48 lit 89 hut 76

Step I: fms fan 64 jar 51 nip 48 lit 89 hut 76 32

Step II: 45 fms fan 64 jar 51 lit 89 hut 76 32 jmo

Step III: jks 45 fms fan 64 jar 89 hut 76 32 jmo 15

Step IV: 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq

Step V: gsv 61 jks 45 fms fan 89 32 jmo 15 biq 73

Step VI: 98 gsv 61 jks 45 fms 32 jmo 15 biq 73 bem

Since, 'gsv' comes at first position in Step V not in Step IV. Therefore, statement first is incorrect.

45 comes third to the left of 64 not right in Step III. Therefore, statement second is incorrect.

Only two elements which are 'fan and 89' comes between fms and hut in Step IV. Therefore, statement third is correct.

51 comes second to the left not right of 89 in Step II. Therefore, statement fourth is incorrect.

76 comes at the fourth position from the right end not from the left end in Step III. Therefore, statement fifth is incorrect.

Hence, the correct answer is only two elements comes between 'fms' and 'hut' in Step IV.

The logic followed here is as follows:

In Step I, the word which starts with the highest letter as per alphabetical series rewritten as the vowel is replaced with the next letter comes and consonant replaced with the previous letter comes as per alphabetical series and new letters will be written in alphabetical order and write at extreme left end and at the same time the lowest number if it is an odd number then write in reverse order at the extreme right end. For example, the highest letter started word is nut which is rewritten as n = m, u = v and t = s and collectively written as msv and lowest number is 13 which is changed into 31.

Step I: msv 37 den kit 58 can 24 met 78 83 any 51

In Step II, the second lowest number will be written at the extreme left end if it is even number then subtracted by 3 if the odd number then just as in step I reverse order. At the same time the word started with the second highest letter will be rearranged as in step I but this time written at extreme right end.

Step II: 21 msv 37 den kit 58 can 78 83 any 51 fls

In Step III, repeat the process as in Step I newly formed letter cluster written at extreme left end and next lowest number written at extreme right end.

Step III: jjs 21 msv den 58 can 78 83 any 51 fls 73

In Step IV, repeat the step 2 letter cluster at the right end and number at the left end.

Step IV: 55 jjs 21 msv can 78 83 any 51 fls 73 cfm

In Step V, repeat the process as in Step I.

Step V: bbm 55 jjs 21 msv 83 any 51 fls 73 cfm 75

In Step VI, repeat the process as in Step II.

Step VI: 38 bbm 55 jjs 21 msv 51 fls 73 cfm 75 bmx

Input: 23 fan 64 ten jar 51 nip 48 lit 89 hut 76

Step I: fms fan 64 jar 51 nip 48 lit 89 hut 76 32

Step II: 45 fms fan 64 jar 51 lit 89 hut 76 32 jmo

Step III: jks 45 fms fan 64 jar 89 hut 76 32 jmo 15

Step IV: 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq

Step V: gsv 61 jks 45 fms fan 89 32 jmo 15 biq 73

Step VI: 98 gsv 61 jks 45 fms 32 jmo 15 biq 73 bem

Hence, the correct answer is 61 jks 45 fms fan 89 hut 76 32 jmo 15 biq.

Statement I:

1. “Blue is pink” is coded as “nq sk hl”

2. “she likes blue” is coded as “bd lv ne”

3. “wall is pink” is coded as “hc nq sk”.

Since, the code for the word pink can be either “nq” or “sk”.

Therefore, statement I alone is not sufficient to answer the given question.

Statement II:

1. “Pink is light” is coded as “sk pm nq”

2. “Raj likes purple” is coded as “du xz ne”

3. “None likes black” is coded as “wq ne yt”.

Since, we cannot conclude the code for the word ‘pink’.

Therefore, statement II alone is not sufficient to answer the given question.

Statement III:

1. “Lotus is pink” is coded as “ur nq sk”

2. “black absorbs blue” is coded as “dv yt lv”

3. “blue looks good” is coded as “lv rc ax”.

Since, we cannot conclude the code for the word ‘pink’.

Therefore, statement III alone is not sufficient to answer the given question.

Since, if we combine any two statements or all statements together we cannot get the answer for the given question.

Hence, the correct answer is all the statements i.e. I, II and III together are not sufficient to answer the given question.

Statement I:

1. Three persons sit between T and U.

2. P sits two places away from U.

3. Q sits to the left of T.

4. Only one person sits to the right of U.

Therefore, statement I alone is not sufficient to answer the given question.

Statement II:

1. V sits second to the right of Q.

2. S sits immediate right to the one who sits two places away from T.

3. P sits to the left of R.

Since, from statement II we cannot get any accurate result. Therefore, statement I alone is not sufficient to answer the given question.

Now, let’s combine statements I and II, we have

Therefore, statement I and II together are required to answer the given question.

Statement III: 

1. Only one person sits between T and P.

2. R sits second to the right of S.

3. Q sits to the left of V who sits to the left of R.

Since, statement III alone does not give any accurate result. Therefore, statement III alone is not sufficient to answer the given question.

