Verbal and non-verbal reasoning, analogies, syllogisms, number series, coding-decoding, blood relations, and analytical puzzles.
A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
V, T, N, L, F, ?, X, V
D
E
C
A
Correct answer
D
Why this answer is correct
Pattern followed here,
Hence, the correct answer is “Option 1”.
Select the option that is related to the third letter cluster in the same way as the second letter cluster is related to the first letter cluster and sixth letter cluster is related to fifth letter cluster.
RMZ : PKX :: CPI : ? :: HQT : FOR
RJB
ANG
TOZ
SMC
Correct answer
ANG
Why this answer is correct
For 'RMZ' related to 'PKX':
| R(18) | M(13) | Z(26) |
|---|---|---|
| −2 ↓ | −2 ↓ | −2 ↓ |
| P(16) | K(11) | X(24) |
For 'HQT' related to 'FOR':
| H(8) | Q(17) | T(20) |
|---|---|---|
| −2 ↓ | −2 ↓ | −2 ↓ |
| F(6) | O(15) | R(18) |
Applying the same logic to 'CPI':
| C(3) | P(16) | I(9) |
|---|---|---|
| −2 ↓ | −2 ↓ | −2 ↓ |
| A(1) | N(14) | G(7) |
Thus, CPI is related to ANG.
Hence, the correct answer is 'Option 2'.
Select the option that is related to the third letter cluster in the same way as the second letter cluster is related to the first letter cluster and sixth letter cluster is related to fifth letter cluster.
AI : YB :: WL : ? :: SP : QI
VE
UH
UE
SH
Correct answer
UE
Why this answer is correct
The logic followed in this pattern is based on alphabetical shifts.
For 'AI' related to 'YB':
| A(1) | I(9) |
|---|---|
| −2 ↓ | −7 ↓ |
| Y(25) | B(2) |
For 'SP' related to 'QI':
| S(19) | P(16) |
|---|---|
| −2 ↓ | −7 ↓ |
| Q(17) | I(9) |
Applying the same logic to 'WL':
| W(23) | L(12) |
|---|---|
| −2 ↓ | −7 ↓ |
| U(21) | E(5) |
Thus, WL is related to UE.
Hence, the correct answer is 'Option 3'.
A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
QT, NS, ?, HN, EJ, BE, YY, VR
HQ
KQ
KS
JR
Correct answer
KQ
Why this answer is correct
Pattern followed here is,
Hence, the correct answer is “Option 2”.
In the following question, set of letter clusters are given. The letter clusters of each set are related to the letter clusters of the same set by some Logic/Rule/Relation. From the given alternatives, select a group of letter clusters which follows the same Logic/Rule/Relation.
(XG, VC, TY) (RB, PX, NT)
(ZP, AM, WH)
(TN, OK, KE)
(QM, OI, ME)
(IZ, EA, AU)
Correct answer
(QM, OI, ME)
Why this answer is correct
The logic followed in this pattern is based on alphabetical shifts within each set of letter clusters.
Each subsequent cluster is formed by subtracting fixed values from the positions of the letters.
For the set '(XG, VC, TY)':
| X(24) | G(7) |
|---|---|
| −2 ↓ | −4 ↓ |
| V(22) | C(3) |
| −2 ↓ | −4 ↓ |
| T(20) | Y(25) |
For the set '(RB, PX, NT)':
| R(18) | B(2) |
|---|---|
| −2 ↓ | −4 ↓ |
| P(16) | X(24) |
| −2 ↓ | −4 ↓ |
| N(14) | T(20) |
Applying the same logic to '(QM, OI, ME)':
| Q(17) | M(13) |
|---|---|
| −2 ↓ | −4 ↓ |
| O(15) | I(9) |
| −2 ↓ | −4 ↓ |
| M(13) | E(5) |
Thus, the set (QM, OI, ME) follows the same logic as the given letter clusters.
Hence, the correct answer is 'Option 3'.
What will be the product of the number of Mondays and Wednesdays in the month of February in the year 2002?
20
25
16
24
Correct answer
16
Why this answer is correct
The given year is 2002.
Since 2002 is not divisible by 4 (2002 ÷ 4 = 500.5), it is a non-leap year.
