Reasoning PYQs

The symbol table is as follows:

 

The symbol table for family tree diagram is as:

1. "P @ Q & S # R" imply that P is the husband of Q, Q is the mother of S and S is the wife of R.

The family tree diagram is as:

Here S is the daughter of P. Hence false.

2. "Q @ P & R # S" imply that Q is the husband P, P is the mother of R and R is the wife of S.

The family tree diagram is as:

Here Q is the father in law of S. Hence, false.

3. "P @ Q & R # S" imply that P is the husband Q, Q is the mother of R and R is the wife of S.

The family tree diagram is as:

Here, P is the father in law of S. Hence, true.

Therefore, P @ Q & R # S is true.

The logic is as:

Row 1: \({40\over 8}\)× 57 = 5 × 57 = 285

Row 2: \( {35 \over 8}\) × 32= 35 × 4 = 140

Similarly,

Row 3:\({35 \over 8}\) × 40 = 35 × 5 = 175

Hence, missing number is 35.

If we observe all the options given, we will get to know:

As we can see that the pattern is not followed by option 4).

Hence, OKS  is the odd one.

The symbol table is as:

The relational diagram is as: 

Hence, father of boy in the picture is brother of swapna.

The direction distance diagram for the given statements is as follows:

Now, the distance from pole to final position is = 76 - 69 = 7 m

Hence, the distance is 7 m.

The coding for the given words is as:

Hence, the code for emotional is ru.

The least possible Venn diagram for the given statements is as:

Conclusions:

1. All pumpkins are plum. → True (As all pumpkins are bananas and all bananas are plum).
2. All plums are guavas. → False (It is possible but not definite).
3. Some plums are pumpkins. → True (As all pumpkins are bananas and all bananas are plum).

Hence, Only conclusions 1 and 3 follow.

Friends: Vivek, Akram, Sumit, Dara and Manjeet.

1) Sumit is elder than Dara.

2. Manjeet is younger than Dara.

Sumit > Dara > Manjeet

3) Two persons are elder than Sumit.

----- > ----- > Sumit > Dara > Manjeet

4) Vivek is elder than Akram. 

Therefore, the final arrangement is as,

Vivek > Akram > Sumit > Dara > Manjeet

Hence, eldest person is Vivek.

Persons:  A, B, C, D, E, F and G.

1) B is sitting between F and A.

2. G is to the immediate left of D.

3. Two persons are sitting between A and D.

4. C is to the immediate right of A.

5. Two persons are sitting between B and E.

The sitting arrangement is as follows:

Hence, F sits between D and B.

The least possible Venn diagram is as:

Conclusions:

1. All books are pen. → True (As all books are schools and all schools are pen).
2. All pens are book. → False (As all books are schools and all schools are pen imply that some pens are books).

Hence, Only conclusion 1 follows.

The logic is as:

Row 1: 14 + 23 = 37

37 × 3 = 111

111 - 14 = 97

Row 2: 22 + 41 = 63

63 × 3 = 189 

189 - 22 = 167

Row 3: 31 + 24 = 55

55 × 3 = 165

165 - 31 = 134

Hence, the missing term is 134.

The logic is as follows:

Row 1 : (11 + 1) × (14 + 1) = 180

Row 2 : (17 + 1) × (18 + 1) = 342

Similarly,

Row 3 : (23 + 1) × (20 + 1) = 504

Hence, the missing term is 504.

Month codes:

Code for Days:

Code for Centuries:

1600 → 6

1700 → 4

1800 → 2

1900 → 0

2000 → 6

2100 → 4

2200 → 2

2300 → 0

For,

15 April 2029,

Date = 15

Code for April = 6

Code for Century = 6

2029 = 2000 + 29

For, 2000 it is 6

For,

29 it is 29

And,

29/ 4 = 7

Adding all these = 15 + 6 + 6 + 29 + 7 = 63

63 / 7 = 0 (here we consider the remainder)

0 is the code for Sunday.

15 April 2029 is Sunday.

Hence, Sunday is the correct answer.

The logic is as:

Here prime numbers are added in the given series:

Hence, missing terms are 39, 52.

The mirror image is as follows:

Hence, the answer is option 3.

Now, by observing all the options, we concluded:

Hence, JPMS is the odd one.

By observing the given series, we got to know that,

Hence, SAJ  is the answer.

Manjot cycles on following path:

Now, as we can see that his path is making right angle triangle, we can apply Pythagoras Triplets here.

3² + 4² = 5²

Pythagoras triplet which involves 5 as hypotenuse is ( 3, 4, 5)

Hence, value of X and Y can be 3 km and 4 km.

Given:

Five objects: K, L, M, N and O.

M = 60 kg 

L = 2N

O = 3L

O = 2K

K = M = 60

⇒ O = 2(60)

    O = 120

Since, O = 3L

120 = 3L

L = 120/3

L = 40

Since, L = 2N

40 = 2N

N = 40/2

N = 20 

Hence, weight of N would be equal to 20 kg.

By observing given information, we got to know that,

By applying the same logic in SENSOR, we get,

Hence, OFTTQU is the answer.