Now, let’s combine statement II and III, we have

Therefore, statements II and III together are required to answer the given question.

Now let’s combine statement I and III together, we get

Hence, the correct answer is data given in any two statements taken together is sufficient to answer the given question.

Statement I:

1. Two persons sit between A and C.

2. G sits fourth to the left of E.

3. H sits immediate left to C.

4. Neither A nor C sits adjacent to G.

Therefore, we can conclude anything from the statement I.

Hence, statement I alone is not sufficient to answer the given question.

Statement II:

1. B sits second to the right of D.

2. F sits opposite to C.

3. E sits three places away from B.

4. Neither H nor A sits adjacent to B.

Therefore, statement II alone is not sufficient to answer the question.

Now, let’s combine statement I and II, we get

Statement III:

1. F sits three places away from D.

2. E sits second to the left of C.

3. G sits adjacent to B and D.

4. A sits to the left of H.

Since, statement III alone is not sufficient to answer the given question.

Now if we combine Statements II and III we get

Therefore, both statement II and III together are required to answer the given question.

Now, we combine statements I and III together we get

Therefore, statement I and III together are necessary to answer the question.

Hence, the correct answer is any two statements out of the three statements together are sufficient to answer the given question.

Statement I:

1. M sits third to the right of P.

2. Only one person sits between S and T neither of sits opposite to M.

3. O sits two places away the person who sits opposite to T.

4. V sits immediate left to the person who sits opposite to O.

Therefore, N sits second to the left of M.

Hence, statement I alone is sufficient to answer the given question.

Statement II:

1. Only two persons sit between V and T.

2. P and V do not sit opposite to each other.

3. N sits to the left of O.

4. Neither S nor U sits opposite to M.

Therefore, statement II alone is not sufficient to answer the given question.

Statement III:

1. N sits immediate right to the person who sits opposite to T.

2. V sits adjacent to S but does not face P.

3. Only one person sits between O and P.

Since, we can conclude anything from the statement III.

Therefore, statement III alone is not sufficient to answer the given question.

Now let’s take statement II and III together, we get

Therefore, we get the required answer.

Hence, the correct answer is either statement I alone or statement II and III together are sufficient to answer the given question.

Since, given expression I, M % P # Q @ S & N * Y is represented as

Therefore, it is clear from expression I that S has only one daughter who is N.

Now expression II, S * L # N % P $ K @ R is represented as

Since, expression II does not give the desired result.

Now expression III, Q # K @ S & O * P # T is represented as

Therefore, expression III also gives the desired result.

Hence, the correct answer is only I and III.$

Here, given captains A, B, C, D and E; ships are F, G, H, I, J and K and ports are K, L, M, N and O.

1. A reached at port L after 4 hours of J.

2. A completed his journey just after the one who reach at port N completed his journey.

3. The one who uses ship J completed his journey at 12pm. Therefore, A completed his journey at 4pm.

4. Only two persons completed their journey between the one who reached at port L and C.

5. The one who reach at port M reached one hour before the one who reached at port O.

6. The one who uses ship I reach at his destination two and half an hour before the one who uses ship J.

7. As many person completed their journey between the one who reached at port O and the one who uses ship I as many between the one who uses ship F and the one who reached at port O.

8. The difference between time taken by C and the one who reached at port N is same as the difference between time taken by the one who uses ship F and E.

9. B reached at port O.

10. D reaches one and half an hour before the one who uses ship G. Therefore, case 2 is eliminated.

11. E takes 50% more of the time taken between the one who uses ship G and B. Hence, the final arrangement is as follows

Hence, the correct combination is A - Ship F - Port L.

Here, given captains A, B, C, D and E; ships are F, G, H, I, J and K and ports are K, L, M, N and O.

1. A reached at port L after 4 hours of J.

2. A completed his journey just after the one who reach at port N completed his journey.

3. The one who uses ship J completed his journey at 12pm. Therefore, A completed his journey at 4pm.

4. Only two persons completed their journey between the one who reached at port L and C.

5. The one who reach at port M reached one hour before the one who reached at port O.

6. The one who uses ship I reach at his destination two and half an hour before the one who uses ship J.

7. As many person completed their journey between the one who reached at port O and the one who uses ship I as many between the one who uses ship F and the one who reached at port O.

8. The difference between time taken by C and the one who reached at port N is same as the difference between time taken by the one who uses ship F and E.

9. B reached at port O.

10. D reaches one and half an hour before the one who uses ship G. Therefore, case 2 is eliminated.

11. E takes 50% more of the time taken between the one who uses ship G and B. Hence, the final arrangement is as follows

Since, E uses Ship H to reach at port N and completed his journey at 1:30pm.

Hence, the correct answer is N - 1:30pm.

Here, given captains A, B, C, D and E; ships are F, G, H, I, J and K and ports are K, L, M, N and O.