Therefore, February 2002 has 28 days.
Number of weeks in 28 days = 28 ÷ 7 = 4 weeks.
In a month consisting of exactly 4 weeks, every day of the week (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday) occurs exactly 4 times.
Number of Mondays in February 2002 = 4
Number of Wednesdays in February 2002 = 4
Product of the number of Mondays and Wednesdays = 4 × 4 = 16
Hence, the correct answer is “Option 3”.
Which of the following pairs of years have identical calendars?
1972 and 1978
1960 and 1967
1966 and 1977
1965 and 1977
Correct answer
1966 and 1977
Why this answer is correct
Let us check the pair 1966 and 1977:
Type of year: Both 1966 and 1977 are Ordinary years (not divisible by 4).
Now, we count the odd days from 1966 to 1976:
1966 (Ordinary year) = 1 odd day
1967 (Ordinary year) = 1 odd day
1968 (Leap year) = 2 odd days
1969 (Ordinary year) = 1 odd day
1970 (Ordinary year) = 1 odd day
1971 (Ordinary year) = 1 odd day
1972 (Leap year) = 2 odd days
1973 (Ordinary year) = 1 odd day
1974 (Ordinary year) = 1 odd day
1975 (Ordinary year) = 1 odd day
1976 (Leap year) = 2 odd days
Total odd days = 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 = 14 odd days.
Since 14 ÷ 7 = 2 with a remainder of 0, the sum of odd days is a multiple of 7.
Because both conditions are satisfied, the years 1966 and 1977 have identical calendars.
Checking other options:
Hence, the correct answer is “Option 3”.
A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
330, 421, ?, 603, 694, 785, 876, 967
508
513
512
509
Correct answer
512
Why this answer is correct
Logic followed here is,
330 + 91 = 421
421 + 91 = 512
512 + 91 = 603
603 + 91 = 694
694 + 91 = 785
785 + 91 = 876
876 + 91 = 967
Hence, the correct answer is “Option 3”.
5 girls R, S, T, V and H are sitting in a row facing north (not necessarily in the same order). Only one girl is to the right of S. H is to the immediate right of R and to the immediate left of V. What is the position of S from the left end of the row?
Second
First
Fourth
Third
Correct answer
Fourth
Why this answer is correct
5 girls R, S, T, V and H are sitting in a row facing north (not necessarily in the same order).
S is fourth from the left end of the row.
Hence, the correct answer is “Option 3”.
7 students P, Q, R, S, T, U and V are sitting around a circular table facing towards the centre (not necessarily in the same order). V is fourth to the right of Q. Considering towards left of S, there is only 1 student between S and Q. T is not the immediate neighbour of V or S. P is fourth to the right of U. Considering towards right of U, how many students are sitting between V and U?
2
3
1
4
Correct answer
2
Why this answer is correct
7 students P, Q, R, S, T, U and V are sitting around a circular table facing towards the centre (not necessarily in the same order).
Considering towards right of U, two students are sitting between V and U.
Hence, the correct answer is “Option 1”.
Two figures given on the left side of (::) are related with some logic/rule/relation. Select the missing figure on the right side of (::) from the given alternatives based on the same logic/rule/relation.
Correct answer
Why this answer is correct
Pattern followed here is,
Similarly,
Hence, the correct answer is “Option 1”.
Two figures given on the left side of (::) are related with some logic/rule/relation. Select the missing figure on the right side of (::) from the given alternatives based on the same logic/rule/relation.
Correct answer
Why this answer is correct
Pattern followed here is,
Similarly,
Hence, the correct answer is “Option 1”.
Select the option that is related to the fifth letter-number cluster in the same way as the second letter-number cluster is related to the first letter-number cluster and fourth letter-number cluster is related to third letter-number cluster. (
NOTE:
Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g.13 – Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
WF851 : UH823 :: QW270 : OY242 :: XS115 : ?
VU87
VT87
VU97
UV97
Correct answer
VU87
Why this answer is correct
WF851 : UH823
QW270 : OY242
Similarly,
XS115 : ?
Hence, the correct answer is 'Option 1'.
