Shortcut Trick
LCM of (25, 40) = 200 units
Let the total work be 200 units
Efficiency of Ajay = 200/25 = 8 units per day
Efficiency of Vijay = 200/40 = 5 units per day
Work done by Vijay in 27 days = 27 × 5 = 135 units
∴ Remaining work by Ajay and Vijay in days = (200 - 135)/13
⇒ 65/ 13 = 5 days
∴ Ajay left after 5 days.
Alternate MethodGiven:
Ajay can complete the work in 25 days.
Vijay can complete the work in 40 days.
Vijay finished the remaining work in 27 days after Ajay left.
Concept used:
Work done by Ajay and Vijay per day together = Ajay's rate + Vijay's rate
Work done by Vijay alone in 27 days = Vijay's daily rate × 27 days
Use the concept of work done to set up an equation and solve for the number of days Ajay worked before leaving.
Calculation:
Work rate of Ajay:
⇒ Ajay's rate = 1/25 (work/day)
Work rate of Vijay:
⇒ Vijay's rate = 1/40 (work/day)
Work rate of Ajay and Vijay together:
⇒ Combined rate = (1/25) + (1/40)
Find a common denominator and add:
⇒ Combined rate = (8 + 5) / 200
⇒ Combined rate = 13 / 200 (work/day)
Work done by Vijay alone in 27 days:
⇒ Work done by Vijay = 27 × (1/40)
⇒ Work done by Vijay = 27/40
Let's say Ajay worked for x days. During these x days, both Ajay and Vijay were working.
Work done by Ajay and Vijay together in x days:
⇒ Work done together = x × (13/200)
The total work = Work done by Ajay and Vijay together + Work done by Vijay alone:
⇒ 1 = (x × 13/200) + 27/40
Convert 27/40 to a fraction with a denominator of 200:
⇒ 27/40 = (27 × 5) / (40 × 5) = 135/200
Substitute and solve for x:
⇒ 1 = (13x / 200) + 135 / 200
Multiply both sides by 200 to clear the fractions:
⇒ 200 = 13x + 135
Subtract 135 from both sides:
⇒ 65 = 13x
Divide both sides by 13:
⇒ x = 65 / 13
⇒ x = 5
∴ Ajay left after 5 days.