1. A reached at port L after 4 hours of J.

2. A completed his journey just after the one who reach at port N completed his journey.

3. The one who uses ship J completed his journey at 12pm. Therefore, A completed his journey at 4pm.

4. Only two persons completed their journey between the one who reached at port L and C.

5. The one who reach at port M reached one hour before the one who reached at port O.

6. The one who uses ship I reach at his destination two and half an hour before the one who uses ship J.

7. As many person completed their journey between the one who reached at port O and the one who uses ship I as many between the one who uses ship F and the one who reached at port O.

8. The difference between time taken by C and the one who reached at port N is same as the difference between time taken by the one who uses ship F and E.

9. B reached at port O.

10. D reaches one and half an hour before the one who uses ship G. Therefore, case 2 is eliminated.

11. E takes 50% more of the time taken between the one who uses ship G and B. Hence, the final arrangement is as follows

Since, The one who used ship J goes two persons before not just before the one who reached at port L. Therefore,statement first is incorrect.

No one not went to the port between D who used Ship I and C who used Ship G. Therefore,statement second is incorrect.

A who reached at port L is the last person not first person who started a journey. Therefore, statement third is incorrect.

B reaches at port O just after two persons of D who reached at port K. Therefore, statement fourth is correct.

Hence, the correct answer is B reaches at port O just after two persons of the one who reached at port K.

Here, given captains A, B, C, D and E; ships are F, G, H, I, J and K and ports are K, L, M, N and O.

1. A reached at port L after 4 hours of J.

2. A completed his journey just after the one who reach at port N completed his journey.

3. The one who uses ship J completed his journey at 12pm. Therefore, A completed his journey at 4pm.

4. Only two persons completed their journey between the one who reached at port L and C.

5. The one who reach at port M reached one hour before the one who reached at port O.

6. The one who uses ship I reach at his destination two and half an hour before the one who uses ship J.

7. As many person completed their journey between the one who reached at port O and the one who uses ship I as many between the one who uses ship F and the one who reached at port O.

8. The difference between time taken by C and the one who reached at port N is same as the difference between time taken by the one who uses ship F and E.

9. B reached at port O.

10. D reaches one and half an hour before the one who uses ship G. Therefore, case 2 is eliminated.

11. E takes 50% more of the time taken between the one who uses ship G and B. Hence, the final arrangement is as follows

Since, E uses ship H and he reached just before A who reached at port L.

Hence, the correct answer is None.

Here, given captains A, B, C, D and E; ships are F, G, H, I, J and K and ports are K, L, M, N and O.

1. A reached at port L after 4 hours of J.

2. A completed his journey just after the one who reach at port N completed his journey.

3. The one who uses ship J completed his journey at 12pm. Therefore, A completed his journey at 4pm.

4. Only two persons completed their journey between the one who reached at port L and C.

5. The one who reach at port M reached one hour before the one who reached at port O.

6. The one who uses ship I reach at his destination two and half an hour before the one who uses ship J.

7. As many person completed their journey between the one who reached at port O and the one who uses ship I as many between the one who uses ship F and the one who reached at port O.

8. The difference between time taken by C and the one who reached at port N is same as the difference between time taken by the one who uses ship F and E.

9. B reached at port O.

10. D reaches one and half an hour before the one who uses ship G. Therefore, case 2 is eliminated.

11. E takes 50% more of the time taken between the one who uses ship G and B. Hence, the final arrangement is as follows

Since, Ship G is used by C not E to reach at port M not N. Therefore, statement A is incorrect.

C is the second person who completed his journey. Therefore, statement B is correct.

A reached at port L by using Ship F not ship H. Therefore, statement C is incorrect.

Hence, the incorrect statements are both A and C.

(LHS) Q K 4 R B # * A 7 G ( 9 T D 2 & J M 5 ^ E 3 (RHS)

Step 1: The numbers which are immediately followed or immediately preceded by the symbol will be reduced by one.

Operation: Symbol → Number or Number → Symbol reduced by 1.

Step 1: (LHS) Q K 4 R B # * A 7 G ( 8 T D 1 & J M 4 ^ E 3 (RHS)

Step 2: The elements which are immediately followed by an odd number will interchange their position.

Arrangement requirement: Element ↔ Odd number

Step 2: (LHS) Q K 4 R B # * 7 A G ( 8 T 1 D & J M 4 ^ 3 E (RHS)

Step 3: The seventh element from the right end will be placed just after the eleventh element from the left end.

Step 3: (LHS) Q K 4 R B # * 7 A G ( & 8 T 1 D J M 4 ^ 3 E (RHS)

Since, in step 2, ninth element from the right side is 1 and just before 1 the element comes is T.

Hence, the correct answer is T.

(LHS) Q K 4 R B # * A 7 G ( 9 T D 2 & J M 5 ^ E 3 (RHS)

Step 1: The numbers which are immediately followed or immediately preceded by the symbol will be reduced by one.

Operation: Symbol → Number or Number → Symbol reduced by 1.

Step 1: (LHS) Q K 4 R B # * A 7 G ( 8 T D 1 & J M 4 ^ E 3 (RHS)

Step 2: The elements which are immediately followed by an odd number will interchange their position.

