Given equation: 126 ÷ 23 – 138 ÷ ( 5 × 4 – 6) + 4 = 1.
BODMAS Table:
Let's check each option one by one.
Option 1) 4 and 6
Given: 126 ÷ 23 – 138 ÷ ( 5 × 4 – 6) + 4 = 1
After interchanging the numbers we get;
⇒ 126 ÷ 23 – 138 ÷ (5 × 6 – 4) + 6 = 1
⇒ 126 ÷ 23 – 138 ÷ (30 – 4) + 6 = 1
⇒ 126 ÷ 23 – 138 ÷ 26 + 6 = 1
⇒ 5.48 – 5.30 + 6 = 1
⇒ 11.48 - 5.30 = 1
⇒ 6.18 ≠ 1
⇒ LHS ≠ RHS
Option 2) 138 and 126
Given: 126 ÷ 23 – 138 ÷ ( 5 × 4 – 6) + 4 = 1
After interchanging the numbers we get;
⇒ 138 ÷ 23 – 126 ÷ (5 × 4 – 6) + 4 = 1
⇒ 138 ÷ 23 – 126 ÷ (20 – 6) + 4 = 1
⇒ 138 ÷ 23 – 126 ÷ 14 + 4 = 1
⇒ 6 – 9 + 4 = 1
⇒ 10 - 9 = 1
⇒ 1 = 1
⇒ LHS = RHS
Option 3) 4 and 1
Given: 126 ÷ 23 – 138 ÷ (5 × 4 – 6) + 4 = 1
After interchanging the numbers we get;
⇒ 126 ÷ 23 – 138 ÷ (5 × 1 – 6) + 4 = 4
⇒ 126 ÷ 23 – 138 ÷ (5 – 6) + 4 = 4
⇒ 126 ÷ 23 – 138 ÷ -1 + 4 = 4
⇒ 5.48 – (-138) + 4 = 4
⇒ 9.48 – (-138) = 4
⇒ -147.48 ≠ 4
⇒ LHS ≠ RHS
Option 4) 23 and 138
Given: 126 ÷ 23 – 138 ÷ ( 5 × 4 – 6) + 4 = 1
After interchanging the numbers we get;
⇒ 126 ÷ 138 – 23 ÷ (5 × 4 – 6) + 4 = 1
⇒ 126 ÷ 138 – 23 ÷ (20 – 6) + 4 = 1
⇒ 126 ÷ 138 – 23 ÷ 14 + 4 = 1
⇒ 0.91 - 1.64 + 4 = 1
⇒ 4.91 - 1.64 = 1
⇒ 3.27 ≠ 1
⇒ LHS ≠ RHS
Hence, the correct answer is "Option 2".