Select the option that is related to the first letter-number cluster in the same way as the fourth letter-number cluster is related to the third letter-number cluster and sixth letter-number cluster is related to fifth letter-number cluster. (
NOTE:
Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g.13 - Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
ACD13 : ? :: KPS15 : JOR196 :: ZYO17 : YXN256
CBZ169
ZBC144
BZC169
ZCB144
Correct answer
ZBC144
Why this answer is correct
KPS15 : JOR196
ZYO17 : YXN256
Similarly,
ACD13 : ?
Hence, the correct answer is 'Option 2'.
Select the option that is related to the fifth number in the same way as the second number is related to the first number and fourth number is related to third number. (
NOTE:
Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g.13 – Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
16 : 5832 :: 22 : 13824 :: 27 : ?
27000
24389
21952
12167
Correct answer
24389
Why this answer is correct
The logic followed here is:
Logic: Second Number = (First Number + 2)3
For the first pair 16 : 5832
⇒ (16 + 2)3
⇒ 183 = 5832.
Applying the same logic to the second pair 22 : 13824
⇒ (22 + 2)3
⇒ 243 = 13824.
Applying the same logic to the third pair 27 : ?
⇒ (27 + 2)3
⇒ 293 = 24389.
Hence, the correct answer is 'Option 2'.
In a certain coded language 'NANS' is coded as 'SZKN' and 'TARE' is coded as 'YZOZ'. How will 'ITCH' be coded in the same code language?
OSYE
MUBB
NSZC
MUAC
Correct answer
NSZC
Why this answer is correct
NANS is coded as SZKN →
TARE is coded as YZOZ →
Similarly, let us find the code for ITCH:
Hence, the correct answer is “Option 3”.
A watch is 4 minutes slow at 1 AM. It gains 8 seconds every hour. When will it show the correct time (in AM) again?
5:00
6:00
7:00
8:00
Correct answer
7:00
Why this answer is correct
The watch is 4 minutes slow at 1 AM.
The watch gains 8 seconds every hour.
First, convert the total lag into seconds:
Total lag = 4 minutes = 4 × 60 seconds = 240 seconds
Now, calculate the total number of hours required to gain 240 seconds:
Hours required = 240 seconds ÷ 8 seconds/hour
Hours required = 30 hours
Now, we add 30 hours to the initial time of 1 AM:
30 hours = 24 hours + 6 hours
1 AM + 24 hours = 1 AM (the following day)
1 AM + 6 hours = 7 AM (the following day)
Therefore, the watch will show the correct time at 7:00 AM.
Hence, the correct answer is “Option 3”.
In the following figure series, select the figure which can be placed at the sign of question mark (?) from the given alternatives.
Correct answer
Why this answer is correct
Pattern followed here is,
Hence, the correct answer is “Option 2”.
In the following figure series, select the figure which can be placed at the sign of question mark (?) from the given alternatives.
Correct answer
Why this answer is correct
Pattern followed here is,
Hence, the correct answer is “Option 4”.
8 years ago from present the ratio of L and M's age was 5 : 6. After 5 years from present their age will be in the ratio 6 : 7. What is the respective ratio of present ages of L and M?
72 : 53
73 : 86
24 : 33
63 : 59
Correct answer
73 : 86
Why this answer is correct
Ages 8 years ago from present:
| L | M |
|---|---|
| 5 | 6 |
Ages 5 years after from present:
| L | M |
|---|---|
| 6 | 7 |
The total time difference between 8 years ago and 5 years after = 8 + 5 = 13 years.
Change in ratio units for L = 6 − 5 = 1 unit
Change in ratio units for M = 7 − 6 = 1 unit
This 1 unit increase corresponds exactly to the 13-year interval from the past timeframe to the future timeframe.
Therefore, 1 unit = 13 years.
Age of L 8 years ago = 5 × 13 = 65 years
Age of M 8 years ago = 6 × 13 = 78 years
To find the present age, we add 8 years to their respective ages from 8 years ago.
Present age of L = 65 + 8 = 73
Present age of M = 78 + 8 = 86
The respective ratio of their present ages is 73 : 86.
Hence, the correct answer is “Option 2”.
Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.