Arrangement requirement: Element ↔ Odd number

Step 2: (LHS) Q K 4 R B # * 7 A G ( 8 T 1 D & J M 4 ^ 3 E (RHS)

Step 3: The seventh element from the right end will be placed just after the eleventh element from the left end.

Step 3: (LHS) Q K 4 R B # * 7 A G ( & 8 T 1 D J M 4 ^ 3 E (RHS)

Since, in step 3 second element from the left end is K and seventh element from the right end is D.

Therefore, between D and K only six letters present as per alphabetical series.

Hence, the correct answer is six.

I. NOVICE, TIRADE, CLICHE, RECANT → Since, the fourth, first, third and second letters respectively of the given words are I, T, I and E therefore, by using these letters no meaningful word can be formed.

II. THWART, GENIAL, QUENCH, IMPUTE → Since, the fourth, first, third and second letters respectively of the given words are A, G, E and M by using these letters two meaningful words can be formed formed which are Game and Mega.

III. METTLE, GRATIS, EXODUS, ROBUST → Since, the fourth, first, third and second letters respectively of the given words are T, G, O and O therefore, by using these letters no meaningful word can be formed.

IV. EVINCE, SAFARI, MALICE, JOSTLE → Since, the fourth, first, third and second letters respectively of the given words are N, S, L and O therefore, by using these letters no meaningful word can be formed.

V. BEHEST, FOSTER, LATENT, SQUALL → Since, the fourth, first, third and second letters respectively of the given words are E, F, T and Q therefore, by using these letters no meaningful word can be formed.

Hence, the correct answer is THWART, GENIAL, QUENCH, IMPUTE.

Given: Eight persons A, B, C, D, E, F, G and H are sitting around a circular table facing towards the center.

Based on the given conditions, we get the following possibilities:

1. One person is sitting between A and E from either side.

B is sitting on the immediate left of A.

Combining these, we get-

2. Three persons are sitting between C and D.

F is the immediate neighbor of D.

H is sitting on the immediate left of G.

F is neither sitting immediately to G nor H.

This eliminates Case 1 from the above and we get the final arrangement as follows:

Now, cards are drawn in clockwise direction starting from A.

The clockwise lineup of drawing cards from A is - A, B, F, D, G, H, E, C. 

The cards drawn are given as- >7, >6, @5, >9, @3, >1, >2, >10, @5, @8, @4, @3, >7, @9 @5.

Therefore, we get the cards drawn by the different persons as follows:

Now, according to the conditions given, since D draws a card of number 9 of a particular type, so the person next to D, who is G will miss a chance. Similarly, A draws a card 10 of '>' type. So, A will be drawing two cards. Hence, the above given arrangement is the final arrangement of cards distributed. 

Therefore, from the above final table, we see that B picks the >6 and @8 cards. The numbers present in the cards are 6 and 8. The product of 6 and 8 is 48.

Hence, the required product is 48.

Given: Eight persons A, B, C, D, E, F, G and H are sitting around a circular table facing towards the center.

Based on the given conditions, we get the following possibilities:

1. One person is sitting between A and E from either side.

B is sitting on the immediate left of A.

Combining these, we get-

2. Three persons are sitting between C and D.

F is the immediate neighbor of D.

H is sitting on the immediate left of G.

F is neither sitting immediately to G nor H.

This eliminates Case 1 from the above and we get the final arrangement as follows:

Now, cards are drawn in clockwise direction starting from A.

The clockwise lineup of drawing cards from A is - A, B, F, D, G, H, E, C. 

The cards drawn are given as- >7, >6, @5, >9, @3, >1, >2, >10, @5, @8, @4, @3, >7, @9 @5.

Therefore, we get the cards drawn by the different persons as follows:

Now, according to the conditions given, since D draws a card of number 9 of a particular type, so the person next to D, who is G will miss a chance. Similarly, A draws a card 10 of '>' type. So, A will be drawing two cards. Hence, the above given arrangement is the final arrangement of cards distributed. 

Therefore, from the above final table, the second card drawn by D is '@3'. 

Hence, the second card picked by D is '@3'.

Given: Eight persons A, B, C, D, E, F, G and H are sitting around a circular table facing towards the center.

Based on the given conditions, we get the following possibilities:

1. One person is sitting between A and E from either side.

B is sitting on the immediate left of A.

Combining these, we get-

2. Three persons are sitting between C and D.

F is the immediate neighbor of D.

H is sitting on the immediate left of G.

F is neither sitting immediately to G nor H.

This eliminates Case 1 from the above and we get the final arrangement as follows:

Now, cards are drawn in clockwise direction starting from A.

The clockwise lineup of drawing cards from A is - A, B, F, D, G, H, E, C. 

The cards drawn are given as- >7, >6, @5, >9, @3, >1, >2, >10, @5, @8, @4, @3, >7, @9 @5.

Therefore, we get the cards drawn by the different persons as follows:

Now, according to the conditions given, since D draws a card of number 9 of a particular type, so the person next to D, who is G will miss a chance. Similarly, A draws a card 10 of '>' type. So, A will be drawing two cards. Hence, the above given arrangement is the final arrangement of cards distributed. 

