The given year is 2013. Since it is not divisible by 4, it is an Ordinary Year. We calculate the sum of odd days starting from 2013 onwards:
2013 (Ordinary Year) ⇒ 1 odd day
2014 (Ordinary Year) ⇒ 1 odd day
2015 (Ordinary Year) ⇒ 1 odd day
2016 (Leap Year) ⇒ 2 odd days
2017 (Ordinary Year) ⇒ 1 odd day
2018 (Ordinary Year) ⇒ 1 odd day
Total sum of odd days = 1 + 1 + 1 + 2 + 1 + 1 = 7 odd days.
Since the sum of odd days becomes a multiple of 7 at the end of the year 2018, the calendar for the next year, 2019, will be exactly the same as the calendar for 2013.
Because 2019 is also an Ordinary Year, the condition is fully satisfied.
Hence, the correct answer is “Option 2”.
Alternate Method
To quickly find the repetition of a calendar, use the remainder when the year is divided by 4:
- Year ÷ 4 leaves remainder 1 ⇒ Calendar repeats after 6 years.
- Year ÷ 4 leaves remainder 2 ⇒ Calendar repeats after 11 years.
- Year ÷ 4 leaves remainder 3 ⇒ Calendar repeats after 11 years.
- Year ÷ 4 leaves remainder 0 (Leap Year) ⇒ Calendar repeats after 28 years.
For the year 2013:
2013 ÷ 4 leaves a remainder of 1 (as 2012 is the previous leap year).
According to the rule, 2013 + 6 = 2019.
Hence, the calendar for 2013 will be the same as the year 2019.