Therefore, from the above final table, we see that F sits third to the right of H. 

Hence, F sits third to the right of H.

Given: Eight persons A, B, C, D, E, F, G and H are sitting around a circular table facing towards the center.

Based on the given conditions, we get the following possibilities:

1. One person is sitting between A and E from either side.

B is sitting on the immediate left of A.

Combining these, we get-

2. Three persons are sitting between C and D.

F is the immediate neighbor of D.

H is sitting on the immediate left of G.

F is neither sitting immediately to G nor H.

This eliminates Case 1 from the above and we get the final arrangement as follows:

Now, cards are drawn in clockwise direction starting from A.

The clockwise lineup of drawing cards from A is - A, B, F, D, G, H, E, C. 

The cards drawn are given as- >7, >6, @5, >9, @3, >1, >2, >10, @5, @8, @4, @3, >7, @9 @5.

Therefore, we get the cards drawn by the different persons as follows:

Now, according to the conditions given, since D draws a card of number 9 of a particular type, so the person next to D, who is G will miss a chance. Similarly, A draws a card 10 of '>' type. So, A will be drawing two cards. Hence, the above given arrangement is the final arrangement of cards distributed. 

Therefore, from the above final table, we see that G only picks a card only once.  

Hence, G picks a card only once.

Given: Eight persons A, B, C, D, E, F, G and H are sitting around a circular table facing towards the center.

Based on the given conditions, we get the following possibilities:

1. One person is sitting between A and E from either side.

B is sitting on the immediate left of A.

Combining these, we get-

2. Three persons are sitting between C and D.

F is the immediate neighbor of D.

H is sitting on the immediate left of G.

F is neither sitting immediately to G nor H.

This eliminates Case 1 from the above and we get the final arrangement as follows:

Now, cards are drawn in clockwise direction starting from A.

The clockwise lineup of drawing cards from A is - A, B, F, D, G, H, E, C. 

The cards drawn are given as- >7, >6, @5, >9, @3, >1, >2, >10, @5, @8, @4, @3, >7, @9 @5.

Therefore, we get the cards drawn by the different persons as follows:

Now, according to the conditions given, since D draws a card of number 9 of a particular type, so the person next to D, who is G will miss a chance. Similarly, A draws a card 10 of '>' type. So, A will be drawing two cards. Hence, the above given arrangement is the final arrangement of cards distributed. 

Therefore, from the above final table, we see that A picks a '@5' card. 

Hence, A picks a '@5' card.

Inferences:

I. Vehicular pollutants can alter internal organs of the person. → True (As it is clearly mentions in the passage vehicular pollutants can damage natural function of internal organs. Hence, follows.)

II. There is a need to completely ban all kinds of vehicle at an urgent basis. → False (As from the passage it cannot be concluded to ban all kinds of vehicle since there are some vehicles which produce less pollution. Hence, does not follow.)

Hence, the correct answer is only inference I follows.

Inferences:

I. It creates a risk of diluting the authenticity of the climate goals by presenting misleading or exaggerated information about environmental initiatives. → True (As it is clear from the passage. Hence, follows.)

II. The absence of comprehensive regulations and standards for environmental claims allows greenwashing to persist without adequate scrutiny. → True (As it is clear from the passage. Hence, follows.)

Hence, the correct answer is both inferences I and II follow.

Courses of Action:

I. Government need to make some legislation that can regulate climate action while ignoring the transboundary impact of their decisions. → False (Since, climate change is a global concern so government cannot ignore its transboundary effects. Hence, does not follow.)

II. Countries need to make regional agreements to avoid risks of unequal spatial distribution of effects. – True (Since, it’s a global concern so governments of all countries are needed to step forward together. Hence, follows.)

Hence, the correct answer is only II follows.

Assumptions:

I. It can increase the volatility in money and exchange markets. → True (As it is clear from the passage it needed a new monetary policy framework. Hence, follows.)

II. It can reduce the cost of holding foreign reserve by the RBI. → True (Since, if many countries start holding Indian rupee it can smooth trade system which was earlier done by dollars or some internationally accepted currency. Hence, follows.)

Hence, the correct answer is both assumptions I and II follows.

As per given instructions, in the first word i.e. CONSCIENTIOUS

Vowels replaced with the next letter and consonants replaced with the previous letter.

Now remove all the repeated words, we get

Final result: F, S, V

Therefore, the third letter from the right side is F.

Now in second word ,i.e., MANIFESTATION

Before N = -1 and After N = +1 and there is no change on N.

Now, remove all the repeated letters then

New result: L, E, D, T, P

Now the rearrange the series according to alphabetical series, we get

Final result: D, E, L, P, T

Therefore, the third letter from the right side is L.

Hence, the correct answer is F and L.

Given: Six persons are from between 20 march to 28 march. Only one person born on each date and they all are born in the same year. 

Note that there are nine dates and six persons. So, there will be three vacant days unless otherwise mentioned in the questions asked. 

Based on the given conditions, we get the following possibilities:

1. R born on the date which is multiple of 3.

R is neither born at first nor born at last.

Combining these, we get-

2. Three persons are born between R and M. 

From this, we get-

Note: (-) denotes confirmed vacant dates in the cases mentioned in. 

3. N and M born on consecutive dates.

There is gap of two days between the date on which L was born and on which N was born.

This eliminates cases 2 and 4 from the above and we get-

4. P was born on one of the days before L on even date but born after the date on which Q was born.

This eliminates cases 1,3, and 6 from the above and we get the final arrangement as follows:

From the above final table, we see that M was born six days after P. 

Hence, M was born six days after P.

Given: Six persons are from between 20 march to 28 march. Only one person born on each date and they all are born in the same year. 

Note that there are nine dates and six persons. So, there will be three vacant days unless otherwise mentioned in the questions asked. 

Based on the given conditions, we get the following possibilities:

1. R born on the date which is multiple of 3.

R is neither born at first nor born at last.

Combining these, we get-

2. Three persons are born between R and M. 

From this, we get-

Note: (-) denotes confirmed vacant dates in the cases mentioned in. 

3. N and M born on consecutive dates.

There is gap of two days between the date on which L was born and on which N was born.

This eliminates cases 2 and 4 from the above and we get-

4. P was born on one of the days before L on even date but born after the date on which Q was born.

This eliminates cases 1,3, and 6 from the above and we get the final arrangement as follows:

If O was born on an odd numbered date before L, then O would have been born on the 23^rd of March. Therefore, the number of persons born between Q and L in that case would be three. 

Hence, the number of persons born between Q and L would be three.

Here, given expression F $ P * M & Q % H @ N,

F $ P means ‘F is the mother of P.’

P * M means ‘P is the wife of M.’

M & Q means ‘M is the brother of Q.’

Q % H means ‘Q is the husband of H.’

H @ N means ‘H is the sister of N.’

Therefore, the family chart of the given expression is as follows

Therefore, from the above diagram it is clear Q is the brother – in – law of N.

Hence, the correct answer is brother – in – law.

Since, given expression R % V ? L @ O * J,

R % V means R is the husband of V.

Now L @ O means ‘L is the sister of O’ and O * J means ‘O is the wife of J.’ Therefore, expression L @ O * J represented as

Now if we place $in place of ? we get the expression as V$ L which means V is the mother of L and since L is the sister of O so V is  also mother of J. Therefore, the final expression becomes R % V $ L @ O * J

Hence, the correct answer is ‘$.’

Here, persons are A, B, C, D, E, F, G, H and J.

1. D and F sits on different cars but one of them sits with the E.

2. F and B travels with the same car.

3. J and B travels in different cars.

4. No two persons whose name starts with the vowel travel in the same car.

5. C and H are going with same car.

6. Either A or H travels with G. Since, between A and H only one will travel in the same car with G therefore, A and H travels in different cars.

7. C travels in the car which has maximum number of persons.

8. Neither J nor D travels in the same car with G. Therefore, case 2 and case 4 are eliminated.

9. Even number of persons does not travel with car P. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Since, H and F travel with the different cars so only one of them travels with person who travels with J. Therefore, statement first is incorrect.

.A and B travels with the same car. Therefore, statement second is incorrect.

G and H travels with the different cars. Therefore, statement third is incorrect.

Maximum number of persons travel in the same car in which E travels. Therefore, statement fourth is correct.

Hence, the correct statement is maximum number of persons travel in the same car in which E travels.

Here, persons are A, B, C, D, E, F, G, H and J.

1. D and F sits on different cars but one of them sits with the E.

2. F and B travels with the same car.

3. J and B travels in different cars.

4. No two persons whose name starts with the vowel travel in the same car.

5. C and H are going with same car.

6. Either A or H travels with G. Since, between A and H only one will travel in the same car with G therefore, A and H travels in different cars.

7. C travels in the car which has maximum number of persons.

8. Neither J nor D travels in the same car with G. Therefore, case 2 and case 4 are eliminated.

9. Even number of persons does not travel with car P. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Since, E travels in car P not car Q. Therefore, statement A is incorrect.

F and G travels in same car. Therefore, statement B is incorrect.

H travels with D but not with A. Therefore, statement C is correct.

Hence, the incorrect statements are Both A and B.

We check the given options one by one and see which one might not be the reason of not renewing contract with company Y as follows:

1. Company X is providing better services which are not provided by company Y to the country Z. → This might be a valid and a genuine reason for country Z to not renew the services with company Y. Hence, this might be the reason of not renewing contract with company Y.  2. Company Y is not providing services according to the standards of the country Z. → This might be a valid and a genuine reason for country Z to not renew the services with company Y. Since, company Y has not clearly upgraded their services, country Z might look for other options. Hence, this might be the reason of not renewing contract with company Y.  3. Company Y is providing better services as per the requirements of the country Z. → This cannot be a valid and a genuine reason for country Z to not renew the services with company Y. Country Z should rather be delighted that company Y has upgraded their services which might help the country's citizens. Hence, this might not be the reason of not renewing contract with company Y.  4. Cost of the services provided by company Y is more than the same services provided by company X. → This might be a valid and a genuine reason for country Z to not renew the services with company Y. Country Z might only be able to afford a certain limit of cost which is provided by company X and not by company Y. Hence, this might be the reason of not renewing contract with company Y.  5. Company Y's dealing with Country Z's top brass was poor and disoriented. → This might be a valid and a genuine reason for country Z to not renew the services with company Y. Country Z's top brass might be hugely upset with the mannerisms of company Y. Hence, this might be the reason of not renewing contract with company Y. 

Hence, option 3 might not be the reason of not renewing contract with company Y.

We cannot say what ground the critic assumes on the basis of which be terms it "not a proper and judicious step."

According to 1^st  assumption, we can not assume that the student may hesitate to eat the cooked meal provided by the Government.

According to 2^nd assumption, we can not assume that the cooked meal served to the students may be hazardous for the health.

Hence, If neither I nor II is implicit.

Given: A certain number of persons live on a four storey apartment such that floor 1 is the bottom most floor and floor 4 is the top most floor. In each floor there are three flats i.e. flat P, flat Q and flat R and flat P is in west of flat Q which is in west of flat R. These persons have different number of chocolates which ranges from 1 to 100. There are some vacant flats in each floor and at least two persons live in each floor and flat.

1. E lives immediately above the flat of K but on flat R. That means E and K lives either on flat P or on flat Q.

2. No one lives to the east of K but according to direction atleast two persons live on each floor and flat.  So, K cannot in flat P.

3. E has the chocolates which is one more than the multiple of least composite and least odd prime number. Since the least composite number is 4 and odd prime number is 3 and their multiplication is 12 so E has 13 chocolates.

4. M have the chocolates which is half of the chocolates of the person who lives immediately above his flat. So, M cannot be on Floor 4.

5. S has chocolates which is 7 less than three times of the number of chocolates E has. So, S has 32 chocolates.

6. A and S lives on same flat but not in flat R.  

7. No one lives between the flat of A and the person who has 7 more chocolates than him.

8. S lives one of the floors below M. Since, the person above M holds twice the number of chocolates he himself has so, A cannot be above M.

9. S does not live to the west of E or V. So, cases 1(a) and 2(d, e) are eliminated.

10. X and V lives on same flat.

11. A and J do not live on the same floor.

12. J has one more chocolate than the number of chocolates of M has.

13. S and X do not live on the same floor and same flat. So, X does not live on Flat P.

14. J and the person who has maximum number of chocolates lives on same floor.

15. J does not live on flat P.

16. X has more chocolates than V who has three times the number of chocolates of A. So, we can conclude X has maximum number of chocolates. So, case 1(b) and 2(c) are eliminated.

Since, there is atleast two persons live on each floor. So, case 2(b) is eliminated.

17. V has three times the number of chocolates of A. From condition 7 we get A has 25 chocolates then V has 75 chocolates.

18. The difference between numbers of chocolates X has and that of V is same as the number of chocolates E holds. So, X has 88 chocolates and M has 44 chocolates so J has 45 chocolates.

19. K has the chocolates which is 1 less than the average number of chocolates of J and V. Therefore, K has 59 chocolates.

Since, X has 88 chocolates which is maximum among all.

Hence, the correct answer is X.

Given: A certain number of persons live on a four storey apartment such that floor 1 is the bottom most floor and floor 4 is the top most floor. In each floor there are three flats i.e. flat P, flat Q and flat R and flat P is in west of flat Q which is in west of flat R. These persons have different number of chocolates which ranges from 1 to 100. There are some vacant flats in each floor and at least two persons live in each floor and flat.

1. E lives immediately above the flat of K but on flat R. That means E and K lives either on flat P or on flat Q.

2. No one lives to the east of K but according to direction atleast two persons live on each floor and flat.  So, K cannot in flat P.

3. E has the chocolates which is one more than the multiple of least composite and least odd prime number. Since the least composite number is 4 and odd prime number is 3 and their multiplication is 12 so E has 13 chocolates.

4. M have the chocolates which is half of the chocolates of the person who lives immediately above his flat. So, M cannot be on Floor 4.

5. S has chocolates which is 7 less than three times of the number of chocolates E has. So, S has 32 chocolates.

6. A and S lives on same flat but not in flat R.  

7. No one lives between the flat of A and the person who has 7 more chocolates than him.

8. S lives one of the floors below M. Since, the person above M holds twice the number of chocolates he himself has so, A cannot be above M.

9. S does not live to the west of E or V. So, cases 1(a) and 2(d, e) are eliminated.

10. X and V lives on same flat.

11. A and J do not live on the same floor.

12. J has one more chocolate than the number of chocolates of M has.

13. S and X do not live on the same floor and same flat. So, X does not live on Flat P.

14. J and the person who has maximum number of chocolates lives on same floor.

15. J does not live on flat P.

16. X has more chocolates than V who has three times the number of chocolates of A. So, we can conclude X has maximum number of chocolates. So, case 1(b) and 2(c) are eliminated.

Since, there is atleast two persons live on each floor. So, case 2(b) is eliminated.

17. V has three times the number of chocolates of A. From condition 7 we get A has 25 chocolates then V has 75 chocolates.

18. The difference between numbers of chocolates X has and that of V is same as the number of chocolates E holds. So, X has 88 chocolates and M has 44 chocolates so J has 45 chocolates.

19. K has the chocolates which is 1 less than the average number of chocolates of J and V. Therefore, K has 59 chocolates.

Hence, M lives in same floor with A.

Given: A certain number of persons live on a four storey apartment such that floor 1 is the bottom most floor and floor 4 is the top most floor. In each floor there are three flats i.e. flat P, flat Q and flat R and flat P is in west of flat Q which is in west of flat R. These persons have different number of chocolates which ranges from 1 to 100. There are some vacant flats in each floor and at least two persons live in each floor and flat.

1. E lives immediately above the flat of K but on flat R. That means E and K lives either on flat P or on flat Q.

2. No one lives to the east of K but according to direction atleast two persons live on each floor and flat.  So, K cannot in flat P.

3. E has the chocolates which is one more than the multiple of least composite and least odd prime number. Since the least composite number is 4 and odd prime number is 3 and their multiplication is 12 so E has 13 chocolates.

4. M have the chocolates which is half of the chocolates of the person who lives immediately above his flat. So, M cannot be on Floor 4.

5. S has chocolates which is 7 less than three times of the number of chocolates E has. So, S has 32 chocolates.

6. A and S lives on same flat but not in flat R.  

7. No one lives between the flat of A and the person who has 7 more chocolates than him.

8. S lives one of the floors below M. Since, the person above M holds twice the number of chocolates he himself has so, A cannot be above M.

9. S does not live to the west of E or V. So, cases 1(a) and 2(d, e) are eliminated.

10. X and V lives on same flat.

11. A and J do not live on the same floor.

12. J has one more chocolate than the number of chocolates of M has.

13. S and X do not live on the same floor and same flat. So, X does not live on Flat P.

14. J and the person who has maximum number of chocolates lives on same floor.

15. J does not live on flat P.

16. X has more chocolates than V who has three times the number of chocolates of A. So, we can conclude X has maximum number of chocolates. So, case 1(b) and 2(c) are eliminated.

Since, there is atleast two persons live on each floor. So, case 2(b) is eliminated.

17. V has three times the number of chocolates of A. From condition 7 we get A has 25 chocolates then V has 75 chocolates.

18. The difference between numbers of chocolates X has and that of V is same as the number of chocolates E holds. So, X has 88 chocolates and M has 44 chocolates so J has 45 chocolates.

19. K has the chocolates which is 1 less than the average number of chocolates of J and V. Therefore, K has 59 chocolates.

Since, all the given statements are not correct.

Hence, the correct answer is None of these.

Given: A certain number of persons live on a four storey apartment such that floor 1 is the bottom most floor and floor 4 is the top most floor. In each floor there are three flats i.e. flat P, flat Q and flat R and flat P is in west of flat Q which is in west of flat R. These persons have different number of chocolates which ranges from 1 to 100. There are some vacant flats in each floor and at least two persons live in each floor and flat.

1. E lives immediately above the flat of K but on flat R. That means E and K lives either on flat P or on flat Q.

2. No one lives to the east of K but according to direction atleast two persons live on each floor and flat.  So, K cannot in flat P.

3. E has the chocolates which is one more than the multiple of least composite and least odd prime number. Since the least composite number is 4 and odd prime number is 3 and their multiplication is 12 so E has 13 chocolates.

4. M have the chocolates which is half of the chocolates of the person who lives immediately above his flat. So, M cannot be on Floor 4.

5. S has chocolates which is 7 less than three times of the number of chocolates E has. So, S has 32 chocolates.

6. A and S lives on same flat but not in flat R.  

7. No one lives between the flat of A and the person who has 7 more chocolates than him.

8. S lives one of the floors below M. Since, the person above M holds twice the number of chocolates he himself has so, A cannot be above M.

9. S does not live to the west of E or V. So, cases 1(a) and 2(d, e) are eliminated.

10. X and V lives on same flat.

11. A and J do not live on the same floor.

12. J has one more chocolate than the number of chocolates of M has.

13. S and X do not live on the same floor and same flat. So, X does not live on Flat P.

14. J and the person who has maximum number of chocolates lives on same floor.

15. J does not live on flat P.

16. X has more chocolates than V who has three times the number of chocolates of A. So, we can conclude X has maximum number of chocolates. So, case 1(b) and 2(c) are eliminated.

Since, there is atleast two persons live on each floor. So, case 2(b) is eliminated.

17. V has three times the number of chocolates of A. From condition 7 we get A has 25 chocolates then V has 75 chocolates.

18. The difference between numbers of chocolates X has and that of V is same as the number of chocolates E holds. So, X has 88 chocolates and M has 44 chocolates so J has 45 chocolates.

19. K has the chocolates which is 1 less than the average number of chocolates of J and V. Therefore, K has 59 chocolates.

Hence, the incorrect combination is V - Floor 4 - Flat R because V lives on Floor 2.